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Drying and dehydrating agents - class-XI

Description: drying and dehydrating agents
Number of Questions: 60
Created by:
Tags: chemistry chemical equilibrium and acids-bases water equilibrium
Attempted 0/60 Correct 0 Score 0

${ H } _{ 3 }{ PO } _{ 4 }$ is a tribasic acid and one of its salt is ${ NaH } _{ 2 }{ PO } _{ 4 }$ What volume of $1M\quad NaOH$ solution should be added to $12g\ { NaH } _{ 2 }{ PO } _{ 4 }$ to convert it into ${ Na } _{ 3 }{ PO } _{ 4 }$? ($at.wt$ of $P=31$)

  1. $100\ ml$

  2. $200\ ml$

  3. $80\ ml$

  4. $300\ ml$


Correct Option: B
Explanation:

$Na{ H } _{ 2 }{ PO } _{ 4 }+NaOH\rightarrow { Na } _{ 2 }{ HPO } _{ 4 }+{ H } _{ 2 }O\quad \quad -(i)$

Moles$=\cfrac { 12 }{ 120 } $    $\cfrac { 12 }{ 120 } $            $\cfrac { 12 }{ 120 } $
${ Na } _{ 2 }{ HPO } _{ 4 }+NaOH\rightarrow { Na } _{ 3 }{ PO } _{ 4 }+{ H } _{ 2 }O\quad \quad \quad -(ii)$
Moles$=\cfrac { 12 }{ 120 } $     $\cfrac { 12 }{ 120 } $           $\cfrac { 12 }{ 120 } $
Moles of $NaOH$ required $=\cfrac { 12 }{ 120 } +\cfrac { 12 }{ 120 } $
                                              $=0.2$ moles
Now, $Mularity=\cfrac { Moles }{ Vol.of\quad sol\quad in\quad ltrs } $
$\therefore $ Volume of $NaOH$ solution $=\cfrac { 0.2 }{ 1 } $
                                                  $=0.2$ litres
                                                  $=200$ml

The $K _{sp}$ of $Ag _{2}CrO _{4}, AgCl, AgBr$ and $AgI$ are respectively, $1.1\times 10^{-12}$, $1.8\times 10^{-10}$, $5.0\times 10^{-13}$ and $8.3\times 10^{-17}$. Which of the following salts will precipitate last if $AgNO _{3}$ solution is added to the solution containing equal moles of $NaCl, NaBr, NaI$ and $Na _{2}CrO _{4}$?

  1. $Ag _{2}CrO _{4}$

  2. $AgI$

  3. $AgCl$

  4. $AgBr$


Correct Option: A
Explanation:
  1. $Ag _2CrO _4\rightleftharpoons 2Ag^++{CrO _4}^{2-}$

    $Ksp=(2s)^2\times s=4s^2$

    $Ksp=(1.1\times 10^{-12})$

    $S=3\sqrt {\cfrac {Ksp}{4}}=6.5\times 10^{-5}$M

    2. $AgCl\rightleftharpoons Ag^++Cl^-$

    $Ksp=S\times S$  ;       $Ksp=1.8\times 10^{-10}$

    $S=\sqrt {Ksp}=1.34\times 10^{-5}$M

    3. $AgBr\rightleftharpoons Ag^++Br^-$

    $Ksp=S\times S$ ;     $Ksp=5\times 10^{-13}$

    $S=\sqrt {Ksp}=0.71 \times 10^{-6}$M

    4. $AgI\rightleftharpoons Ag^++I^-$

    $Ksp=S\times S$  ;    $Ksp=8.3\times 10^{-17}$

    $S=\sqrt{Ksp}=0.9\times 10^{-8}$M

    $\therefore$ Solubility of $Ag _2CrO _4$ is highest, so it will precipitate last.

Dissolution of salt participate in water shows:

  1. Particulate nature of matter.

  2. Continuous nature of matter.

  3. Particle size of salt is very big.

  4. All of these.


Correct Option: A
Explanation:

The salt will dissolve and water will taste salty. Salt particles dissolve in water because they occupy the spaces between the water molecules resulting in spreading of salt particles throughout the particles of water showing particle nature of matter.

An aqueous solution of zinc sulphate is acidic in nature because______.


  1. $ZnSO _{4}$ ionizes

  2. $SO _{4}^{-2}$ reacts with $H _{2}O$

  3. $Zn^{+2}$ reacts with $H _{2}O$

  4. $Zn^{+2}$ & $SO^{-2} _{4}$ reacts with $H _{2}O$


Correct Option: D

KMnO$ _4$ oxidises X$^{n+}$ ion to XO$^- _3$ itself changing into Mn$^{+2}$ in acid solution. $2.68$ $\times$ $10^{-3}$ mole of X$^{n+}$ requires $1.61$ $\times$ $10^{-3}$ mole of MnO$ _4^-$. The value of n is :

  1. $1$

  2. $2$

  3. $4$

  4. $3$


Correct Option: B

Which of the following does not undergo hydrolysis?

  1. $BF _3$

  2. $NaCl _3$

  3. $NF _3$

  4. All of these


Correct Option: C
Explanation:
$(C)\ NF _{3}$
Because it does not have any vacant orbitals to accept lone pair 
$\therefore $ do not under go nudolysis.






Solution of $ FeCI _3 $ and $ H _2O $ is :

  1. Basic

  2. Acidic

  3. Neutral

  4. None of these


Correct Option: B

Salt which on heating produces a mixture of two gases is :

  1. $NaNO3$

  2. $Bi(NO3)3$

  3. $Pb(NO3)2$

  4. $NH4NO3$


Correct Option: A

The mass in grams of potassium permanganate (MM = 158) crystals required to oxidise $750\,\,c{m^3}$ of 0.1 M Mohr's salt solution in acidic medium is about 

  1. 11.8

  2. 5.8

  3. 6.0

  4. 2.4


Correct Option: A

Degree of hydrolysis for a salt of weak acid and strong base can be changed by 

  1. Increasing concentration of salt

  2. Increasing temperature

  3. Adding base

  4. All of these


Correct Option: D

Chloride which is insoluble in water is :

  1. sodium chloride

  2. potassium chloride

  3. mercurous chloride

  4. calcium chloride


Correct Option: C
Explanation:

Chloride salts include sodium chloride (common salt), potassium chloride, calcium chloride, and ammonium chloride. Most chloride salts are readily soluble in water, but mercurous chloride (calomel) and silver chloride are insoluble, and lead chloride is only slightly soluble.

Does $Mg(OH) _2$ react with sodium hydroxide?

  1. True

  2. False


Correct Option: B
Explanation:

A universal indicator is a pH indicator composed of a solution of several compounds that exhibits smooth colour changes over a pH value range from 1-14 to indicate the acidity or alkalinity of solutions. Two basic hydroxides do not react with each other as these are bases but not alkali.

$NaCl + H _2SO _4\overset{\Delta}{\longrightarrow}HCl \ +$

  1. $NaHSO _4$

  2. $Na _2SO4$

  3. $Na _2SO _3$

  4. none of the above


Correct Option: A
Explanation:

Reacting sodium chloride and sulphuric acid at elevated temperature leads to production of sodium bisulphate and hydrogen chloride. Little amount of sodium sulphate is also formed which reacts with the sulphuric acid to yield sodium bisulphate or sodium hydrogen sulphate.
$NaCl\left( s \right) +{ H } _{ 2 }{ SO } _{ 4 }\rightarrow { NaHSO } _{ 4 }\left( s \right) +HCl$

Identify the correct representation of reaction occurring during chloro-alkali process. 

  1. $2NaCl(l)+ 2H _2O(l) \rightarrow 2NaOH(l) + Cl _2(g) + H _2(g)$

  2. $2NaCl(s)+ 2H _2O(aq) \rightarrow 2NaOH(aq) + Cl _2(g) + H _2(g)$

  3. $2NaCl(aq)+ 2H _2O(l) \rightarrow 2NaOH(aq) + Cl _2(aq) + H _2(aq)$

  4. $2NaCl(aq)+ 2H _2O(l) \rightarrow 2NaOH(aq) + Cl _2(g) + H _2(g)$


Correct Option: D
Explanation:

Chloro-alkali process is an industrial process for the electrolysis of sodium chloride. It is used to produce chlorine and sodium hydroxide. Aqueous sodium chloride or brine ina membrane cell.


At cathode: ${ 2H } _{ 2 }O+2{ e }^{ - }\rightarrow { H } _{ 2 }+{ 2OH }^{ - }$ 

At anode: $2{ Cl }^{ - }\rightarrow { Cl } _{ 2 }+2{ e }^{ - }$ 


$2NaCl(aq)+2{ H } _{ 2 }O\rightarrow { Cl } _{ 2 }(g)+{ H } _{ 2 }(g)+2NaOH(aq)$


Option $(D)$ suggests the correct reaction.

Addition of large quantity of Iron salt will coagulate blood.

  1. True

  2. False


Correct Option: A
Explanation:
Addition of large quantity of Iron salt will coagulate blood. A trivalent iron (ferric ions) generates hydroxyl radicals, which subsequently form soluble plasma fibrinogen (FBG) into an insoluble fibrin clot.

The chemical that changes its colour when it is left open in sunlight is:

  1. $FeSO _4\, (s)$

  2. $Pb(NO _3) _2\, (s)$

  3. $AgCl\, (s)$

  4. $BaCl _2\, (aq)$


Correct Option: C
Explanation:

$AgCl\, (s)$ colors changes when exposed in sunlight.

Which of the following salts when dissolved in water would give acidic solution(s)?

  1. $Na _2SO _4$

  2. $(NH _4) _2SO _4$

  3. $CH _3COONa$

  4. $KCI$


Correct Option: B
Explanation:

Ammonium sulfate reacts with water to form sulfuric acid which is highly acidic in nature as it completely dissociates to give hydrogen ions.

What are the products formed when an aqueous solution of magnesium bicarbonate is boiled?

  1. $MgCO _3,\, H _2O,\, CO _2$

  2. $Mg(HCO _3) _2,\, H _2O$

  3. $Mg(OH) _2,\, H _2O$

  4. $Mg,\, CO _2,\, H _2O$


Correct Option: A
Explanation:

When magnesium bicarbonate is boiled $MgCO _3, H _2O$ and $CO _2$ are formed. A small amount of $Mg(OH) _2$ is also formed.

Reaction: $Mg(HCO _ 3) _2\xrightarrow[\Delta]{} MgCO _ 3+H _ 2O+CO _ 2+Mg(OH) _ 2$

Which of the following salts on heating gives a mixture of two gases?

  1. $Ba(NO _3) _2$

  2. $NaNO _3$

  3. $KNO _3$

  4. $RbNO _3$


Correct Option: A
Explanation:

$(A)$  $Ba(NO _3) _2$


$Reason$ :  The elements in the group 2 includes beryllium($Be$), magnesium($Mg$), calcium($Ca$), strontium($Sr$), barium($Ba$) and radium($Ra$).
The group 2 nitrates, on heating, gives metal oxide, nitrogen dioxide and oxygen gas.
For example - $2Ba(NO _3) _2(s)$ $\rightarrow$ $2BaO(s)$ + $4NO _2(g)$ + $O _2(g)$
Group 2 nitrates also become more thermally stable down the group. 

When hydrated $MgCl _2.\, 6H _2O$ is strongly heated:

  1. $MgO$ is formed

  2. $Mg(OH) _2$ is formed

  3. $Mg(OH)Cl$ is formed

  4. Ahydrous $MgCl _2$ is formed


Correct Option: A
Explanation:

Magnesium hydrochloride is hygroscopic in nature and it loses its water molecules with the formation of magnesium oxide. When mixed with hydrated magnesium oxide, magnesium chloride forms a hard material called Sorel cement.

The correct order of pH is

  1. Lemon juice < water < Milk of Magnesia

  2. Lemon juice> water> Milk of Magnesia

  3. Water > lemon juice > milk of Magnesia

  4. Milk of Magnesia > lemon juice > water


Correct Option: A
Explanation:

Milk of magnesia is basic, water is neutral and lemon juice is acidic in nature.

A salt derived from strong acid and weak base will dissolve in water to give a solution which is :

  1. acidic

  2. basic

  3. neutral

  4. none of the above


Correct Option: A
Explanation:

In neutralization reaction the strong acid with weak base reaction the solution becomes acidic in nature as the salt formed in it alongwith water.

Which of the following properties of a solution of $NaCl$ will not vary as the concentration of salt is increased?

  1. $pH$

  2. Density

  3. Refractive index

  4. Electrical conductivity


Correct Option: C
Explanation:

The presence of salts influences most physical properties of sea water (density, compressibility, freezing point, temperature of the density maximum) to some degree but does not determine them. Some properties (viscosity, light absorbtion,refractive index) are not significantly affected by salinity. (Particle and dissolved matter do affect light absorption in sea water and this influence is used in most optical applications.) Two properties which are determined by the amount of salt in the sea are conductivity and osmotic pressure.

If a salt after rubbing with fingers gives the smell of ammonia, then the salt is:

  1. ammonium chloride

  2. sodium carbonate

  3. calcium carbonate

  4. lead sulphide


Correct Option: A
Explanation:

If a salt after rubbing with fingers, gives the smell of ammonia, then the salt may be ammonium chloride.
After rubbing, due to warming, ammonium chloride may decompose to give ammonia and hydrogen chloride.
$\displaystyle NH _4Cl \xrightarrow {warm} NH _3 + HCl$

The phenomenon of crumbling to powder of sodium carbonate crystals on exposure to air is known as :

  1. deliquescence

  2. isomorphism

  3. efflorescence

  4. none of the above


Correct Option: C
Explanation:

The phenomenon of crumbling to a powder of sodium carbonate crystals on exposure to air is known as efflorescence.

Many salts absorb water from the atmosphere. This property is called :

  1. hydration

  2. dehydration

  3. deliquescence

  4. efflorescence


Correct Option: C
Explanation:

Deliquescent salts have strong affinity for moisture and become liquid by absorbing moisture from air. It is hygroscopic in nature e.g. calcium chloride, zinc chloride,magnesium chloride,sodium hydroxide.

Which one of the following substance will be most suitable for cutting a very hard material?

  1. Silicon carbide

  2. Lead

  3. Zinc metal

  4. Sodium chloride crystal


Correct Option: A
Explanation:
Silicon carbide is most suitable for cutting a very hard material.
In manufacturing processes it is used for its hardness in abrasive machining processes such as grinding, honing, water-jet cutting and sandblasting.

Which of the  following methods is not used for preparing a salt?

  1. Reaction between an acid and a base

  2. Action of acid on metals

  3. Action of acid on metal oxides

  4. Dissolution of acids in water


Correct Option: D
Explanation:

If acid is added to water the solution that forms is very dilute and small amount of heat is released so this reaction does not produce any salt.

Which of the following salt gets hydrolyzed in aqueous solution? A salt of :

  1. weak acid and weak base

  2. strong acid and weak base

  3. weak acid and strong base

  4. all of the above


Correct Option: D
Explanation:

Common kind of hydrolysis occurs when a salt of a weak acid or or weak base or both is dissolved in water. Water spontaneously ionizes into hydroxide anions and hydronium cations. The salt also dissociates into its constituent anions and cations.

Aqueous solution of sodium acetate is :

  1. neutral

  2. weakly acidic

  3. strongly acidic

  4. alkaline


Correct Option: D
Explanation:

Sodium acetate is the sodium salt of acetic acid. Acetic acid reacts with sodium carbonate or sodium hydroxide to form a basic solution of sodium acetate which acts as buffer with acetic acid.

Which of the following salt gets hydrolyzed in aqueous solution? 

  1. A salt of weak acid and weak base

  2. A salt of strong acid and weak base

  3. A salt of weak acid and strong base

  4. All of the above


Correct Option: D
Explanation:
Salts, when placed in water, will often react with the water to produce $H _{3}O^+$ or $OH^-$.This is known as a hydrolysis reaction.
A salt can be made of either a weak acid and strong base(i.e., basic salt), strong acid and weak base(i.e., acid salt), or a weak acid and weak base(i.e., either neutral, acidic or basic) gets hydrolyzed in aqueous solution.

A solution of sodium chloride will:

  1. turn red litmus blue

  2. turn blue litmus red

  3. turn red litmus orange

  4. not change the colour of either red or blue litmus


Correct Option: D
Explanation:

Litmus paper can be used as an indicator to know whether a given substance is acidic, basic or neutral in nature.

Acidic substances turn blue litmus paper red but they have no effect on the red litmus paper.
Basic substances turn red litmus paper blue but have no effect on the blue litmus paper.
On the other hand, neutral substances have no effect on the blue as well as the red litmus paper.
Hence, the correct answer is option (D).

All  salts  are:

  1. strong electrolytes

  2. weak electrolytes

  3. non electrolytes

  4. either weak or strong electrolyte


Correct Option: A
Explanation:
As, substances that give ions when dissolved in water are called $electrolytes$.They can be divided into acids, bases and salts, because they all give ions when dissolve in water. 
$Strong$ $electrolytes$ completely ionize when dissolve in water, and no neutral molecules are formed in solution.
Example - $NaCl$, $HNO _{3}$ etc.

As we know, chemically, a salt is an ionic compound as it is composed of two oppositely charged ions - cation and anion. Due to the presence of ions, they are good conductors of heat and electricity in a molten state and in solutions.
So, all salts are strong electrolytes as they completely dissolve in water and dissociates into their component ions.

Hence, option $A$ is correct.

The loss of water of crystallization to the atmosphere by a compound is termed:

  1. deliquescence

  2. dehydration

  3. efflorescence

  4. hydrolysis


Correct Option: C
Explanation:

Efflorescence, spontaneous loss of water by a hydrated salt,  which occurs when the aqueous vapor pressure of the hydrate is greater than the partial pressure of the water vapour in the air. 

An aqueous solution of a salt of a weak base and a strong acid is acidic, because of:

  1. electrolysis

  2. hydrolysis

  3. dissociation

  4. none of these


Correct Option: B
Explanation:

In neutralization reaction weak base reacts with strong acid to give salt of strong acidic solution and water.

${ NH } _{ 4 }OH+{ H } _{ 2 }{ SO } _{ 4 }\rightarrow \left( { NH } _{ 4 } \right) _{ 2 }{ SO } _{ 4 }+{ H } _{ 2 }O$

Aqueous solution of which of the following salts turns the red litmus blue?

  1. $Na _2CO _3$

  2. $NaHCO _3$

  3. $Na _2CO _3\cdot 10H _2O$

  4. All of these


Correct Option: D
Explanation:

Sodium carbonate and sodium bicarbonate are basic salts which turn red litmus blue as they are alkaline in nature having pH more than 7.

A salt is a general name given to the chemical produced during _______ reaction between an acid and a base

  1. decomposition

  2. neutralization

  3. displacement

  4. double decomposition


Correct Option: B
Explanation:

A salt is a general name given to the chemical produced during the neutralization reaction between an acid and a base.

Sea water contains about 24g of salts dissolved per litre of it.

  1. True

  2. False


Correct Option: B
Explanation:

Approximately for every litre of seawater there is $35$ $g$ of salt.

Salts are naturally found in seawater and salts are formed in the neutralization reaction.

Which of the following are efflorescent substances?

  1. $Cu{SO} _{4}.5{H} _{2}O$

  2. ${Na} _{2}{CO} _{3}.10{H} _{2}O$

  3. ${K} _{2}{SO} _{4}.{Al} _{2}{({SO} _{4})} _{3}.24{H} _{2}O$

  4. ${({NH} _{4})} _{2}{SO} _{4}$


Correct Option: A,B
Explanation:

An efflorescent substance is a chemical which has water associated with its molecules, and which, when exposed to air, loses this water through evaporation. An example of an efflorescent substance is the common copper(II) sulfate crystal $(CuSO _4.5H _2O)$, a blue crystalline solid that when exposed to air, slowly loses water of crystallization from its surface to crystallize to form a white layer of anhydrous copper(II) sulfate.


$Na _2CO _3.10H _2O$ loses 9 water molecules first and then becomes completely anhydrous. 

${K} _{2}{SO} _{4}.{Al} _{2}{({SO} _{4})} _{3}.24{H} _{2}O$ is not an efflorescent as its crystals do not lose water of crystallization by efflorescence nor it is oxidised in the air. ${({NH} _{4})} _{2}{SO} _{4}$ do not has associated water molecules.

Which of the following is deliquescent?

  1. $ZnCl _2$

  2. $Hg _2Cl _2$

  3. $HgCl _2$

  4. $CdCl _2$


Correct Option: A
Explanation:

$(A)$  $ZnCl _{2}$


$Reason$ : Zinc chloride is a chemical compound with the formula $ZnCl _{2}$ and its hydrates.All zinc chlorides are colourless or white and highly soluble in water.Zinc chloride or $ZnCl _{2}$ is a $deliquescent$ salt  and forms acidic solutions in polar organic solvents,such as water, ether and acetone etc.
As we know, $deliquescent$ substances are the water soluble substances which absorbs moisture from the air and then dissolve in the absorbed moisture to change into liquid state and this phenomenon is called $deliquescence$.$ZnCl _{2}$ is one of the example of $deliquescent$ substance.

$Na _2CO _3.10H _2O \longrightarrow Na _2CO _3.H _2O$

The given reaction is an example of:

  1. efflorescent substance

  2. deliquescent substance

  3. hygroscopic substance

  4. none of the above


Correct Option: A
Explanation:

In this reaction water is being released. This type of substance is known as efflorescent substance.

If there are three moles of $H _2O$ for every one mole of $LiClO _4$, what is the hydrate formula?

  1. $\displaystyle LiClO _4 \cdot 3H _2O $

  2. $\displaystyle 3LiClO _4 \cdot 3H _2O $

  3. $\displaystyle 3LiClO _4 \cdot H _2O $

  4. $\displaystyle LiClO _4 \cdot (H _2O) _3 $

  5. $\displaystyle 3(LiClO _4) \cdot 3(H _2O) _3 $


Correct Option: A
Explanation:

If there are three moles of $H _2O$ for every one mole of $\displaystyle LiClO _4$. The hydrate formula would be $\displaystyle LiClO _4 \cdot 3H _2O $

$Cu(s)+HNO _3(aq)\rightarrow Cu(NO _3) _2(aq)+H _2O(l)+NO(g)$ 

If $Cu(NO _3) _2$ goes into solution as ions, find the number of ions into which it will dissociate?

  1. $1$

  2. $2$

  3. $3$

  4. $4$

  5. $5$


Correct Option: C

 A student is performing an experiment where a blue salt is being heated to dryness in order to determine the percent of water in the salt. Which pieces of laboratory equipment would be used to help determine this percentage?
 i. A crucible and cover
 ii. Tongs
iii. A triple beam balance 

  1. ii only

  2. iii only

  3. i and iii only

  4. ii and iii only

  5. i. ii and iii


Correct Option: E
Explanation:

In this experiment, a known mass of hydrated copper(II) sulfate is heated to remove the water of crystallization and then weigh into it between 2 g and 3 g of hydrated copper(II) sulphate.A deep blue copper compound is made white through the addition of heat.So the apparatus needed is crucible,cover,tongs and triple beam balance.

Find the substances which dissociate completely when placed into excess amounts of distilled water? 
  1. $C _2H _5OH$

  2. $HCOOH$

  3. $LiNO _3$

  4. $Mg(OH) _2$

  5. All of the above


Correct Option: C
Explanation:

Lithium nitrate, $\displaystyle LiNO _3$  dissociates completely when placed into excess amounts of distilled water.
It is a strong electrolyte.
$\displaystyle LiNO _3 \rightarrow Li^+  +  NO _3^-$

The type of bonding present in a substance can be determined from experimental data.
Based on the information in the table below, which of the following substances is MOST likely to represent the identity of the solid?

Melting Point Density Conductivity Conductivity in Aqueous Solution
$801^{\circ}C$ $2.17\ g/cc$ None Excellent
  1. Platinum, $Pt$

  2. Sodium chloride, $NaCl$

  3. Glucose, $C _{6}H _{12}O _{6}$

  4. Quartz, $SiO _{2}$


Correct Option: B
Explanation:

$(B)$  Sodium chloride, $NaCl$


$Reason$ : Sodium chloride is an ionic compound with the chemical formula $NaCl$, in which sodium(cation) $Na^{+}$ and chloride(anion) $Cl^{-}$ ions are in the ratio $ 1 : 1 $.It is commonly known as table salt, common salt or halite. Seawater is the major source of this salt.
Some properties of sodium chloride are as follows - 
$1)$ It is easily soluble in water and partially or insoluble in other liquids.
$2)$ They are white crystals with a desity of $2.17 g/cc$, which do not have an odor but possess a taste.
$3)$ In its aqueous state $NaCl$ acts as a good conductor of electricity due to the free movement of ions.
$4)$ It has a melting point of $801^{o} C$ and a boilng point of $1,413 ^{o} C$.
$Uses$ :
$1)$ This salt is used in glass production.
$2)$ It is widely used in food industries as a food preservative and as a flavour enhancer.

Identify the correct representation of reaction occurring during chloralkali process.

  1. $2NaCl(l) + 2H _{2}O(l) \rightarrow   2NaOH(l) + Cl _{2}(g) + H _{2}(g)$

  2. $2NaCl(aq) + 2H _{2}O(aq) \rightarrow 2NaOH(aq) + Cl _{2}(g) + H _{2}(g)$

  3. $2NaCl(aq) + 2H _{2}O(l)\rightarrow  2NaOH(aq) + Cl _{2}(aq) + H _{2}(aq)$

  4. $2NaCl (aq) + 2H _{2}O (l)\rightarrow   2NaOH (aq) + Cl _{2}(g) + H _{2}(g)$


Correct Option: D
Explanation:

Sodium chloride in water is a brine solution which gives sodium hydroxide in aqueous solution and hydrogen and chlorine gases. It is known as chloralkali process. It is an industrial process for the electyrolysis of sodium chloride. It is the technology which is used to produce chlorine and caustic soda(sodium hydroxide) on commercial scale.

Which hydrolysis results in basic solution?

  1. Neutralisation reaction

  2. Weak acid

  3. Strong acid

  4. Weak base


Correct Option: B
Explanation:

Base hydrolysis results in basic solution.

A base hydrolysis reaction will resemble the reaction for base dissociation. A common weak base that dissociates in water is ammonia:

$NH _3 + H _2O \rightarrow NH^{4+} + OH^-$

In the hydrolysis of ammonia, the ammonia molecule accepts a proton from the water (because water acts as a Bronsted-Lowry acid), producing a hydroxide anion ($OH^-$). Similar to a basic dissociation reaction, ammonia forms ammonium and a hydroxide from the addition a water molecule. 

State True or False.
$NH _{4}Cl$ when dissolved in water undergoes anionic hydrolysis.

  1. True

  2. False


Correct Option: B
Explanation:

$NH _4Cl $ when dissolved in water undergoes cationic hydrolysis as follows: 
$NH _4Cl $ $\rightarrow $ $NH _4 ^+ + Cl^- $
Ammonium ion being a strong acid takes $OH^- $ ions furnished by water as : 
$NH _4^+ + H _2O \rightarrow NH _4OH\  (freely\  ionized) + H^+ $
Thus concentration of $OH^-$ ions decreases and that of $H^+ $ ion increases due to cationic hydrolysis and consequently the solution become acidic in nature. 

Which of the following substances can be used for drying gases?

  1. Calcium carbonate

  2. Sodium carbonate

  3. Sodium bicarbonate

  4. Calcium oxide


Correct Option: D
Explanation:

Calcium oxide $(CaO)$ absorbs moisture and hence, can be used for drying gases.

Hydrolysis of salts is reverse of :

  1. neutralisation

  2. dehydration

  3. hydration

  4. acidification


Correct Option: A
Explanation:

Hydrolysis of salts is reverse of neutralisation reaction.

The number of ions formed when cupraic ammonium sulphate is dissolved in water is_______.

  1. one

  2. four

  3. two

  4. zero


Correct Option: C
Explanation:

$Cu[(NH _3) _4]SO _4 \rightarrow Cu[(NH _3) _4]^{2+} + SO _4^{2-}$

From the above given reaction, you can see that the number of ions obtained are two.

An aqueous solution of a salt of a weak base and a strong acid is acidic because of:

  1. electrolysis

  2. hydrolysis

  3. dissociation

  4. none of the above


Correct Option: B
Explanation:

A salt of strong acid and weak base undergo hydrolysis on action with water and flourishes $H^{+}$ ion due to hydrolysis of cation. Hence, an aqueous solution of a salt of a weak base and a strong acid is acidic.

Which of the following salts can produce only two types of radicals?

  1. $NaKCO _3$

  2. $CaOCl _2$

  3. $NH _4HSO _4$

  4. $Na(NH _4)HPO _4$


Correct Option: C
Explanation:

$NaKCO _3\rightarrow Na^++K^++CO _{3}^{-2}$
$CaOCl _2\rightarrow Ca^{+2}+OCl^-+Cl^-$
$NH _4HSO _4\rightarrow NH _{4}^{+}+HSO _{4}^{-}$
(2 types of radicals)
$Na(NH _4)HPO _4\rightarrow Na^++NH _{4}^{+}+HPO _{4}^{-}$

The hydrated salt $Na _{2}SO _{4}, 10H _{2}O$ undergoes $X\%$ loss in weight on heating and becomes anhydrous. The value of $X$ will be:

  1. $10$

  2. $45$

  3. $56$

  4. $70$


Correct Option: C
Explanation:

Molecular mass of $Na _2SO _410H _2O=2\times23+32+16\times14+1\times20=322$


On heating the $Na _2SO _410H _2O$ it becomes anhydrous that means 10 $H _2O$ molecules separated

Molecular mass of $10H _2O=20\times1+10\times16=180$

% loss $=\dfrac{180}{322}\times100=55.9$ % $ =56$ %

Which of the following salts will have maximum cooling effect when $0.5$ mole of the salt is dissolved in same amount of water. Integral heat of solution at $298\ K$ is given for each salt.

  1. $KNO _{3}  (\Delta =35.4\ kJ\ mol^{-1})$

  2. $NaCl  (\Delta =5.35\ kJ\ mol^{-1})$

  3. $HBr  (\Delta =83.3\ kJ\ mol^{-1})$

  4. $KOH  (\Delta =55.6\ kJ\ mol^{-1})$


Correct Option: A
Explanation:

More the heat absorbed, more will be the cooling effect. Hence more the positive value of $\Delta H$ more the cooling effect.In the given question KBr has $\Delta H =83.3 kJmol^-$ which is highest among all the gases.

The compound whose $0.1\space M$ solution is acidic:

  1. Ammonium formate

  2. Ammonium sulphate

  3. Ammonium chloride

  4. Sodium formate


Correct Option: B,C
Explanation:

Concept :-

  A compound will be acidic if it form strong acidic solution after dissolving in water.
A. $HCOONH _4 + H _2 O \rightarrow \underset{Weak \, acid}{HCOOH} + \underset{weak \, base}{NH _4OH}$

B. $(NH _4) _2 SO _4 + 2H _2 O \rightarrow \rightarrow \underset{Strong \, acid}{H _2SO _4} + \underset{Weak\, base}{2NH _4OH}$

C. $NH _4 Cl + H _2O \rightarrow \underset{Weak \, base}{NH _4 OH} + \underset{Strong \, acid}{HCl}$

D. $HCO\overset{-}{O}N\overset{+}{a} + H _2O \rightarrow \underset{Strong \, base}{NaOH} + \underset{Weak \ acid}{HCOOH}$

During the preparation of hydrogen chloride gas on a humid day, the gas is usually passed through two guard tube containing calcium chloride. The role of calcium chloride in the guard tube is:

  1. it absorbs the evolved gas

  2. it moisten the gas

  3. it absorbs moisture from the gas

  4. it absorbs $Cl^-$ ions form the gas evolved


Correct Option: C
Explanation:

Calcium chloride is hygroscopic in nature and its anhydrous salt is deliquescent and it can accumulate enough water in its crystal lattice to form a solution. It is used as a drying agent to absorb moisture from the environment.

$MgC{l} _{2}$ and $NaCl$ are both salts that are used to treat roads. Which salt will have the greatest effect on the freezing point and why?

  1. NaCl because i = 2

  2. MgCl2 because i = 3

  3. MgCl2 because i = 2

  4. NaCl because i = 3

  5. Both salts would have the same effect


Correct Option: B
Explanation:

Addition of salt on roads is used to melt the ice, as this causes the lowering of the freezing point of the ice. Hence, freezing point of the ice due to the addition of the salt decreases the freezing point lesser than the $0^oC$.
Which can not be obtained easily , hence ice melts.
Now , as per formula
$ \Delta T _f = i k _f m$
Here , $i = $Vant Hoff's Factor.
which depends upon the number of dissociated ions, more the ions are dissociated from a single formula unit, more will be value of the $i$.
and $i \propto \Delta T _f$
hence , this means higher the value of $i$ , more will be lowering of the freezing point.
So here the (B) $MgCl _2$ is used , which has $i = 3$.

A sodium salt on treatment with ${MgCl} _{2}$ gives white precipitate only on heating. The anion of the sodium salt is:

  1. $ { HCO } _{ 3 }^{ - }$

  2. $ { CO } _{ 3 }^{ 2- }$

  3. $ { NO } _{ 3 }^{ - }$

  4. $ { SO} _{ 4 }^{ 2- }$


Correct Option: A
Explanation:
The salt will be sodium bicarbonate and the anion is $HC{ O } _{ 3 }^{ \ominus  }$
When sodium bicarbonate react with $Mg{ Cl } _{ 2 }$ it produce Magnesium bicarbonate which is also soluble in water
But, on heating $Mg{ \left( HC{ O } _{ 3 } \right)  } _{ 2 }$ it produce $Mg\left( C{ O } _{ 3 } \right) $ which gives white precipitate
$Mg{ \left( HC{ O } _{ 3 } \right)  } _{ 2 }\rightarrow Mg\left( C{ O } _{ 3 } \right)+C{ O } _{ 2 }+{ H } _{ 2 }O$
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