0

Energy efficiency - class-X online quiz

Description: energy efficiency
Number of Questions: 17
Created by:
Tags: energy transformations and energy transfers physics
Attempted 0/17 Correct 0 Score 0

A line having a total resistance of $0.5 \Omega$ delivers $15$kW at $240$ volt to a small factory. The efficiency of transmission will be :

  1. $97\%$

  2. $88.5\%$

  3. $68\%$

  4. $79\%$


Correct Option: A

The weight of a man is 60 kg. If ${ 10 }^{ 5 }$ cal heat is supplied from food and his efficiency is 28%. The height upto which he can climb, will be-

  1. 50 m

  2. 186 m

  3. 200 m

  4. 250 m


Correct Option: B

A crane can lift up $10,000$ kg of coal in $1$ hour from a mine of $180$m depth. If the efficiency of the crane is $60\%$, its input power must be? $(g=10ms^{-2})$

  1. $5$ kW

  2. $8.3$ kW

  3. $50$ kW

  4. $62.5$ kW


Correct Option: A

An engine pump $400$kg of water through height of $10m$ in $40s$. Find the power of the engine if its efficiency is $80\%$ (Taken $g=10ms^{-2}$).

  1. 800W

  2. 900W

  3. 600W

  4. 500W


Correct Option: A
Explanation:

$m=400kg$
$H=10m$
$t=40 \sec$
Input energy $=400\times g \times H=mgn$
$E _i=400 \times 10\times 10=40000 J$
Energy per $\sec , E _1=\dfrac{40000}{40}=1000 J/s$
Power input $=1000 J/s$
output =$1000\times 80\%$
$800J/s$=$800W$

A man of mass 80 kg carrying a load of 20 kg walks up a stair case in 20s.If the number of steps is 40 and width and height of each step are 20 cm and 15 cm respectively.The efficiency of the man is 

  1. 20%

  2. 25%

  3. 40%

  4. 505


Correct Option: A

A carnot engine is designed to operate between $480 \, K$ and $300 \, K$. If the engine actually produce $1.2 \, J$ of mechanical energy per cal. of heat absorbed, then the ratio of actual efficiency to theoretical efficiency is

  1. $3/4$

  2. $4/3$

  3. $1/3$

  4. $3/1$


Correct Option: A

An ideal gas is taken through a cyclic thermo dynamical process through four steps. The amounts of heat involved in these steps are ${ Q } _{ 1 }=5960 J$ ,${ Q } _{ 2 }=5585 J$, ${ Q } _{ 1 }=2980$ J,${ Q } _{ 1 }=3645 J$;espectively, The corresponding works involved are ${ W } _{ 1 }=2200 J$, ${ W } _{ 1 }= -825 J$, ${ W } _{ 2 }=-1100$ J and  ${ W } _{ 4 }$  respectively. Find The value of W and efficiency of the cycle

  1. 1315 J 10%

  2. 275 J 11%

  3. 765 J 10.82%

  4. 675 J 10.82%


Correct Option: A

A man of mass 60 Kg lifts a 15 Kg mass to the top of a building of height 10 m in 5 minutes. H is efficiency is

  1. 10 %

  2. 20 %

  3. 30 %

  4. 40 %


Correct Option: B

Among the following the correct expression of efficiency is 

  1. $ \dfrac {Output \ energy}{Input\  energy} $

  2. $ \dfrac {Work\  done\  by \ the\  machine}{Work\  done\  on\  the\  machine} $

  3. $ \dfrac {Load}{Effort} $

  4. All the above


Correct Option: A
Explanation:

$effieciency = \dfrac{{energy\,\,output}}{{energy\,\,input}}$

Hence,
option $(A)$ is correct answer.

A body of mass  $4\mathrm { kg }$  is moving up an inclined plane rising  $1$  in  $40$  with velocity  $40\mathrm { m } / \mathrm { sec }$  if efficiency is  $50\%$  the calculate power required.

  1. $38.4 \mathrm { W }$

  2. $55 \mathrm { W }$

  3. $78.4 \mathrm { W }$

  4. $108 W$


Correct Option: A

The power of a heart which pumps $5\times{10}^{3}cc$ of blood per minute at a pressure of $120mm$ of mercury ($g=10m{s}^{-2}$ and density of $Hg=13.6\times{10}^{3}kg/m$) is

  1. $1.36W$

  2. $13.6W$

  3. $0.136W$

  4. $136W$


Correct Option: A

The work done during the process when 1 mole of gas is allowed to expand freely into vacuum is:

  1. zero

  2. +ve

  3. -ve

  4. either of these


Correct Option: A

A man weighing 60 kg lifts a body of 15 kg to the top of a building 10 m high in 30 minutes. His efficiency is:

  1. 10%

  2. 20%

  3. 30%

  4. 40%


Correct Option: B
Explanation:

Here, a man weighing 60 kg lifts a body of 15 kg to the top of a building 10 m high in 30 minutes. initially, while lifting the body(doing work) the power is 
$P _i = \dfrac{mgh}{t}$

$P _i = \dfrac{(60+15)(10)(10)}{(30)(60)}$

$P _i = \dfrac{7500}{1800}$

After reaching to the top the power is

$P _f = \dfrac{mgh}{t}$

$P _f = \dfrac{(15)(10)(10)}{(30)(60)}$

$P _f = \dfrac{1500}{1800}$

The efficiency of the man is the ratio of final power to the initial one
$\eta = \dfrac{P _f}{P _i}$

$\eta = \dfrac{\dfrac{1500}{1800}}{\dfrac{7500}{1800}} \times 100$ 

$\eta = \dfrac{1}{5} \times 100$ 

$\eta = 20$%

A motor has an electrical input of $30 kJ$ and is used to raise $100 kg$ load to a height of $25 m$ when fired to a crane winch. What is the efficient of winch ? ($g = 10 \ ms^{-1}$)

  1. $0.75 %$

  2. $83.3 %$

  3. $75 %$

  4. $17.5 %$


Correct Option: B

A machine which is 75% efficient, uses 12 J of energy in lifting 1 kg mass through a certain distance. The mass is then allowed to fall through the same distance. The velocity at the end of its fall is:

  1. $\sqrt{12} $ m/s

  2. $\sqrt{18} $ m/s

  3. $\sqrt{24} $ m/s

  4. $\sqrt{32} $ m/s


Correct Option: B
Explanation:

Efficiency = 75%, Input energy = 12 J
$\therefore \displaystyle \frac{75}{100} = \frac{\text{Output energy}}{\text{Input energy}}$
$\Rightarrow $ Output energy $= \displaystyle \frac{75}{100} \times 12 = 9 J$
$\therefore$ P.E. of the mass = 9 J
At the end of the fall it will be converted to K.E.
$\therefore \displaystyle \frac{1}{2} mv^2 = 9$
$\Rightarrow \displaystyle \frac{1}{2} \times 1 \times v^2 = 9$
$\Rightarrow v^2 = 18$
$\Rightarrow v = \sqrt{18} m/s$

An installation consisting of an electric motor driving a water pump left $75 L$ of water per second to a height of $4.7 m$. If the motor consumes a power of $5 kW$, then the efficiency of the installation is

  1. $39$%

  2. $69$%

  3. $93$%

  4. $96$%


Correct Option: B
Explanation:

Power consumed by motor$5kW= 5 \times 10^3 W= 5000W$

power used i lifting water = $\dfrac{mgh}{t}=7.5 \times 9.8 \times 4.7= 3454.5 W$
Efficiency = $\dfrac{\text{Power used}}{\text{Power consumed}} \times 100$% = $\dfrac{3454.5}{5000} \times 100$% = 69 %

A man of 60 kg gains 1000 cal of heat by eating 5 mangoes. His efficiency is 56%. To what height he can jump by using this energy?

  1. 4m

  2. 20 m

  3. 078 m

  4. 0.2 m


Correct Option: C
- Hide questions