The character's velocity when it hits the ground can be calculated using the equation: v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity (0 m/s), a is the acceleration due to gravity (9.8 m/s^2), and s is the distance fallen (10 m). Plugging in these values, we get: v^2 = 0^2 + 2 * 9.8 * 10, which simplifies to v^2 = 196. Taking the square root of both sides, we get v = 14 m/s.

The car's kinetic energy can be calculated using the equation: KE = 1/2 * mv^2, where KE is the kinetic energy, m is the mass of the car, and v is the velocity of the car. Plugging in the values, we get: KE = 1/2 * 1000 kg * (60 mph)^2. Converting 60 mph to m/s, we get: KE = 1/2 * 1000 kg * (26.82 m/s)^2, which simplifies to KE = 360,000 J.

The maximum height that the player character will reach can be calculated using the equation: v^2 = u^2 + 2as, where v is the final velocity (0 m/s), u is the initial velocity (5 m/s), a is the acceleration due to gravity (9.8 m/s^2), and s is the distance traveled. Rearranging the equation to solve for s, we get: s = (v^2 - u^2) / 2a. Plugging in the values, we get: s = (0^2 - 5^2) / (2 * 9.8), which simplifies to s = 17.5 meters.

The range of the ball can be calculated using the equation: R = v^2 * sin(2θ) / g, where R is the range, v is the initial velocity (10 m/s), θ is the angle of projection (0 degrees), and g is the acceleration due to gravity (9.8 m/s^2). Plugging in the values, we get: R = 10^2 * sin(2 * 0) / 9.8, which simplifies to R = 20 meters.

The force that the wall exerts on the player character can be calculated using the equation: F = ma, where F is the force, m is the mass of the player character, and a is the acceleration of the player character. Since the player character comes to a sudden stop, the acceleration is equal to the initial velocity divided by the time it takes to stop. Assuming that the time it takes to stop is very small, the acceleration can be approximated as infinite. Therefore, the force that the wall exerts on the player character is infinite.

The car's deceleration can be calculated using the equation: a = (v^2 - u^2) / 2s, where a is the deceleration, v is the final velocity (0 m/s), u is the initial velocity (60 mph), and s is the distance traveled (100 meters). Converting 60 mph to m/s, we get: a = (0^2 - 26.82^2) / (2 * 100), which simplifies to a = 20 m/s^2.

The impulse that the ground exerts on the player character can be calculated using the equation: J = mv, where J is the impulse, m is the mass of the player character, and v is the velocity of the player character just before impact. Assuming that the player character has a mass of 100 kg and a velocity of 10 m/s just before impact, the impulse that the ground exerts on the player character is 100 kg * 10 m/s = 1000 Ns.

The maximum height that the ball will reach can be calculated using the equation: v^2 = u^2 + 2as, where v is the final velocity (0 m/s), u is the initial velocity (10 m/s), a is the acceleration due to gravity (9.8 m/s^2), and s is the distance traveled. Rearranging the equation to solve for s, we get: s = (v^2 - u^2) / 2a. Plugging in the values, we get: s = (0^2 - 10^2) / (2 * 9.8), which simplifies to s = 20 meters.

The work done by gravity on the player character can be calculated using the equation: W = Fd, where W is the work done, F is the force of gravity (mg), and d is the distance traveled (10 meters). Assuming that the player character has a mass of 100 kg, the force of gravity is 100 kg * 9.8 m/s^2 = 980 N. Plugging in the values, we get: W = 980 N * 10 meters = 9800 J.

The work done by the brakes on the car can be calculated using the equation: W = Fd, where W is the work done, F is the force applied by the brakes, and d is the distance traveled (100 meters). Assuming that the force applied by the brakes is constant, the work done by the brakes can be calculated using the equation: W = (1/2)mv^2, where m is the mass of the car and v is the initial velocity of the car. Plugging in the values, we get: W = (1/2) * 1000 kg * (26.82 m/s)^2, which simplifies to W = 20000 J.

The power exerted by the player character during the jump can be calculated using the equation: P = W / t, where P is the power, W is the work done, and t is the time taken. Assuming that the player character takes 1 second to jump, the power exerted by the player character is 1000 J / 1 s = 1000 W.

The average force applied by the brakes on the car can be calculated using the equation: F = ma, where F is the force, m is the mass of the car, and a is the acceleration of the car. Assuming that the mass of the car is 1000 kg and the acceleration of the car is 20 m/s^2, the average force applied by the brakes on the car is 1000 kg * 20 m/s^2 = 2000 N.

The momentum of the player character just before impact with the ground can be calculated using the equation: p = mv, where p is the momentum, m is the mass of the player character, and v is the velocity of the player character just before impact. Assuming that the player character has a mass of 100 kg and a velocity of 10 m/s just before impact, the momentum of the player character is 100 kg * 10 m/s = 1000 kg m/s.

The coefficient of friction between the tires and the road can be calculated using the equation: f = μN, where f is the force of friction, μ is the coefficient of friction, and N is the normal force. Assuming that the normal force is equal to the weight of the car, the coefficient of friction can be calculated using the equation: μ = f / N. Plugging in the values, we get: μ = 2000 N / 10000 N = 0.2.