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Coordination Compounds

Description: GATE, IIT, CSIR NET ENGINEERING ETC
Number of Questions: 15
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Tags: GATE Coordination Complexes
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Which of the following sets is an example of double salt?

  1. Fischer salt, zeise’s salt, gmelin’s salt

  2. Magnus’ green salt, turnbull’s blue, mohr salt

  3. Glauber’s salt, microcosmic salt, carnallite

  4. Potash alum, mohr salt, gmelin’s salt

  5. Tutton salts, bromlite, peyrone's salt

Show answer
Correct Option: C
Explanation:

This option is correct because all are double salt.

Which of the following statements is/are true? A. Metal carbonyl and Zeisse’s salt are the example of organometallic compounds. B. Wilkinson’s catalyst contains Ti+4 as the metal cation. C. Cobalt as Co+3 is present in vitamin B12.

  1. Only A

  2. Only B

  3. Only C

  4. A and B

  5. B and C

Show answer
Correct Option: A
Explanation:

This option is correct because metal carbonyl and Zeise’s salt are examples of organometallic compounds.

In coordination complexes, the hydrate isomers differ A. in the number of water molecules of hydration only B. in the number of water molecules only present as ligands C. in their coordination number of the metal atom

  1. Only A

  2. Only B

  3. Both 1 and 2

  4. Only C

  5. All of these

Show answer
Correct Option: C
Explanation:

This option is correct because hydrate isomers differ in the number of water molecules as hydration as ligands.

Which of the following statements is/are incorrect? A. The complex ion trans-dichloro bis (ethylenediamine) rhodium (III) is optical active. B. Secondary valancies are non-directional whereas primary valencies are directional. C. Both geometrical and optical isomerisms are shown by [Co(en)2Cl2]+.

  1. Only A

  2. Only B

  3. Both 1 and 2

  4. Only C

  5. Both 2 and 3

Show answer
Correct Option: C
Explanation:

This option is correct because trans-dichloro bis (ethylenediamine) rhodium(III) is symmetrical and therefore, is optically inactive and according to Werner’s theory, secondary valancy is directional whereas primary valency is non-directional.

An ambidentate ligand A. is linked to the metal atom at two points B. has two donor atoms but only one of the has the capacity to form a coordinate bond C. has two donor atoms but either of two can form a coordinate bond

  1. Only A

  2. Only B

  3. Only C

  4. A and C

  5. B and C

Show answer
Correct Option: C
Explanation:

This option is correct because ambidentate ligand is a monodentate ligand has two donor atoms but either of two can form a coordinate bond.

Geometrical isomerism in coordination compounds is exhibited by __________.

  1. only tetrahedral complexes

  2. square planar and tetrahedral complexes

  3. square planar and octahedral complexes

  4. tetrahedral and octahedral complexes

  5. square planar, tetrahedral and octahedral complexes

Show answer
Correct Option: C
Explanation:

Geometrical isomerism in coordination compounds is exhibited by square planar and octahedral complexes because they have centre of symmetry. Thus, this option is correct.

‘Class a’ acceptors are the metal ions belonging to which of the follwoing? A. Group 1 and 2 B. Inner transition elements C. Transition elements belonging to groups 3 to 6

  1. Only A

  2. Only B

  3. Only C

  4. A, B and C

  5. A and C

Show answer
Correct Option: D
Explanation:

This option is correct because metals ions of group 1, 2, 3, 4, 5, 6 and inner transition elements are classified as ‘class a’ acceptors.

Which of the following statement is correct? A. Coordination compounds are only formed by d- and f-block elements. B. Ni(CO)4 is square planar with dsp2 hybridization. C. [Cu(NH3)4]+2 is square planar in shape.

  1. Only A

  2. Only B

  3. Only C

  4. All of these

  5. None of these

Show answer
Correct Option: C
Explanation:

This option is correct because [Cu(NH3)4]+2 involves dsp2 hybridization with one electron occupying 4p orbital.

If ∆0 < P, the correct electronic configuration for d4 system will be

  1. T2g4, eg0

  2. T2g3, eg1

  3. T2g2, eg2

  4. T2g0, eg4

  5. None of these

Show answer
Correct Option: B
Explanation:

If ∆0 < P, the fourth electron will go to higher energy eg orbital. Thus, this option is correct.

Assertion: Ethylenediaminetetraacetate ion forms an octahedral complex with the metal ion. Reason: It has six donor atoms which coordinate simultaneously with metal ion.

  1. Both A and R are true and R is the correct explanation of A.

  2. Both A and R are true but R is not the correct explanation of A.

  3. A is true but R is false.

  4. A is false but R is true.

  5. Both A and R are false.

Show answer
Correct Option: A
Explanation:

This option is correct because EDTA has six donor atoms which coordinate with metal ion.

Which of the following is not correct? Organometallics can play an ever expanding role in the production of A. Pharmaceuticals B. Agrochemicals C. Flavours

  1. Only A

  2. Only B

  3. Only C

  4. A, B and C

  5. None of these

Show answer
Correct Option: E
Explanation:

This option is correct because organometallics can play an ever expanding role in the production of pharmaceuticals, agrochemicals and flavours.

Which of the following statements is/are true? A. Ni(CO)4 is square planar in shape. B. Strong ligands like CN- forms high spin complexes. C. Fischer salt is a complex salt.

  1. Only A

  2. Only B

  3. Only C

  4. A and C

  5. B and C

Show answer
Correct Option: C
Explanation:

This option is correct because Fischer salt (K3[Co(NO2)6]) is a complex salt.

Which of the following statements is/are false? A. [Co(EDTA)]-4 complex is octahedral in shape. B. dsp2 and sp3 hybridization lead to the same geometry. C. Thiocarbonyl is an anionic ligand.

  1. Only A

  2. Only B

  3. A and B

  4. Only C

  5. B and C

Show answer
Correct Option: E
Explanation:

This option is correct because dsp2 and sp3 hybridization have square planar and tetrahedral geometries and thiocarbonyl is a neutral ligand.

Which of the following statements is incorrect? A. βn is equal to the product of K1, K2, K3 …… Kn. B. K1, K2, K3 …… Kn are called stepwise stability or formation constants. C. βn = K1 + K2 + K3 …… Kn.

  1. Only A

  2. Only B

  3. Only C

  4. A and B

  5. A and C

Show answer
Correct Option: C
Explanation:

This is correct because the overall stability constant (βn) is equal to the product of stepwise stability constants K1, K2, K3 ……Kn, i.e.,  βn = K1 ˣ K2 ˣ K3 ……Kn.

Match the list I (coordination compounds) with list II (isomers):

 
List - I
List - II
(i) [Co(NH3)5Br]SO4 and [Co(NH3)5SO4]Br a. Linkage isomers
(ii) [Co(NH3)6][Cr(CN)6] and [Cr(NH3)6][Co(CN)6] b. Ionisation isomers
(iii) [Cr(H2O)5Cl]Cl2.H2O and [Cr(H2O)4Cl2]Cl.2H2O c. Polymerisation isomers
(iv) [Pt(SCN)6](NH42 and [Pt(NCS)6](NH42 d. Coordination isomers
(v) [Co(NH3)6][Co(NO2)6] and [Co(NH3)3(NO2)3] e. Hydration isomers

  1. i - b, ii - d, iii - e, iv - a, v - c

  2. i - a, ii - d, iii - e, iv - b, v - c

  3. i - b, ii - c, iii - e, iv - a, v - d

  4. i - a, ii - c, iii - b, iv - d, v - e

  5. i - d, ii - e, iii - c, iv - b, v - a

Show answer
Correct Option: A
Explanation:

This option is correct because all the items present in list I are correctly matched with list II.

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