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Engines and cycles - class-XI

Description: engines and cycles
Number of Questions: 45
Created by:
Tags: thermodynamics option b: engineering physics physics heat engine: second law of thermodynamics heat and thermodynamics
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In a heat engine, heat energy is converted into mechanical energy. 

  1. True

  2. False


Correct Option: A
Explanation:

The correct answer is option(A).

In thermodynamics, a heat engine is a system that converts heat or thermal energy—and chemical energy—to mechanical energy, which can then be used to do mechanical work.

How many dead centres are there in one cycle of steam engine ?

  1. $4$

  2. $3$

  3. $2$

  4. $1$


Correct Option: C
Explanation:

There are two dead centers in one cycle of the steam engine:

  • Top dead center
  • Bottom dead center
Hence option C is correct.

For a particular heat engine, 3,000 J of energy goes in at 700 K and 2000 J comes out at 200 K. The rest of the energy is used work.
What is the actual efficiency of this engine?

  1. 0.71

  2. 0.33

  3. 0.67

  4. 0.29

  5. 1.5


Correct Option: B
Explanation:

Amount of heat goes in the engine        $Q _H = 3000$ J

Amount of heat rejected by the engine      $Q _R = 2000$ J
Thus work done by the engine      $W = Q _H - Q _R =3000 - 2000 = 1000$ J

Actual efficiency of heat engine       $\eta = \dfrac{W}{Q _H} = \dfrac{1000}{3000} = 0.33$

A 60J of heat is added to the system, resulting in 15J of work being done by the system. The remaining 45J of heat is released. Find out the efficiency of the system?

  1. 100%

  2. 75 %

  3. 45%

  4. 25%

  5. 15%


Correct Option: D
Explanation:

Amount of heat absorbed       $Q _H = 60$ J

Net work done by the system     $W= 15$ J
Thus efficiency of the system          $\eta = \dfrac{W}{Q _H} = \dfrac{15}{60}  =0.25$
Thus the system is $25$%  efficient.

Find out the most efficient engine in the following

  1. An engine converts 80 KJ of heat energy into 20 KJ of work

  2. An engine converts 50 KJ of heat energy into 15 KJ of work

  3. An engine converts 30 KJ of heat energy into 6 KJ of work

  4. An engine converts 60 KJ of heat energy into 24 KJ of work


Correct Option: D
Explanation:

Efficiency of heat engine= $\frac{work done}{heat input}$ Going by the above options efficiency is maximum in option D, and is equal to 40 percent.

Which of the following engines is more efficient?

  1. Heat utilised - 80 kilojoules , work done - 32 kilojoules

  2. Heat utilised - 60 kilojoules , work done - 12 kilojoules

  3. Heat utilised - 50 kilojoules , work done - 25 kilojoules

  4. Heat utilised - 90 kilojoules , work done - 27 kilojoules


Correct Option: C
Explanation:

Efficiency of engine   $\eta = \dfrac{W}{Q _H}$  

where $W$ is work done and $Q$ is heat taken from source (Heat utilised)
(A) :  $\eta _A = \dfrac{32}{80} = 0.4$
(B) :  $\eta _B = \dfrac{12}{60} = 0.2$
(C) :  $\eta _C = \dfrac{25}{50} = 0.5$
(D) :  $\eta _D = \dfrac{27}{90} = 0.3$
Hence engine C is the most efficient.

The efficiency of a heat engine : 

  1. is independent of the temperature of the source and the sink

  2. is independent of the working substance

  3. can be 100%

  4. is not affected by the thermal capacity of the source or the sink


Correct Option: B
Explanation:

Efficiency is defined as work done per unit of heat consumed . It doesn't depend on the substance on which we work.

The earthen pots prepared by using clay only are generally

  1. Porous

  2. Non-porous

  3. Conductors of electricity

  4. Transparent


Correct Option: A
Explanation:

The earthen pots prepared by using clay only are generally porous to facilitate cooling process.This works through evaporative cooling. Capillary action causes water to seep and evaporate from the mini-pores in the pot, taking the heat from the water inside, thus making the water inside cooler than the outside temperature.

An ideal heat engine working between temperatures $T _1$ and $T _2$ has an efficiency $\eta $ . The new efficiency if the temperatures of both the source and sink are doubled, will be 

  1. $\frac{\eta }{2}$

  2. $\eta $

  3. $ 2 \eta $

  4. $ 3 \eta $


Correct Option: B
Explanation:
Efficiency of heat engine $\eta=\dfrac{output}{input}=\dfrac{{T} _{1}-{T} _{2}}{{T} _{1}}$-------(a)
Now new efficiency of heat engine when sin and source temperature is doubled${\eta} _{new}=\dfrac{2{T} _{1}-2{T} _{2}}{2{T} _{1}}$
${\eta} _{new}=2\dfrac{{T} _{1}-{T} _{2}}{2{T} _{1}}=\eta$ from a
  

The thermal efficiency of a heat engine for which the work output is $2500 J/cycle$ and the heat input is $10000 J/cycle$, is:

  1. $75%$

  2. $40%$

  3. $25%$

  4. $0.25%$


Correct Option: D
A car is moving with a speed of $40 $ km/hr. If the car engine generated 7 kilowatt power, then the resistive force in the path of the car will be:-
  1. 360 Netwon

  2. 630 Newton

  3. Zero

  4. 280 Newton


Correct Option: B
Explanation:

Power= Force $\times$ speed

$R= Power/Speed$
Given, $P=7Kw=7000W$
Speed= $40km/h=11.11m/s$
Resistance= $7000/11.11= 630.063 N$

A system undergoes a cyclic process in which it absorbs $Q _1$ heat and gives out $Q _2$ heat. The efficiency of the process is $\eta$ and the work done is $W$.

  1. $W = Q _1 - Q _2$

  2. $\displaystyle \eta = \frac{W}{Q _1}$

  3. $\displaystyle \eta = \frac{Q _2}{Q _1}$

  4. $\displaystyle \eta = 1 - \frac{Q _2}{Q _1}$


Correct Option: A,B,D
Explanation:

The efficiency of a heat engine is defined as the ratio of work output to the heat input.
Thus, $ \eta = \dfrac{W}{{Q} _{in}} $
Now, since the heat energy only gets converted into work and no other form of energy, thus following the law of conservation of energy,
$ W = {Q} _{out} - {Q} _{in} $
Substituting this value in the above expression, we get another expression for the efficiency of a heat engine

A motor pump is delilvering water at certain rate.In order to increase the rate of delivery by100% ,the power of the motor is to be increased by

  1. 300%

  2. 200%

  3. 400%

  4. 700%


Correct Option: A

The efficiency of a heat engine if the temperature of source $227^0C$ and that of sink is $27^0C$ nearly

  1. 0.4

  2. 0.5

  3. 0.6

  4. 0.7


Correct Option: C
Explanation:

The efficiency of heat engine will be$:$

${T _{\sin k}}/{T _{source}}$
$ = \left( {273 + 27} \right)/\left( {273 + 227} \right)$
$ = 300/500$
$ = 0.6$
So$,$ efficiency will be $0.6$
Hence,
option $(C)$ is correct answer.

A heat engine produces 100 J of heat, does 30 J of work, and emits 70 J into a cold reservoir. What is the efficiency of the heat engine? 

  1. 100%

  2. 70%

  3. 42%

  4. 40%

  5. 30%


Correct Option: E
Explanation:

The efficiency of heat engine is $\eta=\dfrac{W}{Q _{in}}$  

Here work done , $W=30 J$ and heat produced $Q _{in}=100 J$
Thus, % of efficiency, $\eta=\dfrac{30}{100}\times 100=30$ %

A heat engine takes in heat at 750 degrees Celsius and expels heat at 250 degrees Celsius. What is this engine's theoretically ideal (Carnot) efficiency?

  1. 33 percent

  2. 67 percent

  3. 49 percent

  4. 300 percent

  5. 23 percent


Correct Option: C
Explanation:

Temperature of source     $T _H = 750^oC = 750+273 = 1023$  K

Temperature of sink     $T _L = 250^oC = 250+273 = 523$  K

Efficiency of engine        $\eta = 1-\dfrac{T _L}{T _H} = 1  -\dfrac{523}{1023}  =0.49$
Thus the engine is  $49$% efficient.

Let $E _D, E _P, E _S$ denote efficiency of a diesel, a petrol and a steam engine respectively. which of the following is correct?

  1. $E _D < E _P > E _S$

  2. $E _D < E _P < E _S$

  3. $E _P > E _D > E _S$

  4. $E _P < E _S < E _D$


Correct Option: C
Explanation:

Let, $E _D,E _P,E _S$ denote efficiency of a diesel, a petrol stream engine respective.

$E _P>E _D>E _S$
because petrol and diesel using the Carnot cycle.

NA heat engine has an efficiency n.Temperatures of source and sink are each decreased by 100 K. The efficiency of the engine:

  1. increases

  2. decreases

  3. remains constant

  4. becomes 1


Correct Option: A
Explanation:

Efficiency of heat engine,

$n=1-\dfrac{T _2}{T _1}=\dfrac{T _1-T _2}{T _1}$. . . . . .(1)
According to question,
 $T _1\rightarrow T _1-100$
$T _2\rightarrow T _2-100$
New efficiency, $n'=1-\dfrac{T _2-100}{T _1-100}$
$n'=\dfrac{T _1-T _2}{T _1-100}$
From equation (1) and (2), we can conclude that
$n'\propto \dfrac{1}{T _1-100}$
The efficiency of the engine is increases.
The correct option is A.

The most efficient engine is?

  1. Petrol

  2. Electric

  3. Steam

  4. Diesel


Correct Option: B
Explanation:

The electric engine is most efficient. Electric motors are very efficient at converting electricity into work. Physicists throw around abstract numbers like 90%, whereas when discussing combustion engines, they use numbers less than 40%. But you cannot compare the efficiency of converting electricity into motion to the efficiency of converting gasoline into motion.

Efficiency of a heat engine whose sink is at a temperature of $300 \ K$ is $40$%. To increase the efficiency to $60$%, keeping the sink temperature constant, the source temperature must be increased by :

  1. $750\  K$

  2. $500 \ K$

  3. $250\  K$

  4. $1000\  K$


Correct Option: C
Explanation:

We know that in heat engine, sink is at lower temperature than source, hence,


$\eta =1-\dfrac { { T } _{ sink } }{ { T } _{ source } } $

$0.4=1-\dfrac { 300 }{ { T } _{ source } } $

${ T } _{ source } = 500\ K$

In the second case,

$0.6=1-\dfrac { 300 }{ { T } _{ source } } $

${ T } _{ source } = 750\ K$

Hence, an increment of $250\ K$ in source temperature is required.


An engine has an efficiency of 0.25 when temperature of sink is reduced by 58C,if its efficiency is doubled, then the temperature of the source is:

  1. 150K

  2. 222K

  3. 242K

  4. 232K


Correct Option: D
Explanation:

Let us consider $T _1=$ temperature of the source

$T _2=$ temperature of the sink
The efficiency of the engine,
$0.25=1-\dfrac{T _2}{T _1}$
$\dfrac{T _2}{T _1}=0.75$
$T _2=0.75T _1$. . . . . . . . .(1)
When the temperature of the sink is reduced by $58^0C$, then the efficiency is double,
$2\times 0.25=1-\dfrac{T _2-58}{T _1}$
$\dfrac{T _2-58}{T _1}=0.5$
$T _2-58=0.5T _1$
$0.75T _1-58=0.5T _1$ .........(from equation 1)
$0.25T _1-58=0$
$0.25T _1=58$
$T _1=\dfrac{58}{0.25}$
$T _1=232 K$
The correct option is D.

Which of the following is true about refrigeration?

  1. Heat is removed from the inside of the refrigerator

  2. Cold air is produced inside the refrigerator

  3. Hot air is removed from the inside of the refrigerator

  4. Hot air is changed to a cold condensate inside the refrigerator

  5. Hot air inside the refrigerator is expanded to remove its heat


Correct Option: A
Explanation:

A refrigerator is infact a reverse heat engine which absorbs heat from source (material) at lower temperature, do work on it and then passes the heat to the sink (sorrounding) at higher temperature, thus we can say that heat is removed from inside the refrigerator.

A 1 h.p. electric motor operates a pump continuously. The work performed by the motor in one day is

  1. 18 kWh

  2. 36 kWh

  3. 54 kWh

  4. 72 kWh


Correct Option: A

Refrigerators and freezers works by:

  1. Converting hot air to cold air

  2. Keeping hot air out with cold air pressure

  3. Removing heat from inside themselves

  4. Blowing cold inside them

  5. Producing cold air


Correct Option: A
Explanation:

A gas refrigerant or sometimes air is key to refrigeration in freezers.
The gas refrigerant goes into the compressor and the process of compression makes the gas hot. That hot gas moves through the system getting colder and colder. By the time it reaches the valve – and is pushed through the very small opening – it has turned into a cold mist. 

As the mist goes through the coils under the freezer compartment, it starts to evaporate and turn back into a gas. This evaporation process takes the heat from the freezer compartment with it and as the refrigerant starts to warm up, it is sent back to the compressor to start the process all over again. Eventually the process is completed and there is no heat left in the freezer meaning that all objects in the freezer are frozen.

By opening the door of a refrigerator which is inside a room, the temperature of room ____________.

  1. first decreases then increases

  2. remains unchanged

  3. increases

  4. decreases


Correct Option: C
Explanation:

When the door of a refrigerator is opened the temperature of the room increases as the room is acting as the source here where the heat is rejected.

A refrigerator is

  1. head engine

  2. an electric motor

  3. heat engine working in backward direction

  4. air cooler


Correct Option: C
Explanation:

A refrigerator is a heat engine which works in the reverse manner, to cool the substance inside.

A refrigerator is a device which works on the principle that evaporation of a liquid gives a cooling effect.

  1. True

  2. False


Correct Option: A
Explanation:
A refrigerator works on principle of thermodynamics of extracting heat from a body which means making it drop its temprature. There is nothing like cooling a thing its a by product of removing or extracting heat from a material or a body. This is what a refrigerator does. Refirgerator with help of coolant flowing through coolant tubes and condensor does this job of extracting heat from the all items kept in refrigerator.

A refrigerator is a device which works on the principle that evaporation of a liquid gives a cooling effect.
Option A is correct.

 What function is performed by Condenser in a refrigerator?

  1. To deliver the heat to the heat pump

  2. To deliver the heat to the evaporator

  3. To deliver the heat to the refrigerator

  4. To deliver the heat to the atmosphere


Correct Option: D
Explanation:

A condenser is simply a heat exchanger,the purpose of a condenser in the cycle of compression refrigeration is to change the hot gas being discharged from the compressor to a liquid prepared for use in the evaporator. The condenser accomplishes this action by the removal of sufficient heat from the hot gas, to ensure its condensation at the pressure available in the condenser. The heat is shifted to another medium, like water or air, to cool the condenser.

The function is performed by Condenser in a refrigerator to deliver the heat to the atmosphere

The heat pump is also called as the :

  1. Reverse motor

  2. Reverse refrigerator

  3. Reverse oscillator

  4. Reverse engine


Correct Option: B
Explanation:

Though the working principle of refrigerator and heat pump is same but heat pump is used to warm a room whereas refrigerator is used to cool down the temperature of material inside it , so heat pump is also called a reverse refrigerator .

What function does a Condenser perform,in heat pumps?

  1. Condenser performs the most important function of cooling the room.

  2. Condenser performs the most important function of heating the room.

  3. Condenser performs the most important function of freezing outside the room

  4. Condenser performs the most important function of heating the atmosphere


Correct Option: B
Explanation:

A heat pump is a device that transfers heat energy from a source of heat to what is called a "heat sink". Heat pumps move thermal energy in the opposite direction of spontaneous heat transfer, by absorbing heat from a cold space and releasing it to a warmer one. A heat pump uses a small amount of external power to accomplish the work of transferring energy from the heat source to the heat sink. A condenser is a device or unit used to condense a substance from its gaseous to its liquid state, by cooling it.


The function does a Condenser perform,in heat pumps is condenser performs the most important function of heating the room.

What is the function of the evaporator in a refrigerator?

  1. The evaporator supplies the heat to the substance, which is to be cooled.

  2. The evaporator absorbs the heat from the atmosphere.

  3. The evaporator absorbs the heat from the substance, which is to be cooled.

  4. Both a and b


Correct Option: C
Explanation:
Evaporator is an important component together with other major components in a refrigeration system such as compressor, condenser and expansion device. The reason for refrigeration is to remove heat from air, water or other substance.

It is here that the liquid refrigerant is expanded and evaporated. It acts as a heat exchanger that transfers heat from the substance being cooled to a boiling temperature.

Which of the following is not the component of heat pump?

  1. Condenser

  2. Compressor

  3. Cooler

  4. Expansion valve


Correct Option: C
Explanation:

A heat pump is a device that transfers heat energy from a source of heat to what is called a "heat sink". Heat pumps move thermal energy in the opposite direction of spontaneous heat transfer, by absorbing heat from a cold space and releasing it to a warmer one. A heat pump uses a small amount of external power to accomplish the work of transferring energy from the heat source to the heat sink,there are four main components of heat pump: compressor, condenser, expansion valve and evaporator

What is most commonly used as the refrigerant  in heat pumps?

  1. Chlorofluorohydrocarbons

  2. Fluorine gas

  3. Hydrogen gas

  4. Carbon gas


Correct Option: A
Explanation:

A refrigerant is generally a fluid , which undergoes state change , from liquid to gas and back again . Chlorofluorohydrocarbons are most commonly used  as refrigerant in heat pumps . 

An ideal refrigerator operates according to the reverse Carnot cycle and transmits heat from a cold source with water at a temperature of $27^{\circ}C$ to a boiler with water at a temperature of $100^{ \circ  }C$. What amount of water must be frozen in the cooler to convert 1 kg of water into vapor in the boiler ?

  1. 4.94 kg

  2. 3.24 kg

  3. 5.63 kg

  4. 2.12 kg


Correct Option: A

Find coefficient of performance, If in a mechanical refrigerator, the lower temperature coils of evaporator are $-23^oC$ compressed gas in condenser has a temperature of $77^oC$. The coefficient of performance is 

  1. $70\%$

  2. $20\%$

  3. $0.23\%$

  4. $2.5\%$


Correct Option: C

A reversible engine operates between temperatures 900 K & $T _2$($T _2$ < 900 K), & another reversible engine between $T _2$ & 400 K ($T _2$ > 400 K) in series. What is the value of $T _2$ if work outputs of both the engines are equal?

  1. 600K

  2. 625K

  3. 650K

  4. 675K


Correct Option: C
Explanation:
Output work  $W = \Delta T$
Thus for equal work output, temperature difference should be equal.
$900-T _2=T _2-400$
Or  $2T _2 = 1300$ 
$\implies$ $T _2=650 \ K$

A carnot cycle is having maximum efficiency because

  1. it comprises of two adiabatic process which requires no heat in its execution.

  2. it comprises of two isothermal process.

  3. its every process is reversible

  4. none of the above


Correct Option: C
Explanation:
Carnot cycle consists of 4 process. All of them are ideal and practically not possible.

1.Isothermal heat addition- Nothing can be more efficient than this heating since no finite temperature difference exists between heat source and receiver. Hence it is a reversible process and most efficient,

2.Isentropic(reversible adiabatic) expansion- Most efficient expansion, as no heat loss is taking place, full energy is utilised only for expansion and thereby doing work.

3.Isothermal heat rejection- Most efficient heat rejection to a heat sink at same temperature.

4.Isentropic compression- Compressed(without friction) with no heat lost to surrounding. Power input is used only for increasing the pressure and temperature.

In this cycle every process is reversible and hence it is most efficent.
When the cycle is completed input energy and power is used only for the purpose it was intended. Output was completely used for intended purpose

A series combination of two Carnots engines operate between the temperatures of $180^0C$ and $20^0C$. If the engines produce equal amount of work,then what is the intermediate temperature(In $^0C$)?

  1. 80

  2. 90

  3. 100

  4. 110


Correct Option: C
Explanation:


A series combination of two Carnot engines operate between the temperatures of $180^0C$and $20^0C$.If the engines produce equal amount of work
The intermediate temperature in series combination is given by 
$T _i=\dfrac{T _1+T _2}{2}=\dfrac{180+20}{2}=100^oC$

What is the function of refrigerants in heat pumps?

  1. Refrigerants supply heat to the atmosphere

  2. Refrigerants evaporate heat and cool the room

  3. Refrigerant carries heat from the atmosphere to the room,which is to be heated

  4. None of these


Correct Option: C
Explanation:

A refrigerant is a substance or mixture, usually a fluid, used in a heat pump and refrigeration cycle. In most cycles it undergoes phase transitions from a liquid to a gas and back again.A heat pump is a device that transfers heat energy from a source of heat to what is called a "heat sink". Heat pumps move thermal energy in the opposite direction of spontaneous heat transfer, by absorbing heat from a cold space and releasing it to a warmer one. A heat pump uses a small amount of external power to accomplish the work of transferring energy from the heat source to the heat sink.


the function of refrigerants in heat pumps refrigerant carries heat from the atmosphere to the room,which is to be heated

In a cyclic heat engine operating between a source temperature of $600^0C$ and a sink temperature of $20^0 C$, the least rate of heat rejection per kW net output of the engine is,

  1. 0.505kW

  2. 0.490kW

  3. 0.333kW

  4. none of the above


Correct Option: A
Explanation:

$\therefore Heat\quad absorption=\dfrac { { T } _{ 1 }-{ T } _{ 2 } }{ { T } _{ 1 } } $


$=\dfrac { 873-293 }{ 873 } =0.664$


$\therefore Heat\quad Rejected=1-heat\quad absorbed$
$=1-0.664$
$\therefore Heat\quad rejected=0.335$

Hence the heat of rejection per kW is $0.335$

A heat engine is supplied with 250 kJ/s of heat at a constant fixed temperature of $227^0C$; the heat is rejected at $27^0C$, the cycle is reversible, then what amount of heat is rejected?

  1. 24kJ/s

  2. 223kJ/s

  3. 150kJ/s

  4. none of the above


Correct Option: C
Explanation:

The temperature in kelvin scales are $T _1=273+27=300K,T _2=273+237=500K$

$T _1$is temperature of sink And$T _2$ is temperature of source hence by efficiency we get

$\eta=1-\dfrac{T _1}{T _2}=1-\dfrac{Q _1}{Q _2}$


$Q _1=\dfrac{T _1}{T _2}*Q _2=\dfrac{300}{500}*250=150kW$

An engine working on Carnot cycle rejects 40% of absorbed heat from the source, while the sink temperature is maintained at $27^0C$, then what is the source temperature (in $^0C$)?

  1. 477

  2. 346

  3. 564

  4. none of the above


Correct Option: A
Explanation:
$\eta =\dfrac { 60 }{ 100 } $

${ T } _{ 2 }={ 27 }^{ o }C$
${ T } _{ 2 }={ 300 }^{ o }K$
${ T } _{ 1 }=?$

$\eta =\dfrac { { T } _{ 1 }-{ T } _{ 2 } }{ { T } _{ 1 } } $

Here, ${ T } _{ 1 }=Source\quad temperature$
${ T } _{ 2 }=sink\quad temperature$
$\eta =Efficiency$
$\eta =100-rejecion$

$\therefore \dfrac { 60 }{ 100 } =\dfrac { { T } _{ 1 }-{ T } _{ 2 } }{ { T } _{ 1 } } $

$\therefore 0.6=\dfrac { { T } _{ 1 }-300 }{ { T } _{ 1 } } $

$\therefore { T } _{ 1 }\left( 1-0.6 \right) =300$

${ T } _{ 1 }=\dfrac { 300 }{ 0.4 } =\dfrac { 3000 }{ 4 } ={ 750 }^{ o }K$

$\therefore { T } _{ 1 }={ \left( 750-273 \right)  }^{ o }C$
$\therefore { T } _{ 1 }={ 477 }^{ o }C$

One reversible heat engine operates between 1600 K and $T _2$ K, and another reversible heat engine operates between $T _2$ K and 400 K. If both the engines have the same heat input and output, then the temperature $T _2$ must be equal to:

  1. 600

  2. 800

  3. 650

  4. 675


Correct Option: B
Explanation:

${ T } _{ 1 }=1600K$


${ T } _{ 2 }={ T } _{ 2 }K$


${ T } _{ 1 }^{ 1 }={ T } _{ 2 }K$

${ T } _{ 2 }^{ 1 }=400K$

Same input and same output.Then the efficiency is same.
$\eta =\dfrac { { T } _{ 1 }-{ T } _{ 2 } }{ { T } _{ 1 } } $

$\therefore \dfrac { 1600-{ T } _{ 2 } }{ 1600 } =\dfrac { { T } _{ 2 }-400 }{ { T } _{ 2 } } $

$=1600{ T } _{ 2 }-{ T } _{ 2 }^{ 2 }=1600{ T } _{ 2 }-640000$

$\therefore { T } _{ 2 }^{ 2 }=640000$
$\therefore { T } _{ 2 }=800K$

The freezer in a refrigerator is located at the top section so that;

  1. The entire chamber of the refrigerator is cooled quickly due to convection

  2. The motor is not heated

  3. The heat gained from the environment is high

  4. The heat gained from the environment is low


Correct Option: A
Explanation:

The freezer in a refrigerator is located at the top section so that the entire chamber of the refrigerator is cooled quickly due to convection.  
The correct option is A.

If the door of a refrigerator is kept open, the room in which the refrigerator is kept 

  1. gets cooled

  2. gets heated

  3. neither gets cooled nor gets heated

  4. gets cooled or heated depending on the initial temperature of the room


Correct Option: C
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