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Nilakantha Somayaji's Contributions to Trigonometry

Description: Nilakantha Somayaji was an Indian mathematician and astronomer who lived in the 15th century. He is best known for his work on trigonometry, in particular for his development of the sine and cosine series.
Number of Questions: 14
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Tags: indian mathematics trigonometry nilakantha somayaji
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In which century did Nilakantha Somayaji live?

  1. 14th

  2. 15th

  3. 16th

  4. 17th


Correct Option: B
Explanation:

Nilakantha Somayaji lived in the 15th century.

What is Nilakantha Somayaji best known for?

  1. His work on algebra

  2. His work on geometry

  3. His work on trigonometry

  4. His work on astronomy


Correct Option: C
Explanation:

Nilakantha Somayaji is best known for his work on trigonometry.

What is the name of the series that Nilakantha Somayaji developed for the sine function?

  1. The sine series

  2. The cosine series

  3. The tangent series

  4. The cotangent series


Correct Option: A
Explanation:

Nilakantha Somayaji developed the sine series for the sine function.

What is the name of the series that Nilakantha Somayaji developed for the cosine function?

  1. The sine series

  2. The cosine series

  3. The tangent series

  4. The cotangent series


Correct Option: B
Explanation:

Nilakantha Somayaji developed the cosine series for the cosine function.

What is the general formula for the sine series?

  1. $sin(x) = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \frac{x^7}{7!} + \cdots$

  2. $sin(x) = x + \frac{x^3}{3!} + \frac{x^5}{5!} + \frac{x^7}{7!} + \cdots$

  3. $sin(x) = x - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{6!} + \cdots$

  4. $sin(x) = x + \frac{x^2}{2!} + \frac{x^4}{4!} + \frac{x^6}{6!} + \cdots$


Correct Option: A
Explanation:

The general formula for the sine series is $sin(x) = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \frac{x^7}{7!} + \cdots$.

What is the general formula for the cosine series?

  1. $cos(x) = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{6!} + \cdots$

  2. $cos(x) = 1 + \frac{x^2}{2!} + \frac{x^4}{4!} + \frac{x^6}{6!} + \cdots$

  3. $cos(x) = 1 - \frac{x}{2} + \frac{x^2}{4} - \frac{x^3}{6} + \cdots$

  4. $cos(x) = 1 + \frac{x}{2} + \frac{x^2}{4} + \frac{x^3}{6} + \cdots$


Correct Option: A
Explanation:

The general formula for the cosine series is $cos(x) = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{6!} + \cdots$.

What is the value of $sin(\frac{\pi}{2})$ using the sine series?

  1. 0

  2. 1

  3. -1

  4. \frac{1}{2}


Correct Option: B
Explanation:

Using the sine series, we have $sin(\frac{\pi}{2}) = \frac{\pi}{2} - \frac{(\frac{\pi}{2})^3}{3!} + \frac{(\frac{\pi}{2})^5}{5!} - \frac{(\frac{\pi}{2})^7}{7!} + \cdots = 1$.

What is the value of $cos(\frac{\pi}{2})$ using the cosine series?

  1. 0

  2. 1

  3. -1

  4. \frac{1}{2}


Correct Option: A
Explanation:

Using the cosine series, we have $cos(\frac{\pi}{2}) = 1 - \frac{(\frac{\pi}{2})^2}{2!} + \frac{(\frac{\pi}{2})^4}{4!} - \frac{(\frac{\pi}{2})^6}{6!} + \cdots = 0$.

What is the value of $sin(\frac{\pi}{3})$ using the sine series?

  1. 0

  2. 1

  3. -1

  4. \frac{1}{2}


Correct Option:
Explanation:

Using the sine series, we have $sin(\frac{\pi}{3}) = \frac{\pi}{3} - \frac{(\frac{\pi}{3})^3}{3!} + \frac{(\frac{\pi}{3})^5}{5!} - \frac{(\frac{\pi}{3})^7}{7!} + \cdots = \frac{\sqrt{3}}{2}$.

What is the value of $cos(\frac{\pi}{3})$ using the cosine series?

  1. 0

  2. 1

  3. -1

  4. \frac{1}{2}


Correct Option: D
Explanation:

Using the cosine series, we have $cos(\frac{\pi}{3}) = 1 - \frac{(\frac{\pi}{3})^2}{2!} + \frac{(\frac{\pi}{3})^4}{4!} - \frac{(\frac{\pi}{3})^6}{6!} + \cdots = \frac{1}{2}$.

What is the value of $sin(\frac{\pi}{4})$ using the sine series?

  1. 0

  2. 1

  3. -1

  4. \frac{1}{2}


Correct Option:
Explanation:

Using the sine series, we have $sin(\frac{\pi}{4}) = \frac{\pi}{4} - \frac{(\frac{\pi}{4})^3}{3!} + \frac{(\frac{\pi}{4})^5}{5!} - \frac{(\frac{\pi}{4})^7}{7!} + \cdots = \frac{1}{\sqrt{2}}$.

What is the value of $cos(\frac{\pi}{4})$ using the cosine series?

  1. 0

  2. 1

  3. -1

  4. \frac{1}{2}


Correct Option:
Explanation:

Using the cosine series, we have $cos(\frac{\pi}{4}) = 1 - \frac{(\frac{\pi}{4})^2}{2!} + \frac{(\frac{\pi}{4})^4}{4!} - \frac{(\frac{\pi}{4})^6}{6!} + \cdots = \frac{1}{\sqrt{2}}$.

What is the value of $sin(\frac{\pi}{6})$ using the sine series?

  1. 0

  2. 1

  3. -1

  4. \frac{1}{2}


Correct Option: D
Explanation:

Using the sine series, we have $sin(\frac{\pi}{6}) = \frac{\pi}{6} - \frac{(\frac{\pi}{6})^3}{3!} + \frac{(\frac{\pi}{6})^5}{5!} - \frac{(\frac{\pi}{6})^7}{7!} + \cdots = \frac{1}{2}$.

What is the value of $cos(\frac{\pi}{6})$ using the cosine series?

  1. 0

  2. 1

  3. -1

  4. \frac{1}{2}


Correct Option:
Explanation:

Using the cosine series, we have $cos(\frac{\pi}{6}) = 1 - \frac{(\frac{\pi}{6})^2}{2!} + \frac{(\frac{\pi}{6})^4}{4!} - \frac{(\frac{\pi}{6})^6}{6!} + \cdots = \frac{\sqrt{3}}{2}$.

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