Lilavati

Bijaganita

Siddhanta Shiromani

Karanakutuhala

$\sin \theta = \frac{\text{opposite}}{\text{hypotenuse}}$

$\sin \theta = \frac{\text{adjacent}}{\text{hypotenuse}}$

$\sin \theta = \frac{\text{opposite}}{\text{adjacent}}$

$\sin \theta = \frac{\text{hypotenuse}}{\text{adjacent}}$

$\cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}}$

$\cos \theta = \frac{\text{opposite}}{\text{hypotenuse}}$

$\cos \theta = \frac{\text{opposite}}{\text{adjacent}}$

$\cos \theta = \frac{\text{hypotenuse}}{\text{adjacent}}$

$\tan \theta = \frac{\text{opposite}}{\text{adjacent}}$

$\tan \theta = \frac{\text{adjacent}}{\text{opposite}}$

$\tan \theta = \frac{\text{hypotenuse}}{\text{opposite}}$

$\tan \theta = \frac{\text{hypotenuse}}{\text{adjacent}}$

$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$

$\text{Area} = \frac{1}{2} \times \text{base} \times \text{side}$

$\text{Area} = \frac{1}{2} \times \text{side} \times \text{height}$

$\text{Area} = \frac{1}{2} \times \text{side} \times \text{side}$

$\text{Volume} = \frac{4}{3} \times \pi \times \text{radius}^3$

$\text{Volume} = \frac{3}{4} \times \pi \times \text{radius}^3$

$\text{Volume} = \frac{1}{3} \times \pi \times \text{radius}^3$

$\text{Volume} = \frac{2}{3} \times \pi \times \text{radius}^3$

$\text{Circumference} = \pi \times \text{diameter}$

$\text{Circumference} = 2 \times \pi \times \text{radius}$

$\text{Circumference} = \pi \times \text{radius}$

$\text{Circumference} = 2 \times \pi \times \text{diameter}$

$\text{Area} = \pi \times \text{radius}^2$

$\text{Area} = 2 \times \pi \times \text{radius}^2$

$\text{Area} = \frac{1}{2} \times \pi \times \text{radius}^2$

$\text{Area} = \frac{1}{4} \times \pi \times \text{radius}^2$

$\text{Sum} = \frac{n(n+1)}{2}$

$\text{Sum} = \frac{n(n-1)}{2}$

$\text{Sum} = \frac{n(n+2)}{2}$

$\text{Sum} = \frac{n(n-2)}{2}$

$\text{Product} = n!$

$\text{Product} = (n+1)!$

$\text{Product} = (n-1)!$

$\text{Product} = (n+2)!$

$\text{F}_n = \frac{\sqrt{5}}{5} \left[\left(\frac{1+\sqrt{5}}{2}\right)^n - \left(\frac{1-\sqrt{5}}{2}\right)^n\right]$

$\text{F}_n = \frac{\sqrt{5}}{5} \left[\left(\frac{1+\sqrt{5}}{2}\right)^n + \left(\frac{1-\sqrt{5}}{2}\right)^n\right]$

$\text{F}_n = \frac{\sqrt{5}}{5} \left[\left(\frac{1+\sqrt{5}}{2}\right)^n \times \left(\frac{1-\sqrt{5}}{2}\right)^n\right]$

$\text{F}_n = \frac{\sqrt{5}}{5} \left[\left(\frac{1+\sqrt{5}}{2}\right)^n \div \left(\frac{1-\sqrt{5}}{2}\right)^n\right]$

$\text{Area} = \text{base} \times \text{height}$

$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$

$\text{Area} = 2 \times \text{base} \times \text{height}$

$\text{Area} = \frac{1}{4} \times \text{base} \times \text{height}$

$\text{Volume} = \text{length} \times \text{width} \times \text{height}$

$\text{Volume} = 2 \times \text{length} \times \text{width} \times \text{height}$

$\text{Volume} = \frac{1}{2} \times \text{length} \times \text{width} \times \text{height}$

$\text{Volume} = \frac{1}{4} \times \text{length} \times \text{width} \times \text{height}$

$\text{Volume} = \frac{1}{3} \times \text{base area} \times \text{height}$

$\text{Volume} = \frac{1}{2} \times \text{base area} \times \text{height}$

$\text{Volume} = \frac{2}{3} \times \text{base area} \times \text{height}$

$\text{Volume} = \frac{3}{4} \times \text{base area} \times \text{height}$

$\text{Volume} = \frac{1}{3} \times \pi \times \text{radius}^2 \times \text{height}$

$\text{Volume} = \frac{1}{2} \times \pi \times \text{radius}^2 \times \text{height}$

$\text{Volume} = \frac{2}{3} \times \pi \times \text{radius}^2 \times \text{height}$

$\text{Volume} = \frac{3}{4} \times \pi \times \text{radius}^2 \times \text{height}$