Brahmagupta's Contributions to Trigonometry Online Test

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Brahmagupta's Contributions to Trigonometry

Description: Brahmagupta's Contributions to Trigonometry
Number of Questions: 14
Created by: Aliensbrain Bot
Tags: indian mathematics contributions to trigonometry brahmagupta

Brahmagupta's formula for calculating the sine of an angle is given by:

$\sin A = \frac{\sin \frac{A}{2}}{\cos \frac{A}{2}}$
$\sin A = \frac{\sin A}{\cos A}$
$\sin A = \frac{\tan A}{\sec A}$
$\sin A = \frac{\cos A}{\sec A}$

Brahmagupta's formula for calculating the cosine of an angle is given by:

$\cos A = \frac{\cos \frac{A}{2}}{\sin \frac{A}{2}}$
$\cos A = \frac{\cos A}{\sin A}$
$\cos A = \frac{\tan A}{\csc A}$
$\cos A = \frac{\sin A}{\csc A}$

Brahmagupta's formula for calculating the tangent of an angle is given by:

$\tan A = \frac{\sin A}{\cos A}$
$\tan A = \frac{\cos A}{\sin A}$
$\tan A = \frac{\sin A}{\sec A}$
$\tan A = \frac{\cos A}{\csc A}$

Brahmagupta's formula for calculating the cotangent of an angle is given by:

$\cot A = \frac{\cos A}{\sin A}$
$\cot A = \frac{\sin A}{\cos A}$
$\cot A = \frac{\cos A}{\sec A}$
$\cot A = \frac{\sin A}{\csc A}$

Brahmagupta's formula for calculating the secant of an angle is given by:

$\sec A = \frac{1}{\cos A}$
$\sec A = \frac{\cos A}{\sin A}$
$\sec A = \frac{\sin A}{\cos A}$
$\sec A = \frac{\cos A}{\sec A}$

Brahmagupta's formula for calculating the cosecant of an angle is given by:

$\csc A = \frac{1}{\sin A}$
$\csc A = \frac{\sin A}{\cos A}$
$\csc A = \frac{\cos A}{\sin A}$
$\csc A = \frac{\sin A}{\csc A}$

Brahmagupta's formula for calculating the sine of the sum of two angles is given by:

$\sin(A + B) = \sin A \cos B + \cos A \sin B$
$\sin(A + B) = \sin A \sin B + \cos A \cos B$
$\sin(A + B) = \tan A \sec B + \cot A \csc B$
$\sin(A + B) = \cos A \sec B + \sin A \csc B$

Brahmagupta's formula for calculating the cosine of the sum of two angles is given by:

$\cos(A + B) = \cos A \cos B - \sin A \sin B$
$\cos(A + B) = \cos A \sin B + \sin A \cos B$
$\cos(A + B) = \tan A \sec B - \cot A \csc B$
$\cos(A + B) = \sin A \sec B + \cos A \csc B$

Brahmagupta's formula for calculating the tangent of the sum of two angles is given by:

$\tan(A + B) = \frac{\tan A + \tan B}{1 - \tan A \tan B}$
$\tan(A + B) = \frac{\tan A - \tan B}{1 + \tan A \tan B}$
$\tan(A + B) = \frac{\sin A + \sin B}{\cos A + \cos B}$
$\tan(A + B) = \frac{\cos A + \cos B}{\sin A + \sin B}$

Brahmagupta's formula for calculating the cotangent of the sum of two angles is given by:

$\cot(A + B) = \frac{\cot A \cot B - 1}{\cot A + \cot B}$
$\cot(A + B) = \frac{\cot A \cot B + 1}{\cot A - \cot B}$
$\cot(A + B) = \frac{\sin A - \sin B}{\cos A - \cos B}$
$\cot(A + B) = \frac{\cos A - \cos B}{\sin A - \sin B}$

Brahmagupta's formula for calculating the sine of the difference of two angles is given by:

$\sin(A - B) = \sin A \cos B - \cos A \sin B$
$\sin(A - B) = \sin A \sin B + \cos A \cos B$
$\sin(A - B) = \tan A \sec B - \cot A \csc B$
$\sin(A - B) = \cos A \sec B + \sin A \csc B$

Brahmagupta's formula for calculating the cosine of the difference of two angles is given by:

$\cos(A - B) = \cos A \cos B + \sin A \sin B$
$\cos(A - B) = \cos A \sin B - \sin A \cos B$
$\cos(A - B) = \tan A \sec B + \cot A \csc B$
$\cos(A - B) = \sin A \sec B + \cos A \csc B$

Brahmagupta's formula for calculating the tangent of the difference of two angles is given by:

$\tan(A - B) = \frac{\tan A - \tan B}{1 + \tan A \tan B}$
$\tan(A - B) = \frac{\tan A + \tan B}{1 - \tan A \tan B}$
$\tan(A - B) = \frac{\sin A - \sin B}{\cos A - \cos B}$
$\tan(A - B) = \frac{\cos A - \cos B}{\sin A - \sin B}$

Brahmagupta's formula for calculating the cotangent of the difference of two angles is given by:

$\cot(A - B) = \frac{\cot A \cot B + 1}{\cot A - \cot B}$
$\cot(A - B) = \frac{\cot A \cot B - 1}{\cot A + \cot B}$
$\cot(A - B) = \frac{\sin A + \sin B}{\cos A + \cos B}$
$\cot(A - B) = \frac{\cos A + \cos B}{\sin A + \sin B}$

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