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Study of compounds a. hydrogen chloride - class-X

Description: study of compounds a. hydrogen chloride
Number of Questions: 28
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Tags: study of compounds a. hydrogen chloride acids, bases and salts chemistry
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Select the correct statement among the following.

  1. Hydrogen chloride is prepared by passing chlorine gas through hot water

  2. Hydrogen chloride is produced by combination of moist hydrogen gas with chlorine in the presence of diffused sunlight

  3. Hydrogen chloride can't be produced in the dark

  4. Activated carbon is used as a catalyst in the synthesis of hydrogen chloride


Correct Option: B,D
Explanation:
Hydrogen chloride is produced by a combination of moist hydrogen gas with chlorine in the presence of diffused sunlight. The reaction should be maintained in diffused but not in direct sunlight as it is an explosive reaction. And not even in dark as it is very slow (negligible). Activated carbon is used as a catalyst in the synthesis of hydrogen chloride.
Hence, options $B$ and $D$ are correct.

Moist hydrogen gas combines with chlorine in the presence of diffused sunlight to form $HCl$. The catalyst used here is :

  1. oxygen.

  2. silica.

  3. alum.

  4. moisture.


Correct Option: D
Explanation:

Moisture acts as a catalyst in the formation of HCl gas.


It acclerates the reaction.

It provides a reacting medium to hydrogen and chlorine gas.

It increases the interaction between them.


Hence, the correct option is $D$.


The reaction equation of the preparation of $HCl$ by synthesis is given by:

  1. $NaCl + H _2SO _4 \rightarrow NaHSO _4+HCl$

  2. $NaHSO _4+NaCl \rightarrow HCl+NaSO _4$

  3. $H _2+Cl _2 \rightarrow 2HCl$

  4. None of these


Correct Option: C
Explanation:
In the chloralkali process, brine (mixture of sodium chloride and water) solution is electrolyzed producing chlorine (Cl$ _2$), sodium hydroxide, and hydrogen (H$ _2$):

2 NaCl + 2 H$ _2$O → Cl$ _2$ + 2 NaOH + H$ _2$

The pure chlorine gas can be combined with hydrogen to produce hydrogen chloride in the presence of UV light:

Cl$ _2$(g) + H$ _2$(g) → 2 HCl(g)

As the reaction is exothermic, the installation is called an HCl oven or HCl burner. The resulting hydrogen chloride gas is absorbed in deionized water, resulting in chemically pure hydrochloric acid. This reaction can give a very pure product, e.g. for use in the food industry.

Hence, the correct option is $\text{C}$

In the laboratory preparation of $HCl$, which of the following are preferred?

  1. Conc. $H _2SO _4$ as reactant

  2. Conc. $H _2SO _4$ as drying agent

  3. Temperature of reaction mixture below $200^0C$

  4. Use of activated carbon as catalyst


Correct Option: A,B,C
Explanation:

The laboratory preparation of $HCl$ includes dehydration of hydrochloric acid with sulphuric acid. It can also be generated by the reaction of sulphuric acid with sodium chloride. 


The reaction occurs at room temperature. Sulphuric acid acts as a reactant as well as a drying agent.

$NaCl+H _2SO _4 \rightarrow NaHSO _4+HCl$

Hence, the correct options are $\text{A}$, $\text{B}$ and $\text{C}$

Metal chloride + Sulphuric acid$\longrightarrow$.............. + Hydrogen chloride :

  1. Metallic sulphate

  2. Metallic bisulphate

  3. Metallic sulphide

  4. None of the above


Correct Option: C
Explanation:

Metal chloride reaction with sulphuric acid is a double displacement reaction which form a metallic sulphate.

For example :-
$Na _2SO _4$ formed when $NaCl$ reacts with $H _2SO _4$ as

$\underset{chloride}{\underset{metal}{2NaCl}} + \underset{acid}{\underset{sulphuric}{H _2SO _4}} \xrightarrow{\Delta} \underset{Sulphate}{\underset{metallic}{Na _2SO _4}} + \underset{chloride}{\underset{Hydrogen}{2HCl}}$

The reaction of moist hydrogen gas with chlorine is explosive in the presence of :

  1. hydrogen

  2. oxygen

  3. darkness

  4. direct sunlight


Correct Option: D
Explanation:

The reaction of chlorine with moist hydrogen gas is explosive in case of direct sunlight.

In dark no reaction will take place because for activation light is required.
Hence, $HCl$ is prepared in presence of diffused sunlight.

Drying agents used in the purification of hydrogen chloride is/are:

  1. conc. $H _2SO _4$

  2. $P _2O _5$

  3. $CaO$

  4. all of the above


Correct Option: A
Explanation:

Conc. $H _2SO _4$ is a very strong drying agent and it is used in purification of hydrogen chloride.

HCl can be prepared by:

  1. $NaCl$ + $H _{2}SO _{4}$$\overset{420K}\rightarrow$

  2. $NaHSO _{4}$ + $NaCl$ $\overset{823K}\rightarrow$

  3. $NaNO _3$ + $H _{2}SO _{4}$ $\rightarrow$

  4. both (A) and (B).


Correct Option: D
Explanation:
HCl can be prepared by following :

$NaCl$ + $H _{2}SO _{4}$$\overset{420K}\rightarrow NaHSO _4+HCl$

$NaHSO _{4}$ + $NaCl$ $\overset{823K}\rightarrow Na _2SO _4+HCl$.

Hence option D is correct.

In which reaction equilibrium moves in left hand side when pressure is increased?

  1. $H _{2(g)} + Cl _{2(g)} \rightleftharpoons 2HCl _{(g)}$

  2. $2Mg _{(s)} + O _{2(g)} \rightleftharpoons 2MgO _{(s)}$

  3. $2H _{2}O _{(g)} \rightleftharpoons 2H _{2(g)} + O _{2(g)}$

  4. $N _{2(g)} + 3H _{2(g)} \rightleftharpoons 2NH _{3(g)}$


Correct Option: C
Formation of $HCl$ from its elements takes place in the presence of sunlight.
  1. True

  2. False


Correct Option: A
Explanation:

Hydrogen chloride is prepared from chlorine gas and hydrogen gas in the presence of UV light. This reaction is exothermic and the resulting HCl gas is absorbed in deionized water.

${ H } _{ 2 }+{ Cl } _{ 2 }\rightarrow 2HCl$

The compound which does not have oxygen is :

  1. nitric acid

  2. sodium hydroxide

  3. hydrochloric acid

  4. acetic acid


Correct Option: C
Explanation:

Nitric acid $(HNO _3)$ has 3 oxygen atoms in its formula.

Sodium hydroxide $(NaOH)$ has 1 oxygen atom in its formula.
Acetic acid $(CH _3COOH)$ has 2 oxygen atoms in its formula.
Hydrochloric acid $(HCl)$ does not have oxygen atom in its formula.

Hence, option C is correct.

Identify the gas evolved when potassium sulphite is treated with dilute hydrochloric acid.

  1. ${ S } _{ 2 }$

  2. ${ O } _{ 2 }$

  3. ${ SO } _{ 2 }$

  4. None of these


Correct Option: C
Explanation:

When potassium sulphite is treated with dilute hydrochloric acid, sulphur dioxide gas is evolved along with potassium chloride and water.


$ { K } _{ 2 }{ SO } _{ 3 }+HCl\rightarrow KCl + { H } _{ 2 }O+{ SO } _{ 2 }$

Hence, option C is correct.

Which of the following gas is evolved when concentrated hydrochloric acid is made to react with manganese dioxide?

  1. ${ O} _{ 3 }$

  2. ${ O } _{ 2 }$

  3. ${ H} _{ 2 }$

  4. ${ Cl } _{ 2 }$


Correct Option: D
Explanation:

When concentrated hydrochloric acid reacts with manganese dioxide, chlorine gas as well as manganese(II) chloride and water. 


${ MnO } _{ 2 }+4HCl\rightarrow { MnCl } _{ 2 }+{ Cl } _{ 2 }+2{ H } _{ 2 }O$

Hence, option $\text{D}$ is correct.

Iron reacts with hydrogen chloride gas-forming (iron [II] chloride, iron [III] chloride) and hydrogen, The reaction is an example of :

  1. double decomposition

  2. synthesis

  3. simple displacement

  4. None of these


Correct Option: C
Explanation:

Iron reacts with hydrogen chloride gas-forming iron$ [II] $ chloride and hydrogen. The reaction is an example of simple displacement reaction.


$Fe + 2HCl \longrightarrow FeCl _2 + H _2$


Hence, the correct answer is option $\text{D}$.

Hydrochloric acid can be converted into chlorine by heating with :

  1. calcium oxide

  2. lead [III] oxide

  3. lead [IV] oxide

  4. lead [II] oxide


Correct Option: C
Explanation:

Explanation :-

In $HCl$, the chlorine atom present with $-1$ oxidation state and $Cl _2$ has zero oxidation state. It means chlorine undergoes reduction that is only possible in the presence of a strong oxidizing agent.

$\underset{agent (Pb \ in \ +4 \ state)}{\underset{strong \ oxidizing}{PbO _2}} + 4HCl \rightarrow PbCl _2 + Cl _2 + 2H _2O$

Compounds $A$ and $B$ are treated with dilute $HCl$ separately. The gases liberated are $Y$ and $Z$ respectively $Y$ turns acidified dichromate paper green while $Z$ turns lead acetate paper black. So $A$ and $B$ compounds are respectively:

  1. $Na _2SO _3, Na _2S$

  2. $NaCl, Na _2CO _3$

  3. $Na _2S, Na _2SO _3$

  4. $Na _2SO _3, K _2SO _4$


Correct Option: A

On adding few drops of dil. HCl to freshly precipitated ferric hydroxide, a red coloured colloidal solution is obtained. The phenomenon is known as :

  1. protective action

  2. flocculation

  3. coagulation

  4. peptisation


Correct Option: D
Explanation:

Peptization is the process of forming stable colloids by using an electrolyte to break up a precipitate and disperse it into the colloid


Hence, option D is correct.

$HCl$ gas cannot be dried by passing through:

  1. $H _{2}SO _{4}$

  2. $CaO$

  3. $P _{2}O _{5}$

  4. $CO$


Correct Option: B,C
Explanation:

$CaO$ and $P _2O _5$ are basic in nature so when $HCl$ is based over them, they will react with $HCl$ and form Salt and water, whereas $H _2SO _4$ and $CO$ are an acidic and hence greater affinity for water. So they can be used to dry $HCl$.

$HCl$  gas does not effect a dry strip of blue litmus paper but it turns red in the presence of a drop of water ?

  1. Blue litmus paper in the presence of water accepts the proton from $HCl$ and turns blue to red

  2. Blue litmus paper in the presence of water accepts the chloride ion from $HCl$ and turns blue to red

  3. Blue litmus paper in the presence of water with acid do not turn into red

  4. None of the above 


Correct Option: A
Explanation:

A dry litmus paper will not show any effect in the presence of dry HCL due to the absence of moisture ($H^+$ ions) in the litmus paper, whereas on putting a drop of water, the blue litmus paper immediately turns to red due to the presence of water in it hence presence of hydrogen ions ($H^+$ ions).


Hence, option A is correct.

When phosphorous pentoxide is reacted with $HCl$ gas, products are:

  1. $POCl _3$

  2. $P _4O _{10}$

  3. $H _3PO _2$

  4. $HPO _3$


Correct Option: A,D
Explanation:

Phosphorous pentoxide reacts with $HCl$ to form Phosphorous Oxychloride and metaphosphoric acid.


$2P _2O _5 + 3HCl \rightarrow POCl _3 + 3HPO _3$


Hence, $POCl _3$ and $HPO _3$ are correct.

Observing the method of collection of the gas, what you can tell about the density of hydrogen chloride?

  1. A gas that is more dense than air

  2. A gas that is less dense than air

  3. A gas (liqued form ) that is less dense than air

  4. None of these


Correct Option: A
Explanation:

A gas that is more dense than air can be collected by downward delivery. Examples of gases that can be collected by this method are carbon dioxide, chlorine, HCl, sulphur dioxide.

Which compound(s) is/are produced when hydrochloric acid is added to silver nitrate solution?

  1. ${ HNO } _{ 3 }$

  2. $AgCl$

  3. Both A and B

  4. None of these


Correct Option: C
Explanation:

${ AgNO } _{ 3 }+HCl\rightarrow AgCl+{ HNO } _{ 3 }$

$HCl$ is prepared by heating $NaCl$ with $conc.{ H } _{ 2 }S{ O } _{ 4 }$. But $HI$ cannot be prepared by treating $NaI$ with $conc.{ H } _{ 2 }S{ O } _{ 4 }$. Identify the reason.

  1. ${ H } _{ 2 }S{ O } _{ 4 }$ is oxidised by $HI$ and not oxidised by $HCl$

  2. $HI$ is oxidised by ${ H } _{ 2 }S{ O } _{ 4 }$ and $HCl$ is not oxidised by $HI$

  3. $HI$ dissociates on treatment with ${ H } _{ 2 }S{ O } _{ 4 }$ and $HCl$ does not dissociate

  4. Reaction of ${ H } _{ 2 }S{ O } _{ 4 }$ with $HI$ is reversible whereas with $HCl$ is irreversible


Correct Option: B
Explanation:

$HCl$ is prepared by heating $NaCl$ with $conc.{ H } _{ 2 }S{ O } _{ 4 }$. But $HI$ cannot be prepared by treating $NaI$ with $conc.{ H } _{ 2 }S{ O } _{ 4 }$. Because  $HI$ is oxidised by ${ H } _{ 2 }S{ O } _{ 4 }$ and $HCl$ is not oxidised by $HI$.

Hence, option $B$ is correct.

Glaber prepared $HCl$ from which of the following compounds?

  1. $NaCl,H _2SO _4$

  2. $NaCl,H _2CO _3$

  3. $NaCl,HNO _3$

  4. $KCl,H _2SO _4$


Correct Option: A
Explanation:

Glaber is the scientist who prepared hydrogen chloride in the laboratory by reacting sodium chloride with concentrated sulphuric acid.

$NaCl+H _2SO _4\rightarrow NaHSO _4+HCl$

Sodium bisulphate is a by-product in the above reaction . This is insoluble. Therefore, we further add it with more sodium chloride. This mixture has to be heated to a higher temperature of around 823K. It gives dissolvable sodium sulfate and HCl gas.

$NaHSO _4+NaCl\rightarrow Na _2SO _4+HCl$.

Hence option $A$ is correct.

In the Hydrolysis of ICl , the products are :

  1. HI +HCl

  2. HI +HOCl

  3. HCl+HOI

  4. HOCl +HOI


Correct Option: C
Explanation:

In the hydrolysis of ICl, the products are HCl + HOI.


$ICl+H _2O\rightarrow HCl+HOI$

During the hydrolysis of interhalogen compounds, oxyacid of less electronegative or large sized halogen is formed, and other halogen forms halogen acid. 

Thus, less electronegative iodine forms HOI and more electronegative chlorine forms HCl.

The pain due to honey-bee siting can be relieved by using:

  1. washing soda

  2. water

  3. acid

  4. baking soda


Correct Option: D
Explanation:

Honey bee sting has formic acid in it which causes irritation and burns.

To neutralise this effect, we recommend a base to be used.
Hence, bee sting can be relieved using baking soda. 

Which of the following acid is used in fire extinguishers?

  1. Hydrochloric acid

  2. Sulphuric acid

  3. Nitric acid

  4. Oxalic acid


Correct Option: B
Explanation:

Soda-acid extinguisher uses the reaction between sodium bicarbonate solution and sulphuric acid to expel pressurized water onto a fire. The reaction takes place as follows :-

$2NaHCO _3+H _2SO _4 \rightarrow Na _2SO _4+2CO _2+2H _2O$
The $CO _2$ formed forces the water out of the discharge and hence the device must be held in upright position.
However, such extinguisher can't be used in case of fire caused due to electricity (as water is a good conductor of electricity) and fire caused due to oil or petrol (as the oil or petrol may float over water).
Thus, the correct answer is option (B).

Which of the following is known as battery acid?

  1. $HCl$

  2. $H _2SO _4$

  3. $HNO _2$

  4. $H _2S$


Correct Option: B
Explanation:

Sulfuric acid is one of the most important industrial chemicals. It serves as the electrolyte in the lead-acid storage battery commonly used in motor vehicles (acid for this use, containing about 33% $H _2SO _4$ and with specific gravity about 1.25, is often called battery acid).

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