Speed = (45*5/18)m/sec = 20m/sec Total distance covered = 360+140=500m Req time = (500*2/25)sec=40sec

We forecast about future and regret about past.

we cut with knife and chop with axe.

They are the famous dances of that places.

Brother of mother - Uncle  , Uncle's son -  Cousin

This question can be done practically and by drawing a figure.

as all are string instruments

as all other are concerned with intelligence.

Son of Y's son - Grandson , brother of Y's grandson - Y's grandson So , X is Y's grandson

nth term + (n + 1)th term + (n + 1) = (n + 2)th term 1^st term + 2^nd term + 2 = 3^rd term 2^nd term + 3^rd term + 3 = 4^th term     and so on

The sum of 3 consecutive terms is the next terms

Let principal be P , Then S.I. = P and T = 16yrs

Rate = (100 * P / P * 16) = 25/4% p.a

The pattern is combination of 2 series

1. 625 , 125 , 25 , 5                     2. 5 , 25 Pattern in first is divide by 5 and second is multiply by 5 So the missing no. is 25*5=125

It is caused by bacteria

Part filled by A in 1min = 1/20 Part filled by B in 1min = 1/30 Part filled by (A+B) in 1 min = (1/20 + 1/30) = 1/12 = both pipes can fill the tank in 12 min.

Angle traced by hour hand in 12 hour = 360 degree

Angle traced by it in 3.25 hrs = (360/12 * 41/12) degree = 205/2 degree

Angle traced by min hand in 60 min = 360 degree

Angle traced by it in 25 min = (360 * 25 / 60)degree = 150 degree

Required angle = (150 - 205/2) = 95/2 degree

C.P. of 3 toffees = Re 1 ; S.P. of 3 toffees=150% of Re.1=3/2 For Rs . 3/2 , toffees sold = 3 For Re.1,toffees sold = 3*2/3=2

The word is first written twice and the other letters at the even position in the word so obtained from the code.

Let S.P. = Rs.x  Then Loss = Rs x/3, C.P =Rs.x+x/3=Rs.4x/3

Loss%= (x/3*3/4x*100)% = 25%

Required length = √(16)² +(12)² + (32/3)  = √ 256 + 144 + 1024/9

√4624/9 = 68/3

? = 35% of 980 + 150% of 850 - 40% of 1640 = (35/100 * 980 + 150/100 * 850) - (40/100 * 1640) = (343=1275-656) = (1618-656) = 962

63% of 25/7 = 63/100 * 25/7 = 4/9 = 2.25

1/2% = (1/2 * 1/100) = 0.5/100 = 0.005

Let the no. be x. Then , x-2/5x = 510

= 3/5x = 510

x = (510*5/3) = 850

10% of that no = 85

Let the original length be x and the original breadth be y

Original area = (xy)²

New length = (120/100x)m New breadth = (120/100y)m

New area = (120/100x * 120/100y)m²

= (36/25 m² )

Increase % area = (11/25xy * 1/xy * 100)% = 44%