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math & puzzles Online Quiz - 35

Description: math & puzzles Online Quiz - 35
Number of Questions: 20
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Tags: math & puzzles
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In a circular track of 100 kms run A and B.A's speed is 25km/hr and B's is 15km/hr.In hw much time will they cross each other for the 3rd time?

  1. 25 hrs

  2. 20 hrs

  3. 25.71 hrs(approx)

  4. 40 hrs


Correct Option: B

In a race of 100 meters A beat B by 5 meters. In another similar race B beat C by 5 meters.So by how much distance will A beat C in a 100 meter race?

  1. 20

  2. 10

  3. 9.75

  4. 9.25


Correct Option: C

Two trains A and B which run at constant speed are running on parallel tracks.After crossing eact other they take 36minutes and 144minutes to reach their destinations which is to exchange their positions.What is the ratio of their speeds of A and B.

  1. 0.5

  2. 2

  3. 2.4

  4. 4.8


Correct Option: B

Two traders, Chetan and Michael, were involved in the buying and selling of MCS shares over five trading days. At the beginning of the first day, the MCS share was priced at Rs.100, while at the end of the fifth day it was priced at Rs.110. At the end of each day, the MCS share price either went up by Rs.10, or else, it came down by Rs.10. Both Chetan and Michael took buying and selling decisions at the end of each trading day. The beginning price of MCS share on a given day was the same as the ending price of the previous day. Chetan and Michael started with the same number of shares and amount of cash, and had enough of both below are some additional facts about how Chetan and Michael traded over the five trading days. ? Each day if the price went up, Chetan sold 10 shares of MCS at the closing price. On the other hand, each day if the price went down, he bought 10 shares at the closing price. ? If on any day, the closing price was above Rs.110, then Michael sold 10 shares of MCS, while if it was below Rs.90, he bought 10 shares, all at the closing price. 1. If Chetan sold 10 shares of MCS on three consecutive days, while Michael sold 10 shares only once during the five days, what was the price of MCS at the end of day 3?

  1. 90

  2. 100

  3. 110

  4. 120


Correct Option: C

Two traders, Chetan and Michael, were involved in the buying and selling of MCS shares over five trading days. At the beginning of the first day, the MCS share was priced at Rs.100, while at the end of the fifth day it was priced at Rs.110. At the end of each day, the MCS share price either went up by Rs.10, or else, it came down by Rs.10. Both Chetan and Michael took buying and selling decisions at the end of each trading day. The beginning price of MCS share on a given day was the same as the ending price of the previous day. Chetan and Michael started with the same number of shares and amount of cash, and had enough of both below are some additional facts about how Chetan and Michael traded over the five trading days. ? Each day if the price went up, Chetan sold 10 shares of MCS at the closing price. On the other hand, each day if the price went down, he bought 10 shares at the closing price. ? If on any day, the closing price was above Rs.110, then Michael sold 10 shares of MCS, while if it was below Rs.90, he bought 10 shares, all at the closing price. If Chetan ended up with Rs.1300 more cash than Michael at the end of day 5, what was the price of the MCS share at the end of day 4?

  1. Rs. 90

  2. Rs. 100

  3. Rs. 110

  4. Rs. 120


Correct Option: B

Two traders, Chetan and Michael, were involved in the buying and selling of MCS shares over five trading days. At the beginning of the first day, the MCS share was priced at Rs.100, while at the end of the fifth day it was priced at Rs.110. At the end of each day, the MCS share price either went up by Rs.10, or else, it came down by Rs.10. Both Chetan and Michael took buying and selling decisions at the end of each trading day. The beginning price of MCS share on a given day was the same as the ending price of the previous day. Chetan and Michael started with the same number of shares and amount of cash, and had enough of both below are some additional facts about how Chetan and Michael traded over the five trading days. ? Each day if the price went up, Chetan sold 10 shares of MCS at the closing price. On the other hand, each day if the price went down, he bought 10 shares at the closing price. ? If on any day, the closing price was above Rs.110, then Michael sold 10 shares of MCS, while if it was below Rs.90, he bought 10 shares, all at the closing price. If Michael ended up with 20 more shares than Chetan at the end of days 5, what was the price of the shares at the and of day 3?

  1. 90

  2. 100

  3. 110

  4. 120


Correct Option: A

Two traders, Chetan and Michael, were involved in the buying and selling of MCS shares over five trading days. At the beginning of the first day, the MCS share was priced at Rs.100, while at the end of the fifth day it was priced at Rs.110. At the end of each day, the MCS share price either went up by Rs.10, or else, it came down by Rs.10. Both Chetan and Michael took buying and selling decisions at the end of each trading day. The beginning price of MCS share on a given day was the same as the ending price of the previous day. Chetan and Michael started with the same number of shares and amount of cash, and had enough of both below are some additional facts about how Chetan and Michael traded over the five trading days. ? Each day if the price went up, Chetan sold 10 shares of MCS at the closing price. On the other hand, each day if the price went down, he bought 10 shares at the closing price. ? If on any day, the closing price was above Rs.110, then Michael sold 10 shares of MCS, while if it was below Rs.90, he bought 10 shares, all at the closing price. If Michael ended up with Rs.100 less cash than Chetan at the end of day 5, what was the difference in the number of shares possessed by Michael and Chetan (at the end of day 5)?

  1. Michael had 10 less shares than Chetan.

  2. Michael had 10 more shares than Chetan.

  3. Chetan had 10 more shares than Michael.

  4. Both had the same number of shares.


Correct Option: D

Two traders, Chetan and Michael, were involved in the buying and selling of MCS shares over five trading days. At the beginning of the first day, the MCS share was priced at Rs.100, while at the end of the fifth day it was priced at Rs.110. At the end of each day, the MCS share price either went up by Rs.10, or else, it came down by Rs.10. Both Chetan and Michael took buying and selling decisions at the end of each trading day. The beginning price of MCS share on a given day was the same as the ending price of the previous day. Chetan and Michael started with the same number of shares and amount of cash, and had enough of both below are some additional facts about how Chetan and Michael traded over the five trading days. ? Each day if the price went up, Chetan sold 10 shares of MCS at the closing price. On the other hand, each day if the price went down, he bought 10 shares at the closing price. ? If on any day, the closing price was above Rs.110, then Michael sold 10 shares of MCS, while if it was below Rs.90, he bought 10 shares, all at the closing price. What could have been the maximum possible increase in combined cash balance of Chetan and Michael at the end of the fifth day?

  1. 3700

  2. 4000

  3. 4700

  4. 5000


Correct Option: D

sqrt(2+sqrt(2+sqrt(2+sqrt(2+......infinity)))))=? Ex: sqrt(4)=2 write it on paper u'll understand it

  1. -1

  2. 2

  3. both

  4. 3

  5. infinity

  6. none of the above


Correct Option: B

[[512^(2/3)]^(2/3)]^(3/4) Ex: 3^2=9

  1. 2

  2. 4

  3. 8

  4. 16

  5. 32

  6. 64


Correct Option: C

Number of diagonals for an 11-sided polygon

  1. 25

  2. 36

  3. 44

  4. 48

  5. 50

  6. 55


Correct Option: C

There is a circle with diameter of 8 cms.Find the area of largest square inscribed in that circle.

  1. 16

  2. 32

  3. 48

  4. 64

  5. 8

  6. none


Correct Option: B

There is a circle with diameter of 8 cms.Find the Perimeter of largest square circumscribed that circle.

  1. 48

  2. 32

  3. 16

  4. 8

  5. 24

  6. none


Correct Option: B

A shop keeper sold a T.V set for Rs.17,940 with a discount of 8% and earned a profit of 19.6%.What would have been the percentage of profit earned if no discount was offered?

  1. 0.248

  2. 0.25

  3. 0.264

  4. None of these


Correct Option: D

A clock is set right at 8 a.m. The clock gains 10 minutes in 24 hours. What will be the true time when the clock indicates 1 p.m. on the following day?

  1. 48 min. past 12

  2. 38 min. past 12

  3. 28 min. past 12

  4. 25 min. past 12


Correct Option: A

What is the missing number in this series? 8 2 14 6 11 ? 14 6 18 12

  1. 16

  2. 9

  3. 15

  4. 6


Correct Option: B

Dinesh travelled 1200 km by air which formed 2/5 of his trip. One third of the whole trip, he travelled by car and the rest of the journey he performed by train. What was the distance travelled by train?

  1. 600Km

  2. 700Km

  3. 800Km

  4. 900Km


Correct Option: C

A train which travels at a uniform speed due to some mechanical fault after traveling for an hour goes at 3/5th of the original speed and reaches the destination 2 hrs late.If the fault had occurred after traveling another 50 miles the train would have reached 40 min earlier. What is distance between the two stations.

  1. 300

  2. 310

  3. 320

  4. 305


Correct Option: A

The average between a two digit number and the number obtained by interchanging the digits is 9. What is the difference between the two digits of the number?

  1. 8

  2. 2

  3. 5

  4. Cannot be determined


Correct Option: D

Pipe A can fill in 20 minutes and Pipe B in 30 mins and Pipe C can empty the same in 40 mins.If all of them work together, find the time taken to fill the tank

  1. 17 1/7 mins

  2. 20 mins

  3. 8 mins

  4. none of these


Correct Option: A

AI Explanation

To solve this question, we can use the concept of the rate of work.

Let's say that the capacity of the tank is 1 unit.

Pipe A can fill the tank in 20 minutes, which means it can fill 1/20 of the tank in 1 minute.

Pipe B can fill the tank in 30 minutes, which means it can fill 1/30 of the tank in 1 minute.

Pipe C can empty the tank in 40 minutes, which means it can empty 1/40 of the tank in 1 minute.

When all three pipes work together, the net rate of work will be the sum of their individual rates.

So, the net rate of work = (1/20 + 1/30 - 1/40) tank per minute

To find the time taken to fill the tank, we can use the formula:

Time = 1 / (Net rate of work)

Time = 1 / (1/20 + 1/30 - 1/40)

Simplifying this expression, we get:

Time = 17 1/7 minutes

Therefore, the correct answer is option A) 17 1/7 minutes.

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