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Fundamental quantities - class-VII

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The SI unit of specific latent heat is 

  1. $Jkg^{-1}K^{-1}$

  2. $J^{0}K^{-1}$

  3. $J kg^{-1}$

  4. $J kgK^{-1}$


Correct Option: C
Explanation:

The specific latent heat of a substance is the quantity of heat energy required to change the state of a unit mass of a substance.

${E} _{L}= ml$

here ${E} _{L}$ is the heat transferred, in joules,m is the mass, in kilograms, and l is the latent heat in joules per kilogram.

The SI unit for specific latent heat is $J{kg}^{-1}$.

The specific heat capacity of water in SI unit is :

  1. $4.2 Jg^{-1}K^{-1}$

  2. $42 Jg^{-1}K^{-1}$

  3. $420 J kg^{-1}K^{-1}$

  4. $4200 J kg^{-1}K^{-1}$


Correct Option: D
Explanation:

The specific heat capacity  of a substance is the heat needed to raise

the temperature of 1 kg of the substance by 1K (or by ${1}^{0}C$).
The specific heat capacity of water is $4200 J{kg}^{-1}{K}^{-1}$.

The SI unit of thermal capacity is ;

  1. $J\ kg^{-1}\  K^{-1}$

  2. $J^{-1}\ kg\ K^{-1}$

  3. $JK^{-1}$

  4. $J\  kg\ K^{-1}$


Correct Option: C
Explanation:


The heat or thermal capacity of a defined system is the amount of heat required to raise the system's temperature by one degree. It is expressed in units of thermal energy per degree temperature.

$q= C\times t$

$C=\dfrac{q}{\triangle t}$

here,$C=$heat or thermal capacity
        $q=$heat required (J)
        $\triangle t={t} _{1}-{t} _{2}$ (K)

so,The S.I. unit of heat or thermal capacity is $J{K}^{-1}$

Potential is measured in

  1. joule/coulomb

  2. watt/coulomb

  3. newton-second

  4. none of these


Correct Option: A
Explanation:

Potential is work done per unit charge $\displaystyle =\frac {J}{c}$

Name the physical quantity related to the following unit : watt.

  1. $Force$

  2. $Power$

  3. $Work$

  4. $Pressure$


Correct Option: B
Explanation:

Watt is  the SI unit of power, equivalent to one joule per second.

Power $=$ force $\times$ velocity $=$ Work/time
So, $watt=Nms^{-1}=J/s$

Name the physical quantity related to the following unit : pascal.

  1. $Force$

  2. $Pressure$

  3. $Work$

  4. $Distance$


Correct Option: B
Explanation:

The pascal (symbol: Pa) is the SI derived unit of pressure, internal pressure, stress, Young's modulus.

Pressure $=\dfrac{Force}{Area}$ 
So, $1\ pascal=1\ N/m^2$

Column I gives three physical quantities. Select the appropriate units for these from the choices given in column II. Some of the physical quantities may have more than one choice.

Column-I Column - II
a) Capacitance d) Ohm second
b) Inductance e) Coulomb$^{2}$ joule$^{ -1 }$
c) Magnetic induction f) Coulomb volt$^{ -1 }$
g) Newton (ampere/metre)$^{ -1 }$
h) Volt second (ampere)$^{ -1 }$
  1. a-e,f; b-d,h; c-g

  2. a-h; b-d; c-e

  3. a-e; b-g,h; c-g

  4. a-e,f; b-d,h; c-d,e


Correct Option: A
Explanation:

Capacitance is charge per unit volt. 

Volt has unit of work per unit chage. 
So capacitance has units of charge square per unit energy. 
Inductance is defined as volt per unit rate of change of current and voltage per unit current is resistance, so inductance is ohm second. 

The SI unit of magnetic permeability is

  1. ${ Am }^{ -1 }$

  2. ${ Am }^{ -2 }$

  3. ${ Hm }^{ -2 }$

  4. ${ Hm }^{ -1 }$


Correct Option: D
Explanation:

The correct option is D.

The magnetic permeability of any material is its property for allowing the magnetic line of force to pass through it. Therefore, the magnetic material can support the development of the magnetic field. This capability is measured by the magnetic permeability. Also, the magnetic line of force is directly proportional to the conductivity of the material. Its SI unit is Henry per meter i.e. $Hm^{-1}$ or newton per ampere square.

$\left( Coulomb \right) ^{ 2 }{ J }^{ -1 }$ can be the unit of :

  1. electric resistence

  2. electric energy

  3. electric capacity

  4. electric power


Correct Option: C
Explanation:

Electric energy $=ML^{2}T^{-2}$
Electric power $=ML^{2}T^{-3}$
Electric resistance $= ML^{2}I^{-2}T^{-3}$
Electric capacity $=M^{-1}L^{-2}I^{2}T^{4}$$=\left ( \dfrac{I^{2}T^{2}}{(M^{1}L^{2}T^{-2})} \right )=\left ( \dfrac{Q^{2}}{J} \right )$
Hence, option C is correct.

joule is the unit of

  1. heat

  2. temperature

  3. thermometry

  4. work


Correct Option: A,D
Explanation:

Joule is unit of heat , energy and work.

How many fundamental units are present in the SI system of units?

  1. 5

  2. 6

  3. 7

  4. 3


Correct Option: C
Explanation:

There are seven fundamental units in the SI system of units which are mass, length, time, temperature, electric current, mole and luminous intensity.

State whether true or false.
The quantity of matter in a body is called its mass.

  1. True

  2. False


Correct Option: A
Explanation:

Mass of a body is defined as the quantity of matter contained in a body.

The units which can neither derived from one another nor resolved into any thing more basic are called 

  1. Fundamental unit

  2. Scale

  3. Derived unit

  4. Standard unit


Correct Option: A
Explanation:

The units which can neither derived from one another nor resolved into any thing more basic are called fundamental unit. It is independent of any other unit.

State whether given statement is True or False.
The standard quantity used for comparison is called fundamental quantity.

  1. True

  2. False


Correct Option: B
Explanation:
The standard quantity, used for comparison, is called unit with which unknown quantities are compared.
While the fundamental quantity is a quantity which is independent of any other physical quantity. For example, length, time, mass and temperature are fundamental physical quantities. The units used to measure the fundamental quantities is called fundamental units.
Hence, the given statement is false.

One second is defined to be equal to:

  1. 1650763.73 periods of krypton clock

  2. 652189.63 periods of krypton clock

  3. 1650755.73 periods of cesium clock

  4. 9, 19, 26, 31, 770 periods of cesium clock


Correct Option: D
Explanation:

One second is defined to be equal to $9,19,26,31,770$ periods of cesium clock.

Which of the following are dimensionless quantities,(symbols have their usual meaning)
[$\eta$=viscocity,$\rho$=density,$r$=radius,$k$=thermal conductivity,$c$=heat capacity.]

  1. $\dfrac{k}{\rho\times c}$

  2. $\dfrac{\rho \times v \times r}{\eta}$

  3. Specific gravity

  4. Rate of change of angle (in radians) of rotation.


Correct Option: A,B,C
Explanation:

The dimesnion of $k $ is $M^1T^1L^{-3}\theta^{-1}$

$\eta =  ML^{-1}T^{-1}$
$c= L^2MT^{-2}\theta^{-1}$
$\rho = ML^{-3}$
$r = L$
Specific gravity is the ratio of the density of a substance to the density of a reference substance, so the specific gravity is dimensionless.
$\dfrac{k}{\rho\times c} = M^0L^0T^0$
$\dfrac{\rho \times v \times r}{\eta}=M^0L^0T^0$

Which of the following is dimensionally  correct? ($\rho$=density,$\eta$=coefficient of viscosity,$P$=pressure,$S$=surface tension,$r$=radius,$g$=gravitational constant)

  1. $h=\dfrac{2Scos\theta}{\rho \times rg}$

  2. $v=\dfrac{P}{\rho}$

  3. $V=\dfrac{Pr^{4}t}{\eta}$

  4. none of the above


Correct Option: A
Explanation:

Dimensional formula of the following are given as-

$S =MT^{-2}$,  $g = LT^{-2}$,  $\rho = ML^{-3}$,  $r = L$,  $h = L$,  $v = LT^{-1}$,  $P = ML^{-1}T^{-2}$,  $t = T$,  $\eta = ML^{-1}T^{-1}$
Equating LHS and RHS of the following options :
(A) :  LHS = $  L$
RHS $=\dfrac{[MT^{-2}]}{[ML^{-3}][L][LT^{-2}]} = [L]$ 
$\implies$  LHS  = RHS

(B) :  LHS = $  LT^{-1}$
RHS $=\dfrac{[ML^{-1}T^{-2}]}{ML^{-3}} = [L^2 T^{-2}]$ 
$\implies$  LHS  $\neq$ RHS

(C) :   LHS = $  LT^{-1}$
RHS $=\dfrac{[ML^{-1}T^{-2}] [L^4] [T]}{[ML^{-1}T^{-1}]} = [L^4]$ 
$\implies$  LHS  $\neq$ RHS
Thus option A is correct.

Consider the following equation which gives a hypothetical physical quantity mutual dynamic constant $\psi$ as,
$\dfrac{2Scos\theta}{\rho \times rg}$+$\dfrac{1}{2\pi}\dfrac{mgl}{I}$
($I$=moment of inertia ,$S$=surface tension,others symbol have usual meanings)

  1. $\psi$ may exist

  2. $\psi$ will never exist

  3. Such physical quantity is a standard result of electromagnetism ,hence it exists.

  4. none of the above


Correct Option: B
Explanation:

Dimensional formula of the following are given as-

$S =MT^{-2}$,  $g = LT^{-2}$,  $\rho = ML^{-3}$,  $r = L$,  $I = ML^2$,  $m = M$,  $l = L$
Dimensions of  $\dfrac{2S\cos\theta}{\rho g r} = \dfrac{[MT^{-2}]}{[ML^{-3}][L][LT^{-2}]} =[L]$
Dimensions of  $\dfrac{mgl}{2\pi I} = \dfrac{[M][LT^{-2}][L]}{ML^2} =[T^{-2}]$
Since dimensions of the two additive terms are not same, thus $\psi$ can never exist.

Which of the following is not the fundamental quantity,

  1. mass

  2. length


  3. velocity

  4. time


Correct Option: C
Explanation:

We know that the fundamental quantities are mass, length and time. 

velocity = $\dfrac{displacement}{time}$
hence velocity is derived quantity

The most basic rule of dimensional analysis is that of dimensional homogeneity. Only commensurable quantities  may be

  1. compared

  2. equated

  3. added or subtracted 

  4. all of the above 


Correct Option: D
Explanation:

In dimensional analysis, only commensurable quantities may be compared, equated and added or subtracted.

Light year is a unit of:

  1. time

  2. distance

  3. light

  4. intensity of light


Correct Option: B
Explanation:

Light year is a unit of $distance$.

Which one can be represented as the symbol of time?

  1. $m$

  2. $F$

  3. $t$

  4. None


Correct Option: C
Explanation:

Time is generally represented by the symbol $t$.
Mass is represented by symbol $m$ and force by the symbol $F$.

The unit of electric field intensity is:

  1. Newton/ metre

  2. Coulomb/ newton

  3. Newton/ coulomb

  4. Joule/ newton


Correct Option: C
Explanation:

Electric field due to a charge is given by  $E = \dfrac{F}{q}$
Unit of force is Newton $(N)$ and that of charge is Coulomb $(C)$.
So, unit of electric field is  Newton/coulomb  i.e  $N/C$

Among the following indentify the derived quantities.

  1. Gravitational constant

  2. Frequency

  3. Electric charge

  4. Electric current


Correct Option: A,B,C
Explanation:

The derived quantities are gravitational constant, frequency, electric charge because they are made up of several other quantities combined to form one single quantity.

The energy which an electron acquires when accelerated, through a potential difference of $1$ volt is called

  1. $1$ Joule

  2. $1$ eV

  3. $1$ erg

  4. $1$ watt


Correct Option: B
Explanation:

The energy which an electron acquires when accelerated, through a potential difference of 11 volt is called 1 eV. It is a unit of energy.  It is usually used as a measure of particle energies although it is not an SI (System International) unit. The SI unit for energy is the Joule. $1\,eV=1.602\times 10^{-19}\,Joules$

The Sl unit of length is the meter. Suppose we adopt a new unit of length which equals to $x$ meters. The area 1 $m ^ { 2 }$ expressed in terms of the new unit has a magnitude:

  1. $x$

  2. $x ^ { 2 }$

  3. $\dfrac { 1 } { x }$

  4. $\dfrac { 1 } { x ^ { 2 } }$


Correct Option: D
Explanation:

SI unit of Length $=$ meters.

New Unit of Length $=x$ meters.

$1m=\dfrac 1x$ new units

SI unit of area : 

$A= 1m^2$   

$=1\times 1m^2$                        

$=\dfrac 1x\times \dfrac 1x $     

$=\dfrac{1}{x^2}$     

The impulse $J$ required to bring it to rest when it reaches the vertical position.

  1. Impulse of $m\sqrt {\dfrac {gl}{3}}$ when it is applied horizontally at distance $l$ from pivoted point

  2. Impulse of $m\sqrt {\dfrac {gl}{3}}$ when it is applied horizontally at distance $\dfrac {l}{2}$ from pivoted point

  3. Minimum impulse is $m\sqrt {\dfrac {gl}{2}}$ when it is applied at distance $l$ from pivoted point

  4. If rod is stopped by applying minimum impulse then the is impulse imparted by pivot is $\dfrac {m\sqrt {gl}}{2\sqrt {3}}$


Correct Option: A

If $10 ^ { 7 }$ era is taken as unit of energy, $10 ^ { 5 }$ dyne as the unit of force, one second as unit of time. what is, the unit of length?

  1. $1$ $m$

  2. $10$ $m$

  3. $100$ $m$

  4. None


Correct Option: A

The following quantities which have same directions :

  1. force, impulse

  2. impulse, change in momentum

  3. change in velocity, change in momentum

  4. All the above


Correct Option: A

The MKS unit of quantity $\dfrac{\pi \eta r^4}{2}$ is :

  1. $N s {m}^{2} radian  $

  2. $Ns/m/Radian$

  3. $Radian/Ns/m$

  4. $ Ns/m/Radian^2 $


Correct Option: A
Explanation:

Unit of $\pi $ is radians.

Unit of $r$ is $m$.
Unit of coefficient of viscosity, $\eta =N\, s\, { m }^{ -2 } $
Whereas $2$ is just a number, so it is unit less.
Therefore, Unit of given expression $=radian \times$ $N\, s\, { m }^{ -2 }\times { m }^{ 4 }=N\,s \, { m }^{ 2 } \ radian$

In S.l. system the value of $\epsilon _ { 0 }$

  1. $1 c ^ { 2 } N ^ { - 1 } m ^ { - 2 }$

  2. $9 \times 10 ^ { 9 } c ^ { 2 } N ^ { - 1 } m ^ { - 2 }$

  3. $\cfrac { 1 } { 9 \times 10 ^ { 9 } } c ^ { 2 } N ^ { - 1 } m ^ { - 2 }$

  4. $\cfrac { 1 } { 4 \pi \times 9 \times 10 ^ { 9 } } c ^ { 2 } N ^ { - 1 } m ^ { - 2 }$


Correct Option: D

Unit of self inductance is

  1. $\cfrac { newton\ second }{ coulomb\quad \times \quad ampere } $

  2. $\cfrac { joule/coubmb\quad \times \quad second }{ ampere } $

  3. $\cfrac { volt\quad \times \quad metre }{ coulomb } $

  4. $\cfrac { newton\quad \times \quad metre }{ ampere } $


Correct Option: B

If $\epsilon ,\phi $ and  t stand for permittivity,electric flux and time respectively, then dimensions of $ \epsilon \cfrac{d \phi}{dt}$ is same as that

  1. Speed

  2. Current

  3. Charge

  4. Potential difference


Correct Option: B

Which of the following pairs is not matched?

  1. Coefficient of self-induction : henry

  2. Magnetic flux : weber

  3. Electric flux : volt-meter

  4. Electric capacity : farad-meter


Correct Option: D
Explanation:

Electric capacitance of a conductor is the ability with which the conductor can hold the charge.
In SI system, unit of capacitance is farad($F$).
Hence, option D is not matched.

kilowatt-hour is the unit of ____. 

  1. potential difference

  2. electric power

  3. electric energy

  4. charge


Correct Option: C
Explanation:

$\text{Kilowatt hour}$ is the $commercial$ unit of $electrical$ ENERGY.

As the power$(means $ $ \dfrac{Work}{time}=\dfrac{energy}{time})$
so $energy=power\times time $

$\text{so unit of energy= unit of power *unit of time =watt *second }$
Kilowatt-hour is just $3600\times 1000$ times  of the above value of energy.

Oersted is the unit of

  1. Intensity of magnetisation

  2. Magnetic moment

  3. Magnetic induction

  4. Magnetic flux


Correct Option: A
Explanation:

The intensity of magnetic field at a point on the field is defined as the force on a unit north pole placed at that point.
Intensity of magnetization is measured in Oersted as a unit.

The SI unit of pressure is

  1. $Newton$

  2. $Joule$

  3. $N/m^{2}$

  4. $Nm$


Correct Option: C
Explanation:

Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed. It is defines as force per unit area. The SI unit of pressure is $N/m^2$.

The damping force on an oscillator is directly proportional to the velocity. The units of constant of proportionality are

  1. Kg m/s

  2. Kg $m/s^2$

  3. Kg/s

  4. kgs


Correct Option: C

The unit of permittivity of free space, $ \varepsilon _ o $ is

  1. $\dfrac {Coulomb} {newton - meter}$

  2. $ \dfrac {newton - meter^2} { Coulomb ^2} $

  3.  $\dfrac {Coulomb^2}{newton- meter^2} $

  4. $ \dfrac {Coulomb^2} {(newton-metre)^2}$


Correct Option: B

In $S = a + bt + ct^{2}, S$ is measured in metres and $t$ is seconds. The unit of $c$ is

  1. $ms^{-2}$

  2. $m$

  3. $m^{-1}$

  4. None


Correct Option: A

If the volume of a cube is equal to its surface area in magnitude. Then the volume of the cube is? 

  1. $216$ unit

  2. $512$ unit

  3. $64$ unit

  4. None of these


Correct Option: A
Explanation:

Let us take side of cube$=a$
then  $a^3=6a^2$
$\therefore a=6$
So volume of cube is:

$a^3=(6)^3=216$ units

In the eqn. $\left (P+\dfrac {a}{V^2}\right )(V-b)=$ constant, the unit of $a$ is

  1. $dyne\times cm^5$

  2. $dyne\times cm^4$

  3. $dyne/cm^3$

  4. $dyne\times cm^2$


Correct Option: B
Explanation:

Units of both $P $ and $ \dfrac {a}{V^2}$ must be same.
So, $\dfrac {a}{V^2}=P$  $\implies   a=PV^2$ 

Since unit of $P$ is $dyne \ cm^{-2}$ and that of $V$ is $cm^3$.
$\therefore$ Unit of a is  $\dfrac {dyne}{cm^2}(cm^3)^2=dyne\times cm^4$

Unit of specific resistance is

  1. $\Omega/m^2$

  2. $\Omega m^3$

  3. $\Omega m$

  4. $\Omega/m$


Correct Option: C
Explanation:

Specific resistance of a material is given by

$\rho =\displaystyle \frac {RA}{l}$

Substitute the unit in the above expression:
$\rho=\dfrac {\Omega.m^2}{m}=\Omega m$

Which of the following is different from others?

  1. Speed

  2. Density

  3. Force

  4. Time


Correct Option: D
Explanation:

Speed, density and force are the derived physical quantities whereas time is the fundamental physical quantity.

Mass is a _________ physical quantity.

  1. derived

  2. fundamental

  3. semi-derived

  4. valueless


Correct Option: B
Explanation:

There are only $7$ fundamental physical quantity out of which mass is a fundamental quantity.

Which of the following physical quantity is different form others ?

  1. Displacement

  2. Velocity

  3. Force

  4. Kinetic energy


Correct Option: D
Explanation:

Displacement, force, and velocity are vector quantities as they require direction as well as the magnitude for their representation but the kinetic energy is a scalar quantity as it does not require direction for its representation.

Write the SI unit of the physical quantity having following dimensional formula
$\displaystyle [{ M }^{ 0 }{ L }^{ 2 }{ T }^{ -2 }{ K }^{ -1 }]$.

  1. $\displaystyle {m} { kg }^{ 2 }{ K }^{ -1 }$

  2. $\displaystyle {m} ^{2} { kg }^{ 2 }{ T }^{ -1 }$

  3. $\displaystyle {m} ^{2} { s }^{ -2 }{ K }^{ -1 }$

  4. $\displaystyle {m} ^{2} { kg }^{ 2 }{ K }^{ -1 }$


Correct Option: C
Explanation:
SI unit of $M$ is $kg$, that of $L$ is $m$, $T$ is $s$ and temperature (K) is $K$.

So, SI unit of $[M^0L^2T^{-2}K^{-1}]$ is  $m^2s^{-2}K^{-1}$.

Dimensional analysis is the analysis of the relationships between different physical quantities by 

  1.  identifying their fundamental dimensions

  2. units of measure

  3. tracking these dimensions as calculations or comparisons are performed.

  4. All of the above 


Correct Option: D
Explanation:

Dimensional analysis establishes the relation between the physical quantities by comparing the different quantities using their fundamental dimensions.

The dimensional analysis also makes use of the units to measure different quantities and the dimensional analysis is also helpful in performing several calculations.

State whether true or false.
The mass of a body can never be zero.

  1. True

  2. False


Correct Option: A
Explanation:
Mass of a body is defined as the quantity of matter contained in it. Since, all bodies are made up of certain matter. Thus mass of body can never be zero.

Which one of the following is not a fundamental SI unit?

  1. Ampere

  2. Candela

  3. Newton

  4. Kelvin


Correct Option: C
Explanation:

F = ma = kgms-2

SI unit of force is Newton(W)

Hence, newton is a derived unit

A dimensionless quantity

  1. never has a unit

  2. always has unit

  3. may have a unit

  4. does not exit


Correct Option: C
Explanation:

A dimensionless quantity is that is always independent of basic $7$ units:-meter, second, kilogram, Kelvin, Candela, ampere.

But it is not necessary. A dimensionless quantity is unitless. And eg, for this, is radian (unit of angle), which is dimensionless quantity because it is the ratio of two lengths.

Some physical quantities are given in Column I and some possible SI units in which these quantities may be expressed are given in Column II. Match the physical quantities in Column I with the units in Column II.

Column I Column II
i. $GM _eM _s$ a. (volt) (coulomb) (metre)
ii. $3RT/M$ b. $(kilogram)(metre)^3 (second)^2$
iii. $F^2/q^2B^2$ c. $(meter)^2 (second)^{-2}$
iv. $GM _e/R _e$ d. $(farad) (volt)^2 (kg)^{-1}$


where G is universal gravitational constant; $M _e$ mass of the earth; $M _s$, mass of sun; $R _e$ radius of the earth; R, universal gas constant;T, absolute temperature; M, molar mass, F, force; q, charge; B, magnetic field.

  1. $i \rightarrow b., ii \rightarrow c.,d., iii \rightarrow c.,d., iv \rightarrow c.,d.,$

  2. $i \rightarrow a., ii \rightarrow c.,d., iii \rightarrow c.,d., iv \rightarrow c.,d.,$

  3. $i \rightarrow d., ii \rightarrow c.,d., iii \rightarrow c.,d., iv \rightarrow c.,d.,$

  4. $i \rightarrow c., ii \rightarrow c.,b., iii \rightarrow c.,d., iv \rightarrow c.,d.,$


Correct Option: B

Pressure (P), density $\displaystyle (\rho )$ and velocity (V) be taken as fundamental quantities for dimensional analysis.

  1. True

  2. False


Correct Option: B
Explanation:
Pressure is calculated as   $P = \dfrac{Force}{Area}$
Density  $\rho = \dfrac{Mass}{Volume}$

Velocity  $V = \dfrac{Displacement}{time}$

So, pressure, density and velocity are derived from other quantities and so, these are termed as derived quantities , not fundamental quantities.
Hence, the given statement is false.

$S.I$unit of conductivity is 

  1. $siemens / meter$

  2. $siemens \times meter$

  3. $meter \times siemens$

  4. ${m}^{2}/ohm$


Correct Option: A
Explanation:

Conductivity (or specific conductance) of an electrolyte solution is a measure of its ability to conduct electricity. The SI unit of conductivity is siemens per meter $(S/m)$

Which expression has the same SI base units as pressure?

  1. $\dfrac{force}{length\times speed}$

  2. $\dfrac{force}{length\times time}$

  3. $\dfrac{mass}{length\times (time)^2}$

  4. $\dfrac{mass\times (time)^2}{length}$


Correct Option: C
Explanation:
Pressure is force per unit area.
$P = \dfrac FA=\dfrac {MLT^{-2}}{L^2}=\dfrac M{LT^2}$
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