The Hardy-Weinberg equation states that the frequency of the heterozygous genotype is 2pq, where p and q are the frequencies of the two alleles.

Natural selection can alter allele and genotype frequencies, causing deviations from Hardy-Weinberg equilibrium.

The frequency of the recessive allele can be calculated using the Hardy-Weinberg equation: q^2 = 1 - p^2, where p is the frequency of the dominant allele.

To determine if a population is in Hardy-Weinberg equilibrium, we can use the chi-square test. In this case, the chi-square value is 10.24, which is significant (p < 0.05). Therefore, the population is not in Hardy-Weinberg equilibrium.

Mutation, gene flow, non-random mating, and natural selection can all cause deviations from Hardy-Weinberg equilibrium.

The Hardy-Weinberg equilibrium is a useful concept in population genetics because it provides a baseline for comparing real populations, helps identify populations that are evolving, and allows us to predict future allele and genotype frequencies.

The Hardy-Weinberg equation states that the frequency of the homozygous dominant genotype is p^2, where p is the frequency of the dominant allele.

The frequency of the heterozygous genotype can be calculated using the Hardy-Weinberg equation: 2pq = 2 * p * q, where p is the frequency of the dominant allele and q is the frequency of the recessive allele.

To determine if a population is in Hardy-Weinberg equilibrium, we can use the chi-square test. In this case, the chi-square value is 0.64, which is not significant (p > 0.05). Therefore, the population is in Hardy-Weinberg equilibrium.

The Hardy-Weinberg equilibrium does not assume a large population size. However, deviations from Hardy-Weinberg equilibrium are more likely to occur in small populations due to random genetic drift.

The Hardy-Weinberg equilibrium is a dynamic equilibrium, meaning that allele and genotype frequencies can change over time in response to evolutionary forces such as mutation, gene flow, non-random mating, and natural selection.

The Hardy-Weinberg equation states that the frequency of the homozygous recessive genotype is q^2, where q is the frequency of the recessive allele.

The frequency of the heterozygous genotype can be calculated using the Hardy-Weinberg equation: 2pq = 2 * p * q, where p is the frequency of the dominant allele and q is the frequency of the recessive allele.

To determine if a population is in Hardy-Weinberg equilibrium, we can use the chi-square test. In this case, the chi-square value is 0, which is not significant (p > 0.05). Therefore, the population is in Hardy-Weinberg equilibrium.

A large, randomly mating population with no mutation or natural selection is most likely to be in Hardy-Weinberg equilibrium because these conditions minimize the factors that can cause deviations from equilibrium.