This is the right answer. Since, Length of the wire = Circumference of the ring 314 cm = 2 * pi * radius radius = 314/ (2 * 3.14) = 50 cm

Ans: 50 cm

This is the correct answer because Length of the rectangular garden = 40 m Breadth of the rectangular garden = 15 m Perimeter of the garden = 2(length + breadth)                                             = 2(40 m + 15 m)                                             = 2(55 m) = 110 m

Ans: 110 m

This is the right answer because the side of the square chart paper = 13 cm Area of the square chart paper = side * side                            = 13 cm * 13 cm = 169 sq. cm Radius of the colourful sticker = 7 cm Perimeter or circumference of the sticker = 2 * pi * radius                                             = 2 * 22/7 * 7 = 44 cm Perimeter or circumference of the sticker = 44 cm

Ans: 169 sq. cm; 44 cm

This is the right answer. Length of the lawn = 60 m Breadth of the lawn = 50 m Length of each part of the lawn = 30 m. Breadth of each part of the lawn = 25 m. Perimeter of each part of the lawn = 2(length + breadth)                        = 2(30 + 25)m =2 * 55 m = 110 m

Though the formulation is correct but the unit of area is sq. units. So it is the incorrect option as asked in the question.

This is the correct answer. Since a semicircular garden with its diameter as one of the lengths of rectangular house is to be constructed, it means length of the house = diameter of garden Area of the house = 2200 sq. m Breadth of the house is = 11 m Area of the house = length * breadth             2200 sq. m = length * 11 m                 (2200/11) m = length                      200 m = length Length = diameter = 200 m Radius of the semicircular garden is = diameter/2 = (200/2) m                                                         = 100 m

Ans. 100 m

Length of the table top = 34 cm Breadth of the table top = 15 cm Area of the table top to be polished = length * breadth                                                         = 34 cm * 15 cm                                                       = 510 sq.cm Cost of polishing 1 sq.cm area = Rs. 12  Cost of polishing 510 sq.cm = Rs.(12 * 510) = Rs. 6120

Ans. Rs. 6120

Since same wire is used to make a square shape and circular shape, so both will have same circumference/perimeter. Perimeter of square shape = Circumference of circular shape.

This is the right answer as:- Diameter of semicircular silver wire = 70 cm Radius of semicircular silver wire = 70/2 = 35 cm Circumference of the gold ring = circumference of the semicircular silver wire (given in the question) 2 * pi * radius of gold ring = pi * radius of the silver wireradius of gold ring = (pi * radius of the silver wire)/(2 * pi) radius of gold ring                                    = 35 cm/2                                    = 17.5 cm

Ans. 17.5 cm

This is the correct option because both the statements are true in context to 'Area and Perimeter'.

Diameter of old circle = 2 r Radius = r Area = pi * radius * radius Radius of new circle = 2 r Area of new circle = pi * 2 r * 2r                      => pi * 4 * radius * radius Ratio = area of old circle / area of new circle            => 1/4

Ans. 4 * pi * r * r ; 1/4

This is the right answer because:- Length of the window frame = 4m Breadth of the window frame = 2m Area of the window frame = Length * Breadth = 4m * 2m => 8 square meters Length of the wall = 15 m Breadth of the wall = 10 m Area of the wall = Length * Breadth                      = 15 m * 10 m                      =>150 square meters Area to be painted = Area of wall -Area of window frame                                   = 150 sq. m - 8 sq.m                                  = 142 sq.m Cost of painting 1 sq. m = Rs. 3.50 Cost of painting 142 sq.m = Rs. 142 * 3.50                                                 => Rs.497

Ans. Rs. 497

Length of big chart paper = L Breadth of big chart paper = B Area of big chart paper = L x B = LB sq. c m Length of small piece of paper = L/3 Breadth of of small piece of paper = B/3 Area of small piece of paper = L/3 x B/3 = LB/9 sq. cm Ratio = Area of big chart paper / Area of small piece of paper = LB/(LB/9) = 9 : 1

Distance covered in 4 rounds = 42 m Distance covered in 1 round = 42 / 4                                                    =10.5 m Distance covered in 1 round = Circumference of the circle                  = >2 * pi * radius = 10.5 m       radius =10.5 m / (2 * pi) = 1.7 m Area of the circular shape = pi * radius * radius                                                 =>3.14 * 1.7 * 1.7                                              = 9.1 sq. m. Ans. 9.1 sq. m

Length of the tile = 50 m Breadth of the tile = 5 m Area of each tile = Length x breadth             =>50 m x 5 m             =250 sq. m Area to be covered = 45000 sq. m Number tiles of required = Area to be covered /Area of each marble tile                                              = 45000/250                                              = 180 tiles

Area of square sheet = 169 sq.cm Side x side = 169 sq.cm Side = 13 cm Since, square is divided into four circles, so radius of each circle = 1/4 of side of the square = 13/4 = 3.25 cm Circumference of each circle = 2 x pi x radius 2 x 3.14 x 3.25 cm = 20.41 cm Ans. 20.41 cm

Let length of the rectangle is A New length = 2A Let breadth of the rectangle is B New Breadth = B/2 New Area = A x B = AB (Same as old area) New perimeter = 2(2A+B/2) = 4A +B

This is a right answer.

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