Tag: spaces and boundaries - 2

Questions Related to spaces and boundaries - 2

The area of a rectangle of length (x + 2) units and breadth (x -8) units is

  1. $x^2-16$

  2. $x^2-6x-16$

  3. $x^2-10x+16$

  4. $x^2-10$


Correct Option: B
Explanation:

$l\times b=(x+2)(x-8)$
$=x^2+[(2)+(-8)]x+(2)(-8)$
$=x^2-6x-16$

A closed box made of steel of uniform thickness has length breadth and height 12 dm, 10 sm and 8 dm respectively If the thickness of the steel sheet is 1 dm then the inner surface area is

  1. $ \displaystyle 456$ $\displaystyle dm^{2}$

  2. $ \displaystyle 376$ $\displaystyle dm^{2}$

  3. $ \displaystyle 264$ $\displaystyle dm^{2}$

  4. $ \displaystyle 696$ $\displaystyle dm^{2}$


Correct Option: B
Explanation:

A closed box made by steel with uniform thickness length 12 dm ,breath  10 dm and 8 dm and thickness  of steel is 1 dm

Then inner length =12-2=10 dm ,breadth=10-2=8 dm and height=8-2=6 dm 
So surface area of box=$2(lw+wh+lh)=2(10\times 8)+(8\times 6)+(10\times 6)=2(80+48+60)=2\times 188=376 dm ^{2}$

The side of a square is 2 cm Semicircles are constructed on two sides of the square then the area of the whole figure is

  1. $ \displaystyle (4+\pi )cm^{2} $

  2. $ \displaystyle (4+4\pi )cm^{2} $

  3. $ \displaystyle 4\pi cm^{2} $

  4. $ \displaystyle 8\pi cm^{2} $


Correct Option: A
Explanation:

The side of square is 2 cm 

Then area of square =$(2)^{2}=4 cm^{2}$
The Semicircle constructed on two side diameter 2 cm then radius =1 cm
Then area of one semicircle =$\frac{\pi r^{2}}{2}=\frac{\pi (1)^{2}}{2}=\frac{\pi }{2}$
Then  area of two semicircle=$2\times \frac{\pi }{2}=\pi $
So total area of whole figure=$(4+\pi )cm^{2}$

A square of side x is taken A rectangle is cut out from this square such that one side of the rectangle is half that of the square and the other is $\displaystyle \frac{1}{3}$ of the first side of the rectangle
What is the area of the remaining portion?

  1. $\displaystyle \left ( \frac{3}{4} \right )x^{2}$

  2. $\displaystyle \left ( \frac{7}{8} \right )x^{2}$

  3. $\displaystyle \left ( \frac{11}{12} \right )x^{2}$

  4. $\displaystyle \left ( \frac{15}{16} \right )x^{2}$


Correct Option: C
Explanation:

Let the side of square is x 

Then area of square=$x^{2}$
Given one side of rectangle is half of square=$\frac{x}{2}$
And second side is $\frac{1}{3}$ of other side=$\frac{1}{3}\times \frac{x}{2}=\frac{x}{6}$
Then area of rectangle =$\frac{x}{2}\times \frac{x}{6}=\frac{(x)^{2}}{12}$
So remaining area of square =$x^{2}-\frac{(x)^{2}}{12}=\frac{11x^{2}}{12}$

Find the area of a triangle whose sides are 9 cm, 12 cm, and 15 cm.

  1. $34cm^2$

  2. $44cm^2$

  3. $54cm^2$

  4. $55cm^2$


Correct Option: C
Explanation:
Given sides of the triangle
$a=9$cm
$b=12$cm
$c=15$cm
The given triangle is a right angle triangle
because $9^2+12^2=15^2$
$\therefore$Area $=\dfrac{1}{2}\times 9\times 12=54$ sq cm
Area $=54$ sq cm.

Area bounded by $y|y|-x|x|=1,\ y|y|+x|x|=1$ and $y=|x|$ is

  1. $\dfrac{\pi}{2}$

  2. ${\pi}$

  3. $\dfrac{\pi}{4}$

  4. $None\ of\ these$


Correct Option: A

A farmer wishes to cultivate four different crops in equal areas in his $1$ car of land.. The land he should allocate for each crop is:  

  1. $10\ m^{2}$

  2. $25\ m^{2}$

  3. $75\ m^{2}$

  4. $100\ m^{2}$


Correct Option: A

A room is x meters long, y meters broad, and z meters high; find how many square meters of carpet will be required for the floor and how many square meters of paper for the walls?

  1. xy and 2xy + 2yz

  2. xy and 2xz + 2yz

  3. xy and 2xy

  4. xy and 2xy + 2xz


Correct Option: B
Explanation:

$Length = x, breadth = y$
Area of the floor $= xy m^2$
Area of four walls $= 2h(l + b) = 2z (x +y) = 2zx + 2yz$

Find the area of a square inscribed in a circle of radius $\displaystyle 5\sqrt{2}$ cm (in $\displaystyle cm^{2}$)

  1. 75

  2. 100

  3. 125

  4. 150


Correct Option: B
Explanation:

The diagonal of the square will be equal to the diameter of the circle.
So,diagonal of the square $ = 2 \times 5 \sqrt {2} = 10 \sqrt {2} $

Diagonal of a square $ = \sqrt {2} \times side $
So, $ 10 \sqrt {2} = \sqrt {2} \times side $
$ => Side  =  10  cm $

Area of the square $ = { side }^{ 2 } = { 10 }^{ 2 } = 100 $ sq cm

What is the maximum area of a four-sided plane with a perimeter of $12$ inches?

  1. $8$ square inches

  2. $10$ square inches

  3. $6$ square inches

  4. $9$ square inches


Correct Option: D
Explanation:

The area is maximum when the four-sided plane is a square.

The perimeter of a square $ = 4 \times$ side $= 12 $ inches
$ \Rightarrow$ side $= 3  $ inches

Now, area of the square $ =$ side $\times$ side $= 3 \times 3 = 9 $ square inches.