0

Bhaskara II's Work on Calculus and Trigonometry

Description: Bhaskara II was an Indian mathematician and astronomer who lived in the 12th century. He is considered one of the greatest mathematicians of his time, and his work on calculus and trigonometry had a profound impact on the development of mathematics.
Number of Questions: 15
Created by:
Tags: bhaskara ii calculus trigonometry indian mathematics
Attempted 0/15 Correct 0 Score 0

What is the name of Bhaskara II's most famous work on calculus?

  1. Lilavati

  2. Bijaganita

  3. Siddhanta Shiromani

  4. Karanakutuhala


Correct Option: C
Explanation:

The Siddhanta Shiromani is a treatise on astronomy and mathematics that was written by Bhaskara II in 1150. It is divided into four parts, the first of which is devoted to calculus.

What is the name of the theorem that Bhaskara II used to find the area of a circle?

  1. The Pythagorean Theorem

  2. The Law of Cosines

  3. The Law of Sines

  4. The Circle Area Theorem


Correct Option: D
Explanation:

The Circle Area Theorem states that the area of a circle is equal to $\pi r^2$, where $\pi$ is the ratio of a circle's circumference to its diameter and $r$ is the radius of the circle.

What is the name of the method that Bhaskara II used to find the derivative of a function?

  1. The Power Rule

  2. The Product Rule

  3. The Chain Rule

  4. The Quotient Rule


Correct Option: A
Explanation:

The Power Rule states that the derivative of $x^n$ is $nx^{n-1}$, where $n$ is a real number.

What is the name of the method that Bhaskara II used to find the integral of a function?

  1. The Fundamental Theorem of Calculus

  2. The Trapezoidal Rule

  3. The Simpson's Rule

  4. The Midpoint Rule


Correct Option: A
Explanation:

The Fundamental Theorem of Calculus states that the integral of a function $f(x)$ from $a$ to $b$ is equal to $F(b) - F(a)$, where $F(x)$ is the antiderivative of $f(x)$.

What is the name of the trigonometric function that Bhaskara II used to find the sine of an angle?

  1. The Sine Function

  2. The Cosine Function

  3. The Tangent Function

  4. The Cotangent Function


Correct Option: A
Explanation:

The Sine Function is defined as the ratio of the length of the opposite side of a right triangle to the length of the hypotenuse.

What is the name of the trigonometric function that Bhaskara II used to find the cosine of an angle?

  1. The Sine Function

  2. The Cosine Function

  3. The Tangent Function

  4. The Cotangent Function


Correct Option: B
Explanation:

The Cosine Function is defined as the ratio of the length of the adjacent side of a right triangle to the length of the hypotenuse.

What is the name of the trigonometric function that Bhaskara II used to find the tangent of an angle?

  1. The Sine Function

  2. The Cosine Function

  3. The Tangent Function

  4. The Cotangent Function


Correct Option: C
Explanation:

The Tangent Function is defined as the ratio of the length of the opposite side of a right triangle to the length of the adjacent side.

What is the name of the trigonometric function that Bhaskara II used to find the cotangent of an angle?

  1. The Sine Function

  2. The Cosine Function

  3. The Tangent Function

  4. The Cotangent Function


Correct Option: D
Explanation:

The Cotangent Function is defined as the ratio of the length of the adjacent side of a right triangle to the length of the opposite side.

What is the value of $\sin 30^\circ$?

  1. $\frac{1}{2}$

  2. $\frac{\sqrt{3}}{2}$

  3. $\frac{1}{\sqrt{2}}$

  4. $\frac{\sqrt{2}}{2}$


Correct Option: A
Explanation:

$\sin 30^\circ = \frac{1}{2}$

What is the value of $\cos 45^\circ$?

  1. $\frac{1}{2}$

  2. $\frac{\sqrt{3}}{2}$

  3. $\frac{1}{\sqrt{2}}$

  4. $\frac{\sqrt{2}}{2}$


Correct Option: D
Explanation:

$\cos 45^\circ = \frac{\sqrt{2}}{2}$

What is the value of $\tan 60^\circ$?

  1. $\frac{1}{2}$

  2. $\frac{\sqrt{3}}{2}$

  3. $\frac{1}{\sqrt{2}}$

  4. $\frac{\sqrt{2}}{2}$


Correct Option:
Explanation:

$\tan 60^\circ = \sqrt{3}$

What is the value of $\cot 30^\circ$?

  1. $\frac{1}{2}$

  2. $\frac{\sqrt{3}}{2}$

  3. $\frac{1}{\sqrt{2}}$

  4. $\frac{\sqrt{2}}{2}$


Correct Option:
Explanation:

$\cot 30^\circ = \sqrt{3}$

What is the value of $\sin^{-1} \frac{1}{2}$?

  1. $30^\circ$

  2. $45^\circ$

  3. $60^\circ$

  4. $75^\circ$


Correct Option: A
Explanation:

$\sin^{-1} \frac{1}{2} = 30^\circ$

What is the value of $\cos^{-1} \frac{\sqrt{2}}{2}$?

  1. $30^\circ$

  2. $45^\circ$

  3. $60^\circ$

  4. $75^\circ$


Correct Option: B
Explanation:

$\cos^{-1} \frac{\sqrt{2}}{2} = 45^\circ$

What is the value of $\tan^{-1} \sqrt{3}$?

  1. $30^\circ$

  2. $45^\circ$

  3. $60^\circ$

  4. $75^\circ$


Correct Option: C
Explanation:

$\tan^{-1} \sqrt{3} = 60^\circ$

- Hide questions