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Domestic and commercial circuit - class-X

Description: domestic and commercial circuit
Number of Questions: 91
Created by:
Tags: electrical circuits electric current and circuit physics electric current
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Alternating current can not be measured by $D.C$. ammeter because 

  1. $A.C$. cannot pass through $D.C$.

  2. $A.C$. changes direction

  3. average value of current for complete cycle is zero

  4. $D.C$. ammeter will get damaged.


Correct Option: C
Explanation:

While for half-circle, the value of current is different at different points and for complete cycle its average value is zero.

So, we can't measure current by $D.C$ ammeter .

The frequency of ac mains in India is:

  1. $30$ Hz

  2. $50$ Hz

  3. $60$ Hz

  4. $120$ Hz


Correct Option: B
Explanation:

Frequency of AC mains in India is 50 Hz,similar to most European countries. Whereas USA uses 60 Hz

Various distribution circuits are connected in

  1. series

  2. parallel

  3. series or parallel

  4. nothing can be decided


Correct Option: B
Explanation:

Parallel circuit configuration limits the amount of power in each circuit and if one circuit breaker goes out, power remains on in the rest of the home.

Which of the following can be true?

  1. The instantaneous power output of an ac source can be negative.

  2. The average power output of an ac source can be negative.

  3. The instantaneous power output of an ac source can NOT be negative.

  4. The average power output of an ac source can NOT be negative.


Correct Option: A

The wire having a green plastic covering is a:

  1. Live wire

  2. Neutral wire

  3. Earth wire

  4. None of these


Correct Option: C
Explanation:

During wiring in our houses , we use the traditional concept of using red colour wire as live , black as neutral and green for earth.
These colour codes are used to distinguish between live , earth and neutral

Marking on a bulb is 60 W, 220 V. What does it signify ?

  1. The bulb is connected across 220 volts, 60 joules of energy is released in every second.

  2. The bulb is connected across 220 volts, 60 joules of energy is released in every minute.

  3. 60 A of current will flow in the bulb.

  4. 220 A of current will flow in the bulb.


Correct Option: B

Which one of the following is the best material for making connecting wires?

  1. Nichrome

  2. Tungsten

  3. Copper

  4. Manganese


Correct Option: C

The current through a lamp decreases by $1 \%$ The percentage change power of the lamp is

  1. 0.5%

  2. 1%

  3. 1.5%

  4. 2%


Correct Option: D
Explanation:

The current through a lamp decreases by $1\%$ then percentange change power of the lamp is $2\%$.

Hence, option $D$ is the correct answer.

An electric iron uses a power of $1320 W$ when set to higher temperature. If set to lower temperature one third of higher temperature current is used. If iron is connected to a potential of $220 V$, then power used to lower temperature is _____ .

  1. $220 W$

  2. $440 W$

  3. $660 W$

  4. $880 W$


Correct Option: B
Explanation:

Power, $P = VI$ (power at high temperature) 


$1320 = 220 I$ (current at high temperature)

Current at high temperature, $I _t = 6A $

$I _{LT} = \dfrac{6}{3} = 2A$ (current at low temperature) 

$P _{LT} = 220 \times2 \ W$

$ = 440 \ W$ (power at low temperature)

The electrical appliances in a house are connected in :

  1. series

  2. parallel

  3. either in series or parallel

  4. both in series and parallel


Correct Option: B
Explanation:

A parallel connection is preferred in a household circuit.
The main advantages of the parallel system are that the supply can be tapped at any convenient point in the house; moreover each appliance is operated by a separate fuse. If the fuse blows off, only that appliance is to be checked. This system involves less wiring and is cheaper to set up.

Units of power and voltage are represented by

  1. W, V

  2. A, V

  3. W, $\Omega$

  4. V, $\Omega$


Correct Option: A
Explanation:

In our every day lives we use electrical energy to do work for us. This electrical energy is provided either by our power company through the outlets in our wall, or we can buy stored electrical energy in the form of batteries. Different electrical appliances use electrical energy at different rates. Power is the rate at which work is done. The power rating of an appliance tells us the rate at which it uses electrical energy. For example, a 1500 watt hair dryer uses 1500 joules of electrical energy per second.
In any electrical appliance their is a simple relationship between the power output of a component, the potential difference across that component, and the current running through it. This is because charge times potential difference is energy, so (charge per unit time) times (potential difference) gives (energy per unit time).
Thus, we have $P=V I.$
Substituting $V=I R$ from ohm's law, the power relationship can be rewritten as $P={ I }^{ 2 }R$. From this formula, the resistance can be calculated.

hence correct option is A

Fill the blank.
Voltmeter is always connected in . . . .with the device.

  1. series

  2. parallel

  3. series and parallel both.

  4. the cell.


Correct Option: B
Explanation:

A voltmeter is an instrument used for measuring electrical potential difference between two points in an electric circuit. A voltmeter is connected in parallel with a device to measure its voltage.
Hence, the statement is false as the voltmeter is connected in parallel to the device in a circuit.

The melting point of filament of a bulb is 

  1. very low.

  2. very high.

  3. normal.

  4. none of these.


Correct Option: B
Explanation:

The electric bulb is the glass enclosure around the filament that often contains a vacuum or is filled with a low-pressure noble gas to prevent the filament from burning out due to evaporation at high temperature. The coiled filaments of incandescent lamps are made up of tungsten, a high resistance material that is drawn into a wire .It has both a high melting point (3382 degrees Celsius) and a low pressure which keep it from melting or evaporating too quickly. Supplying electricity through this coiled tungsten wire generates the light. Due to the resistance, it is heated until the wire becomes white-hot. The emission of light by heating the filament wire to white-hot level is known as incandescence. Here, the electrical energy is converted to heat energy by the resistance of the wire.A fused electric bulb has its filament cut, because at higher temperature for a longer period of time, the tungsten filament melts and the flow of electric current stops and the bulb loses its original utility. 
Hence, the statement is true.

The wire having a red plastic covering is a

  1. live wire

  2. neutral wire

  3. earth wire

  4. none of these


Correct Option: A
Explanation:

According to old convention, live wire was coded by red colour. Hence live wires were covered with red plastic.

A live wire is ______ in colour.

  1. red

  2. blue

  3. green

  4. yellow


Correct Option: A
Explanation:

A live wire is red on color .The wire had a red plastic covering.

The heater element in an electric iron is made of

  1. Copper

  2. Tungsten

  3. Nichrome

  4. Iron

  5. Platinum


Correct Option: C

Which of the following is not a type of wire in power supply.

  1. Phase Wire

  2. Neutral wire

  3. Zero wire

  4. Earth wire


Correct Option: C
Explanation:

In power supply system, there are three wires - Phase(live) wire, neutral wire and earth wire. hence there is no any wire named Zero wire . so correct option is option C.

The wire having a black plastic covering is a

  1. live wire

  2. neutral wire

  3. earth wire

  4. none of these


Correct Option: B
Explanation:

The wire having a black plastic covering is a neutral wire whereas that having a red covering is a live wire.

A certain network consists of two ideal and indentical voltage sources in series and a large number of ideal resistor. The power consumed in one of the resistor is $4W$ when either of the two sources is active and other is replaced by a short circuit. The power consumed by same resistor when both sources are simultaneously active would be: 

  1. $0$ or $16W$

  2. $4W$ or $8W$

  3. $0$ or $8W$

  4. $8W$ or $16W$


Correct Option: A
Explanation:

$ P=VI$

$ I= \cfrac{nE}{R+r}$ (r=0)
In this case 
$ I= \cfrac{nE}{NR} ; E _1 = E _2$
$ P=VI$
In first case 
$ 4 =E \times \cfrac{E}{NR} = \cfrac{E^2}{NR}$
In second case 
$ x =2E \times \cfrac{2E}{NR} = \cfrac{4E^2}{NR}$
$ \cfrac{x}{4} = \cfrac{4E^2}{NR} \times \cfrac{NR}{E^2}$
$ x= 0 \quad or \quad 16W$

The wire having a green plastic covering is a

  1. live wire

  2. neutral wire

  3. earth wire

  4. none of these


Correct Option: C
Explanation:

The wire having a green plastic covering is a earth wire, black plastic covering is a neutral wire whereas that having a red covering is a live wire.

The colour of the earth wire is generally :

  1. red

  2. blue

  3. black

  4. green


Correct Option: D
Explanation:

The colour of earth wire is generally green in colour green wire stands for grounding / earthing in an electric circuit.

Which of the following does not electrical power in circuit?

  1. ${I}^{2}R$

  2. $I{R}^{2}$

  3. $VI$

  4. $\dfrac{{V}^{2}}{R}$


Correct Option: B
Explanation:

$I{R}^{2}$ is not the formula for power.

All power entering a house enters via

  1. Electricity Meter

  2. Various loads in house

  3. Electricity board motor

  4. Potential Barrier


Correct Option: A
Explanation:

In power distribution system at home, all power enters via electricity meter. This is important to charge the correct amount of electricity bill every month.

The maximum current which can flow through a fuse without melting it is called its

  1. potential

  2. power

  3. rating

  4. capacity


Correct Option: C
Explanation:

The maximum current which can flow through a fuse without melting it is called its rating.
For example a fuse rated at 8 A, can stand current upto 8 A. If current higher than 8 A flows through the fuse, it would melt and circuit gets broken.the rating of a fuse depends upon the thickness of the fuse wire (because length of the wire is fixed). The thicker fuse has higher rating. So, the thickness of the fuse wire in 8 A circuit is more than that of the fuse wire in 5 A circuit.

All appliances in a domestic electric circuit are connected in parallel so that

  1. Voltage drop across each appliance is same.

  2. Current through each appliance is same.

  3. Power consumed by each appliance is same.

  4. It allows amplification of power


Correct Option: A
Explanation:

Voltage drop is the driving force in any electrical circuit. Hence, it is desired to supply same voltage everywhere.

Potential difference of 220-250 V is present between 

  1. Earth wire and neutral wire

  2. Live wire and earth wire

  3. Live wire and neutral wire

  4. B and C both


Correct Option: C
Explanation:

Potential difference between live wire and neutral wire is about 220 V-250 V. which is generally provided for household purposes in homes for electricity. so correct option is C.

The rating of a fuse depends upon the

  1. thickness of the fuse wire

  2. length of the wire

  3. both

  4. none


Correct Option: A
Explanation:

The maximum current which can flow through a fuse without melting it is called its rating.
For example a fuse rated at 8 A, can stand current upto 8 A. If current higher than 8 A flows through the fuse, it would melt and circuit gets broken.

The rating of a fuse depends upon the thickness of the fuse wire(because length of the wire is fixed).the thicker fuse has higher rating. So, the thickness of the fuse wire in 8 A circuit is more than that of the fuse wire in 5 A circuit.

Mark the incorrect statement.

  1. In our homes, we receive supply of electric power through a main supply

  2. Red insulation cover, is called live wire

  3. The earth wire, has insulation of green colour

  4. None


Correct Option: D
Explanation:

In our homes, we receive supply of electric power through a main supply (also called mains), either supported through overhead electric poles or by underground cables. One of the wires in this supply, usually with red insulation cover, is called live wire (or positive). Another wire, with 
black insulation, is called neutral wire (or negative). In our country, the 
potential difference between the two is $220   V$. At the metre-board in the house, these wires pass into an electricity meter through a main fuse. Through the main switch they are connected to the line wires in the house. These wires supply electricity to separate circuits within the house. Often, two separate circuits are used, one of $15   A$ current rating for appliances with higher power ratings such as geysers, air coolers, etc. The other circuit is of 5 A current rating for bulbs, fans, etc. The earth wire, which has insulation of green colour, is usually connected to a metal plate deep in the earth near the house. This is used as a safety measure, especially for those appliances that have a metallic body, for example, electric press, toaster, table fan, refrigerator, etc. The metallic body is connected to the earth wire, which provides a low-resistance conducting path for the current. Thus, it ensures that any leakage of current to the metallic body of the appliance keeps its potential to that of the earth, and the user may not get a severe electric shock.

The old connection colour coding for live wire is

  1. Red

  2. Brown

  3. Light blue

  4. Green


Correct Option: A
Explanation:

Old convention colour for live wire is red whereas in new convention live wire is coded by brown colour.

According to new convention,_____colour is used for live wire. Fill in the blank. 

  1. Red

  2. Brown

  3. Light blue

  4. Green


Correct Option: B
Explanation:

According to new convention, brown colour is coded for live wire, light blue is coded for neutral wire and green or yellow is coded for earth wire.

Which colour is used for earth wire?

  1. Green

  2. Yellow

  3. Both of these

  4. None of these


Correct Option: C
Explanation:

Either green or yellow is used for earth wires.

Name the colour used in insulated wired of electrical appliance.

  1. Blue

  2. Green

  3. Brown

  4. All of these


Correct Option: D
Explanation:

Blue, green and brown are used as insulated wired.

Each electrical appliance is provided with a _______ core flexible cable. Fill in the blank.

  1. 3

  2. 2

  3. 1

  4. 4


Correct Option: A
Explanation:

Each electrical appliance is provided with three (3) core flexible cables. The insulation on the three wires is of different colours i.e  Brown for live wire, blue for neutral wire and green or yellow for earth wire.

Every electric appliance is marked with

  1. power

  2. potential difference

  3. charge

  4. resistance


Correct Option: A,B
Explanation:

Every electric appliance is marked with it's power and potential difference at which it works. This marking is called rating of an electrical appliances.

State SI unit of electric power.

  1. Watt

  2. Kilo watt

  3. Joule

  4. Kilowatt hour


Correct Option: A
Explanation:

SI unit of electric power is Watt
1 Watt = 1  Volt $\times$ 1 ampere.

In a city, electricity costs $0.12 per kilowatt-hour. A bulb of 150-watt operates for 5 hours. Calculate the cost of electricity which is consumed by the bulb.

  1. $0.009

  2. $0.09

  3. $0.90

  4. $9.00

  5. $90.00


Correct Option: B
Explanation:

Cost $=(0.150 kWh) (hr)  \left ( 12 \dfrac {cent}{kWh} \right )= 9 cent
=$0.09$

For a domestic $AC$ supply of $220\ V$ at $50$ cycles per second the potential difference between the terminals of a two-pin electric outlet in a room is given by

  1. $V(t) = 220\sqrt {2}\cos (100\pi t)$

  2. $V(t) = 220\cos (50t)$

  3. $V(t) = 220\cos (100\pi t)$

  4. $V(t) = 220\sqrt {2}\cos (50 t)$


Correct Option: A
Explanation:

Rms value of voltage  $V _{rms} =220 $ volts

Peak value of voltage  $V _o = \sqrt{2}V _{rms}$
$\therefore$ $V _{o} = 220\sqrt{2}$volts   
Frequency  $\nu =50$ $Hz$
$\implies$  $w = 2\pi \nu = 2\pi (50)  = 100\pi$
Thus potential difference is given by  $V = V _o \cos wt$
$\therefore$  $V= 220\sqrt{2} \cos (100 \pi t)$

Which instrument is not used to convert electric energy into heat energy?

  1. Room heater

  2. Electric Iron

  3. Electric Bell

  4. Electric water heater


Correct Option: C
Explanation:

Electric Bell is not used to convert electric energy into heat energy as there is no  use of heat in functioning of an electric bell.In electric bell electrical energy is used to convert sound energy.First it converts electric energy into mechanical energy and which is used to produce sound energy.

Therefore,C is correct option.

Household electrical appliances are joined using ________ combination of resistors

  1. Parallel

  2. Alternating

  3. Continuous

  4. Series


Correct Option: A
Explanation:

In a house, there are many electrical appliances that have to run independent of each other. If one appliance is turned on or off it should not affect the other appliances. Thus even if a single appliance is taken out of the circuit (turned off / open switched ) the circuit breaks and hence the current cannot flow in the circuit so every thing turns off.

 So even if a single appliance is taken out of the circuit (turned off / open switched ) the circuit breaks and hence the current cannot flow in the circuit .
In parallel, even if an appliance gets damaged or is turned off ,the current always has other independent dedicated parallel paths to other appliances and hence every appliance is still works well. 

Which statement is wrong from the following?

  1. The earthing wire is green coloured.

  2. In India, current flowing through wire is AC and its frequency is $50 \,Hz$.

  3. In India, voltage between two wires is $110 \,V$.

  4. T.V., Tublight, bulbs are connected with $5\, A$ line.


Correct Option: C
Explanation:

In India, current flowing through wire is A.C and its frequency is $50Hz$ and voltage $220V$.But, Option C said voltage between two wires is 110V110V, which is wrong.

Therefore, C is correct option.

Which one of the following is different from the others?

  1. Joule

  2. Kilowatt hour

  3. Erg

  4. Watt


Correct Option: D

Which of the following statements is true?

  1. In tree type distribution of electric power, fuses are present only on the main board.

  2. In ring type distribution of electric power, there is an individual fuse for each appliance.

  3. Ring type distribution of electric power is advantageous than the tree type distribution.

  4. All the above.


Correct Option: D
Explanation:

In tree type distribution of electric power, fuses are present only on the distribution board where as in ring type, there is an individual fuse for each appliance. As there is an individual fuse for each appliance in ring type, only faulty appliance will not work and all the other appliances will not be affected. It is easier to install. So, ring type is advantageous than that of tree type. Hence, choice is (4)

Two bulbs of 100 W and 40 W are connected in series. The current through the 100 W bulb is 1A. The current through the 40 W bulb will be

  1. $0.4 A$

  2. $0.6A$

  3. $0.8 A$

  4. $1 A$


Correct Option: D
Explanation:

As the resistances are connected in series , same current will pass through them.

Maximum power in a $0.5 \Omega$ resistance connected with two batteries of 2V emf  and $1 \Omega$ internal resistance in parallel is 

  1. $2 W$

  2. $1.28 W$

  3. $\dfrac{8}{9} W$

  4. $3.2 W$


Correct Option: D

In which of the following the heating effect of an electric current is not used?

  1. Soldering

  2. Welding

  3. Earthing

  4. Fuse


Correct Option: B

At a temperature T K,the pressure of 4.0 g argon in a bulb is p.The bulb is put in a bath having temperature higher by 50 K than the one.0.8 g of argon gas had to be removed to maintained ariginal pressure.The temperature T is equal to 

  1. 510 K

  2. 200 K

  3. 100 K

  4. 73 K


Correct Option: B

in electric bulb rated $160W,80\ V$ has to be operated across  $100\ V,50Hz$ a.c supply. The reactance Which is series with bulb should be-

  1. $30\ \Omega$

  2. $60\ \Omega$

  3. $15\ \Omega$

  4. $120\ \Omega$


Correct Option: C

Two electric bulbs have 60 W and 100 W rating at 220 V then ratio of their resistances will be 

  1. 3:2

  2. 5:3

  3. 9:4

  4. 4:9


Correct Option: B

A bulb rate $220 V, 100 W$ is connected across $110 V$ line. The power dissipated will be

  1. $100 W$

  2. $75 W$

  3. $ 52 W$

  4. $ 25 W$


Correct Option: D

A house hold $20$ liter geyser consist of a coil of resistance $R$, across which an $ac$ source of $rms$ voltage $V$ is connected. The wall thickness of geyser is $t(< < \sqrt{A})$ and the inner surface area of geyser is $A$. The average thermal conductivity of material of walls of geysers is $k$ and $S$ is specific heat capacity of water. Assuming initial temperature of water is equal to the temperature of atmosphere. The time taken to rise the temperature of water by $50^{o}C$ is (Neglect the specific heat of wall of geyser and radiation losses)

  1. $\dfrac{2St}{kA} In \left(\dfrac{50RkA}{rV^{2}}-1\right)$

  2. $\dfrac{20St}{kA} In \left(\dfrac{tV^{2}}{V^{2}t-20RkA}-1\right)$

  3. $\dfrac{20St}{kA} In \left(\dfrac{50tV^{2}}{RkA}\right)$

  4. $\dfrac{20St}{kA} In \left(\dfrac{50RkA}{tV^{2}}\right)$


Correct Option: A

The voltage of domestic ac is $220\ V$. What does this represent?

  1. Mean voltage

  2. Peak voltage

  3. Root mean voltage

  4. Root mean square voltage


Correct Option: C

If 2.2 kW power transmits 22000 V in a line of $10 \Omega$ resistance, the value of power loss will be :-

  1. 0.1 W

  2. 10 W

  3. 100 W

  4. 1000 W


Correct Option: A

Mircrowave oven acts on the principle of 

  1. Giving rotational energy to water

  2. Giving translational energy to water molecular

  3. Giving vibrational energy to water molecules

  4. None of these


Correct Option: D
Explanation:

Microwave oven act on the principle of transferring electron from lower 

to higher energy level in water molecule.

Four wires made of same material have different lengths- and radii, the wire having more resistance in the following case is 

  1. $l= 100 cm, r= 1 mm$

  2. $l= 50 cm, r= 2 mm$

  3. $ l= 100 cm, r=\frac { 1}{2} mm $

  4. $ l= 50 cm, r=\frac { 1}{2} mm $


Correct Option: C

A bulb made of tungsten filament of surface area $0.5 c{ m }^{ 2 }$ is heated to a temperature 3000 k when operated at 220 V. The emissivity of the filament is $ \in =0.35$ and take $\sigma =5.7\times 1{ 0 }^{ -8 }$ mks units. Then the wattage of the bulb is .. (calculate)

  1. 80.8 W

  2. 0.81 W

  3. 81.2 W

  4. 8.12 W


Correct Option: A

What is the frequency of 220$\mathrm { v } \mathrm { DC }$ voltage? 

  1. Zero HZ

  2. 50$\mathrm { Hz }$

  3. 60$\mathrm { Hz }$

  4. 220$\mathrm { Hz }$


Correct Option: A

How the small bulbs, which are used for decoration purpose,are connected?

  1. in parallel

  2. in series

  3. in mixed order

  4. all of the above


Correct Option: B
Explanation:

Bulbs used for decoration purposes are connected end to end, that is, in series. This ensures that same amount of current flows through them and the voltage divides across the bulbs as required for low voltage operation. Thus when one bulb goes out, due to being in series, all the bulbs stop glowing.

Which of the following appliances is not of lower power rating ?

  1. Tubelight O

  2. TV O

  3. Fan O

  4. Geyser O


Correct Option: D

A student in town in India, where the price per unit ($1 unit = 1 kW-hr$) of electricity is $Rs.5.00$, purchases a $1 kVA$ UPS (uninterrupted power supply) battery. A day before the exam, 10 friends arrive to the student's home with their laptops and all connect their laptops to the UPS. Assume that each laptop has a constant power requirement of $90 W$. Consider the following statements :


I. All the 10 laptops can be powered by the UPS if connected directly.
II. All the 10 laptops can be powered if connected using an extension box with a $3 A$ fuse.
III. If all the 10 friends use the laptop for 5 hours, then the cost of the consumed electricity is about $Rs.22.50.$

Select the correct option with the true statements.

  1. I only

  2. I and II only

  3. I and III only

  4. II and III only


Correct Option: C
Explanation:
power supplied by battery $1\ kVA=1000\ W$

$1$ laptop required $90\ W$.

and all $10$ laptop are connected directly so,

$P _T=90\ W\times 10=900\ W$

$1\ unit=1\ KW\ hr$ cost $=5\ Rs$.

So, If $10$ Laptops are used for $5\ hr$ well consumed

$unit=\dfrac{900\times 5\times 3600}{3600000}=4.5$

Total pay amount in $5\ hr=4.5\ unit\times 5$
                         $=22.5\ rupees$

An electric bulb is rated 250 W, 230 V. The energy consumed in one hour is :

  1. $9 \times 10^5$ J

  2. $15 \times 10^5$ J

  3. $25 \times 10^5$ J

  4. $23 \times 10^5$ J


Correct Option: A
Explanation:

Energy ($power\times time$) is measured in Joules and by including time (t) in the power formulae, the energy dissipated by a component or circuit can be calculated.


Energy dissipated Q= Pt.

In the question, the time taken is given as 1 hour = 60 minutes, that is $60\times 60=3600\quad seconds$ and the power is 250 W.

Hence, the energy consumed by the bulb is $250\quad W\times 3600\quad s=9.00,000\quad J.\quad That\quad is,\quad 9\times { 10 }^{ 5 }\quad Joules$. 

A geyser is rated 1500 W, 250 V. This geyser is connected to 250 V mains. The current drawn will be:

  1. $6 A$

  2. $5 A$

  3. $40 A$

  4. $10 A$


Correct Option: A
Explanation:

Power, $P=VI$
For a $1500\ W$ geyser rated for $250\ V$, the current through is given as $I=\dfrac { P }{ V } =\dfrac { 1500 }{ 250 } =6A$
Hence, the current flowing through the heater is $6\ A$.

Which is or are the correct for filament of bulb ?

  1. Low melting point

  2. High melting point

  3. Made of tungsten

  4. Made of nichrome


Correct Option: B,C
Explanation:

The electric bulb is the glass enclosure around the filament that often contains a vacuum or is filled with a low-pressure noble gas to prevent the filament from burning out due to evaporation at high temperature. The coiled filaments of incandescent lamps are made up of tungsten, a high resistance material that is drawn into a wire. It has both a high melting point (3382 degrees Celsius) and a low pressure which keep it from melting or evaporating too quickly. Supplying electricity through this coiled tungsten wire generates the light. Due to the resistance, it is heated until the wire becomes white-hot. The emission of light by heating the filament wire to white-hot level is known as incandescence. Here, the electrical energy is converted to heat energy by the resistance of the wire. A fused electric bulb has its filament cut, because at higher temperature for a longer period of time, the tungsten filament melts and the flow of electric current stops and the bulb loses its original utility. 
Hence, the statement is false.

Three heaters each rated 250 W, 100 V are connected in parallel to a 100 V supply. The total current taken from the supply is :

  1. $2.5 A$

  2. $5 A$

  3. $7.5 A$

  4. $25 A$


Correct Option: C
Explanation:

Power is given as: $P=VI$


For a $60\ W$ lamp rated for $ 250\ V$, the current through is given as: $I=\dfrac { P }{ V } =\dfrac { 250 }{ 100 } =2.5\ A$

Hence, the current flowing through the heater is $2.5\ A$.

In a parallel circuit, the voltage across each of the components is the same, and the total current is the sum of the currents through each component.
Therefore, when three such heaters are connected in parallel, then the current obtained from the supply is given as $2.5+2.5+2.5 = 7.5\ A$

Household electrical appliances are joined using .......... combination of resistors.

  1. Parallel

  2. Alternating

  3. Continuous

  4. Series


Correct Option: A
Explanation:

Household electrical appliances are always joined in parallel.

The current through a 60 W lamp rated for 250 V is 

  1. 0.24 A

  2. 4.2 A

  3. 0.5 A

  4. 6 A


Correct Option: A
Explanation:
The electric power in watts associated with a complete electric circuit or a circuit component represents the rate at which energy is converted from the electrical energy of the moving charges to some other form, e.g., heat, mechanical energy, or energy stored in electric fields or magnetic fields. The power is given by the product of applied voltage and the electric current. That is, $P=VI$. 

For a 60 W lamp rated for 250 V, the current through is given as $I=\dfrac { P }{ V } =\dfrac { 60 }{ 250 } =0.24A$.

Hence, the current flowing through the lamp is 0.24 A.

Substituting I=V/R in the above formula, we get, $P=\dfrac { { V }^{ 2 } }{ R } $.

Given that the voltage is 250 V and the power is 60 W, the resistance of the 

bulb is calculated as follows.

$R=\dfrac { { V }^{ 2 } }{ P } =\dfrac { { 250 }^{ 2 } }{ 60 } =1041.67\Omega$.

When the voltage drops to 200 V, the power is calculated as follows.

$P=\dfrac { { V }^{ 2 } }{ R } =\dfrac { { 200 }^{ 2 } }{ 1041.67 } =\quad 38.40W$

Hence, the power of the bulb is reduced to 38.40 W.

We should not use many electrical appliances simultaneously. True/False?

  1. True

  2. False


Correct Option: A
Explanation:

When many appliances are switched on simultaneously, a lot of current flows through the main circuit and the current may exceed the permissible amount. This causes overloading and may cause a fire. Thus many electrical appliances should not be used simultaneously.

An electric heater consists of a nichrome coil and runs under $220 V$, consuming $1 kW$ power. Part of its coil burned out and it was reconnected after cutting off the burnt portion, The power it will consume now is:

  1. More than $1 kW$

  2. Less that $1 kW$, but not zero

  3. $1 kW$

  4. $0kW$


Correct Option: A
Explanation:

Answer is A.

The electrical resistance of a wire would be expected to be greater for a longer wire, less for a wire of larger cross sectional area, and would be expected to depend upon the material out of which the wire is made.The resistance of a wire can be expressed as $R=\rho \frac { L }{ A } $, 
where,
$\rho $ - Resistivity  - the factor in the resistance which takes into account the nature of the material is the resistivity
L - Length of the conductor
A - Area of cross section of the conductor.
From this relation, we observe that the length is directly proportional to the resistance and the area of cross section is inversely proportional to the resistance.
In this case, the length of the nichrome coil is reduced due to the burn and so the resistance will also be reduced proportionally. 
When the resistance is decreased, more current flows through the coil and apparently, more power is consumed by the heater as power consumed P = VI.
Hence, the power it will consume now is more than 1 kW.

An air conditioner is rated $240\;V,\;1.5\;kW$. The air conditioner is switched on for $8$ hours each day. How much electrical energy is consumed in $30$ days ?

  1. $360\;kW\;h$

  2. $8.64\;kW\;h$

  3. $120\;kW\,h$

  4. $240\;kW\;h$


Correct Option: A
Explanation:

Answer is A.

If a certain amount of power is dissipated for a given time, then energy is dissipated. Energy (powertime) is measured in Joules and by including time (t) in the power formulae, the energy dissipated by a component or circuit can be calculated.
Energy dissipated = Pt .
In this case, the power dissipated is 1.5 kW and it runs for 8 hours a day.
So, in a day, the energy dissipated is 1.5 * 8 = 12 Kwh.
For 30 days, the power dissipated is 12 * 30 = 360 Kwh.
Hence, the electrical energy is consumed by the air conditioner in 30 days is 360 Kwh.

A washing machine rated $300W$ is operated for one hour/day. If the cost of a unit is Rs $3.00$ then the cost of the energy to operate a washing machine for the month of March is

  1. $Rs 25.60$

  2. $Rs 27.50$

  3. $Rs 27.90$

  4. $Rs 26.90$


Correct Option: C
Explanation:

In this case, the washing machine that is rated $ 300\ W$ is operated for $1$ hr/day. The electric bill has to be calculated for the month of March. That is, the total number of hours the washing machine is operated in this month is $31$ hours as this month has $31$ days.
The total energy that is used by the washing machine in a day is given by the formula $Q=Pt$.
Here, the power is $300\ W$ and the time used is $1\ hour$.
So, $Q=300W\times 1h=300Wh= 0.3\ kWh$
Therefore, the total number of $kWh$ for a month is $0.3kWh\times 31=9.3\ kWh $
The cost of $1\ kWh$ is given as $Rs. 3$.

Hence, the total cost for a month is $=9.3kWh\times 3=Rs. 27.90$

A neon lamp is connected to a voltage a.c. source. The voltage is gradually increased from zero volt. It is observed that the neon flashes at $50 V$. The a.c, source is now replaced by a variable dc source and the experiment is repeated. The neon bulb will flash at ?

  1. $50V$

  2. $70V$

  3. $100V$

  4. $35V$


Correct Option: B
Explanation:

Answer is B.

The RMS (Root mean square) value tells us what equivalent DC voltage we would need to get the same power, for the neon bulb to glow.
In this case, the neon bulb glows at 50 V ac voltage. Therefore, for the bulb glow with dc voltage, $50\times \sqrt { 2 }  =50\times 1.414=70V$ dc voltage should be applied.
Hence, the neon bulb will flash at 70 V dc.

Two dissimilar bulbs are connected in series, which bulb will be brighter ?

  1. low resistance bulb

  2. more resistance bulb

  3. high current pass bulb.

  4. low current pass bulb


Correct Option: B
Explanation:

Components connected in series are connected along a single path, so the same current flows through all of the components. The current through each of the components is the same, and the voltage across the circuit is the sum of the voltages across each component.
When two bulbs are connected in series the first bulb will receive more current. As the bulb has its own resistance, less current will flow to the next bulb.
Hence the first bulb will glow more.

The wire having a green plastic covering is a

  1. live wire.

  2. neutral wire.

  3. earth wire.

  4. none of these.


Correct Option: C
Explanation:

Black, Red and Blue are used for hot wires and White is used as the neutral wire in a 120/208 V circuit. Brown, Orange and Yellow are used as hot wires and gray is used as the neutral wire in a 277/480 V. For grounding, regardless of the voltage, Green is used.The wire having a green plastic covering is a earth wire.

An electrician not aware of the colour coding of resistors connected two resistors A and B in series to a 6V battery of internal resistance $3\Omega$ and an ammeter. The ammeter connected in the circuit was not working and hence he disconnected the ammeter from the circuit. The sequence of the colour bands on resistor. A is yellow, violet and brown while that on resistor B is red, violet and black respectively. By using the colour coding of resistors, help the electrician to determine the current flowing through the circuit. 

  1. $12$ mA

  2. $24$ mA

  3. $48$ mA

  4. $32$ mA


Correct Option: A
Explanation:

Given: resistors A and B connected in series to a $6V$ battery of $3\Omega$ internal resistance. The sequence of the colour bands on resistor. A is yellow, violet and brown while that on resistor B is red, violet and black respectively. 

To find the current flowing through the circuit.
Solution:
According to the question the A and B are 3-band resistors, so the thirdcode will be a multiplier.
And using the standard resistor color code table the value of:
yellow is 4, violet is 7, brown is $\times 10^1$, red is 2, black is $\times 10^0$.
The corresponding value of A and B are:
A= $47\times 10^1=470\Omega$, B= $27\times 10^0=27\Omega$
Now A and B are in series are also the internal resistance will also be in series. So the effective resistance of the circuit will be $R _{eq}=470+27+3=500\Omega$.
We know according to Ohm's Law,
$V=IR\implies I=\dfrac VR\\implies I=\dfrac 6{500}=0.012A$
Or the current flowing through the circuit = $12mA$

One unit of electric energy is equal to :

  1. One kilowatt hour

  2. one watt hour

  3. 100 Joules

  4. none of these


Correct Option: A
Explanation:

1 unit of electric energy is equal to


$1unit=1kWh$

$1kWh=1kW\times 1h$

$=1000W\times 3600s$

$\implies 1kWh=3.6\times 10^6J$

Answer-(A)

The wire having a red plastic covering is a

  1. live wire.

  2. neutral wire.

  3. earth wire.

  4. none of these.


Correct Option: A
Explanation:

The wire has a red plastic covering is a live wire. Red wire signifies the phase in an electric circuit. It is the live wire that cannot be connected to another red or bulb wire Red is used in some types of the switch leg.

The electricity tariff in a town is $Rs.3.00$ per unit. Calculate the cost of running an $80 W$ fan for $10 h$ a day for the month of June.

  1. $Rs. 12.00.$

  2. $Rs. 52.00.$

  3. $Rs. 72.00.$

  4. $Rs. 92.00.$


Correct Option: C
Explanation:

Total time for which the fan is used $= (10 hours) \times (30 days) = 300$ hours.
Energy consumed $= (80 W) \times (300$ hours$)$
$= 24,000 Wh = 24 kWh.$
But $1 kWh =1$ unit.
Therefore, $24 kWh = 24$ units
The cost of this power $= 24$ units $\times Rs. 3= Rs. 72.00.$

The wire having a black plastic covering is a

  1. live wire.

  2. neutral wire.

  3. earth wire.

  4. none of these.


Correct Option: B
Explanation:

Black, Red and Blue are used for hot wires and White is used as the neutral wire in a 120/208 V circuit. Brown, Orange and Yellow are used as hot wires and gray is used as the neutral wire in a 277/480 V. For grounding, regardless of the voltage, Green is used.The wire having a black plastic covering is a neutral wire.

The colour code of a resistor is brown, black and brown. Then the value of resistance is _____

  1. $10$ $\Omega$

  2. $100\ m \Omega$

  3. $0.1\ k$$\Omega$

  4. $1000$ $\Omega$


Correct Option: C
Explanation:

First two colours says about significant digits of resistance and the third colour gives multiplier.


Brown colour gives digit $1$, brown colour gives digit $0$ and for multiplier brown colour gives $10^1$.

Hence, resistance  $=R=10\times 10^1=100\Omega$

$\implies R=0.1k\Omega$

Answer-(C)

An electric oven of 2 kW power rating is operated in a domestic electric circuit that has a current rating of 5A. If the supply voltage is 220V, what result do you expect?

  1. circuit will be breaked

  2. fuse will blow

  3. both

  4. none


Correct Option: C
Explanation:

Given,
Power of the oven $(P) = 2kw = 2 \times 103 W$
Voltage supplied $(V) = 220V$
Current $(I) = ? A$
Power $= V \times I$
$\Rightarrow I = P/V = 2 \times 103/220 = 9.09 A$
Since the domestic electric circuit has a current rating of 5A, the flow of 9.09 A by the Oven exceeds the safe limit. Here, fuse will blow and break the circuit.

What is the function of distribution box in domestic electrical circuit

  1. It distributes voltage across appliances as per need

  2. It provides isolation between set of appliances and improves reliability

  3. It distributes Losses among all parts of circuit equally

  4. It allows user to manually distribute power as per his need


Correct Option: B
Explanation:

Distribution box in domestic electrical circuit provides isolation between appliances and allow them to work paralelly. It also ensures failure in one part do not affect the functioning of the other.

Mark the incorrect statement.

  1. The metallic body is connected to the earth wire

  2. The earth wire, has insulation of red colour

  3. Both

  4. None


Correct Option: B
Explanation:

One of the wires in this supply, usually with red insulation cover, is called live wire (or positive). Another wire, with black insulation, is called neutral wire (or negative). In our country, the potential difference between the two is $220   V$. At the metre-board in the house, these wires pass into an electricity meter through a main fuse. Through the main switch they are connected to the line wires in the house. These wires supply electricity to separate circuits within the house. Often, two separate circuits are used, one of $15   A$ current rating for appliances with higher power ratings such as geysers, air coolers, etc. The other circuit is of 5 A current rating for bulbs, fans, etc. The earth wire, which has insulation of green colour, is usually connected to a metal plate deep in the earth near the house. This is used as a safety measure, especially for those appliances that have a metallic body, for example, electric press, toaster, table fan, refrigerator, etc. The metallic body is connected to the earth wire, which provides a low-resistance conducting path for the current. 

Determine the power in 2 hours in an electric motor which takes $5  A$ from $220  V$.

  1. $2200 W$

  2. $1100 W$

  3. $500 W$

  4. $1000 W$


Correct Option: B
Explanation:

$P = VI$
  $= 220 \times 5 = 1100  W$.

A transformer is used to light $100\ W - 110\ V$ lamp from $220\ V$ mains. If the main current is $0.5\ A$, the efficiency of the transformer is

  1. $90$%

  2. $95$%

  3. $96$%

  4. $99$%


Correct Option: A
Explanation:

Voltage in primary coil     $V _p = 220$ V

Current in primary coil    $I _p = 0.5$ A
Thus input power     $P _{in} = V _pI _p$
Output power  (in secondary coil )      $P _{out} = 100$ W
$\therefore$  Efficiency of transformer     $\eta = \dfrac{P _{out}}{P _{in}}\times 100$
$\implies   $        $\eta = \dfrac{100}{(220)(0.5)}\times 100 = 90$ %.

Why is parallel arrangement used in domestic wiring?

  1. For getting same potential difference across each electrical appliance.

  2. For getting different potential difference across each electrical appliance.

  3. For getting high potential difference across each electrical appliance.

  4. For getting low potential difference across each electrical appliance.


Correct Option: A
Explanation:

The usage of parallel arrangement in domestic circuits has many advantages.

  • Each circuit will have the same potential difference which is equal to  the potential difference of the supply line. As a result, each electrical appliance will work under constant voltage.
  • When two or more appliances are used at the same time, each appliance will be able to draw the current as needed. The appliances having low resistance will draw higher current and vice versa.
  • When distribution circuits are in parallel, then each circuit operates separately. So, if one of the distribution circuits gets overloaded, only the fuse in that circuit will be blown off. The other distribution circuits will remain unaffected.

The most important safety method used for protecting home appliances from short circuiting or overloading is

  1. earthing.

  2. use of fuse.

  3. use of stabilizers.

  4. use of electric meter.


Correct Option: B
Explanation:

Answer is B

Fuses are safety devices that are to be built into our electrical system. If there were no fuses and we operated too many appliances on a single circuit, the cable carrying the power for that circuit would get extremely hot, short circuit, and possibly start a fire. To prevent electrical overloads, fuses are designed to trip or blow, stopping the flow of current to the overloaded cable.

Fuse is a piece of wire of a material with a very low melting point. When a high current flow through the circuit due to overloading or short circuit, the wires gets heated and melts. As a result, the circuit is broken and current stops flowing.

The fuse must always be connected to the mains and it must be of correct value. For example, a 15-ampere fuse should trip when the current through it exceeds 15 amperes. A 20-ampere fuse should blow when the current through it exceeds 20 amps.

The resistance of hot turngsten filament is about $10$ times the cold resistance. What will  be the resistance of $100W$ and $200V$ lamp when not in use

  1. $40\Omega $

  2. $20\Omega $

  3. $400\Omega $

  4. $200\Omega $


Correct Option: A
Explanation:

Given,

$P= 100W$
$V= 200V$
${ R } _{hot}= 10 \cdot { R } _{ cold }$
We know,
$ P= I \cdot V$
$ \rightarrow P= \cfrac{ V }{ R } \cdot { V }= { V }^{ 2 } \cdot R$
$ \therefore R= \cfrac{{ V }^{ 2 }}{P}$
where, 
$ P= $ Power
$ I = $ Current
$ R = $ Resistance
$ V =$ Voltage
$ { R } _{ hot }= $ Hot Resistance
${ R } _{ cold }=$ Cold Resistance
So, $ { R } _{ hot}= \cfrac {200 \cdot 200}{ 100}= 400 \Omega$
${ R } _{ cold }= \cfrac{{ R } _{ hot }}{ 10 }= \cfrac{ 400 }{ 10 }= 40 \Omega $
$\Rightarrow { R } _{ cold }= 40 \Omega$
$ 40 \Omega $ will be the resistance of $100W$ and $200V$ lamp when not in use.

The armature current in D.C motor is maximum when the motor has -


  1. picked up maximum speed

  2. just started

  3. intermediate speed

  4. just been switched off


Correct Option: A

The line that draws power supply to your house from Street has

  1. $220\sqrt{2}$ average voltage.

  2. 220 V average voltage

  3. voltage and current Out of phase by $\pi/2$

  4. voltage and current possibly differing in phase $\phi$ such that $| \phi| < \dfrac{\pi}{2}.$


Correct Option: D
Explanation:

As the line has some resistance $(R \, \neq \, 0)$. Also, line that draws power supply has some inductance and capacitance, hence voltage and current differ in phase $\phi$ such that $|\phi| \, < \, \dfrac{\pi}{2}$.

Which arrangement is used for domestic circuits ?

  1. Series

  2. Parallel

  3. Series and parallel both

  4. None


Correct Option: B
Explanation:

For Domestic circuits parallel arrangement is always used because:

  1. In parallel circuits, if one electrical appliance stop working due to some effect then all other appliances keep working normally.
  2. In parallel circuit, each electrical appliance has own switch due to which it can be turn off or on independently, without effecting  other appliances.
  3. In parallel circuits, each electrical appliance gets same voltage as that of the power supply line.
  4. In the parallel connection of electrical appliances, the overall resistance of the house hold circuit is reduced due to which the current from the power supply is high.

If the length of filament of a heater is reduced by  10%, the power of the heater will 

  1. increase by about 9%

  2. increase by about 11%

  3. increase by about 19%

  4. increase by about 10%


Correct Option: D
Explanation:

$P=\dfrac { { V }^{ 2 } }{ R } \ R=\dfrac { \rho l }{ A } \ \therefore P=\dfrac { { V }^{ 2 }A }{ \rho l } $

$ \therefore P\alpha \dfrac { 1 }{ l } \quad $ [Keep in $\dfrac{v^2A}{\rho }$ constant]
$\therefore$ with reduction of $l$ by $10\%$ power will increase by $10\%$.

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