Tag: interpreting data and graphs

Questions Related to interpreting data and graphs

Histogram are a great way to show results of 

maths interpreting data and graphs histograms for non-uniform class widths histograms with unequal class intervals revisiting histograms

  1. categories

  2. continuous data

  3. both $A$ and $B$

  4. None of these

Show answer
Correct Option: B
Explanation:

Answer:-

B) Continuous data
Histogram is curve that is represented in the form of bars for continuous data.

An ogive curve is 

maths interpreting data and graphs histograms for non-uniform class widths histograms with unequal class intervals revisiting histograms

  1. Histogram

  2. Frequency polygon

  3. Cumulative frequency

  4. All the above

Show answer
Correct Option: A

Draw the histogram and use it to find the mode for the following frequency distribution.

House - Rent in Rs. per month $4000 - 6000$ $6000 - 8000$ $8000 - 10000$ $10000 - 12000$
Number of families $200$ $240$ $300$ $50$
maths interpreting data and graphs histograms for non-uniform class widths histograms with unequal class intervals revisiting histograms

  1. Rs. $8000$

  2. Rs. $8350$

  3. Rs. $8500$

  4. Rs. $8750$

Show answer
Correct Option: B
Explanation:
max. frequency = $300$
so group is = $8000-10000$
so mode = $L+\dfrac{f _{1}-f _{0}}{2f _{1}-f _{0}-f _{2}}\times w$
$L$= lower class boundary of the modal group
$f _{1}$ = frequency of the modal group
$f _{0}$= frequency of the class preceding or just before the modal class
$f _{2}$ = frequency of the class succeeding or just after the modal class
$w$= group width
mode = $8000+ \dfrac{300-240}{2\times 300-240-50}\times 2000$
mode= $8000+387.096$
mode = $8387.096$
mode = $8350$

Represent the following data by histogram and hence compute mode.

Price of sugar per kg (in Rs.) 18 - 20 20 - 22 22 - 24 24 - 26 26 - 28 Total
Number of weeks 4 8 22 12 6 52
maths interpreting data and graphs histograms for non-uniform class widths histograms with unequal class intervals revisiting histograms

  1. 21.2 Rs.

  2. 22.2 Rs.

  3. 23.2 Rs.

  4. 24.2 Rs.

Show answer
Correct Option: C
Explanation:
max. frequency = $22$
so group is = $22-24$
so mode = $L+\dfrac{f _{1}-f _{0}}{2f _{1}-f _{0}-f _{2}}\times w$
$L$= lower class boundary of the modal group
$f _{1}$ = frequency of the modal group
$f _{0}$= frequency of the class preceding or just before the modal class
$f _{2}$ = frequency of the class succeeding or just after the modal class
$w$= group width
mode = $22+ \dfrac{22-8}{2\times 22-8-12}\times 2$
mode= $22+1.167$
mode = $23.167$
mode = $23.2$