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Test - 3

Description: Test - 3
Number of Questions: 20
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Tags: Test - 3 Structural Analysis Civil Engineering - CE
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A rigid bar is suspended by three rods made of the same material as shown in the figure. The area and length of the central rod are 3A and L respectively, while that of the two outer rods are 2A and 2L respectively. If a downward force of 50 kN is applied to the rigid bar, the forces in the central and each of the outer rods will be

  1. 16.67 kN each

  2. 30 kN and 15 kN

  3. 30 kN and 10 kN

  4. 21.4 kN and 14.3 kN


Correct Option: C
Explanation:

 

The maximum and minimum shear stresses in a hollow circular shaft of outer diameter 20 mm and thickness 2 mm, subjected to a torque of 92.7 Nm will be

  1. 59 MPa and 47.2 MPa

  2. 10 MPa and 80 MPa

  3. 118 MPa and 160 MPa

  4. 200 MPa and 160 MPa


Correct Option: B
Explanation:

 

The shear stress at the neutral axis in a beam of triangular section with a base of 40 mm and height of 20 mm, subjected to a shear force of 3 kN is

  1. 3 MPa

  2. 6 MPa

  3. 10 MPa

  4. 20 MPa


Correct Option: C
Explanation:

 

A metal bar of length 100 mm is inserted between two rigid supports and its temperature is increased by 10°C. If the coefficient of thermal expansion is 12 x 10–6 per °C and the Young’s modulus is 2 x 105 MPa, the stress in the bar is

  1. zero

  2. 12 MPa

  3. 24 MPa

  4. 2400 MPa


Correct Option: C
Explanation:

 

The right triangular truss is made of members having equal cross-sectional area of 1550 mm2 and Young’s modulus of 2 x 105 MPa. The horizontal deflection of the joint Q is

  1. 2.47 mm

  2. 10.25 mm

  3. 14.1 mm

  4. 15.68 mm


Correct Option: D
Explanation:

 

The influence line diagram (ILD) shown is for the member

  1. PS

  2. RS

  3. PQ

  4. QS


Correct Option: A
Explanation:

 Member PQ will remain always in compression for normal loading on the given truss and member RS will be in tension.

Now as per variation of nature of force it should be member PS not QS.

A two span continuous beam having equal spans each of length L is subjected to a uniformly distributed load $\omega$ per unit length. The beam has constant flexural rigidity.

The reaction at the middle support is

  1. $\omega$L

  2. $\frac{5 \omega L}{2}$

  3. $\frac{5 \omega L}{4}$

  4. $\frac{\omega L^2}{16}$


Correct Option: C
Explanation:

 

The span(s) to be loaded uniformly for maximum positive (upward) reaction at support P, as shown in the figure below, is (are)

  1. PQ only

  2. PQ and QR

  3. QR and RS

  4. PQ and RS


Correct Option: D
Explanation:

 

A vertical PQ of length L is fixed at its top end P and has a flange to the bottom end Q. A weight W is dropped vertically from a height h (<L) on to the flange. The axial stress in the rod can be reduced by

  1. increasing the length of the rod

  2. decreasing the length of the rod

  3. decreasing the area of cross-section of the rod

  4. increasing the modulus of elasticity of the material


Correct Option: A
Explanation:

 

The members EJ and IJ of a steel truss (shown in the figure below) are subjected to a temperature rise of 30oC. The coefficient of thermal expansion of steel is 0.000012 per oC per unit length. The displacement (mm) of joint E relative to joint H along the direction HE of the truss is

  1. 0.255

  2. 0.589

  3. 0.764

  4. 1.026


Correct Option: D
Explanation:

 

Beam GHI is supported by the pontoons as shown in the figure below. The horizontal cross sectional area of each pontoon is 8 m2, the flexural rigidity of the beam is 10000 kN-m2 and the unit weight of water is 10 kN-m3.

When the middle pontoon is removed, the deflection at H will be

  1. 0.2 m

  2. 0.4 m

  3. 0.6 m

  4. 0.8 m


Correct Option: B
Explanation:

 

The degree of static indeterminacy of the rigid frame having two internal hinges as shown in the figure below, is

  1. 8

  2. 7

  3. 6

  4. 5


Correct Option: D
Explanation:

 

The unit load method used in structural analysis is

  1. applicable only to statistically indeterminate structures

  2. another name for stiffness method

  3. an extension of Maxwell’s reciprocal theorem

  4. derived from Castigliano’s theorem


Correct Option: A
Explanation:

 

For linear elastic systems, the type of displacement function for the strain energy is

  1. linear

  2. quadratic

  3. cubic

  4. quartic


Correct Option: B
Explanation:

 $\text{For linear elastic system,}\\ \text{strain energy} E = \frac{1}{2} P \times \triangle = \frac{1}{2} \times P \times \frac{P.L}{AE} = \frac{1}{2}\frac{P^2L}{AE} = \frac{1}{2}E \epsilon ^2\\ E \propto \epsilon^2 \text{which represents quadratic equation.}$

For a linear elastic structural system, minimization of potential energy yields

  1. compatibility conditions

  2. constitutive relations

  3. equilibrium equations

  4. strain-displacement relations


Correct Option: C
Explanation:

 For a linear elastic structural, minimization of potential energy yields compatibility conditions.

Muller Breslau principle in structural analysis is used for

  1. drawing influence line diagram for any force function

  2. writing virtual work equation

  3. super position of load effects

  4. none of these


Correct Option: A
Explanation:

 Muller Breslau used for drawing influence line diagram for any force function by means of deflected diagram.

A curved member with a straight vertical leg is carrying a vertical load at Z, as shown in the figure. The stress resultant(s) in the XY segment is/are

  1. bending moment, shear force and axial force

  2. bending moment and axial force only

  3. bending moment and shear force only

  4. axial force only


Correct Option: D
Explanation:

 

A bar of varying square cross section is loaded symmetrically as shown in the figure. Loads shown are placed on one of the axes of symmetry of cross-section. Ignoring self weight, the maximum tensile stress in N/mm2 anywhere is

  1. 16.0

  2. 20.0

  3. 25.0

  4. 30.0


Correct Option: C
Explanation:

 

The stiffness K of a beam deflecting in a symmetric mode, as shown in the figure, is

  1. $\frac{EI}{L}$

  2. $\frac{2EI}{L}$

  3. $\frac{4EI}{L}$

  4. $\frac{6EI}{L}$


Correct Option: B
Explanation:

 

The symmetry of stress tensor at a point in the body under equilibrium is obtained from

  1. conservation of mass

  2. force equilibrium equations

  3. moment equilibrium equations

  4. conservation of energy


Correct Option: C
Explanation:

 $\text{Symmetry of stress tensor means}\\ \hspace{3cm}\sigma_{ab}=\sigma_{ba}\\ \text{and this is only possible under moment equilibrium equations.}$

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