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Ordered Sets and Relations: Exploring the Orderly World of Sets

Description: Ordered Sets and Relations: Exploring the Orderly World of Sets
Number of Questions: 15
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Tags: set theory ordered sets relations
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Which of the following is an example of a partially ordered set?

  1. The set of integers with the usual ordering

  2. The set of real numbers with the usual ordering

  3. The set of all subsets of a given set

  4. The set of all functions from a set to itself


Correct Option: C
Explanation:

A partially ordered set is a set with a relation that is reflexive, antisymmetric, and transitive. The set of all subsets of a given set is a partially ordered set with the subset relation.

What is the relation between the sets A = {1, 2, 3} and B = {2, 3, 4}?

  1. A is a subset of B

  2. B is a subset of A

  3. A and B are equal

  4. A and B are disjoint


Correct Option: B
Explanation:

A set A is a subset of a set B if every element of A is also an element of B. In this case, every element of B is also an element of A, so B is a subset of A.

Which of the following is an example of an equivalence relation?

  1. The relation of equality on the set of real numbers

  2. The relation of divisibility on the set of integers

  3. The relation of congruence modulo 5 on the set of integers

  4. The relation of being a friend on the set of people


Correct Option: C
Explanation:

An equivalence relation is a relation that is reflexive, symmetric, and transitive. The relation of congruence modulo 5 on the set of integers is an equivalence relation because it is reflexive (every integer is congruent to itself modulo 5), symmetric (if a is congruent to b modulo 5, then b is congruent to a modulo 5), and transitive (if a is congruent to b modulo 5 and b is congruent to c modulo 5, then a is congruent to c modulo 5).

What is the inverse of the relation R = {(1, 2), (2, 3), (3, 4)}?

  1. R-1 = {(2, 1), (3, 2), (4, 3)}

  2. R-1 = {(1, 3), (2, 4), (3, 1)}

  3. R-1 = {(1, 4), (2, 1), (3, 2)}

  4. R-1 = {(4, 1), (3, 2), (2, 3)}


Correct Option: A
Explanation:

The inverse of a relation R is the relation that consists of all the ordered pairs (b, a) such that (a, b) is in R. In this case, the inverse of R is {(2, 1), (3, 2), (4, 3)}.

Which of the following is an example of a function?

  1. The relation of equality on the set of real numbers

  2. The relation of divisibility on the set of integers

  3. The relation of congruence modulo 5 on the set of integers

  4. The relation of being a friend on the set of people


Correct Option: B
Explanation:

A function is a relation that assigns to each element of a set a unique element of another set. The relation of divisibility on the set of integers is a function because each integer is assigned a unique set of divisors.

What is the domain of the function f(x) = x2 + 1?

  1. The set of all real numbers

  2. The set of all integers

  3. The set of all positive real numbers

  4. The set of all negative real numbers


Correct Option: A
Explanation:

The domain of a function is the set of all possible values of the independent variable. In this case, the independent variable is x, and x can be any real number. Therefore, the domain of the function f(x) = x2 + 1 is the set of all real numbers.

What is the range of the function f(x) = x2 + 1?

  1. The set of all real numbers

  2. The set of all integers

  3. The set of all positive real numbers

  4. The set of all negative real numbers


Correct Option: C
Explanation:

The range of a function is the set of all possible values of the dependent variable. In this case, the dependent variable is f(x), and f(x) is always a positive real number. Therefore, the range of the function f(x) = x2 + 1 is the set of all positive real numbers.

Which of the following is an example of a one-to-one function?

  1. The function f(x) = x2

  2. The function f(x) = x3

  3. The function f(x) = sin(x)

  4. The function f(x) = cos(x)


Correct Option: C
Explanation:

A one-to-one function is a function that assigns to each element of the domain a unique element of the range. In other words, each element of the range is assigned to exactly one element of the domain. The function f(x) = sin(x) is one-to-one because each value of x is assigned to a unique value of sin(x).

Which of the following is an example of an onto function?

  1. The function f(x) = x2

  2. The function f(x) = x3

  3. The function f(x) = sin(x)

  4. The function f(x) = cos(x)


Correct Option: D
Explanation:

An onto function is a function that assigns to each element of the range at least one element of the domain. In other words, every element of the range is assigned to at least one element of the domain. The function f(x) = cos(x) is onto because every value of cos(x) is assigned to at least one value of x.

Which of the following is an example of a bijective function?

  1. The function f(x) = x2

  2. The function f(x) = x3

  3. The function f(x) = sin(x)

  4. The function f(x) = cos(x)


Correct Option: C
Explanation:

A bijective function is a function that is both one-to-one and onto. In other words, each element of the domain is assigned to a unique element of the range, and every element of the range is assigned to at least one element of the domain. The function f(x) = sin(x) is bijective because it is both one-to-one and onto.

What is the composition of the functions f(x) = x2 and g(x) = x + 1?

  1. f(g(x)) = x2 + 1

  2. f(g(x)) = x2 + 2x + 1

  3. f(g(x)) = x2 + 3x + 1

  4. f(g(x)) = x2 + 4x + 1


Correct Option: B
Explanation:

The composition of the functions f(x) and g(x) is the function f(g(x)). To find f(g(x)), we first substitute g(x) into f(x). This gives us f(g(x)) = f(x + 1). We then simplify f(x + 1) to get f(g(x)) = x2 + 2x + 1.

What is the inverse of the function f(x) = x3 - 1?

  1. f-1(x) = x1/3 + 1

  2. f-1(x) = x3 + 1

  3. f-1(x) = x1/3 - 1

  4. f-1(x) = x3 - 1


Correct Option: A
Explanation:

To find the inverse of a function, we switch the roles of the independent and dependent variables. In other words, we solve the equation y = f(x) for x in terms of y. In this case, we have y = x3 - 1. Solving for x, we get x = (y + 1)1/3. Therefore, the inverse of the function f(x) = x3 - 1 is f-1(x) = x1/3 + 1.

Which of the following is an example of a reflexive relation?

  1. The relation of equality on the set of real numbers

  2. The relation of divisibility on the set of integers

  3. The relation of congruence modulo 5 on the set of integers

  4. The relation of being a friend on the set of people


Correct Option: A
Explanation:

A reflexive relation is a relation that relates every element of a set to itself. In other words, for every element x in the set, (x, x) is in the relation. The relation of equality on the set of real numbers is reflexive because for every real number x, (x, x) is in the relation.

Which of the following is an example of an antisymmetric relation?

  1. The relation of equality on the set of real numbers

  2. The relation of divisibility on the set of integers

  3. The relation of congruence modulo 5 on the set of integers

  4. The relation of being a friend on the set of people


Correct Option: B
Explanation:

An antisymmetric relation is a relation that does not relate any element to itself. In other words, for every element x in the set, (x, x) is not in the relation. The relation of divisibility on the set of integers is antisymmetric because for every integer x, (x, x) is not in the relation.

Which of the following is an example of a transitive relation?

  1. The relation of equality on the set of real numbers

  2. The relation of divisibility on the set of integers

  3. The relation of congruence modulo 5 on the set of integers

  4. The relation of being a friend on the set of people


Correct Option: B
Explanation:

A transitive relation is a relation that relates any two elements that are related to a third element. In other words, if (x, y) is in the relation and (y, z) is in the relation, then (x, z) is in the relation. The relation of divisibility on the set of integers is transitive because if x divides y and y divides z, then x divides z.

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