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Transition Elements and their Compounds

Description: transition elements General Characteristics of 3d ElementsValence Bond and Crystal Field TheoryCoordination Complexes
Number of Questions: 15
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Tags: transition elements General Characteristics of 3d Elements Valence Bond and Crystal Field Theory Coordination Complexes
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Which of the following pairs of ‘transition metal - its ore’ is not correctly matched?

  1. Ni - pentlandite

  2. Co - linnaeite

  3. Nb - scheelite

  4. Cu - malachite

  5. Hg - cinnabar


Correct Option: C
Explanation:

Scheelite is a calcium tungstate mineral with the chemical formula CaWO4. Pyrochlorite (CaNaNb2O6) is an important ore/mineral of niobium.

Among the following, the ore(s) of titanium is/are

  1. ilmenite
  2. hausmannite
  3. linnaeite
  1. 1 only

  2. 2 only

  3. 3 only

  4. 1 and 2 only

  5. 2 and 3 only


Correct Option: A
Explanation:

Ilmenite (Fe.TiO3) is an oxide ore of titanium. Hausmannite (Mn3O4) is an oxide ore of manganese. Linnaeite (Co3S4) is the sulphide ore of cobalt. Hence, only ilmenite (Fe.TiO3) is the oxide ore of titanium.

Which of the following statements is/are false? (P) Manganese is used as scavenger in making steel. (Q) All known isotopes of technetium are radioactive, except 98Tc. (R) Rhenium is used in making electric furnace windings and spectrophotometer filaments.

  1. P only

  2. Q only

  3. P and Q

  4. Q and R

  5. All of these


Correct Option: B
Explanation:

(P) Manganese is an important additive in steel making and acts as a scavenger as it has the property of removing both oxygen and S and thus preventing bubbles and brittleness. (Q) Technetium (99Tc) was the first man-made element with radioactive property. All known isotopes of technetium (includes 97Tc, 98Tc) have radioactive property. It is one of the fission products of uranium. It obtained by spent fuel rods in nuclear reactors. (R) Rhenium is used in making electric furnace windings and spectrophotometer filaments due to its very high melting point (3180oC).

Which of the following matches of ‘element/ion- its electronic configurations’ is not correct?

  1. V - 3d34s2

  2. Cu - 3d104s1

  3. Fe2+ - 3d64s1

  4. Mn2+ - 3d74s0

  5. Sc+ - 3d14s1


Correct Option: D
Explanation:

26Mn2+has the electronic configuration of 3d54s0. 3d74s0 is the electronic configuration of 27Co2+.

Identify the incorrect statement(s).

  1. In floatation process, ZnO and SO3 are formed from sulphide ores.
  2. To prevent corrosion of Zn, Fe is used as coating material.
  3. Cd metal is used in nuclear reactors as neutron excitation material.
  4. Mercury is used extensively in the production of sodium hydroxide and chlorine gas commercially.
  1. 1 and 2

  2. 2 and 3

  3. 3 and 4

  4. 1, 2, 3

  5. 2, 3, 4


Correct Option: B
Explanation:
  1. The floatation process is the concentration method of sulphide ores. Zinc ores mainly ZnS are concentrated by floatation method, then roasted in air to give ZnO and SO2.
    1. Zn is used extensively for coating for the appliances made up of corrosive metals like Fe to prevent them from rusting.
    2. Cd metal absorbs neutrons very well, and is used to make control rods in nuclear reactors.
    3. The largest use of mercury is in electrolytic cells for the production of sodium hydroxide and chlorine gas at commercial level.

Match the entries in Group - I with Group - II.

 
Group - I
Group - II
A. Wilkinson’s catalyst 1. Pt/PtO
B. Adams catalyst 2. [PH3P]3.Rh.Cl
C. Lazier catalyst 3. TiCl4/Al(C2H5)3
D. Ziegler-Natta catalyst 4. 2CuO.Cr2O3
  1. A - 2, B - 1, C - 4, D - 3

  2. A - 2, B - 4, C - 1, D - 3

  3. A - 1, B - 2, C - 4, D - 3

  4. A - 4, B - 1, C - 2, D - 3

  5. A - 4, B - 2, C - 1, D - 3


Correct Option: A
Explanation:

Wilkinson’s catalyst ([PH3P]3.Rh.Cl) is used in hydrogenation of alkenes. Adams catalyst (Pt/PtO) is used in various reduction reactions. Lazier catalyst (2CuO.Cr2O3) is an effective catalyst for the reduction of aldehydes, ketones and esters to the corresponding alcohols, and aliphatic double bonds. Ziegler-Natta catalyst (TiCl4/Al(C2H5)3) is used in the synthesis of polymers of alpha-olefins. Hence, the representation of codes A - 2, B - 1, C - 4, D - 3 is correct.

Match the List - A (metal), List - B (ore) and List - C (ore type) and select the correct answer using the codes given below the lists.

   
List - A
List - B
List - C
P. Cu 1. Smaltite i. Sulphide
Q. Zn 2. Chalcocite ii. Arsenide
R. Fe 3. Franklinite iii. Carbonate
S. Co 4. Siderite iv. Oxide
  1. P - 3 - i, Q - 2 - iv, R - 4 - iii, S - 1 - ii

  2. P - 2 - i, Q - 3 - iv, R - 1 - iii, S - 4 - ii

  3. P - 2 - i, Q - 3 - ii, R - 1 - iii, S - 4 - iv

  4. P - 2 - i, Q - 3 - iv, R - 1 - ii, S - 4 - iii

  5. P - 2 - i, Q - 3 - iv, R - 4 - iii, S - 1 - ii


Correct Option: E
Explanation:

Chalcocite (CuS) is a sulphide ore of copper. Franklinite (ZnO.Fe2O3) is an ore of zinc. Siderite (FeCO3) is the carbonate ore of iron. Smaltite (CoAs2) is the arsenide ore of cobalt. Hence, the correct answer is P - 2 - i, Q - 3 - iv, R - 4 - iii, S - 1 - ii.

Match the entries in Group-I (element) with those in Group-II (electronic configuration) and select the correct answer using the codes given below.

 
Group - I
Group - II
P. Cu 1. 4d7, 5s1
Q. Mo 2. 4d8, 5s1
R. Ru 3. 3d10, 4s1
S. Rh 4. 4d5, 5s1
  1. P - 3, Q - 4, R - 1, S - 2

  2. P - 2, Q - 4, R - 1, S - 3

  3. P - 3, Q - 1, R - 4, S - 2

  4. P - 2, Q - 3, R - 1, S - 4

  5. P - 2, Q - 3, R - 4, S - 1


Correct Option: A
Explanation:

29Cu has the electronic configuration of 3d10, 4s1. 42 Mo has the electronic configuration of 4d5, 5s1. 44 Ru has the electronic configuration of 4d7, 5s1. 45Rh has the electronic configuration of 4d8, 5s1.

Hence, the correct answer is P - 3, Q - 4, R - 1, S - 2.

The clusters of H3Ru3NiCp(CO)9 is used to catalyse

  1. Ammonia synthesis

  2. CO methanation

  3. CO2 methanation

  4. Hydrodesulfurisation

  5. Butane hydrogenolysis


Correct Option: A
Explanation:

H3Ru3NiCp(CO)9 clusters contain Ru-Ni as core metals and catalyse the ammonia synthesis.

In an extraction of iron, which of the following constitutes the ‘charge’ in the blast furnace besides coke and oxide ore?

  1. Quicklime

  2. Limestone

  3. Dolomite

  4. Silica

  5. None of these


Correct Option: B
Explanation:

The mixture of iron ore, coke and limestone is called ‘charge’. Iron ore is not pure iron oxide. It also contains an assortment of rocky material. This wouldn't melt at the temperature of the furnace, and would eventually clog it up. The limestone is added to convert this into slag which melts and runs to the bottom. The heat of the furnace decomposes the limestone to give calcium oxide.

Identify the incorrect statement(s). (P) The central metal atom shows +VI oxidation state in potassium chromate and potassium dichromate. (Q) Limonite and willemenite are ores of zinc. (R) Zinc oxide is called as white lead and used as a whitening material.

  1. P only

  2. Q only

  3. R only

  4. P and Q only

  5. Q and R only


Correct Option: E
Explanation:

P. The central metal atom in potassium chromate and potassium dichromate is Cr. Chromium has +VI oxidation state in K2CrO4 and K2Cr2O7. Q. Limonite (Fe2O3.3H2O) is an ore of iron and willemite is an ore of zinc. R. Zinc oxide is an inorganic compound with the formula ZnO. ZnO is a white powder that is insoluble in water, and it is widely used as an additive in numerous materials and products including rubbers, plastics, ceramics, glass, cement, etc. White lead (PbCO3).2Pb(OH)2 is a complex chemical compound containing both a carbonate and a hydroxide portion and occurs naturally as a mineral for lead. White lead compounds were used as pigmenting materials like cement, lubricants, etc. but due to its toxicity, it is not used frequently.  Hence, both the statements Q and R are incorrect.

Which of the following d-electronic configurations in an octahedral complex will give maximum CFSE?

  1. Low spin-d4

  2. High spin-d4

  3. Low spin-d5

  4. High spin-d5

  5. High spin-d7


Correct Option: C
Explanation:

In octahedral complexes, CFSE is given by the formula: CFSE = value of t2g (n) + value of eg (n) Dq, Now, CFSE for low-spin d4 = -4 (4) + 6 (0) = -16 + 0 = -16 Dq CFSE for high-spin d4 = -4 (3) + 6 (1) = -12 + 6 = -6 Dq CFSE for low-spin d5 = -4 (5) + 6 (0) = -20 + 0 = -20 Dq CFSE for high-spin d5 = -4 (3) + 6 (2) = -12 + 12 = 0 Dq CFSE for low-spin d7 = -4 (5) + 6 (2) = -20 + 12 = -8 Dq Hence, low-spin d5 will give maximum CFSE in an octahedral complex.

Which metal ion represents zero value of CFSE, if it is associated with weak field ligand?

  1. Fe3+

  2. Fe2+

  3. Cr2+

  4. Mn+

  5. Mn3+


Correct Option: A
Explanation:

In a weak field ligand, the filling of electrons is in accordance with Hund’s rule. The CFSE is given by the formula  CFSE = value of t2g (n) + value of eg (n) Dq, Fe3+ corresponds to the d5 configuration. Now, CFSE for Fe3+ (d5) = - 4 (3) + 6 (2) = - 12 + 12 = 0 Dq CFSE for Fe2+ (d6) = - 4 (4) + 6 (2) = - 16 + 12 = - 4 Dq CFSE for Cr2+ (d4) = - 4 (3) + 6 (1) = - 12 + 6 = - 6 Dq CFSE for Mn+ (d6) = - 4 (4) + 6 (2) = - 16 + 12 = - 4 Dq CFSE for Mn3+ (d4) = - 4 (3) + 6 (1) = - 12 + 6 = - 6 Dq Hence, the metal ion with zero CFSE is Fe3+ when it is associated with weak field ligand.

Match the List - A (transition metal/complex) with List - B (uses) and select the correct answer using the codes given below.

 
List - A
List - B
A. Hf 1. Polymerisation
B. AlEt3/TiCl4 2. Making of lead free petrol
C. VC2 3. Neutron moderator
D. Pt-Re alloys 4. Ethyne production
  1. A - 2, B - 1, C - 4, D - 3

  2. A - 3, B - 4, C - 1, D - 2

  3. A - 3, B - 1, C - 4, D - 2

  4. A - 4, B - 2, C - 1, D - 2

  5. A - 4, B - 1, C - 2, D - 3


Correct Option: C
Explanation:

Hafnium is used to make control rods for regulating the free neutron levels in the nuclear reactors employed in submarines. The mixture of AlEt3 and TiCl4 is called Zeigler-Natta catalyst and is used extensively in polymerising alkenes (like ethylene to polyethylene). VC2 (vanadium carbide) on treated with water produce ethyne and thus it is used in the production of ethyne. Pt-Re alloys are used as catalysts for making low-lead or lead free petrol. Hence, the correct sequence is A - 3, B - 1, C - 4, D - 2.

Which of the following statements is/are false? P. CuCl2 is used as a catalyst in the manufacture of ammonia by Haber process. Q. CuCl exhibits blue colour in aqueous solution. R. Fractional crystallisation of metals to get maximum pure form is known as zone-refining.

  1. P only

  2. Q only

  3. R only

  4. P and Q

  5. Q and R


Correct Option: D
Explanation:

P. Iron (Fe) is used as a catalyst in the manufacture of ammonia by Haber process. CuCl2 is used as catalyst in Deacon process for the preparation of Cl2 from HCl. Q. CuCl in aqueous solution form Cu+ ions, which possess no colour due to the presence of completely filled d-orbitals. R. Zone melting is a group of techniques used to purify an element or a compound/metal or control its composition by melting a short region (i.e. zone) and causing this liquid zone to travel slowly through a relatively long ingot, or charge of the solid. As the zone travels, it redistributes impurities along the charge. The final distribution of the impurity depends on its distribution in the starting charge of material. This method is based on fractional crystallisation and so it is also called as zone-refining. Hence, both the statements P and Q are false.

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