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Electrical cells - class-X

Description: electrical cells
Number of Questions: 21
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Tags: patterns and properties of metals chemistry
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Which of the following statement is incorrect about electrochemical cell?

  1. Electrons are released at anode

  2. Chemical energy is converted into electrical energy

  3. Salt bridge maintains the electrical neutrality of the electrilytes

  4. Cell can work indefinitely


Correct Option: C

The following electrochemical cell is taken $Cu| Cu^{2+}(aq)|| Ag^{+}(aq))| Ag$ and has emf $E _{r}>0$ by which of the following actions $E _{1}$ increases?

  1. Adding $NH _{3}$ to the cathodic chamber

  2. Adding $HCl$ to the cathodic chamber

  3. Adding $AgNO _{3}$ to the anodic chamber

  4. Adding $NH _{3}$ to the anodic chamber


Correct Option: A

Find out ${E} _{cell}$ of following electrochemical cell (${E} _{{Br} _{2}/{Br}^{-}}=1.09V$)
$Pt(s)\mid {Br} _{2}(l)\mid{Br}^{-}(0.01M)\mid\mid{H}^{+}(0.01M)\mid{H} _{2}(g)(1bar)\mid Pt(s)$

  1. $-1.32V$

  2. $+1.09V$

  3. $-2.15V$

  4. $-1.92V$


Correct Option: C

The following electrochemical cell has been set up: $Pt(s)|Fe^{3+}, Fe^{2+}(a=1)||Ce^{4+}, Ce^{3+}(a=1)|Pt(s); E^{\circ}(Fe^{3+}|Fe^{2+})= 0.77V$; $E^{\circ}(Ce^{4+}|Ce^{3+})= 1.61V$. If an ammeter is connected between the two platinum electrodes, predict the direction of flow of current. Will the current increase or decrease with time?

  1. Ce electrode to Fe electrode, decrease

  2. Ce electrode to Fe electrode, increase

  3. Fe electrode to Ce electrode, decrease

  4. Fe electrode to Ce electrode, increase


Correct Option: A

After some time, the voltage of an electrochemical cell becomes zero. This is because ____________________.

  1. their electrode potential becomes zero.

  2. their reduction potential become equal but have opposite sign

  3. their reduction potential become equal and have the same sign.

  4. the ions of the electrolyte in the salt bridge stop moving.


Correct Option: B

Which one of the following statements is incorrect regarding an electrochemical cell?

  1. The electrode on which oxidation takes place is called anode.

  2. Anode is the negative pole.

  3. The direction of the current is same as that of the direction of flow of electrons.

  4. The flow of current is partly due to flow of electrons and partly due to flow of ions.


Correct Option: C

The first electro-chemical was invented by:

  1. Luigi Galvani.

  2. Alessandro Volta.

  3. Deniel.

  4. Lechanche


Correct Option: A
Explanation:

The first electrochemical cell was invented by Luigi Galvani in 1791. It was greatly improved by Alessandro Volta in the years of 1800.

Statement $1$: In an electrolytic cell, the anode becomes positive and the cathode becomes negative.
Statement $2$: Anions migrate to the anode and cations migrate to the cathode.

  1. Statement $1$ and Statement $2$ are correct and Statement 2 is the correct explanation of Statement $1$.

  2. Both the Statement $1$ and Statement $2$ are correct, but Statement $2$ is NOT the correct explanation of Statement $1$.

  3. Statement $1$ is correct, but Statement $2$ is not correct.

  4. Statement $1$ is not correct, but Statement $2$ is correct.


Correct Option: B
Explanation:
|  In electrolytic cell |  In galvanic cell | | --- | --- | |  Anode $=+ve$ |  Anode $=-ve$ | |  Cathode $=-ve$ |  Cathode $=+ve$ |
Anions migrate to anode in electrolytic cell 
Cations migrate to cathode in electrolytic cell 

The apparatus in which electrical energy is converted into chemical energy is known as:

  1. voltameter

  2. coulometer

  3. both (A) and (B)

  4. none of these


Correct Option: C
Explanation:

The apparatus in which electrical energy is converted into chemical energy is known as voltameter or coulometer.
Ag or Cu voltameters or coulemeters are used to measure the total charge passed through solution in terms of mass of Ag or Cu deposited there on voltameter or coulometer cathode.

Consider a spontaneous electrochemical cell containing $Cd, Cd^{2+}, Ag^{+}$, and $Ag$.
The reduction potential of $Cd$ is $-0.403\ V$ and $Ag$ is $0.799\ V$.

What is the balanced equation for the reaction that is occurring, and what is the electrochemical cell voltage?

  1. $Ag^{+} + Cd \rightarrow Cd^{2+} + Ag; 1.19\ V$

  2. $2Ag^{+} + Cd \rightarrow Cd^{2+} + 2Ag; 1.20\ V$

  3. $Ag^{+} + Cd \rightarrow Cd^{2+} + Ag^{+}; 0.40\ V$

  4. $2Ag^{+} + Cd \rightarrow Cd^{2+} + 2Ag; 2,30\ V$


Correct Option: B
Explanation:
We have,
$E^0$ of Cd = -0.403V ( oxidation will favour)
$E^0$ of  Ag = 0.799V (reduction will favour)

So, the net reaction becomes:

$2 Ag^+ + Cd \rightarrow Cd^{2+} + 2Ag$

and $E^0 _{cell}  = 0.799 - (-0.403) = 1.202 V$

Which of the following is true of an electrolytic cell?

  1. An electric current causes an otherwise non-spontaneous chemical reaction to occur.

  2. Reduction occurs at the anode

  3. A spontaneous electrochemical reaction produces an electric current

  4. The electrode to which the electrons flow is where oxidation occurs

  5. None of the above


Correct Option: A
Explanation:

An electrolytic cell is a device which makes a non spontaneous reaction spontaneous by the use of electricity.

The chemical change in an electrolytic cell is non-spontaneous. 

  1. True

  2. False


Correct Option: A
Explanation:
An electrolytic cell converts electrical energy into chemical energy.
The redox reaction is not spontaneous and electrical energy has to be supplied to initiate the reaction. Both the electrodes are placed in a same container in the solution of molten electrolyte. Here, the anode is positive and cathode is the negative electrode. The reaction at the anode is oxidation and that at the cathode is reductionThe external battery supplies the electrons. They enter through the cathode and come out through the anode.

What is a voltaic cell?

  1. A cell in which a spontaneous redox reaction produces electricity.

  2. A cell in which an oxidation reaction produces electricity.

  3. A cell that produces voltage.

  4. A cell full of volts.

  5. Any cell that undergoes a spontaneous reaction.


Correct Option: A
Explanation:

A voltaic cell is a cell in which a spontaneous redox reaction produces electricity. It is an electrochemical cell and is also called galvanic cell. Chemical energy is converted into electrical energy. The dry cell, nickel cadmium cell, lead storage cell and fuel cells are examples of voltaic cell.

The value of equilibrium constant for a feasible cell reaction is:

  1. $< 1$

  2. $= 1$

  3. $> 1$

  4. zero


Correct Option: C
Explanation:

$K = antilog \left (\dfrac {nE^{\circ}}{0.0591}\right )$
For feasible cell, $E^{\circ}$ is positive, hence from the above equation $K > 1$ for feasible cell reactions.

An electrochemical cell consists of?

  1. A cathode, anode, electrolyte, wire and two compartments.

  2. Cathode, anode, and wire

  3. Two compartments that conduct electricity.

  4. A positive and negative side.

  5. A cathode and an anode.


Correct Option: E
Explanation:

An electrochemical cell consists of a cathode, anode, electrolyte, wire and two compartments. An electrochemical cell is a device used to study chemical reactions electrically.

Consider the reaction;
$Cl _2(g)+2Br^-(aq)\rightarrow 2Cl^-(aq)+Br _2$
The emf of the cell when
$[Cl^-]=[Br _2]=[Br]=0.01 M$ and $Cl _2$ gas at 1 atm pressure will be: ($E^0$ for the above reaction is = 0.29 volt)

  1. 0.54 volt

  2. 0.35 volt

  3. 0.24 volt

  4. -0.29 volt


Correct Option: A

In an electrochemical cell, anode and cathode are__________.

  1. Positively and negatively charges ions

  2. Positively and negatively charges electrodes

  3. Negatively and positively charged electrodes

  4. Negatively and positively charged ions


Correct Option: B
Explanation:

In both kinds of electrochemical cells, the anode is the electrode at which the oxidation half-reaction occurs, and the cathode is the electrode at which the reduction half-reaction occurs. The anode is considered positive and the cathode is considered negative. 


Hence, the correct option is $\text{B}$

Electrochemical cells are also called:

  1. electrolytic cells

  2. galvanic cells

  3. fuel cells

  4. voltaic cells


Correct Option: A,B,D
Explanation:

Electrochemical cell which convert electrical energy into chemical energy is called as electrolytic cell. 
Electrochemical cell which converts chemical energy into electrical energy is called as Galvanic or Voltaic cell

Foe the electrochemical cell:
$Zn\left( s \right) |{ Zn }^{ 2+ }\left( aq \right) \parallel { Cl }^{ - }\left( aq \right) |{ Cl } _{ 2 }\left( g \right) |Pt\left( s \right) $
Given : ${ E } _{ { Zn }^{ 2+ }/Zn }^{ o }=-0.76\ Volt$
             ${ E } _{ { Cl }^{ - }/{ Cl } _{ 2 }\left( g \right)  }^{ o }=-1.36\ Volt$
From these data one can deduce that:

  1. $Zn + Cl _{2} \rightleftharpoons Zn^{2+} + 2Cl^{-}$ is a non-spontaneous reaction at standard conditions.

  2. $Zn^{2+} + 2Cl^{-} \rightleftharpoons Cl _{2} + Zn$ is a spontaneous reaction at standard conditions with ${ E } _{ cell }^{ o } = 2.12\ volt.$

  3. $Zn + Cl _{2} \longrightarrow Zn^{2+} + 2 Cl^{-}$ is a spontaneous reaction at standard conditions with ${ E } _{ cell }^{ o } = 2.12\ volt.$

  4. $Zn + Cl _{2} \longrightarrow Zn^{2+} + 2 Cl^{-}$ is a spontaneous reaction at standard conditions with ${ E } _{ cell }^{ o } = 0.60\ volt.$


Correct Option: C
Explanation:
$Cl=\to zn^{2+} +2e^- \to Zn$
$2Cl\to Cl _2^- +2e^-$
for sponlareous reaction $E^o$ cell $>$ zero
$\Delta G <$ zero
$Zn^{3+}+2Cl^{-}\to Cl _2+Zn$ 
$Zn \to Zn^{2+} +2e^-$
$Cl _2 \to 2e^- \to 2Cl^- $(cathode)
$Zn +Cl _2 \to Zn^{3+}+2Cl^- ....(1)$
$E^o _{RP}$ (cathode) $=0.76$
$E^o $ cell $=E^o _{OP}+E^o _{RP}$
$=2.12$
as $E^o > 0$
$\Delta G < $ zero
so reaction $(1)$ is sponlareous at $2.12$

In an electrolytic cell:

  1. anode is positively charged

  2. cathode is negatively charged

  3. oxidation takes place at anode

  4. reduction takes place at cathode


Correct Option: A,B,C,D
Explanation:

In electrolytic cell,

anode is positively charged and $-ve$ charged ions are attracted to it and oxidation takes place by loss of electron,
cathode is negatively charged and $+ve$ charge ions are attracted to it and reduction takes place by gain of electron;
hence, all options are corrrect. 

The electrochemical cell shown below is a concentration cell.
$M|{ M }^{ 2+ }$ (saturated solution of a sparingly soluble salt, $M{X} _{2})\parallel {M}^{2+}(0.001 mol{dm}^{-3})| M$. 
The emf of the cell depends on the difference in concentrations of ${M}^{2+}$ ions at the two electrodes.
The emf of the cell at $298K$ is $0.099V$
The solubility product (${K} _{sp}:{mol}^{3}{dm}^{-9}$) of ${MX} _{2}$ at $298K$ based on the information available for the given concentration cell is: (take $2.303\times R\times 298/F=0.059V$)

  1. $1\times {10}^{-15}$

  2. $4\times {10}^{-15}$

  3. $1\times {10}^{-12}$

  4. $4\times {10}^{-12}$


Correct Option: A
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