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Solving Quadratic Equations

Description: This quiz is designed to assess your understanding of solving quadratic equations. Quadratic equations are equations of the form ax^2 + bx + c = 0, where a, b, and c are real numbers and a is not equal to 0. To solve a quadratic equation, you can use the quadratic formula, factoring, or completing the square.
Number of Questions: 15
Created by:
Tags: algebra quadratic equations factoring completing the square quadratic formula
Attempted 0/15 Correct 0 Score 0

Solve the quadratic equation: x^2 - 5x + 6 = 0

  1. x = 2, 3

  2. x = -2, -3

  3. x = 1, 6

  4. x = -1, -6


Correct Option: A
Explanation:

To solve this equation, we can use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a. Plugging in the values of a, b, and c, we get: x = (-(-5) ± √((-5)^2 - 4(1)(6))) / 2(1). Simplifying this, we get: x = (5 ± √(25 - 24)) / 2. Further simplifying, we get: x = (5 ± 1) / 2. Therefore, x = 2 or x = 3.

Solve the quadratic equation: 2x^2 + 7x - 4 = 0

  1. x = 1, -2

  2. x = -1, 2

  3. x = 1, 4

  4. x = -1, -4


Correct Option: A
Explanation:

To solve this equation, we can use factoring. We can factor the left-hand side as follows: (2x - 1)(x + 4) = 0. Setting each factor equal to 0, we get: 2x - 1 = 0 and x + 4 = 0. Solving these equations, we get: x = 1/2 and x = -4. Therefore, the solutions to the quadratic equation are x = 1 and x = -2.

Solve the quadratic equation: 3x^2 - 2x - 8 = 0

  1. x = 2, -4/3

  2. x = -2, 4/3

  3. x = 1, -8

  4. x = -1, 8


Correct Option: A
Explanation:

To solve this equation, we can use the quadratic formula. Plugging in the values of a, b, and c, we get: x = (-(-2) ± √((-2)^2 - 4(3)(-8))) / 2(3). Simplifying this, we get: x = (2 ± √(4 + 96)) / 6. Further simplifying, we get: x = (2 ± √100) / 6. Therefore, x = 2 or x = -4/3.

Solve the quadratic equation: x^2 - 6x + 9 = 0

  1. x = 3, 3

  2. x = -3, -3

  3. x = 1, 9

  4. x = -1, -9


Correct Option: A
Explanation:

To solve this equation, we can use completing the square. We can rewrite the left-hand side as follows: x^2 - 6x + 9 = (x - 3)^2. Setting this equal to 0, we get: (x - 3)^2 = 0. Taking the square root of both sides, we get: x - 3 = 0. Solving for x, we get: x = 3. Therefore, the only solution to the quadratic equation is x = 3.

Solve the quadratic equation: 4x^2 + 12x + 9 = 0

  1. x = -3/2, -3/2

  2. x = 3/2, 3/2

  3. x = 1, 9

  4. x = -1, -9


Correct Option: A
Explanation:

To solve this equation, we can use the quadratic formula. Plugging in the values of a, b, and c, we get: x = (-12 ± √(12^2 - 4(4)(9))) / 2(4). Simplifying this, we get: x = (-12 ± √(144 - 144)) / 8. Further simplifying, we get: x = (-12 ± 0) / 8. Therefore, x = -3/2 or x = -3/2.

Solve the quadratic equation: 2x^2 - 5x + 2 = 0

  1. x = 1, 2

  2. x = -1, -2

  3. x = 1, -2

  4. x = -1, 2


Correct Option: A
Explanation:

To solve this equation, we can use factoring. We can factor the left-hand side as follows: (2x - 1)(x - 2) = 0. Setting each factor equal to 0, we get: 2x - 1 = 0 and x - 2 = 0. Solving these equations, we get: x = 1/2 and x = 2. Therefore, the solutions to the quadratic equation are x = 1 and x = 2.

Solve the quadratic equation: 3x^2 + 7x + 2 = 0

  1. x = -1, -2

  2. x = 1, 2

  3. x = -1, 2

  4. x = 1, -2


Correct Option: A
Explanation:

To solve this equation, we can use the quadratic formula. Plugging in the values of a, b, and c, we get: x = (-7 ± √(7^2 - 4(3)(2))) / 2(3). Simplifying this, we get: x = (-7 ± √(49 - 24)) / 6. Further simplifying, we get: x = (-7 ± √25) / 6. Therefore, x = -1 or x = -2.

Solve the quadratic equation: 5x^2 - 2x - 3 = 0

  1. x = 1, -3

  2. x = -1, 3

  3. x = 1, 3

  4. x = -1, -3


Correct Option: A
Explanation:

To solve this equation, we can use factoring. We can factor the left-hand side as follows: (5x + 3)(x - 1) = 0. Setting each factor equal to 0, we get: 5x + 3 = 0 and x - 1 = 0. Solving these equations, we get: x = -3/5 and x = 1. Therefore, the solutions to the quadratic equation are x = 1 and x = -3.

Solve the quadratic equation: 2x^2 + 3x - 5 = 0

  1. x = 1, -5

  2. x = -1, 5

  3. x = 1, 5

  4. x = -1, -5


Correct Option: A
Explanation:

To solve this equation, we can use the quadratic formula. Plugging in the values of a, b, and c, we get: x = (-3 ± √(3^2 - 4(2)(-5))) / 2(2). Simplifying this, we get: x = (-3 ± √(9 + 40)) / 4. Further simplifying, we get: x = (-3 ± √49) / 4. Therefore, x = 1 or x = -5.

Solve the quadratic equation: 4x^2 - 12x + 9 = 0

  1. x = 3, 3

  2. x = -3, -3

  3. x = 1, 9

  4. x = -1, -9


Correct Option: A
Explanation:

To solve this equation, we can use completing the square. We can rewrite the left-hand side as follows: 4x^2 - 12x + 9 = (2x - 3)^2. Setting this equal to 0, we get: (2x - 3)^2 = 0. Taking the square root of both sides, we get: 2x - 3 = 0. Solving for x, we get: x = 3/2. Therefore, the only solution to the quadratic equation is x = 3/2.

Solve the quadratic equation: 3x^2 - 5x - 2 = 0

  1. x = 1, -2

  2. x = -1, 2

  3. x = 1, 2

  4. x = -1, -2


Correct Option: A
Explanation:

To solve this equation, we can use factoring. We can factor the left-hand side as follows: (3x + 1)(x - 2) = 0. Setting each factor equal to 0, we get: 3x + 1 = 0 and x - 2 = 0. Solving these equations, we get: x = -1/3 and x = 2. Therefore, the solutions to the quadratic equation are x = 1 and x = -2.

Solve the quadratic equation: 2x^2 + 7x + 3 = 0

  1. x = -1, -3

  2. x = 1, 3

  3. x = -1, 3

  4. x = 1, -3


Correct Option: A
Explanation:

To solve this equation, we can use the quadratic formula. Plugging in the values of a, b, and c, we get: x = (-7 ± √(7^2 - 4(2)(3))) / 2(2). Simplifying this, we get: x = (-7 ± √(49 - 24)) / 4. Further simplifying, we get: x = (-7 ± √25) / 4. Therefore, x = -1 or x = -3.

Solve the quadratic equation: 5x^2 - 3x - 2 = 0

  1. x = 1, -2

  2. x = -1, 2

  3. x = 1, 2

  4. x = -1, -2


Correct Option: A
Explanation:

To solve this equation, we can use factoring. We can factor the left-hand side as follows: (5x + 2)(x - 1) = 0. Setting each factor equal to 0, we get: 5x + 2 = 0 and x - 1 = 0. Solving these equations, we get: x = -2/5 and x = 1. Therefore, the solutions to the quadratic equation are x = 1 and x = -2.

Solve the quadratic equation: 2x^2 - 5x + 2 = 0

  1. x = 1, 2

  2. x = -1, -2

  3. x = 1, -2

  4. x = -1, 2


Correct Option: A
Explanation:

To solve this equation, we can use the quadratic formula. Plugging in the values of a, b, and c, we get: x = (-(-5) ± √((-5)^2 - 4(2)(2))) / 2(2). Simplifying this, we get: x = (5 ± √(25 - 16)) / 4. Further simplifying, we get: x = (5 ± √9) / 4. Therefore, x = 1 or x = 2.

Solve the quadratic equation: 3x^2 + 7x + 2 = 0

  1. x = -1, -2

  2. x = 1, 2

  3. x = -1, 2

  4. x = 1, -2


Correct Option: A
Explanation:

To solve this equation, we can use the quadratic formula. Plugging in the values of a, b, and c, we get: x = (-7 ± √(7^2 - 4(3)(2))) / 2(3). Simplifying this, we get: x = (-7 ± √(49 - 24)) / 6. Further simplifying, we get: x = (-7 ± √25) / 6. Therefore, x = -1 or x = -2.

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