• Transition Metals and Their Complexes
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Transition Metals and Their Complexes

Description: GATE NET SLET
Number of Questions: 15
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Tags: GATE NET SLET General Characteristics of 3d Elements Valence Bond and Crystal Field Theory Enzyme Catalysis Oxides B, Al, Si, N, P, and S Coordination Complexes
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Which of the following statements is/are not correct?

  1. Mn metal is used as a scavenger in making steel.
  2. All known isotopes of Tc are radioactive, except Tc98.
  3. Re is used in the making of electric furnace windings and spectrophotometer filaments.

  1. Only 1

  2. Only 2

  3. Only 3

  4. 1 and 2

  5. 2 and 3

Show answer
Correct Option: B
Explanation:

This option is correct because Technetium (99Tc) was the first man-made element with radioactive property. All known isotopes of technetium (includes 97Tc, 98Tc) have radioactive properties. It is one of the fission products of uranium. It is obtained by spent fuel rods in nuclear reactors.

Which of the following d-electronic configurations will give maximum CFSE in an octahedral complex?

  1. Low spin-d4

  2. High spin-d4

  3. Low spin-d5

  4. High spin-d5

  5. High spin-d7

Show answer
Correct Option: C
Explanation:

In octahedral complexes, CFSE is given by the formula:  CFSE = value of t2g (n) + value of eg (n) Dq, Now, CFSE for low-spin d4 = -4 (4) + 6 (0) = -16 + 0 = -16 Dq CFSE for high-spin d4 = -4 (3) + 6 (1) = -12 + 6 = -6 Dq CFSE for low-spin d5 = -4 (5) + 6 (0) = -20 + 0 = -20 Dq CFSE for high-spin d5 = -4 (3) + 6 (2) = -12 + 12 = 0 Dq CFSE for low-spin d7 = -4 (5) + 6 (2) = -20 + 12 = -8 Dq Hence, low-spin d5 will give maximum CFSE in an octahedral complex.

The clusters of H3Ru3NiCp(CO)9 are used to catalyse

  1. azane synthesis

  2. flue gas

  3. carbonic oxide methanation

  4. Hydrodesulfurization

  5. butyl hydride hydrogenolysis

Show answer
Correct Option: A
Explanation:

Correct answer. H3Ru3NiCp(CO)9 clusters contain Ru-Ni as core metals, which catalyse the azane synthesis.

Which of the following is/are the ore(s) of titanium?

  1. Ilmenite
  2. Hausmannite
  3. Linnaeite

  1. Only 1

  2. Only 2

  3. Only 3

  4. 1 and 2

  5. 2 and 3

Show answer
Correct Option: A
Explanation:

Ilmenite (Fe.TiO3) is the oxide ore of titanium. Hausmannite (Mn3O4) is the oxide ore of manganese. Linnaeite (Co3S4) is the sulphide ore of cobalt. Hence, only ilmenite (Fe.TiO3) is the oxide ore of titanium.

Transitional elements are named transition elements because their characters are

  1. in between s- and p-block elements

  2. like that of p- and d-block elements

  3. members of I – A group

  4. like inactive elements

  5. like active elements

Show answer
Correct Option: A
Explanation:

d-block elements are placed between s- and p-.

Which of the following statements is/are incorrect?

  1. CuCl2 is used as a catalyst in the manufacture of ammonia by Haber process.
  2. CuCl exhibits blue colour in an aqueous solution.
  3. Fractional crystallisation of metals to get the purest form is known as zone-refining.

  1. Only 1

  2. Only 2

  3. Only 3

  4. 1 and 2

  5. 2 and 3

Show answer
Correct Option: D
Explanation:

Correct answer. CuCl2 is used as a catalyst in Deacon process for the preparation of Cl2 from HCl. CuCl, in an aqueous solution, forms Cu ions, which possess no colour due to the presence of completely filled d-orbitals.

Which of the following statements is/are incorrect?

  1. In floatation process, ZnO and SO3 are formed from sulphide ores.
  2. Fe is used as coating material to prevent the corrosion of Zn.
  3. Cd metal is used in nuclear reactors as a neutron excitation material.
  4. Mercury is used extensively in the production of sodium hydroxide and chlorine gas commercially.

  1. Only 1

  2. 2 and 3

  3. 3 and 4

  4. 1, 2 and 3

  5. 2, 3 and 4

Show answer
Correct Option: B
Explanation:

This option is correct because Zn is used as a coating material to prevent the corrosion of Fe. Cd metal absorbs neutrons very well, and is used to make control rods in nuclear reactors.

Match the following ||| |---|---| |Column - I |Column - II| |A. Hf |1. Polymerisation| |B. Al(C2H5)3/TiCl4 |2. Making of lead-free petrol| |C. VC2 |3. Neutron moderator| |D. Pt-Re alloys|4. Acetylene production|

  1. A - 2, B - 1, C - 4, D - 3

  2. A - 3, B - 4, C - 1, D - 2

  3. A - 3, B - 1, C - 4, D - 2

  4. A - 4, B - 2, C - 1, D - 2

  5. A - 4, B - 1, C - 2, D - 3

Show answer
Correct Option: C
Explanation:

This option is correct. Hafnium is used to make control rods for regulating the free neutron levels in the nuclear reactors employed in submarines. The mixture of Al(C2H5)3 and TiCl4 is called Zeigler-Natta catalyst and is used extensively in polymerising alkenes (like ethylene to polyethylene). VC2 (vanadium carbide), on treatment with water, produces acetylene and thus, is used in the production of acetylene. Pt-Re alloys are used as catalysts for making low-lead or lead-free petrol.

Which metal ion represents zero value of CFSE in octahedral complexes if it associated with a weak field ligand?

  1. Fe(III)

  2. Fe(II)

  3. Cr(II)

  4. Mn(I)

  5. Mn(III)

Show answer
Correct Option: A
Explanation:

Correct answer. In weak field ligand, the filling of electrons are in accordance with Hund’s rule. The CFSE is given by the formula:  CFSE = value of t2g (n) + value of eg (n) Dq, Fe(III) corresponds to the d5 configuration. Now, CFSE for Fe(III) (d5) = -4 (3) + 6 (2) = -12 + 12 = 0 Dq CFSE for Fe(II) (d6) = -4 (4) + 6 (2) = -16 + 12 = -4 Dq CFSE for Cr(II) (d4) = -4 (3) + 6 (1) = -12 + 6 = -6 Dq CFSE for Mn(I) (d6) = -4 (4) + 6 (2) = -16 + 12 = -4 Dq CFSE for Mn(III) (d4) = -4 (3) + 6 (1) = -12 + 6 = -6 Dq Hence, the metal ion with zero CFSE is Fe(III) when it associated with a weak field ligand.

Match the list - A (metal), list - B (ore) and list - C (ore type) and select the correct answer using the codes given below the lists |||| |---|---|---| |List - A|List - B|List - C| |P. Cu|1. Smaltite|i. sulphide| |Q. Zn |2. Chalcocite|ii. arsenide| |R. Fe |3. Franklinite|iii. carbonate| |S. Co|4. Siderite|iv. oxide|

  1. P - 3 - i, Q - 2 - iv, R - 4 - iii, S - 1 - ii

  2. P - 2 - i, Q - 3 - iv, R - 1 - iii, S - 4 - ii

  3. P - 2 - i, Q - 3 - ii, R - 1 - iii, S - 4 - iv

  4. P - 2 - i, Q - 3 - iv, R - 1 - ii, S - 4 - iii

  5. P - 2 - i, Q - 3 - iv, R - 4 - iii, S - 1 - ii

Show answer
Correct Option: E
Explanation:

This option is correct because chalcocite (CuS) is a sulphide ore of copper. Franklinite (ZnO.Fe2O3) is the ore of zinc. Siderite (FeCO3) is the carbonate ore of iron. Smaltite (CoAs2) is the main ore of cobalt.

Which of the following statements is/are incorrect?

  1. The central metal atom shows +4 oxidation states in potassium chromate and potassium dichromate.
  2. Limonite and sphalerite are ores of zinc.
  3. Zinc oxide is known as white lead with the formula (PbCO3)2.Pb(OH)2 and is used as a whitening material.

  1. Only 1

  2. Only 2

  3. Only 3

  4. 1 and 2

  5. 2 and 3

Show answer
Correct Option: E
Explanation:

Correct answer. Limonite (Fe2O3.3H2O) is the ore of iron and sphalerite is the ore of zinc. Zinc oxide is an inorganic compound with the formula ZnO. ZnO is a white powder that is insoluble in water, and it is widely used as an additive in numerous materials and products including rubbers, plastics, ceramics, glass, cement, etc. White lead (PbCO3)2•Pb(OH)2 is a complex chemical compound, containing both a carbonate and a hydroxide portion and occurs naturally as a mineral for lead. White lead compounds were used as pigmenting materials like cement, lubricants, etc. But due to its toxicity, they are not used frequently.

Match the entries in Group - I with Group - II ||| |---|---| |Group - I|Group - II | |A. Wilkinson’s catalyst|1. Pt/PtO| |B. Adams catalyst|2. [PH3P]3.Rh.Cl| |C. Lazier catalyst|3. TiCl4/Al(Et)3| |D. Ziegler-Natta catalyst |4. 2CuO.Cr2O3|

  1. A - 2, B - 1, C - 4, D - 3

  2. A - 2, B - 4, C - 1, D - 3

  3. A - 1, B - 2, C - 4, D - 3

  4. A - 4, B - 1, C - 2, D - 3

  5. A - 4, B - 2, C - 1, D - 3

Show answer
Correct Option: A
Explanation:

Correct answer. Wilkinson’s catalyst ([PH3P]3.Rh.Cl) is used in the hydrogenation of alkenes. Adam's catalyst (Pt/PtO) is used in various reduction reactions. Lazier catalyst (2CuO.Cr2O3) is an effective catalyst used for the reduction of aldehydes, ketones and esters to the corresponding alcohols, and aliphatic double bonds. Ziegler-Natta catalyst (TiCl4/Al(Et)3) is used in the synthesis of polymers of alpha-olefins.

Which of the following statements is/are false?

  1. In Raschig process, hydrazine is prepared from the reduction of phosphine with sodium hypochlorite in a dilute aqueous solution.
  2. Borazole is known as inorganic benzene.
  3. Boric acid is a Lewis base.

  1. Only 1

  2. Only 2

  3. Only 3

  4. 1 and 3

  5. 2 and 3

Show answer
Correct Option: D
Explanation:

Correct answer. Hydrazine (N2H4) is a nitrogen hydride. In Raschig process, it is prepared by the reaction of ammonia with sodium hypochlorite in a dilute aqueous solution and Boric acid is a weak monobasic acid. It is not a protonic acid, but acts as a Lewis acid by accepting an electron pair from a hydroxyl ion. Hence, statements 1 and 3 are false.  

Match the entries in Group - I with Group - II ||| |---|---| |Group - I (Ores) |Group - II (Corresponding metal)| |P. Patronite|1. V| |Q. Crocoite|2. Ni| |R. Garnierite|3. Pt| |S. Sperrylite|4. Cr| | |5. Cu|

  1. P - 1, Q - 4, R - 2, S - 3

  2. P - 3, Q - 4, R - 2, S - 5

  3. P - 3, Q - 4, R - 1, S - 2

  4. P - 1, Q - 2, R - 5, S - 3

  5. P - 4, Q - 3, R - 2, S - 1

Show answer
Correct Option: A
Explanation:

Patronite is the sulphide ore of vanadium. Crocoite (PbCrO4) is the ore of chromium. Garnierite (NiMgSiO3.nH2O) is the ore of nickel. Sperrylite is the sulphide ore of platinum. Hence, the correct answer using the codes is P - 1, Q - 4, R - 2, S - 3.

Match the following salt names with their molecular formula ||| |---|---| |(i) Fischer salt|(a) [Pt(NH3)4][PtCl4]| |(ii) Zeise’s salt|(b) Fe2[Fe(CN)6]| |(iii) Magnus’ green salt|(c) K3[Co(NO2)6]| |(iv) Turnbull’s blue|(d) K3[Fe(CN)6]| |(v) Gmelin’s salt|(e) K[PtCl3(C2H4)]|

  1. (i) - c, (ii) - e, (iii) - a, (iv) - b, (v) - d

  2. (i) - c, (ii) - e, (iii) - a, (iv) - d, (v) - b

  3. (i) - d, (ii) - e, (iii) - a, (iv) - c, (v) - b

  4. (i) - d, (ii) - a, (iii) - e, (iv) - c, (v) - d

  5. (i) - c, (ii) - a, (iii) - e, (iv) - b, (v) - d

Show answer
Correct Option: A
Explanation:

In this option, all salt names are correctly matched with their molecular formulae.

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