this answer is correct because Berrylium is having typically small size which leads to formation of covalent compounds and its anamolous propertis because of which it is not considered as an alkaline earth metal compound.

this option is correct because higher the hydration enthalpy more molecules of water will get attached to the molecule and hence higher will be the formation of hydrated compounds.

this answer is correct because in Mg the outermost electons are tightly bonded because of the nuclear force of attraction and cannot be excited to the higher energy level by the energy provided by the flame and hence it does not respond to the flame test.

this option is correct because radium is having radioactive isotopes and is used in radiotherapy whic in turn is used in cancer therapy.

this option is correct because Be being small in size does not react directly to form hydride however its hydride can be obtained by the reduction of berrylum chloride with lithium aluminium hydride as per the following reaction:2BeCl₂ + LiAlH₄  ------------> 2BeH₂ + HCl + AlCl₃

this option is correct because halides of Be are covalent in nature because of its small size and hence are soluble in organic solvents like benzene.

this option is correct because magnesium is present in chlorophyll and helps in capturing he energy from the sunlight for making food for plants.

With base: Be(OH)₂ + 2OH^- ---------> [Be(OH)₄]^2- With acid: Be(OH)₂ + 2HCl + 2H₂O -----------> [Be(OH)₄]Cl₂

The hydroxide of beryllium is amphoteric in nature and beryllium has covalent nature also, because of which it is least soluble and has lowest value of K_sp.

this option is correct because BeCl2 invapour phase exist as a chain structure and forms a chloro bridged dimer.

this option is correct because Ma comes higher than Boron and silicon in the electrochemical series hence can be used as a reducing agent in the metallurgy of boron and silicon.

this option is correct because actually solubility decreases as the atomic number of the metal ion increases and it becomes less stable with increasing atomic number of the metal ion involved.

This option is correct.

this option is correct because when cation exchange resin is first treated with carboxylic acid it becomes capable of donating its hydrogen ions and when comes in contact with the hardness causing cations it exchanges is H⁺ ions with the hardness producing cation.

this option is correct because in electronic configuration of be is 1s²2s² which is not involving d orbitals hence it cannot extend its coordination number more than four as its it not having a d orbital.

This option is correct because superoxide species is represented as O₂^- since compound on a awhole is neutral hence oxidation state of potassium is +1.

Sodium remains outside the cell fluid and helps in nerve signal transmission.

this option is correct because in alkali metals when one elctron is detached from the outermost shell then it acquires noble gas configuration resuting in large second ionisation enthalpy and hence it does not show +2 oxidation state.

this option is correct because K⁺ ion is having a great biological significance as it remains present within the cell fluid and supports the sodium pump or sodium potassium pump

this option is correct because all the options are correctly matched as sodium carbonate is used as a detergent and sodium silicate in glass, sodium hydroxide in absorption of SO2 and sodium oxy chloride in bleaching action.

This option is correct because of the high solubility of K₂CO₃ in solution it cannot be precipitated out as Na₂CO₃ and hence solvay process cannot be employed for the formation of K₂CO₃

this option is correct because of this factor only it is usedas a collant as in nuclear eactors it has to withstand high temperatures which is supported by its high specefic heat.

This option is correct because of electrolysis of brine solution is carried out in castner kellner cell for the formation of sodium hydroxide ommercially.

With the increase in atomic number, the extent of hydration decreases and hence, the ions become less heavy, which leads to the higher mobility.

This option is correct because the advantage of low solubility is taken and sodium carbonate is precipitated from the solution