Question 1

In ancient India, which trigonometric function was known as the "jya"?

Sine
Cosine
Tangent
Cosecant

Answer

Correct Option: A

Question 2

What was the primary use of trigonometry in Indian military science?

Calculating the range of weapons
Determining the height of fortifications
Measuring the distance to enemy positions
All of the above

Answer

Correct Option: D

Question 3

Which Indian mathematician is credited with developing the concept of the sine function?

Aryabhata
Brahmagupta
Bhaskara II
Madhava of Sangamagrama

Answer

Correct Option: A

Question 4

What is the formula for calculating the sine of an angle in a right triangle?

$$sin \theta = \frac{opposite}{hypotenuse}$$
$$sin \theta = \frac{adjacent}{hypotenuse}$$
$$sin \theta = \frac{opposite}{adjacent}$$
$$sin \theta = \frac{hypotenuse}{opposite}$$

Answer

Correct Option: A

Question 5

Which Indian mathematician developed the concept of the cosine function?

Aryabhata
Brahmagupta
Bhaskara II
Madhava of Sangamagrama

Answer

Correct Option: B

Question 6

What is the formula for calculating the cosine of an angle in a right triangle?

$$cos \theta = \frac{opposite}{hypotenuse}$$
$$cos \theta = \frac{adjacent}{hypotenuse}$$
$$cos \theta = \frac{opposite}{adjacent}$$
$$cos \theta = \frac{hypotenuse}{opposite}$$

Answer

Correct Option: B

Question 7

Which Indian mathematician developed the concept of the tangent function?

Aryabhata
Brahmagupta
Bhaskara II
Madhava of Sangamagrama

Answer

Correct Option: C

Question 8

What is the formula for calculating the tangent of an angle in a right triangle?

$$tan \theta = \frac{opposite}{hypotenuse}$$
$$tan \theta = \frac{adjacent}{hypotenuse}$$
$$tan \theta = \frac{opposite}{adjacent}$$
$$tan \theta = \frac{hypotenuse}{opposite}$$

Answer

Correct Option: C

Question 9

Which Indian mathematician developed the concept of the cotangent function?

Aryabhata
Brahmagupta
Bhaskara II
Madhava of Sangamagrama

Answer

Correct Option: D

Question 10

What is the formula for calculating the cotangent of an angle in a right triangle?

$$cot \theta = \frac{hypotenuse}{opposite}$$
$$cot \theta = \frac{hypotenuse}{adjacent}$$
$$cot \theta = \frac{opposite}{hypotenuse}$$
$$cot \theta = \frac{adjacent}{opposite}$$

Answer

Correct Option: D

Question 11

Which Indian mathematician developed the concept of the secant function?

Aryabhata
Brahmagupta
Bhaskara II
Madhava of Sangamagrama

Answer

Correct Option: D

Question 12

What is the formula for calculating the secant of an angle in a right triangle?

$$sec \theta = \frac{hypotenuse}{opposite}$$
$$sec \theta = \frac{hypotenuse}{adjacent}$$
$$sec \theta = \frac{opposite}{hypotenuse}$$
$$sec \theta = \frac{adjacent}{opposite}$$

Answer

Correct Option: B

Question 13

Which Indian mathematician developed the concept of the cosecant function?

Aryabhata
Brahmagupta
Bhaskara II
Madhava of Sangamagrama

Answer

Correct Option: D

Question 14

What is the formula for calculating the cosecant of an angle in a right triangle?

$$cosec \theta = \frac{hypotenuse}{opposite}$$
$$cosec \theta = \frac{hypotenuse}{adjacent}$$
$$cosec \theta = \frac{opposite}{hypotenuse}$$
$$cosec \theta = \frac{adjacent}{opposite}$$

Answer

Correct Option: A

Question 15

Which Indian mathematician developed the concept of the versine function?

Aryabhata
Brahmagupta
Bhaskara II
Madhava of Sangamagrama

Answer

Correct Option: D

Question 16

What is the formula for calculating the versine of an angle in a right triangle?

$$vers \theta = 1 - \sin \theta$$
$$vers \theta = 1 - \cos \theta$$
$$vers \theta = 1 - \tan \theta$$
$$vers \theta = 1 - \cot \theta$$

Answer

Correct Option: A

Description: This quiz is designed to assess your understanding of the use of trigonometry in Indian military science.
Number of Questions: 16
Created by: Aliensbrain Bot
Tags: trigonometry indian military science mathematics

The Use of Trigonometry in Indian Military Science

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