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teamwork Online Quiz - 2

Description: teamwork Online Quiz - 2
Number of Questions: 15
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Tags: teamwork
Attempted 0/15 Correct 0 Score 0

Sorted Input in aggregator transformation improves the session performance

  1. True

  2. False


Correct Option: A

When we enable the dynamic lookup cache then the designer adds port "NewLookupRow"

  1. True

  2. False


Correct Option: A
  1. Session Parameter,mapping Parameter,System variable

  2. System variable,Session Parameter,mapping Parameter

  3. System variable,mapping Parameter,Session Parameter

  4. None of above


Correct Option: A

what are the two modes of data movement in infomatica?

  1. Normal,Large

  2. Simple,Large

  3. Normal,Bulk

  4. none of above


Correct Option: C
  1. Static Cache

  2. Dynamic Cache

  3. Persistant Cache

  4. Shared Cache

  5. All the Above


Correct Option: E

when the source is file where can we set the file properties.

  1. session level

  2. mapping level

  3. worlflow level

  4. none of the above


Correct Option: A

we can call the stored procedure in ports like :SP.Identifier(arguments)

  1. True

  2. False


Correct Option: A

Examine the description of the STUDENTS table: STD_ID NUMBER(4) COURSE_ID VARCHAR2(10) START_DATE DATE END_DATE DATE Which two aggregate functions are valid on the START_DATE column? (Choose two.)

  1. SUM(start_date)

  2. AVG(start_date)

  3. COUNT(start_date)

  4. AVG(start_date, end_date)

  5. MIN(start_date)

  6. MAXIMUM(start_date)


Correct Option: C,E

AI Explanation

To answer this question, let's go through each option to determine which aggregate functions are valid on the START_DATE column:

Option A) SUM(start_date) - The SUM function is used to calculate the sum of numerical values. However, the START_DATE column is of type DATE, not a numerical value. Therefore, this option is incorrect.

Option B) AVG(start_date) - The AVG function is used to calculate the average of numerical values. Since the START_DATE column is of type DATE, this option is incorrect.

Option C) COUNT(start_date) - The COUNT function is used to count the number of rows or non-null values in a column. This function is valid for the START_DATE column since it counts the number of occurrences of the column values. Therefore, this option is correct.

Option D) AVG(start_date, end_date) - The AVG function calculates the average of numerical values. However, in this option, there are two columns provided (START_DATE and END_DATE), which is not valid for the AVG function. Therefore, this option is incorrect.

Option E) MIN(start_date) - The MIN function is used to find the minimum value in a column. Since the START_DATE column is of type DATE, this option is valid.

Option F) MAXIMUM(start_date) - The MAXIMUM function is not a valid aggregate function in SQL. Therefore, this option is incorrect.

The correct answers are C) COUNT(start_date) and E) MIN(start_date) because both functions are valid for the START_DATE column.

You would like to display the system date in the format "Monday, 01 June, 2001". Which SELECT statement should you use?

  1. SELECT TO_DATE (SYSDATE, 'FMDAY, DD Month, YYYY') FROM dual;

  2. SELECT TO_CHAR (SYSDATE, 'FMDD, DY Month, YYYY') FROM dual;

  3. SELECT TO_CHAR (SYSDATE, 'FMDay, DD Month, YYYY') FROM dual;

  4. SELECT TO_CHAR (SYSDATE, 'FMDY, DDD Month, YYYY') FROM dual;

  5. SELECT TO_DATE (SYSDATE, 'FMDY, DDD Month, YYYY') FROM dual;


Correct Option: C
  1. CASCADE

  2. UNIQUE

  3. NONUNIQUE

  4. CHECK

  5. PRIMARY KEY

  6. NOT NULL


Correct Option: B,D,E,F
  1. DROP emp_dept_vu;

  2. DELETE emp_dept_vu;

  3. REMOVE emp_dept_vu;

  4. DROP VIEW emp_dept_vu;

  5. DELETE VIEW emp_dept_vu;

  6. REMOVE VIEW emp_dept_vu;


Correct Option: D

Which is an iSQL*Plus command?

  1. INSERT

  2. UPDATE

  3. SELECT

  4. DESCRIBE

  5. DELETE

  6. RENAME


Correct Option: D

Which are DML statements? (Choose all that apply.)

  1. COMMIT

  2. MERGE

  3. UPDATE

  4. DELETE

  5. CREATE

  6. DROP


Correct Option: B,C,D

You need to modify the STUDENTS table to add a primary key on the STUDENT_ID column. The table is currently empty. Which statement accomplishes this task?

  1. ALTER TABLE students ADD PRIMARY KEY student_id;

  2. ALTER TABLE students ADD CONSTRAINT PRIMARY KEY (student_id);

  3. ALTER TABLE students ADD CONSTRAINT stud_id_pk PRIMARY KEY student_id;

  4. ALTER TABLE students ADD CONSTRAINT stud_id_pk PRIMARY KEY

  5. ALTER TABLE studentsMODIFY CONSTRAINT stud_id_pk PRIMARY KEY


Correct Option: D
  1. DELETE employees;

  2. DESCRIBE employees;

  3. ROLLBACK TO SAVEPOINT C;

  4. GRANT SELECT ON employees TO SCOTT;

  5. ALTER TABLE employeesSET UNUSED COLUMN sal;

  6. SELECT MAX(sal) FROM employees WHERE department_id = 20;


Correct Option: D,E
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