STEP1 EXEC PGM=P1 STEP2 EXEC PGM=P2,COND=EVEN STEP3 EXEC PGM=P3,COND=((8,LE,STEP1),ONLY) If the condition code of the step1 is 4 and the step2 was abended then which statement is correct.

  1. step1, step2 and step3 will execute

  2. only step1 and step3 will execute

  3. only step1 and step2 will execute

  4. only step1 will execute


Correct Option: A

AI Explanation

To determine which statement is correct, let's analyze the given JCL statements and their conditions.

STEP1 - EXEC PGM=P1 This step executes program P1.

STEP2 - EXEC PGM=P2, COND=EVEN This step executes program P2 only if the previous step's condition code is an even number.

STEP3 - EXEC PGM=P3, COND=((8,LE,STEP1),ONLY) This step executes program P3 only if the condition code of STEP1 is less than or equal to 8.

Given the conditions and the scenario provided:

  • The condition code of STEP1 is 4.
  • The step2 was abended.

Let's go through each option to understand why it is correct or incorrect:

Option A) step1, step2, and step3 will execute This option is correct because even though step2 was abended, step3 will still execute since the condition for step3 is based on the condition code of step1, which is 4 (less than or equal to 8).

Option B) only step1 and step3 will execute This option is incorrect because step2 is conditioned to execute if the condition code of step1 is even. Since the condition code of step1 is 4 (even), step2 should execute.

Option C) only step1 and step2 will execute This option is incorrect because step3 is conditioned to execute if the condition code of step1 is less than or equal to 8. Since the condition code of step1 is 4 (less than or equal to 8), step3 should execute.

Option D) only step1 will execute This option is incorrect because both step2 and step3 have conditions that allow them to execute based on the condition code of step1.

Therefore, the correct answer is Option A) step1, step2, and step3 will execute.

Find more quizzes: