XeF₂ has three lone pairs of electrons with linear geometry.

SF₄ has one lone pair of electrons with seesaw geometry.

I^3- and XeF₂ both have three lone pair of electrons with linear geometry. HgCl₂ has zero lone pair of electrons with linear geometry. SO₂ has one lone pair of electron with bent shape.  Hence, 1, 2, 3 all molecules have linear geometry.

P. NH₃ and PCl₃ both molecules have one lone pair of electrons with trigonal pyramidal geometry. S. CO₂ has zero lone pair of electrons with linear geometry. XeCl₂ has three lone pairs of electrons with linear geometry. Hence, P and S statements are incorrect.

The capped square antiprismatic molecular geometry describes the shape of compounds where nine atoms, groups of atoms, or ligands are arranged around a central atom, defining the vertices of a gyroelongated square pyramid. Example is ReH₉^2-.

According to VSEPR theory, BrF₄^- and XeF₄ both have four bond pair of electrons and two lone pair of electrons with square planar shape. TeCl₄ has four bond pair of electrons and one lone pair of electrons with distorted trigonal bipyramidal shape.  Hence, 1 and 2 have square planar shape.

The nitronium ion or sometimes the nitryl ion NO₂⁺ is a generally reactive cation created by the removal of an electron from the paramagnetic nitrogen dioxide molecule. In [O = N = O]+ nitrogen atom has sp hybridisation and thus it is linear in shape. In NO2- the nitrogen atom has sp2 hybridisation and bent shape.

XeOF₅^- has one lone pair of electrons with pentagonal pyramidal shape. PCl₃ has one lone pair of electrons with trigonal pyramidal shape. SF₆ has zero lone pair of electrons with octahedral geometry. BrF₃ has two lone pair of electrons and bent geometry. Hence, the correct answer using the codes is P - 3, Q - 4, R - 1, S - 2.

P. XeCl₂ has three lone pairs of electrons with linear geometry. Q. XeF₆ has six bond pairs of electrons and one lone pair of electrons with distorted pentagonal bipyramidal shape. R. ICl₄^- ion and XeF₄ molecule has four bond pairs of electrons and two lone pair of electrons with square planar geometry. Hence, only the statement P is false.

SF₄ and XeO₂F₂ have sp³d hybridisation and one lone pair of electrons with seesaw geometry. XeOF₂ has sp³d hybridisation and two lone pairs of electrons with T-shaped geometry. XeO₃F₂ has sp³d hybridisation and zero lone pair of electrons with trigonal bipyramidal geometry.

ReF₈^- has square antiprismatic molecular geometry (the shape of compounds where eight atoms, groups of atoms, or ligands are arranged around a central atom, defining the vertices of a square antiprism). W(CH₃)₆ has trigonal prismatic geometry (the shape of compounds where six atoms, groups of atoms, or ligands are arranged around a central atom, defining the vertices of a triangular prism). Na[CoCl₂(NH₃)₄] has octahedral geometry. SeF₄ has one lone pair of electrons with distorted trigonal bipyramidal shape. Hence, the representation of codes A - 2, B - 1, C - 4, D - 3 is correct.

 Based on VSEPR theory BrF₅ has one lone pair of electrons and sp³d² hybridisation with square pyramidal geometry. The bond angle in F-Br-F is 84.8 degrees.    Hence, statement Q is false.

NH₄⁺ and ClO₄^- both ions have four bond pairs of electrons and zero lone pairs of electrons with tetrahedral geometry. IF₄⁺ has four bond pairs of electrons and one lone pair of electrons with seasaw geometry. ClO₂^- has three bond pairs of electrons and two lone pairs of electrons with V-shaped geometry. Hence, i and iv are identical in geometry.

SnCl₂ has one lone pair of electrons with V-shaped geometry. SeH₂ has two lone pair of electrons with V-shaped geometry.

SbCl₅ has zero lone pairs of electrons with trigonal bipyramidal geometry. SnCl₂ has one lone pair of electrons with V-shaped geometry. ICl has three lone pairs of electrons with linear shape. ICl₄^- has two lone pairs of electrons with square planar shape. Hence, the correct answer using the codes is P - 2 - i, Q - 3 - iv, R - 4 - iii, S - 1 - ii.

Both XeF₂ and [I(CN)₂]^- have sp³d and three lone pairs of electrons with linear geometry. Hence, statement R is false.

The molecules having two bond pairs and one lone pairs of electrons with bent shape are- O₃, SO₂, CCl_2, etc. The molecules having two bond pairs and two lone pairs of electrons with bent shape are- H₂O, OF_2, etc. The molecules having two bond pairs and zero lone pairs of electrons with linear shape are- BeCl₂, HgCl₂, CO_2, etc.

(P) The molecules/ions having two bond pairs and three lone pairs with linear geometry are- XeF_2, I₃^-, XeCl_2, etc. (Q) BF₃ and SO₃ have three bond pairs and zero lone pairs with identical geometry, trigonal planar. (R) XeOF₄ molecule has 5 bond pairs and one lone pair with square pyramidal shape. Hence, statement P is only incorrect.

BH₂⁺ has sp hybridisation and zero number of lone pair of electrons with linear shape. SnBr₂ has sp² hybridisation and one lone pair of electrons with V-shaped geometry. XeF₃⁺ has sp³d hybridisation and two lone pair of electrons with T-shaped geometry. IF₅ has sp³d² hybridisation and one lone pair of electrons with square pyramidal geometry. Hence, the representation of codes A - 2, B - 1, C - 4, D - 3 is correct.

XeOF₅^- has six bond pairs and one lone pair with pentagonal pyramidal shape. WCl₂F₄ has six bond pairs and zero lone pair with octahedral geometry. TeF₄ has four bond pairs and one lone pair with seasaw geometry. XeO₄ has four bond pairs and zero lone pair with tetrahedral shape. Hence, the representation of codes A - 2, B - 1, C - 3, D - 4 is correct.