Putnam Mathematical Competition
Description: The Putnam Mathematical Competition is an annual mathematics competition for undergraduate students in the United States and Canada. It is one of the most prestigious mathematics competitions in the world, and is known for its challenging problems. | |
Number of Questions: 15 | |
Created by: Aliensbrain Bot | |
Tags: mathematics mathematical competitions putnam mathematical competition |
Let $f(x)$ be a continuous function on the interval $[0, 1]$. If $f(0) = 0$ and $f(1) = 1$, then there exists a point $c$ in the interval $(0, 1)$ such that $f(c) = c$.
Let $A$ be a $3 imes 3$ matrix with real entries. If the determinant of $A$ is zero, then $A$ is not invertible.
Let $p$ be a prime number. If $a$ and $b$ are integers such that $a^p + b^p = c^p$, then $a + b = c$.
Let $f(x)$ be a continuous function on the interval $[0, 1]$. If $f(x) > 0$ for all $x$ in $[0, 1]$, then there exists a point $c$ in the interval $(0, 1)$ such that $f(c) = 1$.
Let $A$ be a $3 imes 3$ matrix with real entries. If the eigenvalues of $A$ are all real, then $A$ is diagonalizable.
Let $p$ be a prime number. If $a$ and $b$ are integers such that $a^p + b^p = c^p$, then $a = b = c$.
Let $f(x)$ be a continuous function on the interval $[0, 1]$. If $f(x) > 0$ for all $x$ in $[0, 1]$, then there exists a point $c$ in the interval $(0, 1)$ such that $f(c) > 1$.
Let $A$ be a $3 imes 3$ matrix with real entries. If the determinant of $A$ is nonzero, then $A$ is invertible.
Let $p$ be a prime number. If $a$ and $b$ are integers such that $a^p + b^p = c^p$, then $a + b + c = 0$.
Let $f(x)$ be a continuous function on the interval $[0, 1]$. If $f(x) > 0$ for all $x$ in $[0, 1]$, then there exists a point $c$ in the interval $(0, 1)$ such that $f(c) = 2$.
Let $A$ be a $3 imes 3$ matrix with real entries. If the eigenvalues of $A$ are all distinct, then $A$ is diagonalizable.
Let $p$ be a prime number. If $a$ and $b$ are integers such that $a^p + b^p = c^p$, then $a^2 + b^2 = c^2$.
Let $f(x)$ be a continuous function on the interval $[0, 1]$. If $f(x) > 0$ for all $x$ in $[0, 1]$, then there exists a point $c$ in the interval $(0, 1)$ such that $f(c) = 3$.
Let $A$ be a $3 imes 3$ matrix with real entries. If the determinant of $A$ is equal to the product of its eigenvalues, then $A$ is diagonalizable.
Let $p$ be a prime number. If $a$ and $b$ are integers such that $a^p + b^p = c^p$, then $a + b + c = p$.