2010|Electronics and Comm (GATE Exam)-Previous Question Paper Solution

Description: GATE Exam Previous Year Question Paper Solution Electronics and Communication (ECE) - 2010
Number of Questions: 65
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Tags: EC-GATE-2010 Matrices and Determinants Electronics & Communication Engineering - EC Signals and System Differential Calculus Network Graphs Electronic Devices Analog Circuits
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Assuming that flip-flops are in reset condition initially, the count sequence observed at QA in the circuit shown is

  1. 0010111…

  2. 0001011…

  3. 0101111…

  4. 01101..........…


Correct Option: D
Explanation:

Match the logic gates in Column A with their equivalents in Column B.

  1. P-2, Q-4, R-1, S-3

  2. P-4, Q-2, R-1, S-3

  3. P-2, Q-4, R-3, S-1

  4. P-4, Q-2, R-3, S-1


Correct Option: D
Explanation:

For the 8085 assembly language program given below, the content of the accumulator after the execution of the program is

  1. 00H

  2. 45H

  3. 67H

  4. E7H


Correct Option: C
Explanation:

The Boolean function realised by the logic circuit shown below is

  1. F =$\sum$m(0, 1, 3, 5, 9, 10, 14)

  2. F =$\sum$m(2, 3, 5, 7, 8, 12, 13)

  3. F =$\sum$m(1, 2, 4, 5, 11, 14, 15)

  4. F =$\sum$m(2, 3, 5, 7, 8, 9, 12)


Correct Option: D
Explanation:

For the output F to be 1 in the logic circuit shown, the input combination should be

  1. A = 1, B = 1, C = 0

  2. A = 1, B = 0, C = 0

  3. A = 0, B = 1, C = 0

  4. A = 0, B = 0, C = 1


Correct Option: D
Explanation:

In the circuit shown, the device connected to Y5 can have address in the range.

  1. 2000 - 20FF

  2. 2D00 - 2DFF

  3. 2E00 - 2EFF

  4. FD00 - FDFF


Correct Option: B
Explanation:

If the scattering matrix [S] of a two port network is [S] = $ \left[ \begin{array} \ 0.2\angle0^\circ & 0.9 \angle90^\circ \\ 0.9\angle90^\circ & 0.1 \angle 90^\circ \end{array} \right] $ then the network is

  1. lossless and reciprocal

  2. lossless but not reciprocal

  3. not lossless but reciprocal

  4. neither lossless nor reciprocal


Correct Option: C
Explanation:

A transmission line has a characteristic impedance of 50$\Omega$ and a resistance of 0.1$\Omega$ /m. if the line is distortion less, the attenuation constant (in Np/m) is

  1. 500

  2. 5

  3. 0.014

  4. 0.002


Correct Option: D
Explanation:

Thick oxide in a CMOS process is preferably grown using

  1. wet oxidation

  2. dry oxidation

  3. epitaxial deposition

  4. ion implantation


Correct Option: B
Explanation:

Dry oxidation is used to achieve high quality oxide growth.

Compared to a p-n junction with NA=ND=1014/cm3, which one of the following statements is TRUE for a p-n junction with NA=ND=1020/cm3?

  1. Reverse breakdown voltage is lower and depletion capacitance is lower.

  2. Reverse breakdown voltage is higher and depletion capacitance is lower.

  3. Reverse breakdown voltage is lower and depletion capacitance is higher.

  4. Reverse breakdown voltage is higher and depletion capacitance is higher.


Correct Option: C
Explanation:

Reverse bias breakdown or Zener effect oauts in highly doped PN junction through tunneling mechanism. In a highly doped PN Junction, the conduction and valence beads on opposite tides of the junction are sufficiently doe. dogleg raven. bias that electron may tunnel directly from the valence hand on the p-side into the conduction bend on n-side.

Breakdown voltage $V_B \propto \dfrac{1}{N_AN_D}$

So, breakdown voltage decreases as concentration increases

Depletion capacitance $C = \left[ \dfrac{\epsilon_0 N_AN_D}{2(V_{be} + V_R) (N_A + N_D) } \right]^{8/x} $

Thus $C \propto N_AN_D$

Depletion capacitance increases as concentration increases

A plane wave having the electric field component $E_1$ = 24 cos(3$\times$108t -$\beta$y)$\widehat a_z$V/m and traveling in free space is incident normally on a lossless medium with m = m0 and e = 9e0 which occupies the region y ≥ 0. The reflected magnetic field component is given by

  1. $\dfrac{1}{10\pi} cos(3 \times 10^8 t + y) a_x \ A/m $

  2. $\dfrac{1}{20\pi}$cos (3$\times$108t + y)$\widehat a_x$ A/m

  3. -$\dfrac{1}{20\pi}$cos (3$\times$108t + y)$\widehat a_x$ A/m

    • $\dfrac{1}{10\pi}$cos (3$\times$108t + y)$\widehat a_x$ A/m

Correct Option: A
Explanation:

In the circuit shown, all the transmission line sections are lossless. The Voltage Standing Wave Ration (VSWR) on the 60W line is

  1. 1.00

  2. 1.64

  3. 2.50

  4. 3.00


Correct Option: B
Explanation:

At room temperature, a possible value for the mobility of electrons in the inversion layer of a silicon n-channel MOSFET is

  1. 450 cm2/ VS

  2. 1350 cm2/ VS

  3. 1800 cm2/ VS

  4. 3600 cm2/ VS


Correct Option: B
Explanation:

The silicon sample with unit cross-sectional area shown below is in thermal equilibrium. The following information is given: T=300K, electronic charge=1.6x10-19C, thermal voltage=26mV and electron mobility = 1350cm2/V-s

The magnitude of the electric field at x = 0.5 $\mu$m is

  1. 1kV/cm

  2. 5kV/cm

  3. 10 kV/cm

  4. 26kV/cm


Correct Option: C
Explanation:

Sample is in thermal equilibrium so, electric field

$E = \dfrac{1}{1\mu m} = 10 \ kV/cm$

The silicon sample with unit cross-sectional area shown below is in thermal equilibrium. The following information is given: T=300K, electronic charge=1.6x10-19C, thermal voltage=26mV and electron mobility = 1350cm2/V-s

The magnitude of the electron drift current density at x = 0.5 $\mu$m is

  1. 2.16$\times$104 A/cm2

  2. 1.08$\times$104 A/cm2

  3. 4.32$\times$103 A/cm2

  4. .48$\times$102 A/cm2


Correct Option: A
Explanation:

   Sample is in thermal equilibrium so, electric field

$E = \dfrac{1}{1\mu m} = 10 \ kV/cm$

 

Suppose that the modulating signal is m(t) = 2cos (2$\pi$fmt) and the carrier signal is xC(t) = AC cos(2$\pi$fCt), which one of the following is a conventional AM signal without over-modulation?

  1. x(t) = Acm(t) cos(2$\pi$fct)

  2. x(t) = Ac[1 + m(t)]cos(2$\pi$fct)

  3. x(t) = Ac cos(2$\pi$fct) + $\dfrac{A_0}{4}$m(t) cos (2$\pi$fCt)

  4. x(t) = Ac cos(2$\pi$fmt) cos(2$\pi$fct) + Ac sin(2$\pi$fmt) sin(2$\pi$fct)


Correct Option: C
Explanation:

Consider a baseband binary PAM receiver shown below. The additive channel noise n(t) is whit with power spectral density SN(f)=N0/2=10-20 W/Hz. The low-pass filter is ideal with unity gain and cutoff frequency 1MHz. Let Yk represent the random variable y(tk). Yk=Nk if transmitted bit bk=0 Yk=a+Nk if transmitted bit bk=1 Where Nk represents the noise sample value. The noise sample has a probability density function, PNk(n)=0.5لe-ل|n| (This has mean zero and variance 2/ل2). Assume transmitted bits to be equiprobable and threshold z is set to a/2=10-6V.

The probability of bit error is

  1. 0.5xe-3.5

  2. 0.5xe-5

  3. 0.5xe-7

  4. 0.5xe-10


Correct Option: D
Explanation:

Consider a baseband binary PAM receiver shown below. The additive channel noise n(t) is whit with power spectral density SN(f)=N0/2=10-20 W/Hz. The low-pass filter is ideal with unity gain and cutoff frequency 1MHz. Let Yk represent the random variable y(tk). Yk=Nk if transmitted bit bk=0 Yk=a+Nk if transmitted bit bk=1 Where Nk represents the noise sample value. The noise sample has a probability density function, PNk(n)=0.5لe-ل|n| (This has mean zero and variance 2/ل2). Assume transmitted bits to be equiprobable and threshold z is set to a/2=10-6V.

The value of the parameter ل (in V-1) is

  1. 1010

  2. 107

  3. 1.414$\times$10-10

  4. 2$\times$10-20


Correct Option: B
Explanation:

Consider an angle modulated signal x(t) = 6cos[2π x 106t + 2sin(8000πt) + 4cos(8000pt)] V. The average power of x(t)

  1. 10W

  2. 18W

  3. 20W

  4. 28W


Correct Option: B
Explanation:

$Power \qquad P = \dfrac{6^2}{2} = 18W$

Consider the pulse shape s(t) as shown. The impulse response h(t) of the filter matched to this pulse is


Correct Option: C
Explanation:

The Nyquist sampling rate for the signal s(t) = $\dfrac{sin(500 \pi t)}{\pi t}$ $\times$ $\dfrac{sin(700 \pi t)}{\pi t}$ is given by

  1. 400 Hz

  2. 600 Hz

  3. 1200Hz

  4. 1400 Hz


Correct Option: C
Explanation:

X(t) is a stationary process with the power spectral density Sx(f)>0 for all f. The process is passed through a system shown below. Let Sy(f) be the power spectral density of Y(t). Which one of the following statements is correct?

Let Sy(f) be the power spectral density of Y(t). Which one of the following statements is correct?

  1. Sy(f)>0 for all f

  2. Sy(f)=0 for |f|>1kHz

  3. Sy(f)=0 for f=nf0, f0=2kHz, n any integer

  4. Sy(f)=0 for f=(2n+1)f0=1kHz, n any integer


Correct Option: D
Explanation:

The transfer function of a discrete time LTI system is given by H(z) = $\dfrac{ 2-\dfrac{3}{4}z^{-1} }{ 1 - \dfrac{3}{4}z^{-t} + \dfrac{1}{8}z^{-2} }$ Consider the following statements: S1: The system is stable and causal for ROC:|z|>½ S2: The system is stable but not causal for ROC:|z|<¼ S3: The system is neither stable nor causal for ROC: ¼<|z|<½

Which one of the following statements is valid?

  1. Both S1 and S2 are true.

  2. Both S2 and S3 are true.

  3. Both S1 and S3 are true.

  4. S1, S2 and S3 are all true.


Correct Option: C
Explanation:

Consider the z-transform X(z) = 5z2 + 4z-1 + 3; 0<|z| < $\infty$. The inverse z-transform x[n] is

  1. 5$\delta$[n + 2] + 3$\delta$[n] + 4$\delta$[n - 1]

  2. 5$\delta$[n - 2] + 3$\delta$[n] + 4$\delta$[n + 1]

  3. 5 u[n + 2] + 3 u[n] + 4 u[n - 1]

  4. 5 u[n - 2] + 3 u[n] + 4 u[n + 1]


Correct Option: A
Explanation:

A continuous time LTI system is described by $\dfrac{d^2 y(t)}{dt^2} + 4 \dfrac{dy(t)}{dt} 3 y(t) = 2 \dfrac{dx(t)}{dt} + 4 \times (t)$. Assuming zero initial condition, the response y(t) of the above system for the input x(t) = e-2tu(t) is given by

  1. (et-e3t)u(t)

  2. (e-t-3-3t)u(t)

  3. (e-t+e-3t)u(t)

  4. (et+e3t)u(t)


Correct Option: B
Explanation:

For an N-point FFT algorithm with N = 2m which one of the following statements is TRUE?

  1. It is not possible to construct a signal flow graph with both input and output in normal order.

  2. The number of butterflies in the mth stage is N/m.

  3. In-place computation requires storage of only 2N node data.

  4. Computation of a butterfly requires only one complex multiplication.


Correct Option: D
Explanation:

Two discrete time systems with impulse responses h1[n] = $\delta$[n -1] and h2[n] = $\delta$[n - 2] are connected in cascade. The overall impulse response of the cascaded system is

  1. $\delta$[n - 1] + $\delta$[n - 2]

  2. $\delta$[n - 4]

  3. $\delta$[n - 3]

  4. $\delta$[n - 1] $\delta$[n - 2]


Correct Option: C
Explanation:

The trigonometric Fourier series for the waveform f(t) shown below contains

  1. only cosine terms and zero value for the dc component

  2. only cosine terms and a positive value for the dc component

  3. only cosine terms and a negative value for the dc component

  4. only sine terms and a negative for the dc component


Correct Option: C
Explanation:

Given f(t) = L–1 $\left[ \dfrac{3s+1}{s3 + 4s2 + (K-3)s} \right]$. If $\displaystyle lim_{x \rightarrow \theta}$f(t) = 1, then the value of K is

  1. 1

  2. 2

  3. 3

  4. 4


Correct Option: B
Explanation:

A circuit consists of a resistor, an inductor and a capacitor connected in series to a 150 V AC mains. For the circuit, R = 9 Ohms, XL = 28 Ohms and XC = 16 Ohms. What is the value of the current in the circuit?

  1. 10 A

  2. 15 A

  3. 20 A

  4. 25 A


Correct Option: A
Explanation:

Z = $\sqrt{R^2 + (X_L - X_C)^2 }$ = $\sqrt{9^2 + (28 - 16)^2 }$ = 15 Ohms = I = 150/15 = 10 A

For parallel RLC circuit, which one of the following statements is NOT correct?

  1. The bandwidth of the circuit deceases if R is increased.

  2. The bandwidth of the circuit remains same if L is increased.

  3. At resonance, input impedance is a real quantity.

  4. At resonance, the magnitude of input impedance attains its minimum value.


Correct Option: D
Explanation:

In the circuit shown, the power supplied by the voltage source is

  1. 0W

  2. 5W

  3. 10W

  4. 100W


Correct Option: A
Explanation:

In the circuit shown, the switch S is open for a long time and is closed at t = 0. The current i(t) for t$\ge$ 0+ is

  1. i(t)=0.5-0.125e-1000tA

  2. i(t)=1.5-0.125e-1000tA

  3. i(t)=0.5-0.5e-1000tA

  4. i(t)=0.375e-1000tA


Correct Option: A
Explanation:

         Here we see in given figure           i(0) = .75/2 = .375 A           i(infinite) = 1.5/3 = .5 A           i(t) = A + B e^(-1000 t)           Put t= 0 and then put t= infinite          Then we get A= .5      and B= -.125           

For the two-port network shown below, the short circuit admittance parameter matrix is

  1. $\left[ \begin{array} \ 4 & -2 \\ -2 & 4 \end{array} \right] $S

  2. $\left[ \begin{array} \ 1 & -0.5 \\ -0.5 & 1 \end{array} \right] $S

  3. $\left[ \begin{array} \ 1 & 0.5 \\ 0.5 & 1 \end{array} \right] $S

  4. $\left[ \begin{array} \ 4 & 2 \\ 2 & 4 \end{array} \right] $S


Correct Option: A
Explanation:

The electric field component of a time harmonic plane EM wave traveling in a nonmagnetic lossless dielectric medium has an amplitude of 1 V/m. If the relative permittivity of the medium is 4, the magnitude of the time-average power density vector (in W/m2) is

  1. $\frac{1}{30 \pi}$

  2. $\frac{1}{60 \pi}$

  3. $\frac{1}{120 \pi}$

  4. $\frac{1}{240 \pi}$


Correct Option: C
Explanation:

Which of the following options is the closest in meaning to the word below.

Circuitous

  1. Cyclic

  2. indirect

  3. confusing

  4. crooked


Correct Option: B
Explanation:

25 persons are in a room. 15 of them play hockey, 17 of them play football and 10 of them play both hockey and football. Then the number of persons playing neither hockey nor football is

  1. 2

  2. 17

  3. 13

  4. 3


Correct Option: D
Explanation:

Choose the most appropriate word from the options given below to complete the following sentence. If we manage to ________ our natural resources, we would leave a better planet for our children.

  1. uphold

  2. restrain

  3. Cherish

  4. conserve


Correct Option: D
Explanation:

Here conserve is most appropriate word.

5 skilled workers can build a wall in 20 days; 8 semi-skilled worker can build a wall in 25days; 10 unskilled workers can build a wall in 30 days. If a team has 2 killed, 6 semi-skilled and 5 unskilled workers, how long will it take to build the wall?

  1. 20 days

  2. 18 days

  3. 16 days

  4. 15 days


Correct Option: D
Explanation:

In a uniformly doped BJT, assume that NE, NB and NC are the emitter, base and collector dopings in atoms/cm3, respectively. If the emitter injection efficiency of the BJT is close unity, which one of the following conditions is TRUE?

  1. NE = NB = NC

  2. NE >>NB and NB > NC

  3. NE = NB and NB < NC

  4. NE < NB < NC


Correct Option: B
Explanation:

If 137 + 276 = 435 how much is 731 + 672?

  1. 534

  2. 1403

  3. 1623

  4. 1513


Correct Option: C
Explanation:

Choose the most appropriate word from the options given below to complete the following sentence.
His rather casual remarks on politics _______ his lack of seriousness about the subject.

  1. masked

  2. belied

  3. cherish

  4. conserve


Correct Option: C
Explanation:

Betrayed means reveal unintentionally that is most appropriate.

The question below consists of a pair of related of related words followed by four pairs of words. Select the pair that best expresses the relation in the original pair. Unemployed: Worker

  1. fallow : land

  2. unaware : sleeper

  3. wit : jester

  4. renovated : house


Correct Option: A
Explanation:

Just as a worker is unemployed a piece of land unused is fallow.

Modern warfare has changed from large scale clashes of armies to suppression of civilian populations. Chemical agents that do their work silently appear to be suited to such warfare; and regretfully, there exist people in military establishments who think that chemical agents are useful tools for their cause. Which of the following statements best sums up the meaning of the above passage?

  1. Modern warfare has resulted in civil strife.

  2. Chemical agents are useful in modern warfare.

  3. Use of chemical agents in warfare would be undesirable.

  4. People in military establishments like to use chemical agents in war.


Correct Option: C

With digits 2, 2, 3, 3, 3, 4, 4, 4, 4, how many distinct 4-digit numbers greater than 3000 can be formed?

  1. 50

  2. 51

  3. 52

  4. 54


Correct Option: B
Explanation:

Hari (H), Gita (G), Irfan (I) and Saira (S) are sibiligs (i.e. brothers and sisters). All were born on 1st January. The age difference between any two successive siblings (that is born one after another) is less than3 years. Given the following facts: i. Hair's age + Gita's age > Irfan's age + Saira's age. ii. The age difference between Gita and Saira is 1 year. However, Gita is not the oldest and Saira is not the youngest. iii. There are not twins.

In what order were they born (0ldest first)?

  1. HSIG

  2. SGHI

  3. IGSH

  4. IHSG


Correct Option: B
Explanation:

A function n(x) satisfied the differential equation $\frac{d^2 n(x)}{dx^2} - \frac{n(x)}{L^2}$ = 0 where L is a constant. The boundary conditions are: n(0) = K and n (∞) = 0. The solution to this equation is

  1. n(x) = K exp(x/L)

  2. n(x) = K exp(-x/$\sqrt{5}$)

  3. n(x) = K2 exp(-x/L)

  4. n(x) = K exp(-x/L)


Correct Option: D
Explanation:

If $A^.$ = xy + x2$\hat{a}_y$ then $\oint_c A^. dl^.$over the path shown in the figure is

  1. 0

  2. $\frac{2}{\sqrt{3}}$

  3. 1

  4. 2$\sqrt{3}$


Correct Option: C
Explanation:

The eigen values of a skew-symmetric matrix are

  1. always zero

  2. always purely imaginary

  3. either zero or purely imaginary

  4. always real


Correct Option: C
Explanation:

Eigen values of a skew-symmetric matrix are either zero or pure imaginary occuring in conjugate pairs.

Consider differential equation $\frac{dy(x)}{dx} - y$(x) = x with the initial condition y(0) = 0. Using Euler’s first order method with a step size of 0.1, the value of y (0.3) is

  1. 0.01

  2. 0.031

  3. 0.0631

  4. 0.1


Correct Option: B
Explanation:

If ey = $X^{\frac{1}{x}}$, then y has a

  1. maximum at x = e

  2. minimum at x = e

  3. maximum at x = e-1

  4. minimum at x = e-1


Correct Option: A
Explanation:

The residues of a complex function X(z) = $\frac{1 - 12z}{z(z - 1)(z - 2)}$at its poles are

  1. $\frac{1}{2}$, $\frac{1}{2}$ and 1

  2. $\frac{1}{2}$, $\frac{1}{2}$and – 1

  3. $\frac{1}{2}$, 1 and –3/2

  4. $\frac{1}{2}$, – 1 and $\frac{2}{3}$


Correct Option: C
Explanation:

 X(z)= (1-2z)/{z(z-1)(z-2)}      Poles are located at z=0, z=1 and z=2          At z=0            = z(1-2z)/{z(z-1)(z-2)} = 1/2          At z=1            =(z-1)(1-2z)/{z(z-1)(z-2)}= 1            At z=2           =(z-2)(1-2z)/{z(z-1)(z-2)} = -3/2      

In the silicon BJT circuit shown below, assume that the emitter area of transistor Q1 is half that of transistor Q2.

The value of current I0 is approximately

  1. 0.5 mA

  2. 2 mA

  3. 9.3 mA

  4. 15 mA


Correct Option: B
Explanation:

Consider the common emitter amplifier shown below with the following circuit parameters.

B = 100, gm = 0.3861 A/V, r0 = $\infty$, rp = 259 W, RS = 1 kW, RB = 93 kW, RC = 250 W, RL = 1 kW, C1 = $\infty$ and C2 = 4.7 mF.

The lower cut-off frequency due to C2 is

  1. 33.9 Hz

  2. 27.1 Hz

  3. 13.6 Hz

  4. 16.9 Hz


Correct Option: B
Explanation:

Consider the common emitter amplifier shown below with the following circuit parameters.

B = 100, gm = 0.3861 A/V, r0 = $\infty$, rp = 259 W, RS = 1k W, RB = 93kW, RC = 250 W, RL = 1k W, C1 = $\infty$ and C2 = 4.7mF.

The resistance seen by the source Vs is

  1. 258$\Omega$

  2. 1252$\Omega$

  3. 93 K$\Omega$

  4. $\infty$


Correct Option: B
Explanation:

By using given solution figure and solution                            Rin = 1000 + [(9300 * 259)/(9300 + 259)] = 1252 om                                                      

The amplifier circuit shown below uses a silicon transistor. The capacitors CC and CE can be assumed to be short at signal frequency and the effect of output resistance R0 can be ignored. If CE is disconnected from the circuit, which one of the following statements is TRUE?

  1. The input resistance Ri increases and the magnitude of voltage gain AV decreases.

  2. The input resistance Ri decreases and the magnitude of voltage gain AV decreases.

  3. Both input resistance Ri and the magnitude of voltage gain AV decrease.

  4. Both input resistance Ri and the magnitude of voltage gain AV increase.


Correct Option: A
Explanation:

Assuming the OP-AMP to be ideal, the voltage gain of the amplifier shown below is

  1. $ - \dfrac{R_2}{R_1}$

  2. $ - \dfrac{R_3}{R_1}$

  3. $ - \dfrac{R_2 || R_3}{R_1}$

  4. $ - \dfrac{R_2 || R_3}{R_1}$


Correct Option: A
Explanation:

The transfer characteristic for the precision rectifier circuit shown below is (assume ideal OP-AMP and practical diodes)


Correct Option: B
Explanation:

For the asymptotic Bode magnitude plot shown below, the system transfer function can be

  1. $$ \dfrac{10s+1}{0.1s + 1} $$

  2. $$ \dfrac{100s+1}{0.1s + 1} $$

  3. $$ \dfrac{100s}{10s + 1} $$

  4. $$ \dfrac{0.1s+1}{10s + 1} $$


Correct Option: A
Explanation:

Here by using figure            K = 1,   w1 = .1 rad/s         and      w2 = 10 rad/s             H(s)     = K (1 + s/w1)/(1 + s/w2)  = 1(1 + s/.1)/(1 + s/10)  = (1 + 10s)/(1 + .1s)            

The transfer function Y(s)/R(s) of the system shown is

  1. 0

  2. $\dfrac{1}{s+1}$

  3. $\dfrac{2}{s+1}$

  4. $\dfrac{2}{s+3}$


Correct Option: B
Explanation:

The given solution is right. Here R(s) is the input transfer function when it passes through the circuit it converts into E(s) output transfer function. Here Y(s) is the final output transfer function. Here H(s) is the output transfer function out from the circuit finally.                   

The signal flow graph of a system is shown below.

Which of the following is the state variable representation of the system?

  1. $ x = \left[ \begin{array} \ 1 & 1 \\ -1 & 0 \end{array} \right] x + \left[ \begin{array} \ 0 \\ 2 \end{array} \right] u $ y = [0 & 0.5] x

  2. $ x = \left[ \begin{array} \ -1 & 1 \\ -1 & 0 \end{array} \right] x + \left[ \begin{array} \ 0 \\ 2 \end{array} \right] u $ y = [0 & 0.5] x

  3. $ x = \left[ \begin{array} \ 1 & -1 \\ -1 & 0 \end{array} \right] x + \left[ \begin{array} \ 0 \\ 2 \end{array} \right] u $ y = [0.5 & 0.5] x

  4. $ x = \left[ \begin{array} \ -1 & 1 \\ -1 & 0 \end{array} \right] x + \left[ \begin{array} \ 0 \\ 2 \end{array} \right] u $ y = [0.5 & 0.5] x


Correct Option: D
Explanation:

The signal flow graph of a system is shown below.

The transfer function of the system is

  1. $ \dfrac{s+1}{(s^2+1)} $

  2. $ \dfrac{s-1}{(s^2+1)} $

  3. $ \dfrac{s+1}{(s^2+s+1)} $

  4. $ \dfrac{s-1}{(s^2+s+1)} $


Correct Option: C
Explanation:

A system with transfer function $ \left[ \begin{array} \ Y(s) \\ X(s) \end{array} \right] $ = $\dfrac{s}{s+p}$has an output y(t) = cos $ \left( \begin{array} \ 2t - \dfrac{\pi}{3} \end{array} \right) $for the input signal x(t) = p cos $ \left( \begin{array} \ 2t - \dfrac{\pi}{2} \end{array} \right) $. Then, the system parameter ‘p’ is

  1. $\sqrt3$

  2. $\dfrac{2}{\sqrt3}$

  3. 1

  4. $\dfrac{\sqrt3}{2}$


Correct Option: B
Explanation:

A unity negative feedback closed loop system has a plant with the transfer function G(s) = $\dfrac{1}{s^2 + 2s +2}$ and a controller Gc(S) in the feed forward path. For a unit set input, the transfer function of the controller that gives minimum steady state error is

  1. GC(s) = $\dfrac{s+1}{s+2}$

  2. GC(s) = $\dfrac{s+2}{s+1}$

  3. GC(s) = $\dfrac{(s+1)(s+4)}{(s+2)(s+3)}$

  4. GC(s) = 1 + $\dfrac{2}{s}$+ 3s


Correct Option: D
Explanation:

A fair coin is tossed independently four times. The probability of the event “the number of time heads shown up is more than the number of times tails shown up” is

  1. $\frac{1}{16}$

  2. $\frac{1}{8}$

  3. $\frac{1}{4}$

  4. $\frac{5}{16}$


Correct Option: D
Explanation:

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