$\Rightarrow$  The given number is $31520332$.

(A) Place value of 5 in 
$91,25,678=5000$
Face value of 5 in 
$91,25,678=5$
$\therefore :difference=5000-5$
$=4995$ 

Face value of a digit in any place will be the digit itself.

Face values of 5 and 9 are 5 and 9 respectively. 

The difference between $88.888$ and $100$ is,

In the given sequence there are 3 such combinations where an even number is immediately preceded by an odd number and immediately followed by even number.

Let the required number be $n$
Then, $3n+9=45$
$\Rightarrow$  $3n=45-9$
$\Rightarrow$  $3n=36$
$\Rightarrow$  $n=\cfrac{36}{3}=12$
Hence the required number is $12$

Place value of $5$ in
$91,25,678 = 5000$
Face value of $5$ in
$91,25,678 = 5$
$\displaystyle \therefore $ difference  $= 5000 - 5
= 4995$

Sum of face values of all the digits of 
$749205=7+4+9+2+0+5=27$

Lets take an example : $245$- place value for Hundred's place digit is $200$ and face value is $2$.

$2015! + 3^{7886}$

$2015! \Rightarrow$ Unit digit $\Rightarrow \underline { 0 }$

$3^{7886}=3^{4n+2}$, So unit digit $\Rightarrow 9$

$\therefore 0+9 \Rightarrow \underline{9}$.

$\therefore$ Digit at unit place $\Rightarrow 9$ 

Let the numbers Of all kind is $x$

Face value of a digit is the value of the digit in the number. 

$\Rightarrow$  1–10 = 2 times

The sequence $51+61+71...+341$ is an arithmetic progression.

Let the ten's digit be $x$. Then, unit's digit $= \left(11 - x\right)$.
So, number $= 10x + \left(11 - x\right) = 9x + 11$.
Therefore $\left(9x + 11\right) + 27 = 10 \left(11 - x\right) + x  \Leftrightarrow  9x + 38 = 110 - 9x \Leftrightarrow   18x = 72 \Leftrightarrow   x = 4$.
Thus, ten's digit $= 4$ and unit's digit $= 7$.
Hence, required number $= 47$.