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Reverberation - class-IX

Description: reverberation
Number of Questions: 59
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Tags: study of sound sound waves acoustics wave motion physics
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Why do we hear more clearly in a room with curtains than in a room without curtains?

  1. sound is absorbed by the curtains.

  2. less reverberation

  3. a and b

  4. none


Correct Option: A
Explanation:

We hear more clearly in a room with curtains than of that in a room without curtains because curtains act as a good sound absorbent. So, they absorb the sound produced in the room and thus, prevent unwanted echo of sound due to refraction. Otherwise, the inter lapping of sounds would be most undesirable as we won't be able to hear clearly.

_________ is a device which is based on multiple reflection and isused for sending amplified sound in a particular direction.

  1. Bulb horn

  2. Megaphone

  3. Ear trumpet

  4. all


Correct Option: B
Explanation:

Megaphone is based on multiple reflection of sound. It is a horn shaped tube designed to send amplified sound in a particular direction. It is also called Loud hailer.

Which of the following device does not work on the multiple reflections of sound waves?

  1. stethoscope

  2. hydrophone

  3. soundboard

  4. megaphone


Correct Option: B
Explanation:

Stethoscope is a medical diagnostic instrument based on multiple reflection of sound waves.
This is used by doctors for listening to the sounds produced inside the body.
Sound board is a concave rigid surface which is placed behind the speaker in a big hall so that his words can be heard clearly even by the people sitting away from the stage.

The persistence of audible sound due to the successive reflections from the surrounding objects even after the source has stopped to produce that sound is called

  1. reflection

  2. echo

  3. reverberation

  4. rarefaction


Correct Option: C
Explanation:

According to the definition of reverberation, it is the persistence of audible sound due to the successive reflections from the surrounding objects even after the source has stopped to produce that sound.

Reverberation time of a hall used for speeches should be very short. Why?

  1. Multiple echos will enhance the sound quality.

  2. Multiple echos will interfere with the original sound

  3. Both a and b

  4. None of the above


Correct Option: B
Explanation:

Reverberation time of a hall used by speeches should be very small so that due to multiple reflection of sound, we will hear the same voice again and again distracting our concentration to hear important points of the speech. If we hear same sound many times it will irritate us.

Curved surfaces which are used in big hall to direct the sound waves towards the people sitting in a hall are known as:

  1. megaphone

  2. hydrophone

  3. bulb horn

  4. none of the above


Correct Option: D
Explanation:

Sound boards are the curves surfaces (concave) which are used in a big hall to direct the sound waves towards the people sitting in a hall. The source of sound is placed at the focus of the sound board.

Mark the correct statement .
i) rock music also becomes less pleasing with excessive reverberation.
ii) excessive reverberation is desirable in case of orchestral and choral music.
iii) excessive reverberation makes the speech of a person indistinct.

  1. i, ii

  2. ii, iii

  3. i, iii

  4. all


Correct Option: D
Explanation:

Reverberation is the phenomenon of persistence of sound after it has been stopped as a result of multiple reflections from surfaces such as furniture, people, air etc. within a closed surface. But the excessive reverberation is undesirable as the sound produced will continue to be heard repeatedly while the next sound being sent forth. This is unpleasant to hear and there is no clarity of sound.

So, all the statements are correct.

device based on multiple reflection used as hearing aid.

  1. bulb horn

  2. ear trumpet

  3. megaphone

  4. all


Correct Option: B
Explanation:

Ear trumpet or hearing aid is used by the persons who are hard of hearing. The sound waves received by the wide end of the trumpet are reflected into a much narrower area.

If the ceiling of a cineural is made flat, what will happen

  1. no sound will be audible at all.

  2. picture will vanish.

  3. sound will not reach properly to every person.

  4. picture will not be clear to everyone


Correct Option: C
Explanation:

Ceiling in a cinema hall is made curve so that the sound of music, dialogue etc must reach evenly to all the audience.
So that the sound after reflection from curved surface reaches all corners of the hall evenly.

Identify the device which work on the reflection of light:

  1. megaphone

  2. stethoscope

  3. sound boards

  4. All


Correct Option: C
Explanation:

Sound board is device which works on the reflection of light while others works on the reflection of sound.

Excessive reverberation in any auditorium/hall is not desirable because :

  1. sound becomes blurred

  2. sound become distorted

  3. sound remains same 

  4. both A and B


Correct Option: D
Explanation:

Excessive reverberation in any auditorium or hall is not desirable because the sound becomes blurred and distorted. So the reverberation needs to be reduced.

Megaphones or loudhailers, horns, musical instruments such as trumpets and  shehnais, are all designed to ______.

  1. send sound in a particular direction without spreading it in all directions.

  2. send sound in a particular direction spreading it in all directions.

  3. collect sound from all directions spreading it in all directions.

  4. all of the above


Correct Option: A
Explanation:

Megaphones or loudhailers, horns, musical instruments such as trumpets and shehnais, are all designed to send sound in a particular direction without spreading it in all direction.
In these instruments, a tube followed by a conical opening reflects sound successively to guide most of the sound waves from the source in the forward direction towards the audience.

Why the ceiling of concert halls, cinema halls made curved?

  1. To make the hall beautiful

  2. For proper light conditions

  3. So that the sound can reach all corners properly

  4. So that the picture or the stage can be visible to each and every person.


Correct Option: C
Explanation:

In concert halls, cinema halls, conference halls, the ceiling are made curved, so that the sound after reflection from the curved surface reaches all corners of the hall evenly.

In an auditorium or big hall excessive reverberation is highly _______.

  1. undesirable

  2. desirable

  3. zero

  4. none of the above


Correct Option: A
Explanation:

Sound created in a big hall will persist  by repeated reflection from the walls until it is reduced to a value where it is no longer audible. The repeated reflection that results in this persistence of sound is called reverberation. In an auditorium or big hall excessive reverberation is highly undesirable.

If the ceiling of a cinema is made flat, what will happen?

  1. No sound will be audible at all

  2. Picture will vanish

  3. Sound will not reach properly to every person

  4. Pictures will not be clear to everyone


Correct Option: C
Explanation:

Ceiling in a cinema hall is made curve so that the sound of music, dialogue etc must reach evenly to all the audience. So that the sound after reflection from the curved surface reaches all corners of the hall evenly.

Reverberation time of a hall used for speeches should be very short. Otherwise

  1. multiple echos will enhance the sound quality

  2. multiple echos will interfere with the original sound

  3. multiple echos will not interfere with the original sound 

  4. both A and B


Correct Option: B
Explanation:

Reverberation time of a hall used for speeches should be very short because multiple echoes will interfere with the original sound. So, reverberation time is reduced to avoid multiple echoes.

Why do we hear more clearly in a room with curtains than in a room without curtains? 

  1. sound is absorbed by the curtains

  2. less reverberation without curtains

  3. high reverberation without curtains

  4. both A and B


Correct Option: B
Explanation:

There is more reverberation in rooms with curtains so we can hear sound more clearly.

Mark the correct statement :

i)rock music also becomes less pleasing with excessive reverberation.
ii)excessive reverberation is desirable in case of orchestral and choral music. 
iii)excessive reverberation makes the speech of a person indistinct. 

  1. i, ii

  2. ii, iii

  3. i, iii

  4. All of them


Correct Option: D
Explanation:

A certain amount of reverberation may improve the quality of sound. However, excessive reverberation is sometimes undesirable as it interferes with the original sound and hence makes the speech or music indinstict

Mark the correct match

  1. Good reflectors of sound-Tiles, Marble slabs

  2. Bad reflectors of sound - Thick curtains, thick carpets

  3. Good absorbers of sound - Holed cardboard

  4. All


Correct Option: D
Explanation:

Sound is not reflected equally from different materials. Hard surfaces reflects more sound.
Bad reflectors of sound are good absorbers. Soft thick curtains, thick carpets, holed card boards are examples of good absorbers of sound.

Identify the device which work on the reflection of sound.

  1. Megaphone

  2. Stethoscope

  3. Sound boards

  4. All of the above


Correct Option: D
Explanation:

Megaphone, Stethoscope and Sound boards work on the reflection of sound.

$1.$Megaphone is a portable, cone shaped acoustic horn used to amplify a person's voice or other sounds and direct it in a given direction.
$2.$Stethoscope is an acoustic medical device for listening to the internal sounds of an animal or human body.
$3.$Sound board is the surface of a string instrument that the string vibrate against.

Which of the following are examples of multiple reflections of sound?

  1. Stethoscope

  2. Sound board

  3. Megaphone

  4. All of the above


Correct Option: D
Explanation:

Process in which sound waves bounces off obstacles and reflects many times before reaching destinations is known as multiple reflection of sound, So, all of the above are examples of multiple reflections of sound

What is multiple reflection of sound?

  1. Process in which sound waves bounces off obstacles and reflects many times before reaching destinations

  2. Process in which sound waves penetrates in obstacles and reflects many times before reaching destinations

  3. Process in which sound waves bounces off obstacles and deflects one time before reaching destinations

  4. None


Correct Option: A
Explanation:

Process in which sound waves bounces off obstacles and reflects many times before reaching destinations is known as multiple reflection of sound

The persistence of audible sound due to the successive reflections from the surrounding objects even after the source has stopped to produce that sound is called _________.

  1. reflection

  2. echo

  3. reverberation

  4. rarefaction


Correct Option: C
Explanation:

In big rooms or halls,echos (due to multiple reflection of sound from the walls, roof, floor) follow so closely behind the original sound that the original sound appears to be prolonged even when the source of sound stops producing sound.

Why do distant sounds such as those of traffic and loudspeakers become louder during the night time than during the day time?

  1. Due to the reflection of sound waves.

  2. Due to the refraction of sound waves.

  3. Due to the absence of other sounds.

  4. Due to a clear perception of hearing.


Correct Option: A
Explanation:

Sound waves travel differently at night than during the day. During the day, the sound bends away from the ground;during the night, it bends towards the ground. 

In an unoccupied hall of a choultry you will experience the echo effect of sound. If the same hall is furnished with almirahs, tables, chairs,and other commodities, you may not experience the echo clearly. It is because, 

  1. Sound waves get absorbed by the objects in the hall.

  2. The area of reflecting surface decreases.

  3. Reflected sound is reflected again.

  4. Sound does not get reflected again.


Correct Option: A
Explanation:

echo is heard due to reflection of sound and if obstacles are placed in path of sound then they will either absorb sound or will not perfectly reflect sound as before so echo will be not effective one .

so the answer is A.

The persistence of sound in a closed enclosure, due to continuous reflections at the walls, even after the source has stopped producing sound is known as

  1. The persistence of hearing

  2. An echo

  3. Reverberation

  4. The ultra sounds


Correct Option: C
Explanation:

Reverberation is the phenomenon of persistence of sound in a closed enclosure, due to multiple reflection of sound from the walls, even after the source has stopped producing sound. The intensity of sound gets reduced after each reflection.

Select the instrument that works on the principle of multiple reflection of sound.

  1. Watthour meter

  2. Sonar

  3. Stethoscope

  4. Decibel meter


Correct Option: C
Explanation:

The sound of a heartbeat ( or lungs ) reaches the doctor's ears by the multiple reflections of sound waves though the stethoscope tube.

Perforated card boards are used in halls, for

  1. reflection of sound

  2. absorption of sound

  3. refraction of sound

  4. as a decorative material


Correct Option: B
Explanation:

Perforated card boards are used for the absorption of sound, as they are good sound absorbents and decrease reverberation time. 

For good absorption of sound in auditorium it requires

  1. a few windows to be opened

  2. all closed windows

  3. maps hanging from walls

  4. hanging light curtains.


Correct Option: A
Explanation:

A few window should be kept opened for the good absorption of sound in auditorium. Because if we open few windows, more sound will absorbed and more will be the sound clarity and better sound effect can be experienced. 

In an auditorium the big curtain when falls suddenly then the reverberation time

  1. increases

  2. decreases

  3. Remains same

  4. becomes zero


Correct Option: B
Explanation:

The reverberation time will get decreased because curtain will abrosh the sound and more sound will get abrashed then the earlier.  

Which of the following has largest absorption coefficient?

  1. heavy curtain

  2. cork

  3. marble

  4. open window


Correct Option: D
Explanation:

The absorption coefficient of a body is the ratio of the heat radiation absorbed by the body to the total heat radiation incident on it. Since an open window can allow all the radiation into it, it is a good absorber. Hence its coefficient is highest.

Upholstered seats in cinema halls are arranged for

  1. absorption of sound

  2. reflection of sound

  3. diffraction of sound

  4. to hear an echo


Correct Option: A
Explanation:

Upholstered seats in cinema halls are arranged for better absorption of sound and to decrease the reverberation time. 

The total absorption of a volume $12000 m^3$ is equal to $1000 m^2$ in the units of an open window. Total absorption of the hall is increased to $2000m^2$ due to entry of audience. The change in its reverberating time is

  1. $1s$

  2. $2s$

  3. $3s$

  4. $4s$


Correct Option: A

The volume of a cinema theatre is 100m x 60m x 20m and total acoustic absorption in it is 6800metric sabine. The reverberation time in that theatre is

  1. 1.5 s

  2. 2 s

  3. 3 s

  4. 4 s


Correct Option: C
Explanation:

$R.T=\frac{1.61}{10}\times \frac{V}{A}$
=2.84se
=3 sec

In theatres, big halls., the reverberation of sound is a common problem.

  1. True

  2. False


Correct Option: A
Explanation:

since the halls and theatres are big enough so that we can distinguish between the generated sound and the reflected sound so the reverbereation  easily happens .

so the answer is A.

A meeting hall of volume $100\times30\times10 m^3$ has a reverberation time of 3 seconds. If 1000 visitors are in the hall. The absorption of total visitors if the sound absorption of each visitor is 0.5 is:

  1. 500metric sabin

  2. 600metric sabin

  3. 700metric sabin

  4. 800metric sabin


Correct Option: A
Explanation:

absorption of each visitor is 0.5
so, absorption for 1000 visitor is $1000\times 0.5$
$=500 metric sabine$

A source of sound A emitting waves of frequency 1800 Hz is falling towards ground with a terminal speed v. The observer B on the ground directly beneath the source receives wave of frequency 2150hz. The source A receives waves, reflected from frequency nearly: (Speed of sound = 343 m/s)

  1. 2150 Hz

  2. 2500Hz

  3. 1800Hz

  4. 2400Hz


Correct Option: B
Explanation:
Frequency received by source A is
$f=1800\left( \dfrac { 343+V }{ 343-V }  \right) $
$for\quad V;$
$2150=1800\left( \dfrac { 343 }{ 343-V }  \right) $
$343-V=\dfrac { 1800\times 343 }{ 2150 } $
$V=56\quad m/s$
$\therefore \quad \quad f=1800\left( \dfrac { 399 }{ 287 }  \right) \simeq 2500Hz$

A man standing between two parallel hills, claps his hand and hears successive echoes at regular intervals of $1\ s$. If velocity of sound is $340 \mathrm { ms } ^ { - 1 }$, then the distance between the hill is

  1. $100\ m$

  2. $170\ m$

  3. $510\ m$

  4. $340\ m$


Correct Option: B

The time of reverberation of a room A is one second. What will be the time (in seconds) of reverberation of a room, having all the dimensions double of those of room A:

  1. 2

  2. 4

  3. $\frac{1} {2}$

  4. 1


Correct Option: A
Explanation:

Time of reverberation $\propto$ $\frac{V} {A}$ (sabine's formula)

Where V = volume of room and A = area of room
Area of new room becomes 4 times of A and Volume becomes 8 times of V
Time of reverberation will be 2 seconds

Standing waves and echoes are based on which acoustic phenomenon?

  1. Diffraction

  2. Polarization

  3. Interference

  4. Reflection


Correct Option: D

The reverberation time of a theatre is $0.1 sec$. The volume of the other theatre is exactly half. If the total absorption is same then the reverberation time of second one

  1. $5 sec$

  2. $0.5 sec$

  3. $0.05 sec$

  4. $0.005 sec$


Correct Option: B

When a source of sound crosses an obsever then change in appearent frequency obseved by the  observer is $2$% of its initial frequency. If the speed of sound is $350 m/s$ then be-

  1. 3.5 m/s

  2. 3.5 cm/s

  3. 3.5 ft/s

  4. zero


Correct Option: A

An auditorium of dimensions $(100\times40\times10)\space m^3$ contains $1000\space m^2$ curtains of absorption coefficient $0.2\space m^{-2},\space 2000 m^2$ of carpets of absorption coefficient $0.7\space m^{-2}$. If $1000$ men of absorption coefficients $0.9$ per person are sitting in the hall, then reverberation time is

  1. $2.7\space s$

  2. $7.2\space s$

  3. $3.5\space s$

  4. $3.7\space s$


Correct Option: A
Explanation:

Volume of the room          $V = 100\times 40 \times 10 = 4\times 10^4      m^3$

Effective surface area of the room           $A = (0.2) 1000  +  (0.7) 2000  +  (0.9) 1000  =  2500$
Now reverberation time       $T _r = 0.161  \dfrac{V}{A}$
$T _r = 0.161  \dfrac{4\times 10^4}{2500} = 2.576    s$

A stone is dropped from the top of a tower of $125m$ high into a pond which is at base of the tower. When will the splash be heard at the top? (Given $g = 10ms^{-1}$ and speed of sound $=340ms^{-1}.$)

  1. $5s$

  2. $0.36s$

  3. $5.36s$

  4. $2s$


Correct Option: C

When all of the audience come out of the audotirium the reverberation time became$\frac{4}{3}$ of that when packed with the audience. If all $400$ persons come out, the ratio of the absorption of the auditorium to that a person is 

  1. $1600$

  2. $1200$

  3. $3000$

  4. $1000$


Correct Option: B

The reverberation time of a hall of volume $200m^{-3}$ is $1.7s$. The reverberation time if $20$ persons having absorptions $0.4$ entered the hall, nearly is 

  1. $1.5s$

  2. $1.4s$

  3. $1.3s$`

  4. $1.2s$


Correct Option: D

A stone is dropped into a lake from a tower 500 metre high. The sound of the splash will be heard by the man approximately after

  1. 11.5 seconds

  2. 21 seconds

  3. 10 seconds

  4. 14 seconds


Correct Option: A

Fill in the blank.

___________ is created when a sound or signal is reflected causing a large number of reflections to build up and then decay as the sound is absorbed by the surfaces of objects in the space.

  1. Reverbaration

  2. Echo

  3. Response

  4. Heat


Correct Option: A
Explanation:

A reverberation, or reverb, is created when a sound or signal is reflected causing a large number of reflections to build up and then decay as the sound is absorbed by the surfaces of objects in the space which could include furniture and people, and air. 

The walls and ceiling of an auditorium are covered with a fibrous material to

  1. Make the auditorium fire proof

  2. Absorb sound and prevent echoes

  3. Give an ethnic look to the auditorium

  4. To prevent leakage of water from the roof


Correct Option: B
Explanation:

  We know that soft , porous and fibrous materials are good absorbers of sound , so they are used to the walls and ceiling of an auditorium to absorb the sound .

    If this is not done , sound waves after reflections (echoes) from walls and ceiling , will interfere and due to this at some places in auditorium , sound will not be heard (destructive interference) and at some places intensity of sound will be very large (constructive interference)

What will happen if the reverberation time in a big hall is too long?

  1. Sound will persist for some time in the hall

  2. The reflection may become an echo.

  3. Multiple reflection may occur

  4. All the above will happen


Correct Option: D
Explanation:

The multiple reflection of sound from the walls of a room or hall causing sound to persist for some time is called reverberation. If the hall is too long , the reflection will become an echo.

A man standing between two cliffs hears the first echo of a sound after 2 sec and the second echo 3 sec after the initial sound. If the speed of sound be $330   {m}/{sec}$ the distance between the two cliffs should be

  1. 1650 m

  2. 990 m

  3. 825 m

  4. 656 m


Correct Option: C
Explanation:

Let $d _{1}$ and $d _{2}$ be the distances of first and second cliff from man .

Echo after 2s will be heard when sound travels a distance of $2d _{1}$ , because an echo comes back to initial point after reflection .
    therefore  by ,   distance=speed$\times$time ,
         or                 $2d _{1}=330\times2=660$ ,
         or                 $d _{1}=660/2=330m$ ,
similarly Echo after 3s will be heard when sound travels a distance of $2d _{2}$ ,  
    therefore   
         or                 $2d _{2}=330\times3=990$ ,
         or                 $d _{2}=990/2=495m$ ,
as the man is in between the cliffs , therefore distance between cliffs willbe ,
             $d=d _{1}+d _{2}=330+495=825m$

(1) The reflected pulse will be in same orientation of incident pulse due to a phase change of $\pi$ radians.
(2) During reflection the wall exerts a force on string in upward direction.
For the above given two statements choose the correct option given below.

  1. Only (1) is true

  2. Only (2) is true

  3. Both are true

  4. Both are wrong


Correct Option: D
Explanation:

The pulse will be of same orientation as before after the phase change of $2\pi$ radians

During the reflection string tries to move upward but wall applies downward force to stop movement of connected end. So both the statements are wrong.

(A).  The reverberation time is dependent on the shape of the enclosure,  position of the sources and observer.
(B) The unit of absorption coefficient in S.I. system in metric is sabine

  1. both (A) and (B) are true

  2. both (A) and (B) are false

  3. (A) is true but (B) is false

  4. (A) is false but (B) is true


Correct Option: B
Explanation:
The reverberation time is independent on the shape of the enclosure, position of the sources and observer.
Absorption coefficient is unitless.

A hall has volume 4x6x10 m$^3$. If the total sound absorption of the hall is 27.2metric sabine and 40 visitors are in the hall and each is equivalent to 0.5metric sabine sound absorption then the reverberation time is

  1. 0.8644s

  2. 0.05s

  3. 0.72s

  4. 1.8s


Correct Option: A
Explanation:

$volume =240m^{3}$
$Area =27.2m^{2}+40\times 0.5m^{2}$
=47.2
$R.T.=0.161\times \frac{V}{A}$
=0.8186s

The reverberation time of a room is t seconds. Another room of double the dimensions with the walls of the same absorption coefficient will have a reverberation time :

  1. $t^{2}$

  2. $2 t$

  3. $t/2$

  4. t$^{3}$


Correct Option: B
Explanation:

Given: $\dfrac{V _{1}}{V _{2}}=\dfrac{1}{8} \
\ \dfrac{A _{1}}{A _{2}}=\dfrac{1}{4}$
$R.T. _{1}=t $
$R.T=0.161\dfrac{v}{A}$
$\dfrac{R.T. _{1}}{R.T. _{2}}=\dfrac{0.161 \times \dfrac{v _1}{A _1}}{0.161 \times \dfrac{v _2}{A _2}}=\dfrac{v _{1}A _{2}}{v _{2}A _{1}}=\dfrac{1}{8}\times \dfrac{4}{1} =\dfrac{1}{2}$
$R.T _{2}=2R.T _{1}$
          $=2\times t$
          $=2t$ 

The ratio of the absorption of an auditorium to that of a person is 1000. If 500 persons are accommodated in that auditorium then the ratio of the reverberation times with and without
audience is:

  1. 1/3

  2. 2/3

  3. 3/2

  4. 3/4


Correct Option: B
Explanation:

The reverberation time of the auditorium with volume V and total absorption coefficient A is given by:
$T _1=

\dfrac{0.17V}{A}$. Now when we will include n number of people each

having an absorption coefficient $A _p$ in the auditorium than the

reverberation time of the auditorium will be:
$T _2= \dfrac{0.17V}{A+nA _p}$. Now, here $A _p/A=1/1000$ and $n=500$ Using this two values the $T _2/T _1=2/3$.

The reverberation times in a cinema theatre are 3s, 2s when it is empty, filled with audience respectively.  The reverberation time when the theatre is half filled  with audience is

  1. 2.3 s

  2. 2.4 s

  3. 2.5 s

  4. 2.6 s


Correct Option: B
Explanation:

let Area be A, when empty
let Area of audience be $A _{2}$ when full
so Area of cinema theatre when full $=A _{1}+A _{2}$
Area when half full $=A _{1}+\frac{A _{2}}{2}$
$R.T. \alpha \frac{1}{A}  ; \frac{R.T _{1}}{R.T _{2}}=\frac{A _{2}+A _{1}}{A _{1}}$
$3A _{1}=2A _{1}+2A _{2}  ; A _{1}=2A _{2} ; A _{2}=^{A _{1}}/ _{2}$
$R.T _{3}\alpha \frac{1}{A _{1}\frac{A _{2}}{2}} =\frac{4}{5 A _{1}}$
$ this \frac{4}{5} times     3 sec =2.4 sec$
 

A pendulum has a frequency of 5 vibrations per second. An observer starts the pendulum and fire a gun simultaneously. He hears echo from the cliff after 8 vibrations of the pendulum. If the velocity of sound in air is 340  $ms^{-1}$, find the distance between the cliff and the observer :

  1. 252 m

  2. 240 m

  3. 272 m

  4. 182 m


Correct Option: C
Explanation:

The sensation of any sound persists in our ear for about 0.1 seconds. This is known as the persistence of hearing. If the echo is heard within this time interval, the original sound and its echo cannot be distinguished. So the most important condition for hearing an echo is that the reflected sound should reach the ear only after a lapse of at least 0.1 second after the original sound dies off. 
It is given that a pendulum has a frequency of $5$ vibrations per second. An observer starts the pendulum and fire a gun simultaneously. He hears echo from the cliff after $8$ vibrations of the pendulum which means that he hears the echo after 1.6 seconds. The speed of sound is given as $340 m/s$.
T
he distance traveled by sound of the gun shot in $1.6 $ seconds is calculated from the formula 
Distance traveled $=velocity\quad of\quad sound\times time\quad taken$. That is, $340 \times 1.6 $ = 544 m. This is twice the minimum distance between a source of sound (man) and the reflector (cliff) as it is reflected sound. 
So, the cliff is at a distance of 272 m least from the man, for the reflected sound or the echo to be heard distinctly in 1.6 seconds.

The term reverberation time is generally understood to be the reverberation time at which of the following frequencies?

  1. 1024 Hz

  2. 2048 Hz

  3. 512 Hz

  4. 256Hz


Correct Option: B
Explanation:

When a reflecting surface is less than 17 m away from the source, the echo that returns appears to be the original sound, just prolonged. This effect is called reverberation. The time interval between the original sound and the returning echo must be less than 0.1 seconds. It depends on the adsorption coefficient of the material which usually defines at 2048 Hz frequency.

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