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Boolean Algebra

Description: this is a test for number systems in computers
Number of Questions: 25
Created by:
Tags: computer dos operating systems commands fundamentals multiple objective choice questions Boolean Algebra Circle
Attempted 0/25 Correct 0 Score 0

The number 39 when represented in 2’s complement form is

  1. 11011001

  2. 12111

  3. 110111

  4. none of these


Correct Option: A

The binary number (1101.111)2 when represented by floating point notation is

  1. (.1101111 x 24)

  2. (1101111)2

  3. (.1101111)2

  4. none of these


Correct Option: A

An arbitrary number system has a radix of 32 with ‘0’ to ‘9’ and ‘A’ to ‘V’ as its 32 basic digits, ‘0’ being the first and ‘V’ being the 32nd. The number immediately following ‘V’ in the arbitrary number system will be

  1. (V0)32

  2. (10)32

  3. (V1)32

  4. none of these


Correct Option: B

Binary number (1110101)2, when converted into an equivalent decimal number gives the result as

  1. 117

  2. 58

  3. 116

  4. 57


Correct Option: A

The numbers that come immediately after and before hexadecimal number (FFEF)16 are, respectively

  1. (FFF0)16 and (FFE0)16

  2. (FFFE)16 and (FEE0)16

  3. (FFF0)16 and (FFFE)16

  4. (FFF0)16 and (FFEE)16


Correct Option: D

Binary number (1101)2 when added to another binary number (101)2 yields

  1. 10010

  2. 13

  3. 11010

  4. 11001


Correct Option: A

An arbitrary number system has a radix of 32 with ‘0’ to ‘9’ and ‘A’ to ‘V’ as its 32 basic digits, ‘0’ being the first and ‘V’ being the 32nd. Decimal number (128)10 in this arbitrary number system

  1. can be expressed as (40)32

  2. is (128)32

  3. is (100)32

  4. cannot be determined from the given data


Correct Option: A

Amongst the following 4-bit groups, pick the one that is forbidden in 8421 BCD code:

1001, 1, 1010, 2, 0101, 0110

  1. 1001

  2. 0110

  3. 1010

  4. 2


Correct Option: C
Explanation:

1010 is a forbidden code in the above series.

The decimal number 78 in 5421 BCD code will be

  1. 01111

  2. 10101011

  3. 1001110

  4. none of these


Correct Option: B

64 in decimal is equivalent to

  1. 64 in octal 100

  2. 100 in octal

  3. 1000 in binary

  4. none of these


Correct Option: B

One's complement of (11)2 in 8-digit arithmetic is

  1. 00000000

  2. 11111100

  3. 11111111

  4. none of these


Correct Option: B

9's complement of (2903)10 is

  1. 7096

  2. 2903

  3. There's nothing like 9's complement

  4. none of these


Correct Option: A

Two's complement of (101)2 in 8-digit arithmetic is

  1. 00041

  2. 11111010

  3. 11111011

  4. none of these


Correct Option: C

Decimal 15 in binary system can be written as

  1. 1111

  2. 1110

  3. 1100

  4. 1


Correct Option: A

128 in decimal is equivalent to

  1. 80 in hexadecimal

  2. 180 in octal

  3. 100 in binary

  4. none of these


Correct Option: A

(011)2 is equivalent to

  1. (.75)10

  2. (0.24)10

  3. (0.375)10

  4. none of these


Correct Option: A

The number that immediately precede (777)2 and (1111)2 are receptively

  1. (776)8 and (1110)2

  2. (7770)8 and (1110)2

  3. (776)8 and (11110)2

  4. none of these


Correct Option: A

Decimal equivalent of BCD 8421 number (10000.1001) is

  1. 80.9

  2. 128.9

  3. 80.25

  4. 128.25


Correct Option: A

1's complement of (11101)2, (FFF)16, (F1EA)16 and (732)8 are

  1. (03)2, (000)16, (0E15)16 and (045)8

  2. (03)2, (000)16, (0E15)16 and (156)8

  3. (03)2, (111)16, (1F26)16 and (045)8

  4. none of these


Correct Option: A

Number (- 39) when represented in Sign-Bit magnitude form is

  1. 11011001

  2. 120111

  3. 11011

  4. none of these


Correct Option: D

Number (- 13) when represented in 1's complement form is

  1. 11011001

  2. 12111

  3. 11110

  4. 04111


Correct Option: C

The numbers that immediately follow (777)8 and (1111)2 are receptively

  1. (1)8 and (10)2

  2. (7770)8 and (11110)2

  3. (7777)8 and (11111)2

  4. none of these


Correct Option: A

If 4 in binary system is 100, then 8 will be

  1. 10

  2. 100

  3. 111

  4. 1


Correct Option: D

The hexadecimal number (FFF.FF)16 in floating point notation is written as

  1. (.FFFFF X 162)

  2. (.FFFFF X 163)

  3. (.FFFFF)

  4. None of these


Correct Option: B

The decimal number (839.57)10, when represented by floating point notation, is

  1. (0.83957)

  2. (.83957 x 23)

  3. (.83957 x 83)

  4. (.83957 x 103)


Correct Option: D
Explanation:

Binary equivalent of 839 is 1101000111 and that of the decimal part is 10010001.... Thereafter, normalising it with K = 3, we get (.83957 x 103).

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