Tag: electron configuration

Questions Related to electron configuration

On the Mulliken scale, the average of ionization potential and electrons affinity is known as _____(electronegativity/affinity).

  1. electronegativity

  2. electroneaffinity

  3. electropositivity

  4. none


Correct Option: A
Explanation:

On Mulliken scale, the average of ionization potential and electrons affinity is known as electronegativity.

If the E.N. value of Nitrogen in the pauling scale is 3.0, then he value in mulliken scale will be

  1. $11.2$

  2. $22.4$

  3. $8.4$

  4. $3.0$


Correct Option: C

Which of the following is the correct order of hydrated radii?

  1. $Li^{+} < Na^{+} < K^{+} < Rb^{+} < Cs^{+}$

  2. $Rb^{+} < Na^{+} < Li ^{+} < Cs^{+} < K^{+}$

  3. $Cs^{+} < Rb^{+} < K^{+} < Na ^{+}< Li^{+}$

  4. $Li^{+} < K^{+} < Na^{+} < Rb ^{+} < Cs ^{+}$


Correct Option: A

Electronegativity of $F$ on Pauling's scale is 4.0. The value on Mulliken's scale is:

  1. $11.2$

  2. $14.4$

  3. $16.8$

  4. None of these


Correct Option: A
Explanation:

Mulliken proposed that the arithmetic mean of the first ionization energy (I) and the electron affinity (Eea) should be a measure of the tendency of an atom to attract electrons.
$X= \dfrac{E _i + E _{Ea}}{2}$
Electronegativity of $F$ on Mulliken's scale is hence $11.2$

EN(mulliken scale) of the element (A) is $E _1$ and IP is $E _2$. Hence, EA will be:

  1. $2E _1 - E _2$

  2. $E _1 - E _2$

  3. $E _1 - 2E _2$

  4. $(E _1 + E _2)/2$


Correct Option: A
Explanation:

As we know,
$\displaystyle EN = \frac{(IP) + (EA)}{2}$ 


$EA = 2 EN - IP$

$EA = 2E _1 - E _2$

The ionic radii of ${Rb}^{+}$ and ${I}^{-}$ are $1.46$ and $2.16$ $\mathring { A } $, respectively. The most probable type of structure exhibited by it is

  1. $CsCl$ type

  2. $NaCl$ type

  3. $ZnS$ type

  4. $Ca{F} _{2}$ type


Correct Option: B

Which pair of element has almost identical electronegativity values?

  1. $In,Tl$

  2. $B,Al$

  3. $B,Ga$

  4. $Al,Tl$


Correct Option: A
Explanation:

Both have close IE and electron affinity values(both are metals) and hence similar electronegativity values.
$Electronegativity=\dfrac{IE+EA}{2}$

Mulliken scale of elecrtonegativity uses the concept of:

  1. E. A. and EN of pauling

  2. E.A. and atomic size

  3. E.A. and I.P.

  4. E.A. and bond energy


Correct Option: C
Explanation:

Mulliken proposed that the arithmetic mean of the first ionization energy and the electron affinity should be a measure of the tendency of an atom to attract electrons.

If the ionisation potential is IP, electron affinity is EA and electronegativity is x then which of the following relation is correct.

  1. 2X-EA-IP=0

  2. 2EA-X-IP=0

  3. 2IP-X-EA=0

  4. All of the above


Correct Option: A
Explanation:
Electron affinity: The amount of energy released when an electron is added to the outermost shell of one mole of an isolated gaseous atom in its lower energy state.

Ionisation energy: Minimum energy required to remove most loosly held outer most shell e – in ground state from an isolated gaseous atom is known as ionisation potential.

$\displaystyle X= \frac{IP+EA}{2}$

$2X-IP-EA=0$

Electronegativity of F on Pauling scale is 4.0. Its value on Mulliken scale is__________.

  1. 12.35

  2. 11.0

  3. 15.2

  4. 14.2


Correct Option: A
Explanation:

Electronegativity of F on Pauling scale is 4.0. Its value on Mulliken scale is 11.2
$\displaystyle \chi (Pauling) = 0.34 \chi (Mulliken) -0.2 $
$\displaystyle 4.0 = 0.34\chi (Mulliken) -0.2 $
$\displaystyle \chi (Mulliken) = 12.35 $