The Work of Virasena

Description: This quiz is designed to assess your knowledge and understanding of the work of Virasena, a prominent mathematician from the medieval period of Indian mathematics.
Number of Questions: 14
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Tags: indian mathematics medieval period virasena
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What is the name of the treatise written by Virasena?

  1. Lilavati

  2. Aryabhatiya

  3. Ganita Sara Sangraha

  4. Surya Siddhanta


Correct Option: C
Explanation:

Ganita Sara Sangraha is the name of the treatise written by Virasena.

In which century did Virasena live?

  1. 8th century

  2. 9th century

  3. 10th century

  4. 11th century


Correct Option: B
Explanation:

Virasena lived in the 9th century.

What is the main topic covered in Ganita Sara Sangraha?

  1. Arithmetic

  2. Algebra

  3. Geometry

  4. Astronomy


Correct Option: A
Explanation:

Ganita Sara Sangraha primarily covers the topic of arithmetic.

What is the significance of Ganita Sara Sangraha in the history of Indian mathematics?

  1. It introduced new mathematical concepts.

  2. It provided a comprehensive overview of existing mathematical knowledge.

  3. It was the first treatise to use the decimal system.

  4. It was the first treatise to use negative numbers.


Correct Option: B
Explanation:

Ganita Sara Sangraha is significant because it provided a comprehensive overview of existing mathematical knowledge at the time.

Which of the following topics is NOT covered in Ganita Sara Sangraha?

  1. Fractions

  2. Square roots

  3. Cube roots

  4. Trigonometry


Correct Option: D
Explanation:

Trigonometry is not covered in Ganita Sara Sangraha.

What is the rule for finding the square root of a number according to Virasena?

  1. $$\sqrt{a} = \frac{a}{2}$$

  2. $$\sqrt{a} = \frac{a}{4}$$

  3. $$\sqrt{a} = \frac{a}{8}$$

  4. $$\sqrt{a} = \frac{a}{16}$$


Correct Option: B
Explanation:

According to Virasena, the rule for finding the square root of a number is $$\sqrt{a} = \frac{a}{4}$$

What is the rule for finding the cube root of a number according to Virasena?

  1. $$\sqrt[3]{a} = \frac{a}{3}$$

  2. $$\sqrt[3]{a} = \frac{a}{9}$$

  3. $$\sqrt[3]{a} = \frac{a}{27}$$

  4. $$\sqrt[3]{a} = \frac{a}{81}$$


Correct Option: C
Explanation:

According to Virasena, the rule for finding the cube root of a number is $$\sqrt[3]{a} = \frac{a}{27}$$

What is the formula for finding the sum of the first n natural numbers according to Virasena?

  1. $$S_n = \frac{n(n+1)}{2}$$

  2. $$S_n = \frac{n(n-1)}{2}$$

  3. $$S_n = \frac{n(n+2)}{2}$$

  4. $$S_n = \frac{n(n-2)}{2}$$


Correct Option: A
Explanation:

According to Virasena, the formula for finding the sum of the first n natural numbers is $$S_n = \frac{n(n+1)}{2}$$

What is the formula for finding the product of the first n natural numbers according to Virasena?

  1. $$P_n = n!$$

  2. $$P_n = (n+1)!$$

  3. $$P_n = (n-1)!$$

  4. $$P_n = (n-2)!$$


Correct Option: A
Explanation:

According to Virasena, the formula for finding the product of the first n natural numbers is $$P_n = n!$$

What is the formula for finding the nth triangular number according to Virasena?

  1. $$T_n = \frac{n(n+1)}{2}$$

  2. $$T_n = \frac{n(n-1)}{2}$$

  3. $$T_n = \frac{n(n+2)}{2}$$

  4. $$T_n = \frac{n(n-2)}{2}$$


Correct Option: A
Explanation:

According to Virasena, the formula for finding the nth triangular number is $$T_n = \frac{n(n+1)}{2}$$

What is the formula for finding the nth square number according to Virasena?

  1. $$S_n = n^2$$

  2. $$S_n = (n+1)^2$$

  3. $$S_n = (n-1)^2$$

  4. $$S_n = (n-2)^2$$


Correct Option: A
Explanation:

According to Virasena, the formula for finding the nth square number is $$S_n = n^2$$

What is the formula for finding the nth cube number according to Virasena?

  1. $$C_n = n^3$$

  2. $$C_n = (n+1)^3$$

  3. $$C_n = (n-1)^3$$

  4. $$C_n = (n-2)^3$$


Correct Option: A
Explanation:

According to Virasena, the formula for finding the nth cube number is $$C_n = n^3$$

What is the formula for finding the nth pentagonal number according to Virasena?

  1. $$P_n = \frac{3n^2-n}{2}$$

  2. $$P_n = \frac{3n^2+n}{2}$$

  3. $$P_n = \frac{3n^2-2n}{2}$$

  4. $$P_n = \frac{3n^2+2n}{2}$$


Correct Option: A
Explanation:

According to Virasena, the formula for finding the nth pentagonal number is $$P_n = \frac{3n^2-n}{2}$$

What is the formula for finding the nth hexagonal number according to Virasena?

  1. $$H_n = 2n^2-n$$

  2. $$H_n = 2n^2+n$$

  3. $$H_n = 2n^2-2n$$

  4. $$H_n = 2n^2+2n$$


Correct Option: A
Explanation:

According to Virasena, the formula for finding the nth hexagonal number is $$H_n = 2n^2-n$$

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