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Let's play with water - class-IX

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In an experiment, 2.4 g of iron oxide on reduction with hydrogen gave 1.68 g of iron. In another experiment, 2.9 g of iron oxide gave 2.09 g of iron on reduction. Which law is illustrated from the above data?

  1. Law of constant proportions

  2. Law of multiple proportions

  3. Law of reciprocal proportions

  4. Law of conservation of mass


Correct Option: A
Explanation:
In experiment 1,
$2.4\ g$ of iron oxide gives $1.68\ g$ iron on reduction with hydrogen.
$FeO \rightarrow Fe+O _2$
Percent of $Fe$ in $FeO$ is = $\frac{1.68}{2.4} \times 100=70$
Therefore ratio of $m _{Fe}:m _{O}::7:3$
In experiment 2:
$2.9\ g$ of iron oxide gives $2.09\ g$ iron on reduction.
Percent of $Fe$ in $FeO$ is = $\frac{2.09}{2.9} \times 100=72$

Therefore ratio of $m _{Fe}:m _{O} \approx 7:3$
When a given chemical compound contains its component elements in fixed ratio (by mass) and does not depend on its source and method of preparation, it follows law of constant proportion.
option A is correct

A sample of calcium carbonate $(CaCO _{3})$ has the following percentage composition:
Ca = 40%; C = 12%; O = 48%.
If the law of constant proportions is true, then the weight of calcium in 4 g of a sample of calcium carbonate from another source will be:

  1. 0.016 g

  2. 0.16 g

  3. 1.6 g

  4. 16 g


Correct Option: C
Explanation:

In $100$ $g$ $CaCO _3$, $40$ $g$ $Ca$ is present.

In $4$ $g$ $CaCO _3$, Let $x$ $g$ $Ca$ be present
$\cfrac{x}{4}=\cfrac{40}{100}$
$\implies x=1.6$ $g$

A sample of calcium carbonate $\left( CaC{O} _3 \right)$ has the following percentage composition:
Ca = 40%; C = 12%; O = 48%.
If the law of constant proportions is true, then the weight of calcium in 4 g of a sample of calcium carbonate from another source will be ?

  1. 0.016 g

  2. 0.16 g

  3. 1.6 g

  4. 16 g


Correct Option: C
Explanation:

Calcium carbonate from any source contains 40% calcium. 

So each 1 g of calcium carbonate contains 0.4g of calcium.
Thus, for 4 g of calcium carbonate, the amount of calcium $=4\times 0.4=1.6g$

Different samples of water were found to contain hydrogen and oxygen in the ratio of 1 : 8. This shows the law of:

  1. multiple proportions

  2. constant proportions

  3. reciprocal proportions

  4. conservation of mass


Correct Option: B
Explanation:

Law of Constant proportion states that a chemical compound always contains same elements combined together in the same proportion by mass.

All samples of carbon dioxide contain carbon and oxygen in the mass ratio of $3 : 8$. This is in agreement with the law of :

  1. conservation of mass

  2. constant proportion

  3. multiple proportions

  4. gaseous volumes


Correct Option: B
Explanation:

LAW OF CONSTANT OR DEFINITE PROPORTION : It was given by Proust.
It states that all chemical compounds are found to have constant composition irrespective of their method of preparation or sources.
THE LAW OF MULTIPLE PROPORTION : It was given by Dalton.
It states that when one element combines with the other element to form two or more different compounds, the mass of one element which combines with a constant mass of the other bear a simple ratio to one another.

Law of constant composition is also called as the law of :

  1. Conservation of mass

  2. Conservation of energy

  3. Multiple proportion

  4. Definite proportion


Correct Option: D
Explanation:

Law of constant composition is also called as the law of Definite proportion which says that the law of constant composition is a chemistry law which states samples of a pure compound always contain the same elements in the same mass proportion.

When hydrogen and oxygen combine to form water, they form:

  1. an unstable compound

  2. a stable mixture

  3. an unstable mixture

  4. an extremely stable compound


Correct Option: D
Explanation:

When hydrogen and oxygen combine to form water, they form water an extremely stable compound. We can say water is a stable compound because tremendous energy is released is a signal that hydrogen and oxygen are very eager to become water or in another way it is very hard to break water molecules apart into its components.

$2H _2+O _2\longrightarrow 2H _2O$

In ammonia, nitrogen and hydrogen always combine in $14:3$ ratio by mass. This is in agreement with :

  1. Law of conservation of mass

  2. Law of definite proportion

  3. Law of multiple proportion

  4. Law of combining volume


Correct Option: B
Explanation:

Law of definite proportion states that elements always combine in the definite ratio by mass. So it is in agreement with the law of definite proportion.

Law of definite proportion does not apply to nitrogen oxide because:

  1. Atomic weight of nitrogen is not conserved

  2. Molecular weight of nitrogen is variable

  3. Equivalent weight of nitrogen is variable

  4. Atomic weight of oxygen is variable


Correct Option: C
Explanation:

Nitrogen forms multiple compounds with oxygen. Hence, we cannot apply the law of definite proportion to nitrogen oxide.

The ratio of mass of nitrogen and oxygen in nitric oxide is in :

  1. $7:16$

  2. $1:8$

  3. $7:8$

  4. $7:15$


Correct Option: C
Explanation:

Formula of Nitric oxide is NO. Mass of nitrogen in NO is 14 g. Mass of oxygen is 16. Therefore ratio is $14:16$ i.e $7:8$.

A solution of copper oxide was prepared by heating, igniting and precipitation. Which of the following method will give higher ratio of copper oxide?

  1. Heating

  2. Precipitation

  3. Ignition

  4. All of the above will give the same ratio


Correct Option: D
Explanation:

In a compound the ratio of the atoms or element by mass remains always same irrespective of the source of compound. This means a certain compound always formed by the combination of atoms in same ratio by mass. Hence, copper oxide made from any method will always give the same ratio of copper oxide.

In a compound the ratio of the atoms or element by mass remains always same irrespective of :

  1. temperature

  2. nature of compound

  3. source of compound

  4. size of compound


Correct Option: C
Explanation:

Compounds are formed by the combination of two or more elements. In a compound the ratio of the atoms or element by mass remains always same irrespective of the source of compound. This means a certain compound always formed by the combination of atoms in same ratio by mass. If the ratio of mass of constituent atoms will be altered the new compound is formed.

If the ratio of the atoms by mass is altered then :

  1. new compound formed

  2. same compound are formed

  3. no reaction takes place

  4. state of compound are changed


Correct Option: A
Explanation:

In a compound the ratio of the atoms or element by mass remains always same irrespective of the source of compound. This means a certain compound always formed by the combination of atoms in same ratio by mass. If the ratio of mass of constituent atoms will be altered the new compound is formed.

Law of constant proportion states that :

  1. a chemical compound always contains exactly the same proportion of elements by mass.

  2. mass can neither be created nor destroyed in a chemical reaction.

  3. when two elements combine with each other to form two or more than two compounds, the masses of one the element which combines with the fixed mass of the other, bears a simple whole number ratio.

  4. total mass of products is always equal to the total mass of reactants.


Correct Option: A
Explanation:

Law of Constant Proportion states that a chemical compound always contains exactly the same proportion of elements by mass. This law is also known as Law of definite proportions. Joseph Louis Proust gave this law hence, this law is also known as Prousts Law.

Hydrogen combines with oxygen to form water. Water exists in:

  1. liquid

  2. solid

  3. gas

  4. plasma


Correct Option: A,B,C
Explanation:

Hydrogen combines with oxygen to form water. Water exists in solid ( ice), liquid ( water) and gas ( water vapor).

Hydrogen combines with oxygen to form $H _2O$ in which 16 g of oxygen combine with 2 g of hydrogen. Hydrogen also combines with carbon to form $CH _4$ in which 2 g of hydrogen combine with 6 g of carbon.If carbon and oxygen combine together then they will do show in the ratio of 

  1. 13 : 32

  2. 6 : 16

  3. 1 : 2

  4. 12 : 24


Correct Option: B

Two gases found dissolved in natural water are 

  1. oxygen and carbon dioxide

  2. hydrogen and oxygen

  3. sulphur dioxide and hydrogen

  4. chlorine and ammonia


Correct Option: A

A sample of pure carbon dioxide, irrespective of its source contains 27.27 % carbon and 72.73% oxygen. The given data supports: 

  1. Law of constant composition

  2. Law of conservation of mass

  3. Law of reciprocal proporties

  4. Law of multiple proportions


Correct Option: A

In Haber's process, the volume of ammonia relative to the total volume of reactants at STP is:

  1. one fourth

  2. one half

  3. same

  4. three fourth


Correct Option: B
Explanation:

This reaction occurs in Haber's process-


$N _2$ + $3H _2$ $\rightarrow$ $2NH _3$

The total volume of reactants at STP is 4x

The volume of ammonia is 2x.

Hence, Volume of ammonia = $\dfrac{1}{2}$(Volume of reactant)

$2.16$ grams of Cu, on reaction with $HNO _{3}$, followed by ignition of the nitrate, gave $2.7$ g of copper oxide. In another experiment $1.15$ g of copper oxide, upon reaction with hydrogen, gave $0.92$ g of copper. This data illustrate the law of:

  1. multiple proportions

  2. definite proportions

  3. reciprocal proportions

  4. conservation of mass


Correct Option: B
Explanation:

In the first sample of copper oxide (obtained by the action of nitric acid on Cu), the mass of Cu is 2.16 g and the mass of oxygen is $\displaystyle 2.7 - 2.16  =  0.54$ g. 

The ratio of the mass of Cu to the mass of oxygen is $\displaystyle \dfrac {2.16}{0.54} = 4 :1$

In the second sample of copper oxide (which reacts with hydrogen) , the mass of Cu is 0.92 g and the mass of oxygen is $\displaystyle 1.15 - 0.92  =  0.23$ g. 
The ratio of the mass of Cu to the mass of oxygen is $\displaystyle \dfrac {0.92}{0.23} = 4 :1$
Hence, this illustrates the law of definite Proportions.

An experiment showed that a lead chloride solution is formed when 6.21 g of lead combines with 4.26 g of chlorine. What is the empirical formula of this chloride? 

[Pb = 207; Cl = 35.5]

  1. $PbCl _3$

  2. $PbCl _2$

  3. $PbCl _4$

  4. $PbCl$


Correct Option: C
Explanation:
  Mass        Atomic weight    Relative no. of moles    Simplest ratio
Lead           6.21 g        207     6.21/207 = 0.03    0.03/0.03 = 1
Chlorine 4.26 g        35.5     4.26/35.5 = 0.12    0.12/0.03 = 4


Hence, empirical formula is $PbCl _4$

Common salt obtained from Clifton beach contained $60.75\%$ chlorine while $6.40$ g of a sample of common salt from Khewra mine contained $3.888$ g of chlorine. State the law illustrated by these chemical combinations.

  1. Law of reciprocal proportion

  2. Law of multiple proportion

  3. Law of constant composition

  4. None of the above


Correct Option: C
Explanation:

First case :


Common salt from Clifton beach contains $=$ $60.75\%$ $Cl _2$

$100$ g of salt $=60.75$ g of $Cl _2$

$1$ g of salt $=\dfrac {60.75}{100}=0.6075$ g of $Cl _2$

Second case :


$6.40$ g of $NaCl$ from Khewra mine $=3.888$ g of $Cl _2$

$1$ g of $NaCl$ from Khewra mine $=\dfrac {3.888}{6.40}=0.6075$ g of $Cl _2$

Thus, the weight of $Cl _2$ in $1$ g of salt in both the cases is same. Hence, the law of constant composition is verified.


Hence the correct option is C.

A sample of calcium carbonate $\displaystyle \left ( CaCO _{3} \right )$ has the percentage composition as given: $Ca = 40\%,\ C = 12\%,\ O = 48\%$. 


If the law of constant proportions is true, then the weight of calcium in $4$ g of a sample of calcium carbonate obtained from another source will be :

  1. $0.016$ g

  2. $0.16$ g

  3. $1.6$ g

  4. $16$ g


Correct Option: C
Explanation:

In $100 $ g $\displaystyle CaCO _{3}$, weight of $Ca$ is $40 $ g.

In $4$ g $\displaystyle CaCO _{3}$, weight of $Ca$ is $=\displaystyle \frac{40}{100}\times 4=1.6$ g

Hence, the correct option is $C$

1.2375 g of cupric oxide on being heated in a current of hydrogen gave 0.9322 g of the metal In another experiment 0.9369 g of pure copper was dissolved in nitric acid Excess of acid evaporated and the residue has ignited The weight of the cupric oxide left was 1.2469 g. Which law of chemical combination is shown by the above results?

  1. Law of constant proportions

  2. Law of multiple proportions

  3. Law of conservation of mass

  4. Law of constant volumes


Correct Option: B
Explanation:

law of multiple proportion is shown as copper reacts with two different compounds .

The percentage of copper and oxygen in a sample of CuO obtained from different methods were found to be same. This proves the law of :

  1. Constant proportion

  2. Multiple proportion

  3. Reciprocal proportion

  4. None of these


Correct Option: A
Explanation:

The percentage of copper and oxygen in a sample of CuO obtained from different methods were found to be same. This proves the law of Constant proportion as the ratio of Cu:O remains constant

$1.375$ g of cupric oxide was reduced by heating in a current of hydrogen and the weight of copper obtained was $1.098$ g. In another experiment, $1.156$ g of copper was dissolved in nitric acid and the resulting solution was evaporated to dryness. The residue of copper nitrate when strongly heated was converted into $1.4476$ g of cupric oxide. State the law illustrated by these chemical combinations.

  1. Law of reciprocal proportion

  2. Law of multiple proportion

  3. Law of constant composition

  4. None of these


Correct Option: C
Explanation:

Law of constant composition states that all samples of a given chemical compound have the same elemental composition by mass. 

Here, in the first experiment 1.375 g of cupric oxide was reduced by heating in a current of hydrogen and the weight of copper obtained was 1.098 g.
Which means 1.375 g of cupric oxide has 1.098 g of carbon and $1.375-1.098 = 0.277$ g of oxygen. 
Copper and oxygen are in the ration $\frac{1.098}{0.277} = \frac{1}{4}$. 
In the second experiment 1.156 g of copper was dissolved in nitric acid to form copper nitrate, which on strongly heating got converted into 1.4476 g of cupric oxide. 
Which means 1.4476 g of cupric oxide has 1.156 g of copper and $ 1.4476-1.156 =0.2911 g $ oxygen.
Copper and oxygen are in the ratio $\frac{1.156}{0.2911} = \frac{1}{4}$.
Which mean what ever may be the source of a compound, it has same elemental composition by mass in all samples.

A pair of compounds which is an illustration of law of multiple proportions is:

  1. ${H} _{2}O$ and ${D} _{2}O$

  2. $NaOH$ and $KOH$

  3. $NaCl$ and $NaBr$

  4. $CO$ and ${CO} _{2}$


Correct Option: D
Explanation:

Carbon combines with oxygen in $1:1$ ratio to form carbon monoxide and $1:2$ ratio to form carbon dioxide.

Any sample of pure water, irrespective of its source, contains 88.89% oxygen and 11.11 % hydrogen by mass. The data supports the:

  1. Law of conservation of mass

  2. Law of constant composition

  3. Law of multiple proportion

  4. Law of reciprocal proportion


Correct Option: B
Explanation:

This law states that all samples of a given chemical compound have the same elemental composition by mass e.g. oxygen makes 8/9th of the mass of pure water while hydrogen makes up the remaining 1/9th of the mass.

Hydrogen combines with nitrogen in a 3:14 weight ratio to form ammonia. If every molecule of ammonia contains three atoms of hydrogen and one atom of nitrogen, an atom of nitrogen must weigh :

  1. 14 times the mass of a hydrogen atom

  2. 14/3 times the mass of a hydrogen atom

  3. 3 times the mass of a hydrogen atom

  4. 3/14 times the mass of a hydrogen atom


Correct Option: A
Explanation:

Atoms of different elements combine in simple whole number ratios to form chemical compounds. Combination always takes place in the simplest possible way between particles of different weights.

Hydrogen combines with oxygen in a 1:8 weight ratio to form water. If every molecule of water contains two atoms of hydrogen and one atom of oxygen, an atom of oxygen must weigh :

  1. 8 times the mass of a hydrogen atom

  2. 16 times the mass of a hydrogen atom

  3. 1/16 times the mass of a hydrogen atom

  4. 1/8 times the mass of a hydrogen atom


Correct Option: B
Explanation:

The law of definite proportions and constant composition states that all samples of a given chemical compound have the same elemental composition by mass e.g. oxygen makes up up about 8/9th of mass of any sample of pure water while hydrogen makes up the remaining 1/9th of mass.

When elements react, their atoms combine in :

  1. a simple whole number ratio (unique for each pair of elements)

  2. arbitrary proportions

  3. simple whole number ratios (more than one possible)

  4. 1:1 ratios


Correct Option: C
Explanation:

The law of multiple proportions state that if two elements form more than one compound between them then the ratios of the masses of the second element which combine with a fixed mass of the first element will be ratios of small whole numbers.

When $3\ g$ of carbon is burnt in $8\ g$ of oxygen, $11 g$ of carbon dioxide is produced. What mass of carbon dioxide will be formed when $3\ g$ of carbon is burnt in $50\ g$ oxygen?

  1. $12\ g$

  2. $13\ g$

  3. $11\ g$

  4. $10\ g$


Correct Option: C
Explanation:

This is governed by the law of definite proportion. Carbon and oxygen combine in $3:8$ ratio. So $11 \ g$ of carbon dioxide is formed. 


Hence, in the latter case too, only $8 \ g$ of $O _2$ will be reacted with 3g of carbon (because carbon is the limiting reagent here ) to form 11g of $CO _2$ and  $42 \ g$ of oxygen will remain unreacted.

Hence, the correct option is C.

When $1.375\ g$ of cupric oxide is reduced on heating in a current of hydrogen, the weight of copper remaining $1.098\ g$. In another experiment, $1.179\ g$ of copper is dissolved in nitric acid and resulting copper nitrate converted into cupric oxide by ignition. The weight of cupric oxide formed is $1.476 \ g$. This is in agreement with :

  1. Law of definite proportion

  2. Law of mass conservation

  3. Law of momentum conservation

  4. None of the above


Correct Option: A
Explanation:

First experiment
$\bullet$ Copper oxide $=1.375 g$
$\bullet$ Copper left $= 1.098 g$
$\bullet$ Oxygen present $= 1.375 - 1.098 = 0.277 g$
Percentage of oxygen in $CuO = (0.277) (100$ %) $1.375 = 20.15$ %

Second Experiment
$\bullet$ Copper taken $= 1.179 g$
$\bullet$ Copper oxide formed $= 1.476 g$
$\bullet$ Oxygen present $= 1.476 - 1.179 = 0.297 g$
Percentage of oxygen in $CuO = (0.297) (100$ %) $1.476 = 20.12$ %
Percentage of oxygen is approximately (within significant figures limit) the same in both the above cases. So the law of constant composition is illustrated.

In chemistry, the law of definite proportion, sometimes called Proust's law or the law of definite composition, or law of constant composition states that a given chemical compound always contains its component elements in fixed ratio and does not depend on its source and method of preparation.

Who stated the law of constant proportion?

  1. Archimedes

  2. Dalton

  3. Proust

  4. Antony Lavoisier


Correct Option: C
Explanation:

The law ofconstant proportion is given by Proust.

A 78.0 g sample of an unknown compound contains 12.4 g of hydrogen.  What is the percent by mass of hydrogen in the compound?

  1. 25%

  2. 35%

  3. 16%

  4. 50%


Correct Option: C
Explanation:

% of $H$$=$$\dfrac{12.4}{78}\times100$$=16$%

The percentage of copper and oxygen in samples of CuO obtained by different methods were found to be the same. This illustrates the law of:

  1. Constant proportion

  2. Conservation of mass

  3. Multiple proportion

  4. Reciprocal proportion


Correct Option: A
Explanation:

In chemistry, the law of definite proportions, sometimes called Proust's law or the law of definite composition, states that a chemical compound always contains exactly the same proportion of elements by mass and this law further says that, in any particular chemical compound, all samples of that compound will be made up of the same elements in the same proportion or ratio. For example, any water molecule is always made up of two hydrogen atoms and one oxygen atom in a ratio.

Which of the following statement is incorrect for the composition of water?

  1. For water, the gravimetric or mass ratio of hydrogen to oxygen is $1:8$

  2. In water, the ratio of hydrogen and oxygen is $2:1$ by volume

  3. The ratio in which hydrogen and oxygen combine gives the composition of water.

  4. None of the above


Correct Option: D
Explanation:

All of the following statements are correct for the composition of water.
A
For water, the gravimetric or mass ratio of hydrogen to oxygen is 1:8.
B
In water, the ratio of hydrogen and oxygen is 2:1 by volume.
C
The ratio in which hydrogen and oxygen combine gives the composition of water.
Note:
$2H _2 + O _2 \rightarrow 2H _2O$
Thus, the composition of water is $H : O = 2: 1 $
It is the ratio in which hydrogen and oxygen combine. The atomic masses of H and O are 1 and 16 respectively. Hence, for water, the gravimetric or mass ratio of hydrogen to oxygen is 2:16 or 1:8.
In water, the ratio of hydrogen and oxygen is 2:1
by volume. It is equal to the ratio in which hydrogen and oxygen combine.

Nitrogen reaction with oxygen to form nitrogen (III) oxide.


What will be the volume ratio of the reactants and products of the given reaction?

  1. 2 : 3 : 2

  2. 2 : 3 : 4

  3. 1 : 3 : 2

  4. 2 : 1 : 2


Correct Option: A
Explanation:

$2 N _2 + 3 O _2 \rightarrow 2N _2 O _3$

reactants = $N _2 \, \& \, O _2$
Product = $N _2O _3$
Ratio are $2 : 3 : 2$ by law of constant proportions 
{stionchiometry coefficient) 


A sample of $CaCO _3$ has Ca - 40%, C = 12% and 0 = 48%. If the law of constant proportions is true, then the mass of Ca in 5 g of $CaCO _3$ from another source will be:

  1. 2.0 g

  2. 0.2 g

  3. 0.02 g

  4. 20.0 g


Correct Option: A
Explanation:

Since, mass percentage of Ca in $CaCO _3 = 40 \text{%} $ and law of constant proportion is true.
So, the mass percentage of $Ca $ in $ 5gm$ $CaCO _3$ will also be $40\text%.$
Hence,$ 40\text{% of 5gm =}$$ 5\times $$\dfrac{40}{100}$ $= 2gm $
Hence, answer is option A.

Potassium combines with two isotopes of chlorine $(^{35} Cl\,\, and\,\, ^{37}Cl)$ respectively to form two samples of $KCl$ Their formation follows the law of:

  1. constant proportions

  2. multiple proportions

  3. reciprocal proportions

  4. none of these


Correct Option: A
Explanation:
According to the Law of Definite Proportions, a chemical compound will always have exactly the same proportion of elements by mass.
This means that the elements that make up a compound will always have the same per cent composition by mass, regardless of the actual mass of the sample.
In this case, potassium chloride has a molar mass of 74.551 g/mol. The two elements that form potassium chloride are potassium, which has a molar mass of 39.0983 g/mol, and chlorine, which has a molar mass of 35.4527 g/mol.
This tells you that every mole of potassium chloride weighs 74.551 g, out of which 39.0983 g is potassium and 35.4527 g is chlorine.

Therefore, chlorine and potassium will always be in a ratio by mass of
$\dfrac{35.4527g}{39.0983g}$=0.90681
so the constant proportion is the right answer 

In the reaction, $N _2 + 3H _2 \rightarrow 2NH _3$, the ratio of volumes of nitrogen, hydrogen and ammonia is 1 : 3: 2. These figures illustrate the law of: 

  1. constant proportions

  2. Gay-Lussac

  3. multiple proportions

  4. reciprocal proportions


Correct Option: B
Explanation:

ANS; B
Gay Lussac’s Law of Combining Volumes states that when gases react, they do so in volumes which bear a simple ratio to one another, and to the volume of the product(s) formed if gaseous, provided the temperature and pressure remain constant.

The law of constant proportions was enunciated by: 

  1. Dalton

  2. Berthelot

  3. Avogadro

  4. Proust


Correct Option: D
Explanation:

Proust defined law of constant proportions. It is also called as $\text{Proust's law}$. it states that a given chemical compound always contains its component elements in fixed ratio by mass and does not depend on the method of preparation of the compound. 
Hence, answer is option D.

Zinc sulphate contains 22.65% Zn and 43.9% $H _2O$. If the law of constant proportions is true, then the mass of zinc required to give 40 g crystals will be:

  1. 90.6 g

  2. 9.06 g

  3. 0.906 g

  4. 906 g


Correct Option: B
Explanation:

$ZnSO _4-22.65\% Zn $ $43.9\% H _2O$


$100g$ crystal has $22.65$ $Zn$


$40g$ crystal has $x$ $Zn$

$x=\cfrac{40\times 22.65}{100}=\cfrac{906}{100}=9.06g$
Hence, mass of $Zinc$ required is $9.06g$.

3 volumes of hydrogen are required to combine with one volume of nitrogen to form 2 volumes of ammonia. When 1 mole of hydrogen is allowed to react with the mole of nitrogen, the two gases?

  1. Do not combine

  2. Combine and both the gases are used up completely

  3. 2/3 mole of nitrogen remains unreacted

  4. Some hydrogen remains uncombined


Correct Option: C
Explanation:

$3H _2+N _2\rightarrow 3NH _3$
So 3 moles of hydrogen produced 1 mole of ammonia
1 mole hydrogen produces $X$ moles of ammonia
$X=\dfrac{1\times 1}{3}=\dfrac{1}{3}$ moles
Hence option $C$ is correct.

If a mixture containing 3 moles of hydrogen and 1 mole of nitrogen is converted completely into ammonia, the ratio of initial and final volumes under the same temperature and pressure would be:

  1. 3 : 1

  2. 1 : 3

  3. 2 : 1

  4. 1 : 2


Correct Option: C
Explanation:

3 moles of hydrogen and 1 mole of nitrogen is convened completely into ammonia.

$3H _2+N _2\rightarrow 2NH _3$

Hence option C is correct.

So 4 volumes of reactants (3+1) and 2 volumes of products that is the ratio of initial and final is 2:1

If water samples are taken from the sea, rivers, clouds, lakes or snow, they will be found to contain hydrogen and oxygen in the ration of $1 : 8$. This clearly demonstrates the law of ?

  1. Chemical equilibrium

  2. Definite proportions

  3. Combining volumes

  4. The relation of elements in the periodic tables


Correct Option: B
Explanation:
In chemistry, the law of definite proportion states that a given chemical compound always contains its component elements in a fixed ratio (by mass) and does not depend on its source and method of preparation. Since in all the water samples given, taken from the sea, rivers, clouds, lakes or snow, the hydrogen and oxygen ratio is constant, hence it clearly demonstrates the law of definite proportions.

If you put a waterproof, nine-volt battery in a mug of water containing two teaspoonfuls of salt, the water will be broken into gases and bubbles will start forming. What are these gases?

  1. Carbon dioxide and nitrogen

  2. Hydrogen and oxygen

  3. Fluorine and chlorine

  4. Sulphur dioxide and 'laughing gas'


Correct Option: B
Explanation:

Water will start comparing electrostatically,


$2H _2O \underset{electroysis}{\rightarrow} 2H _2+O _2$


These gases are hydrogen and oxygen.

A sample of pure water, irrespective of source, contains 88.89% oxygen and 11.11% hydrogen
by mass. The data supports the:

  1. law of conservation of mass

  2. law of constant composition

  3. law of multiple proportion

  4. law of reciprocal proportion


Correct Option: B
Explanation:

According to the law of constant composition in a given compound, the elements always combine in the same proportion as each other.

Water($H _{2}O$) molecule consists of two hydrogen atoms of relative mass 1 and one oxygen atom of relative mass 16. 

Therefore, the ratio in which 2 atoms of hydrogen and one atom of oxygen are combined is $1:8$ and will always be the same irrespective of the source of water.

Therefore, the correct option is $B$

When one mole each of CO and $O _2$ are made to react at STP, the total number of moles at an end of the reaction is:

  1. 1.5 moles

  2. 1 mole

  3. 4 moles

  4. 2 moles


Correct Option: A
Explanation:

$2CO + O _2 \rightarrow 2CO _2$


Initially, we have one mole of each CO and $O _2$.

1 mole of CO will react with 0.5 mole of $O _2$ to form 1 mole of $CO _2$.

the total no. of moles at the end of the reaction is 0.5 mole $O _2$ + 1 mole of CO$ _2$= 1.5 moles

64g of an organic compound has 24 g carbon and rest hydrogen and oxygen.  The empirical formula of the compound is

  1. ${C _2}{H _8}{O _2}$

  2. ${C _2}{H _4}O$

  3. $C{H _4}O$

  4. $C{H _2}O$


Correct Option: C

Zinc sulphate contains $22.65$% $Zn$ and $43.9$% ${H} _{2}O$. If the law of constant proportions is true, then the mass of zinc required to give $40g$ crystal will be:

  1. $9.06g$

  2. $90.6g$

  3. $0.906g$

  4. $906g$


Correct Option: A
Explanation:
100g of crystals are obtained from = 22.65g of $Zn$

$\therefore $ 40 g of crystals are obtained from =$\frac { 22.65 }{ 100 } \times40$

= 9.06g 

Which of the following statements is/are correct?

  1. A sample of $CaCO _3$ contains $Ca = 40\%,\ C = 12\%$ and $O= 48\%$. If the law of constant composition is true, then the mass of $Ca$ in $10$ g of $CaCO _3$ from another source is $4.0$ g.

  2. $12$ g of carbon is heated in vacuum and there is no change in the mass. This is the best example of the law of conservation of mass.

  3. Air is heated at constant pressure and there is no change in mass but the volume increases. This is the best example of the law of conservation of mass.

  4. $SO _2$ gas was prepared by (i) heating $Cu $ with conc. $H _2SO _4$ (ii) burning sulphur in oxygen (iii) reacting sodium sulphite $(Na _2SO _3)$ with dilute $H _2SO _4$. It was observed that is each case, $S$ and $O$ combine in the ratio of $1:1$. This data illustrates the law of constant composition.


Correct Option: A,D
Explanation:

(A) A sample of $CaCO _3$ contains $Ca = 40\%$, $C = 12\%$ and $O= 48\%$. If the law of constant composition is true, then the mass of $Ca$ in $10$ g of $CaCO _3$ from another source is $\dfrac {40 \times 10 }{100}= 4.0 $ g


According to the law of constant composition, all samples of a given chemical compound have the same elemental composition by mass.
Hence, the statement A is true.

(B) $12$ g of carbon is heated in vacuum and there is no change in the mass. This is not the best example of the law of conservation of mass as there is no chemical transformation involved since there is a vacuum.
The Law of Conservation of Mass states that matter can be changed from one form into another, mixtures can be separated or made and pure substances can be decomposed but the total amount of mass remains constant.
Hence, the statement B is false.

(C) Air is heated at constant pressure and there is no change in mass but the volume increases. This is not the best example of the law of conservation of mass as there is no chemical transformation involved since there is a vacuum.

The Law of Conservation of Mass states that matter can be changed from one form into another, mixtures can be separated or made and pure substances can be decomposed but the total amount of mass remains constant.
Hence, the statement C is false.

(D) $SO _2$ gas was prepared by (i) heating $Cu$ with conc. $H _2SO _4$ (ii) burning sulphur in oxygen (iii) reacting sodium sulphite $(Na _2SO _3)$ with dilute $H _2SO _4$. It was observed that is each case, S and O combine in the ratio of $1:1$. This data illustrates the law of constant composition.

According to the law of constant composition, all samples of a given chemical compound have the same elemental composition by mass.

Hence, the statement D is true.

$14$ g of element X combines with $16$ g of oxygen. On the basis of this information, which of the following is a correct statement?

  1. The element X could have an atomic weight of $7$ amu and its oxide is $XO$

  2. The element X could have an atomic weight of $14$ amu and its oxide is $\displaystyle X _{2}O$

  3. The element X could have an atomic weight of $7$ amu and its oxide is $\displaystyle X _{2}O$

  4. The element X could have an atomic weight of $14$ amu and its oxide is $\displaystyle XO _{2}$


Correct Option: C
Explanation:

$14$ g of an element X combines with $16$ g of oxygen, then the element X could have an atomic weight of $7$ amu and its oxide is $X _2O $.
When the atomic weight is $7$, $14$ g will corresponds to $2$ moles.
$16$ g of oxygen corresponds to $1$ mole. 

The formula $X _2O $ suggests the valency of $1$ for X.

The % loss in mass after heating a pure sample of potassium chlorate (Mol. mass = 122.5) will be:

  1. 12.25

  2. 24.50

  3. 39.17

  4. 49.0


Correct Option: C
Explanation:

$2KClO _3\rightarrow 2KCl+3O _2$
$2\times 122.5$ grams shows a wieght loss of  $3\times32 grams$
So 245 grams of $KClO _3$ is 100%
96 grams of $O _2$ is X%
$x=\frac{100\times 96}{245}=39.17$.
Hence option C is correct.

The volume of oxygen at NTP evolved when 1.70 g of sodium nitrate is heated to a constant mass is: 

  1. 0.112 litre

  2. 0224 litre

  3. 22.4 litre

  4. 11.2 litre


Correct Option: B
Explanation:
The chemical equation is:

$2NaNO _3(s)→  2NaNO _2 (s)+ O _2(g)$

2 moles of NaNO$ _3$ give one mole of Oxygen/22.4 L oxygen at STP

weight of NaNO$ _3$ = 85g

2 moles of NaNO$ _3$ weigh = 2(23+14+48) = 170g

170 g of NaNO$ _3$ will produce 22.4 L Oxygen at STP

​1.70 g will produce $= \cfrac{1.70}{170}×22.4 =0.224$ litres

Hence, the correct option is $\text{B}$

The mass of residue left after strongly heating 1.38 g of silver carbonate will be: 

  1. 1.16 g

  2. 1.33 g

  3. 2.66 g

  4. 1.08 g


Correct Option: A
Explanation:

$Ag _2CO _3\rightarrow Ag _2O+CO _2(g)$
I mole of $Ag _2CO _3$ (275.74) grams  on decomposition gives a mass residue of 231.73 grams of $Ag _2O$ remaning mass is liberated as $CO _2$ gas.
If 1.38 grams $Ag _2CO _3$ is hetaed it produces X grams of mass residue of  $Ag _2O$
$X=\frac{1.38\times 231.739}{275.745}=1.16$ grams
Hence option A is correct.

At NTP, 10 litre of hydrogen sulphide gas reacted with 10 litre of sulphur dioxide gas. The volume of gas, after the reaction is complete, would be:

  1. 5 litre

  2. 10 litre

  3. 15 litre

  4. 20 litre


Correct Option: A
Explanation:

$2H _2S+SO2\rightarrow 2H _2O+3S$

According to the equation $2\times 22.4 $ litre of  $H _2S$ gas reacts with $22.4$ litre of $SO _2$
So $5$ litre of $H _2S$ reacts with $10$ litre of $SO _2$
Hence option $A$ is correct.

The process of obtaining salt from sea water involves:

  1. evaporation

  2. condensation

  3. sublimation

  4. none of these


Correct Option: A
Explanation:
The process of obtaining salt from sea water involves the process evaporation is used an a large scale to obtain common salt from sea water. Sea water is trapped in shallow lakes and allowed to stand there. The heat of sun gradually evaporates water in the shallow lakes and common salt is left behind as a solid. Sea water has many salts dissolved in it.

Changing of liquid into vapours without heating is called:

  1. freezing

  2. steaming

  3. evaporation

  4. none of above


Correct Option: C
Explanation:
Changing of liquid into vapours is called evaporation and it causes cooling.
And in freezing the liquid changes into solid and causes cooling.
And in steaming the liquid boils and changes in vapour but causes heating

Rainfall is related to which process?

  1. Evaporation

  2. Condensation

  3. Sublimation

  4. Heating


Correct Option: A,B,D
Explanation:

The water vapor rises in the atmosphere due to heating of water by sunlight and there it cools down and forms tiny water droplets through something called condensation. When they all combine together, they grow bigger and are too heavy to stay up there in the air. This is when they will fall to the ground as rain, or maybe snow or hail by gravity.

Sublimation is not involved in rainfall process

The thermal resistance of heat transfer is low in:

  1. Drop wise condensation

  2. Filmwise condensation

  3. Bulk wise condensation

  4. None of these


Correct Option: A
Explanation:

The thermal resistance of heat transfer is low in drop wise condensation.


 Thermal resistance is a heat property and a measurement of a temperature difference by which an object or material resists a heat flow.

State the following statement is weather true or false :
The evaporation of water takes place only in sunlight.

  1. True

  2. False


Correct Option: B
Explanation:

The evaporation takes place at all the time

When you get in your car in the morning and are breathing warmer air, the warm air comes into contact with the cooler windshield and forms a foggy window. It is an example of :

  1. evaporation

  2. sublimation

  3. condensation

  4. both A and C


Correct Option: C
Explanation:

Condensation is the process by which water vapor in the air is changed into liquid water.Cloud formation is caused by condensation of water vapor in the atmosphere condensing into a liquid state. Thus Option C is correct.

The process of changing water vapour into water is called:

  1. boiling

  2. evaporation

  3. melting

  4. condensation


Correct Option: D
Explanation:

The process of changing water vapour into water is called condensation.

Condensation is simply the process of change of the vapour from gaseous state to liquid when comes in contact of cool surface.
And this process can't be boiling as in boiling we have to provide heat and it is the change of liquid state into vapour form.
And the process is not evaporation as it also changes water into vapour.
Melting is not the required process as it is the change of state from solid to liquid.

Evaporation causes:

  1. cooling

  2. heating effect

  3. an increase in weight

  4. an increase in density


Correct Option: A
Explanation:

Evaporation causes cooling.

Because in evaporation the water changes form liquid to vapour state so the vapour of water causes the surface to becomes cool.
Evaporation causes cooling because during evaporation the particle of the liqued absord energy from the surroundings to regain the energy lost during evaporation. the absorbtion of heat from the surrounding makes the surrounding  cool.

Which of the following is an example of evaporation?

  1. Drying of hair

  2. Preparation of common salt from sea water

  3. Dew in the morning

  4. Cooling of hot tea


Correct Option: A,B,D
Explanation:
Evaporation is a type of vaporization that occurs on the surface of a liquid as it changes into the gas phase.
Drying of leads to water loss in hair or water evapouration leads to water evapouration.
Producing of salt also leads of water evaporation from salted water.
Cooling of hot tea leads to water codensation not evaporation.

In which of the following processes evaporation involves

  1. Hot tea gets cool over time

  2. Preparation of common salt from sea water

  3. Wet clothes dry in sun

  4. A,B,C


Correct Option: D
Explanation:

Evaporation is the process of a liquid converts into gaseous phase. In all these process liquid moles are evaporated into gaseous phase. Hence, option D is correct.

Wet clothes dry in sun Due to

  1. Evaporation

  2. Condensation

  3. Sublimation

  4. Freezing


Correct Option: A
Explanation:

Wet clothes dry in sun due to evaporation the water in wet clothes takes heat energy from sun and gets evaporated.This process involves evaporation.
Hence, option A is correct.

Drying clothes is an example of :

  1. condensation

  2. evaporation

  3. hydration

  4. all of the above


Correct Option: B
Explanation:

Drying clothes is an example of evaporation as in evaporation water evaporates by the heat of the sun thus helping in drying of clothes .

And hydration means the process of absorbing water .
And condensation means water that collects as droplets on a cold surface when humid air is in contact with it.

Dew formation on the leaves and grass in the winter season due to

  1. Condensation

  2. Evaporation

  3. Sublimation

  4. Deposition


Correct Option: A
Explanation:

Dew forms in the morning on leaves and grass because of the warmer deposits water molecules on the cool leaves.This what is called condensation.
Hence option A is correct.

Evaporation is the process of a substance in:

  1. liquid form transitioning into the gas phase

  2. solid form transitioning into the gas phase

  3. liquid form transitioning into the solid phase

  4. None of these


Correct Option: A
Explanation:

Evaporation of the substance is the process in which the substance transition from liquid phase to gas phase. Condensation is the process in which gas returns to liquid form. Hence, options A is correct.

The fog appeared on sun glasses when it get in contact with steam

  1. Condensation

  2. Evaporation

  3. Sublimation

  4. None of the above


Correct Option: A
Explanation:

The fog appeared on sun glasses when gets in front of hot steam due to condensation.Condensation is the process where the vapor converts into liquid.
Hence option A is correct.

Which of the following involves evaporation

  1. drying up of mopped floor

  2. Drying of wet hair after some time

  3. drying up of water bodies like lakes and rivers

  4. A,B,C


Correct Option: D
Explanation:

Evaporation is the process of a liquid converts into gaseous phase.In all these process liquid moles are evaporated into gaseous phase.So all the above processes involves evoporation.
Hence option D is correct.

Formation of water droplets on cold soda can while we are having soda in summer season is due to :

  1. Condensation

  2. Evaporation

  3. Sublimation

  4. Freezing


Correct Option: A
Explanation:

The formation of water droplets on cold soda can while having soda in summer season is due to the process of condensation.

Condensation is the process where:

  1. solid substance converts into gas

  2. liquid substance converts into gas

  3. gaseous substance converts into liquid

  4. solid substance converts into liquid


Correct Option: C
Explanation:

Condensation is the process where a gaseous substance converts into liquid.
Ex: Rainfall.


Hence option C is correct.

The mirror in the bathroom during a shower becomes foggy due to:

  1. condensation

  2. evaporation

  3. sublimation

  4. both A and B


Correct Option: A
Explanation:
The mirror in the bathroom during a shower becomes foggy because warmer water vapor in the air hits the cooler surface of the mirror. This phenomenon is due to condensation. Hence option A is correct.
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