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Coordination Compounds (GATE)

Description: Chemistry
Number of Questions: 15
Created by:
Tags: Coordination Complexes s.p. and d Block Elements Chemistry Life Sciences GATE
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Which of the following transition metal metallocenes has the highest electron count?

  1. Cobaltocene

  2. Nickelocene

  3. Rhodocene

  4. Ferrocene

  5. Manganocene


Correct Option: B
Explanation:

With 20 valence electrons, nickelocene, [Ni(η5-C5H5)2], has the highest electron count of the transition metal metallocenes.

Which of the following coordination complexes has/have sp3d2 hybridisation of central metal ion(s)?

  1. [CoF6]3-
  2. [Zn(H2O)6]2+
  3. [Fe(CN)6]3-
  1. Only 1

  2. Only 2

  3. Only 3

  4. Only 1 and 2

  5. Only 2 and 3


Correct Option: D
Explanation:

[CoF6]3- is an outer orbital complex with octahedral geometry (sp3d2 hybridisation). [Zn(H2O)6]2+ is an outer orbital complex with square planar geometry (sp3d2 hybridisation).

Which of the following pairs of formula and its IUPAC name is mismatched?

  1. [Rh(η5-C5H5)2] : bis(η5-cyclopentadienyl)rhodium(II)

  2. K2[OsCl5N] : potassium pentachloronitridoosmate(III)

  3. Cr(η6-C6H6)2 : bis(η6-benzene)chromium

  4. [Co(NH3)5CO3]Cl : pentaamminecarbonatocobalt(III) chloride

  5. [Cr(H2O)4Cl2]Cl : tetraaquadichlorochromium(III) chloride


Correct Option: B
Explanation:

Osmium is in +6 oxidation state in given complex. Hence, the correct IUPAC name of K2[OsCl5N] is potassium pentachloronitridoosmate(VI).

Which of the following metal aquo complexes has/have only one unpaired electron?

i. [Ti(H2O)6]3+ ii. [Ni(H2O)6]2+ iii. [Cu(H2O)6]2+

  1. Only i

  2. Only ii

  3. Only iii

  4. Only i and ii

  5. Only i and iii


Correct Option: E
Explanation:

[Ti(H2O)6]3+: (t2g)1 has one unpaired electron. [Cu(H2O)6]2+: (t2g)6(eg)3 has one unpaired electron.

Arrange the following central metal ions in order of increasing nephelauxetic effect.

a. Co(III) b. Ir(III) c. Fe(III)

  1. a < b < c

  2. a < c < b

  3. b < a < c

  4. c < b < a

  5. c < a < b


Correct Option: D
Explanation:

The nephelauxetic effect not only depends upon the ligand type, but also upon the central metal ion. These too can be arranged in order of increasing nephelauxetic effect as follows: Mn(II) < Ni(II) ≈ Co(II) < Mo(II) < Re(IV) < Fe(III) < Ir(III) < Co(III) < Mn(IV).

Match the columns ||| |---|---| |Column I (Complex) |Column II (Use)| |P. Ziegler-Natta catalyst|1. Polymerisation of alkenes| |Q. [PtCl2(NH3)2]|2. Cancer treatment| |R. [Ni(CO)4]|3. Mond's process| |S. RhCl(PPh3)3|4. Hydrogenation of alkenes|

  1. P - 1; Q - 2; R - 3; S - 4

  2. P - 4; Q - 2; R - 3; S - 1

  3. P - 1; Q - 3; R - 2; S - 4

  4. P - 2; Q - 1; R - 3; S - 4

  5. P - 3; Q - 2; R - 1; S - 4


Correct Option: A
Explanation:

Ziegler-Natta catalysts are used to polymerise terminal-1 alkenes (ethylene and alkenes with the vinyl double bond). Cisplatin, cis-PtCl2(NH3)2, is an anti-cancer drug that is used to treat various types of cancers. On moderate heating, Ni(CO)4 decomposes to form carbon monoxide and nickel metal. Combined with the easy formation from CO and even impure nickel, this decomposition is the basis of Mond's process for the purification of nickel. Wilkinson's catalyst, (RhCl(PPh3)3, catalyses the hydrogenation of alkenes.

 

Match the columns ||| |---|---| |Column I (Common name) |Column II (Chemical name)| |a. Vaska's complex|i. trans-chlorocarbonylbis(triphenylphosphine)iridium(I)| |b. Wilkinson's catalyst|ii. chlorotris(triphenylphosphine)rhodium(I)| |c. Jacobsen's catalyst|iii. N,N'-bis(3,5-di-tert-butylsalicylidene)-1,2-cyclohexanediaminomanganese chloride|

  1. a - i, b - ii, c - iii

  2. a - i, b - iii, c - ii

  3. a - ii, b - i, c - iii

  4. a - iii, b - ii, c - i

  5. a - iii, b - i, c - ii


Correct Option: A
Explanation:

This is the correct option. Vaska's complex is the common name for trans-chlorocarbonylbis(triphenylphosphine)iridium(I). Wilkinson's catalyst is the common name for chlorotris(triphenylphosphine)rhodium(I). Jacobsen's catalyst is the common name for N,N'-bis(3,5-di-tert-butylsalicylidene)-1,2-cyclohexanediaminomanganese chloride.

Which of the following is a pair of paramagnetic complexes?

  1. [W(CO)6] and [Cr(NH3)6]3+

  2. [Co(NH3)6]3+ and [W(CO)6]

  3. [Fe(CN)6]3- and [Co(NH3)6]3+

  4. [Co(NH3)6]3+ and [Cr(NH3)6]3+

  5. [Cr(NH3)6]3+ and [Fe(CN)6]3-


Correct Option: E
Explanation:

[Cr(NH3)6]3+: t2g3 eg0; 3 unpaired electrons; paramagnetic [Fe(CN)6]3-: t2g5 eg0; one unpaired electron; paramagnetic

Which of the following statements is/are false?

  1. [Fe(CN)6]3- complex is an inner orbital complex.
  2. Order of decreasing nephelauxetic effect is F > Cl > Br > I.
  3. [Ni(H2O)6]2+ has two unpaired electrons.
  1. Only 1

  2. Only 2

  3. Only 3

  4. Only 1 and 2

  5. Only 2 and 3


Correct Option: B
Explanation:

Correct order of nephelauxetic effect is F < H2O < NH3 < en < NCS < Cl < CN < Br < N3− < I.

Geometrical isomerism is exhibited by

  1. [Zn(NH3)2Cl2]

  2. [Co(NH3)6]3+

  3. [Pt(NH3)2Cl2]

  4. [Ni(CN)4]2-

  5. All of the above


Correct Option: C
Explanation:

[Pt(NH3)2Cl2] is a heteroleptic square planar complex of Ma2b2 type. In a square planar complex of formula [Ma2b2], the two similar ligands may be arranged adjacent to each other in a cis isomer or opposite to each other in a trans isomer.

Match the columns.

 
Column I (Complex) Column II (Central metal atom)
P. Chlorophyll 1. Iron
Q. Haemoglobin 2. Zinc
R. Vitamin B12 3. Magnesium
S. Carboxypeptidase A 4. Cobalt
  1. P - 1; Q - 2; R - 3; S - 4

  2. P - 2; Q - 3; R - 4; S - 1

  3. P - 3; Q - 1; R - 4; S - 2

  4. P - 3; Q - 2; R - 4; S - 1

  5. P - 4; Q - 1; R - 2; S - 3


Correct Option: C
Explanation:

Chlorophylls are green pigments in plants and contain Mg. Haemoglobin is the red pigment or colour of blood and contains iron (Fe). Vitamin B12 is a cyanide ion substituted cobalamin derivative (cyanocobalamin) with the presence of cobalt mineral at 6 position. Carboxypeptidase A is a zinc metalloenzyme that breaks peptide linkages in the digestion of proteins.

 

Which of the following statements is/are false?

  1. Increase in the extent of back donation causes the stretching frequencies to be found at lower wavenumbers.
  2. The correct order of C-O stretching frequency is Mn(CO)6]+ < [Cr(CO)6] < [V(CO)6]-.
  3. C-O stretching frequency in Ni(CO)4 is higher than in Fe(CO)5.
  1. Only 1

  2. Only 2

  3. Only 3

  4. Only 1 and 2

  5. Only 2 and 3


Correct Option: B
Explanation:

Increase in the extent of back donation causes the stretching frequencies to be found at lower wavenumbers. In [V(CO)6]-, vanadium has a -1 charge and with the addition of six C-O ligands, there is a tendency to relieve part of the negative charge by extensive back donation. The tendency is less in [Cr(CO)6] and even less when the metal has a positive charge as in [Mn(CO)6]+. Thus, the correct order of decreasing C-O stretching frequency is Mn(CO)6]+, 2090 cm-1 > [Cr(CO)6], 1981 cm-1 > [V(CO)6]-, 1859 cm-1.

Arrange the following transition metal ions in the increasing order of Δ (splitting energy) values.

  1. Co3+
  2. V2+
  3. Cr3+
  4. Mn2+
  1. 1 < 2 < 3 < 4

  2. 1 < 3 < 2 < 4

  3. 2 < 4 < 3 < 1

  4. 4 < 2 < 3 < 1

  5. 4 < 3 < 2 < 1


Correct Option: D
Explanation:

The metal ions can be arranged in order of increasing Δ, and this order is largely independent of the identity of the ligand. Mn2+ < Ni2+ < Co2+ < Fe2+ < V2+ < Fe3+ < Cr3+ < V3+ < Co3+

Linkage isomerism will be shown by which of the following?

i. SO32- ii. NO2- iii. SCN

  1. Only 1

  2. Only 2

  3. Only 1 and 3

  4. Only 2 and 3

  5. All of the above


Correct Option: E
Explanation:

All the three given ligands will show linkage isomerism. The sulphito group (SO32-), an ambidentate ligand, can be coordinated to metal ions through either the oxygen or the sulphur. So, it will show linkage isomerism. NO2- is an ambidentate ligand. It can attach at either the nitrogen atom or the oxygen atom. Hence, it will show linkage isomerism. SCN is an ambidentate ligand. Since it can attach at either the sulphur atom or the nitrogen atom, it will show linkage isomerism.

Which of the following statements is incorrect?

  1. [Mn(CN)6]3-, [Fe(CN)6]3- and [Co(C2O4)3]3- are diamagnetic inner orbital complexes that involve d2sp3 hybridisation.

  2. The ligand field strength increases in the order SCN- < C2O42- < NCS- < en < CO.

  3. [Mn2(CO)10] has one Mn-Mn bond and [Co2(CO)8] has one Co-Co bond.

  4. [MnCl6]3-, [FeF6]3- and [CoF6]3- are paramagnetic outer orbital complexes that involve sp3d2 hybridisation.

  5. M-C bond length in [Fe(CN)6]3- is lower than that in [Mn(CN)6]3-.


Correct Option: A
Explanation:

Correct Answer: [Mn(CN)6]3-, [Fe(CN)6]3- and [Co(C2O4)3]3- are diamagnetic inner orbital complexes that involve d2sp3 hybridisation.

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