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Aptitude

Description: Numerical Ability Numerical Ability
Number of Questions: 15
Created by:
Tags: Numerical Ability
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A room 18 metres and 42 cm long and 15 metres and 35 cm wide, is to be paved with minimum number of square tiles. The number of tiles needed is

  1. 15

  2. 30

  3. 21

  4. 18

  5. 16


Correct Option: B
Explanation:

It is correct answer.Solution:Maximum size of square tile = HCF of 15.35 and 18.42 = 3.07No. of tiles = (18.42 * 15.35)/(3.07 * 3.07) = 30

A positive number is divided by 4, instead of being multiplied by 4. By what percent is the result of the required value?

  1. 6.00

  2. 6.25

  3. 6.75

  4. 5.25

  5. 6.50


Correct Option: B
Explanation:

It is correct answer.Solution :Let the no. be x.

Then the correct answer is 4x.

The incorrect value obtained is x/4.

The required % = ((x/4)/4x) * 100 = 6.25%

The mean of 15 numbers is 60. If the mean of first 8 results is 59 and that of last 8 results is 63, find the 8th result.

  1. 86

  2. 104

  3. 50

  4. 76

  5. 62


Correct Option: D
Explanation:

It is correct answer.Sum of 15 results =(15*60) = 900Sum of First 8 results=(8*59) = 472Sum of Last 8 results= (8*63) = 504It is quite obvious that the 8th result is included twice.Therefore,value of the 8th result = Sum of 1st eight results + Sum of last eight results - Sum of 15 results                                                            =  472 + 504 - 900 = 76

The difference between simple interest and compound interest on a sum of money at 6% per annum for 2 years is Rs. 216. Find the sum.

  1. Rs. 50,000

  2. Rs. 65,000

  3. Rs. 60,000

  4. Rs. 62,000

  5. Rs. 70,000


Correct Option: C
Explanation:

It is correct answer.

Let the sum be Rs x.

Therefore,  Simple Interest = x*6*2/100 = 0.12x           Compound Interest = x (1+6/100)^2 - x =0.1236x    

Difference in CI and SI =0.12x - 0.1236x = 0.0036x 

Difference which is given = 216 * 10000/36= 60,000

If the cost price of 15 articles be equal to selling price of 20 articles, what is the loss or profit percentage?

  1. 25% loss

  2. 20 % loss

  3. 20% gain

  4. 25% gain

  5. No loss or gain


Correct Option: A
Explanation:

It is correct answer.

Solution :

Profit / loss percentage = - 5/20 * 100 = 25%

Loss as it is in negative.

Vikram, Vivek and Vikrant can do a work 3, 4and 5 days, respectively. On completing that work together, they get an amount of Rs. 4700. What is the individual share of each one of them in that amount?

  1. 1200, 2500 and 1000 respectively

  2. 1800, 2000 and 2500 respectively

  3. 2000, 1500 and 1200 respectively

  4. 1300, 1400 and 2000 respectively

  5. 800,1600 and 2300 respectively


Correct Option: C
Explanation:

It is correct answer. Solution : Vikram's one day work  = 1/3

Vivek's one day work =1/4 Vikrant's one day work =1/5 Vikram's share : Vivek's share : Vikrant's Share=   1/3 : 1/4 : 1/5 The ratio becomes 20 : 15 : 12 (By Finding L.C.M) Vikram's Share=20/47*4700=2000 Vivek's Share=15/47*4700=1500 Vikrant's Share=12/47*4700=1200

The minute hand of a clock overtakes the hour hand at intervals of 63 minutes of the correct time. How much does the clock gain or lose?

  1. 27/11

  2. 540/77

  3. 1440/143

  4. 65/11

  5. 470/77


Correct Option: B
Explanation:

It is a correct answer. Solution : In a correct clock, the minute hand gains 55 min, over the hour hand in 60 min. To be together again,the minute hand must gain 60 minutes over the hour hand. 55min are gained in = 720/11 min But they are together after 63 min. Therefore, Gain in 63 min = (720/11)-63 = 27/11 min. Gain in 24 hours = (27/11) * 60 * 24/63 = 540/77 min.

A taxi leaves from Dehradun at 6 a.m. and reaches Delhi at 12 noon. If another taxi leaves Delhi at 10 a.m. and reaches Dehradun at 7 p.m., then at what time do the taxis meet?

  1. 11:20 a.m.

  2. 10:50 a.m.

  3. 12 noon

  4. 10 a.m.

  5. 11 a.m.


Correct Option: A
Explanation:

It is correct answer. Solution :

Converting all the time into 24hr format we get 6 a.m=6:00 , 12 noon = 12:00, 10 a.m = 10:00 and 7 p.m = 19:00

Required Time = 600+((1200-600)*(1900-600)/((1200-600)+(1900-1000))) = 600 + 520 = 11:20  ...............i.e 11:20 a.m

A leak in the bottom of the container can empty it in 6 hours. A pipe fills in the container at the rate of 4 litres/minute. When the container is full, the inlet in opened but due to the leak, the container is emptied in 8 hours. What is the capacity of the tank?

  1. 8590 litres

  2. 5000 litres

  3. 3750 litres

  4. 2440 litres

  5. 5760 litres


Correct Option: E
Explanation:

It is the correct answer. Solution : Combined 1 hour work of the inlet and leak is 1/8 hour. 1 hour work of inlet = 1/x 1/6 - 1/x = 1/8 x = 24 hour Rate of inlet = 4 litre/minute = 240 litre/hr Capacity of the container = 24*240=5760 litre

The average of the marks secured by 30 students of Grade A is 50, that of 40 students of Grade B is 30 and that of 45 students of Grade C is 55. What is the combined average of the students of the three grades?

  1. 49.28

  2. 45

  3. 43.26

  4. 1725

  5. 38.33


Correct Option: B
Explanation:

It is a correct answer.

Solution  = (30*50 + 40*30 + 45*55) / (30+40+45)                  =(1500 + 1200 + 2475) / 115                  =5175/115                  =45

Suman takes thrice as much time as Rahul and four times as much as Varun to finish a task. They together complete the task in one day. Find the time taken by each of them to complete the task.

  1. 6 days

  2. 14 days

  3. 5 days

  4. 10 days

  5. 8 days


Correct Option: E
Explanation:

It is correct answer.

Let alone time of Suman be x .

Then alone time of Rahul = x/3 and that of Varun be x/4.

Suman's one day work + Rahul's one day work + Varun's one day work = Combined one day work                     

   (1/x) + (1/(x/3)) + (1/(x/4)) = 1                                                  x = 8

In a cricket match,1/5 of all the seats is located in the front section. 5/6 of the seats in the front section of the stadium were sold. If 3/4 of all the seats were sold, then find the fraction of the unsold seats that were in the front section.

  1. 1/30

  2. 2/9

  3. 4/5

  4. 2/15

  5. 4/15


Correct Option: D
Explanation:

It is correct answer.Solution: Total Seats = cSeats in front section = a (i.e 1/5*c)a = c/5 Seats sold in front section = 5/6*a = (5/6*c/5) = c/6Seats unsold in front section = c/5 - c/6 = c/30Total seats sold = 3/4*cTotal seats unsold = c/4Fraction of seats unsold in front section = 2c/15

The number of ways in which 21 people can sit around a conference table so that none of them have the same neighbours in any two arrangements is

  1. 20!*2

  2. 21!/2

  3. 21!

  4. 20!/2

  5. 20!


Correct Option: D
Explanation:

It is the correct answer.

Solution : 21 people can sit around a conference table in 20! ways (Fixing the position of 1 person in each case)

But in the above we have included both clockwise and anticlockwise orders that will have the same neighbours.

Hence,the required no. of arrangements are 1/2 * 20!.

It is a correct answer.

Vivek is 3 times as old as Tarun. Sourabh was twice as old as Vivek 4 years ago. In 4 years, Vivek will be of 31 years. What is the present age of Tarun and Sourabh, respectively?

  1. 9 and 50

  2. 9 and 54

  3. 12 and 60

  4. 9 and 46

  5. 50 and 9


Correct Option: A
Explanation:

It is a correct answer .Solution-Let Vivek's present age = x Similarly,Let Tarun's present age = y and Sourabh's present age = z
We know, x = 3*y z-4 = 2*(x-4) and (x+4) = 31 (Given In statement) x=27 Therefore, y = 9 z = 50 The age of tarun is 9 years and of sourabh is 50 years.

Six balls are drawn at random from a bag containing six white, five green and four black balls. The probability that exactly 3 of them are white is

  1. 16/143

  2. 48/143

  3. 12/143

  4. 32/143

  5. 4/1001


Correct Option: B
Explanation:

It is the correct answer. Solution- Total no of balls = 15No of ways of drawing 6 balls from 15 balls randomly=15C6 No of ways of drawing 3 white balls from 6 white balls = 6C3 No of ways of drawing other 3 balls from remaining 9 balls = 9C3 Required probability=(6C3 * 9C3) / 15C6 = 48/143

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