Torque on current carrying loop - class-XII
| Description: torque on current carrying loop | |
| Number of Questions: 73 | |
| Created by: Shankara Prabhu | |
| Tags: physics magnetic effects of current and magnetism |
The torgue required to keep a magnet of length $20cm$ at $30^o$ to a uniform field is $2 \times^{-5}N-m$. The magnetic force on each pole is
A magnetic dipole placed in two perpendicular magnetic fields $\vec{B}$ and $\vec{B} _\circ{}$ is in equilibrium making an angle $\theta $ with $\vec{B}$ then
A bar magnet of moment $\overline{M}$ is in a magnetic field of induction $\overline{B}$. Then the couple is:
A current carrying a coil suspended freely in a uniform magnetic field is in stable equilibrium, if the angle between its magnetic dipole moment vector and the magnetic field is
A current carrying loop is placed in a uniform magnetic field. The torque acting on it does depend upon
A coil carrying electric current is placed in a uniform magnetic field with its axis making a nonzero angle $\theta$ with the field, then
A current carrying coil is subjected to a uniform magnetic field. The coil will orient so that its plane becomes
A magnetic field is produced and directed along y-axis. A magnet is placed along x-axis .The direction of the torque on the magnet is:
There is no couple acting when two bar magnets are placed co-axially separated by a distance because :
A circular loop of area 0.02 m$^2$ carrying a current of 10A, is held with its plane perpendicular to a magnetic field induction 0.2 T. The torque acting on the loop is
If a current carrying loop is placed in non uniform magnetic field, then the loop
a) experiences a force
b) experiences a torque
c) will develop induced current
d) oscillates
A conducting circular loop of radius $r$ carries a constant current $i$. It is placed in a uniform magnetic field $\bar{B} _{o}$ such that $\bar{B} _{o}$ is perpendicular to the plane of the loop. The magnetic force acting on the loop is
A rectangular coil of wire carrying a current is kept in a uniform magnetic field. The torque acting on the coil will be maximum when
The torque acting on a magnetic dipole of moment $P _{m}$ when placed in a magnetic field is
A current carrying loop in a uniform magnetic field will experience
A rectangular coil of wire carrying a current is kept in a uniform magnetic field. The torque acting on the coil will be zero when
The coil of a galvanometer has $500$ turns and each turn has an average area of $3\times 10^{-4} m^2$. when a current of $0.5$ A passes through it. If a torque of $1.5 Nm$ is required for this coil carrying same current to set it parallel to a magnetic field, calculate the strength of the magnetic field.
If X amount of work is required to rotate a bar magnet in a magnetic field by $60^0$, from a position parallel to the field, What is the torque required to maintain it in new position.
A circular coil of $25$ turns and radius of $12$cm is placed in a uniform magnetic field of $0.5$ T normal to the plane of coil. If the current in the coil is $5$A, then total torque experienced by the coil is
A closely wound solenoid of 2000 turns and area of cross-section $1.5 \times 10^{-4}m^2$ carries a current of 2.0 A. It is suspended through its centre and perpendicular to its length, allowing it to turn in a horizontal plane in a uniform magnetic field $5 \times 10^{-2}T$, making an angle of 30$^o$ with the axis of the solenoid. The torque on the solenoid will be
At a place the horizontal component of earth's field is $0.5 \times 10^{-4}T$. A bar magnet suspended horizontally perpendicular to earth's field experiences a torque of $4.5\times 10^{-4}N-m$ at that place. The magnetic moment of the magnet is:
A coil in the shape of equilateral tringale of side $0.02\ m$ is suspended from the vertex such that it is hanging in a vertical place between the pole-pieces of a permanent magnet producing a horizontal magnetic field of $5 \times 10^{-2}\ T.$ When a current of $0.1\ A$ passed through it and the magnetic field is parallel to its plane then couple acting on the coil is :
A bar magnet when placed at an angle of $30^o$ to the direction of magnetic field of induction of $ 5\times10^{-5} T$, experiences a moment of a couple $2.5\times10^{-6} N-m$. If the length of the magnet is $5\ cm$ its pole strength is:
A bar magnet is held perpendicular to a uniform magnetic field. If the couple acting on the magnet is to be halved by rotating it, then the angle by which it is to be rotated is:
If a current is passed through a loop which is placed in a magnetic field, then the acting torque will not depend on
A charged particle is moving with uniform velocity $V\hat {j}$ through a uniform magnetic field $B(-\hat {i})$ and a unifom electric field $\vec {E}$. Then $\vec {E}$ is
At some location on earth the horizontal components of earth's magnetic field is $18 \times 10^-6 T.$ At this location, magnetic needle of length 0.12 m and pole strength 1.8 Am is suspended from its mid-point using a thread, it makes $45^0$ angle with horizontal in equilibrium to keep this needle horizontal, the vertical force that should be applied at one of its ends is:
Two bar magnets with magnetic moments2$\mathrm { M }$ and $\mathrm { M }$ are fastened together at right angles to each other at their centres to forma crossed system, which can rotate freelyabout a vertical axis through the centre. The crossed system sets in earth's magnetic fieldmaking an angle $\theta$ with the magnetic merid-ian such that
The magnetic moment of a magnetic wire of length L is M . It is bent at its middle point such that of makes an angle of ${60^0}$ . The magnetic moment of this bent wire will be :
If the net force acting on the loop is zero then :
A bar magnet of magnetic moment 1.5 J/T is along the direction of the uniform magnetic field of 0.22T. The work done in turning the magnet opposite to the field direction and the torque required to keep in that position are
On applying a uniform magnetic field on a current-carrying coil the coil rotates in such a way that its plane
A very long magnet of pole strength 16 A-m is placed vertically with its one pole on the table. At what distance from the pole, there will be a neutral point on the table. $(B _H =4 \times 10^{-5} \ Wbm^{-2})$
The torque $(\vec t)$ experienced by a current - loop of magnetic moment $(\vec M)$ placed in magnetic field $\vec B$ is -
A coil of area 0.01 m$^2$ is lying in a perpendicular magnetic field of 0.1 Tesla. If a current of 10 A is passed in it then the maximum torque acting on the coil will be
A flat coil carrying a current has a magnetic moment $\vec{\mu}$. It is placed in a magnetic field $\vec B$. The torque on the coil is $\vec{\tau}$
A current-carrying loop suspended freely in a uniform magnetic field will experience
Asteady current 'I' flows in a small square loop of wire of side $L$ in a horizontal plane. The loop is now folded about its middle such that half of it lies in a vertical plane. Let $\overline{\mu} _1$ and $\overline{\mu} _2$ respectively denote the magetic moments of the current loop before and after folding. Then:
A current carring wire is bent to from a circuital coil. If this coil is placed in any other magnetic filed the maximum torque on the coil, the number of turns will be
The plane of a rectangular loop of wire with sides $0.05 m$ and $0.08 m$ is parallel to a uniform magnetic field of induction $1.5\times 10^{-2}T$ . A current of $10.0 A$ flows through the loop. If the side of length $0.08 m$ is normal and the side of length $0.05 m$ is parallel to the lines of field, then the torque acting on it is
A flat coil carrying a current has a magnetic moment $\vec{\mu}$. It is placed in a magnetic field $\vec B$ such that $\vec{\mu}$ is antiparallel to $\vec B$. The coil is
A dipole of dipole moment p is kept at the centre of a ring of radius R and charge Q. The dipole moment has direction along the axis of the ring. The resultant force on the ring due to the dipole is
A current loop in a magnetic field
A current carrying loop lies on a smooth horizontal place. Then
The plane of a rectangular loop of wire with sides $0.05\ m$ and $0.08\ m$ is parallel to a uniform magnetic field of induction $1.5\times 10^{-2}\ T$. A current of $10.0\ ampere$ flows through the loop. If the side of length $0.08\ m$ is normal and the side of length 0.05m is parallel to the lines of induction, then the torque acting on the loop is
When a current carrying coil is placed in a uniform magnetic field with its magnetic moment anti-parallel to the field
A coil carrying electric current is placed in uniform magnetic field. Then :
A current carrying coil is subjected to a uniform magnetic field. The coil will orient so that its plane becomes
A current carrying loop is free to turn in a uniform magnetic field. The loop will then come into equilibrium when it's plane is inclined at
A coil of area $100\ cm^{2}$ having $500$ turns carries a current of $1\ m A$. It is suspended in a uniform magnetic field of induction $10^{-3}Wb /m^{2}$ . It's plane makes an angle of $60^{o}$ with the lines of induction. The torque acting on the coil is :
A circular coil of $1$ turn and area $0.01 m$ carries a current of $10 A$. It is placed in a uniform magnetic field of induction $0.1T$ such that the plane of the circle is perpendicular to the direction of the field, the torque acting on the coil is
A current carrying coil tends to set itself____
A rectangular coil of wire of area $400 \ cm^{2}$ contains $500$ turns. It is placed in a magnetic field of induction $4\times 10^{-3}\ T$ and it makes an angle $60^o$ with the field. A current of $0.2 \ A$ is passed through it. The torque on the coil is :
A rectangular coil of length $10 cm$ and breadth $20 cm$ is placed in uniform magnetic field of induction $20 Wbm^{-2}$ . A current of $2A$ is passed through the coil. If it consists of $100$ turns, the maximum torque experienced is :
When a coil of area $\overline{\mathrm{A}}$ carrying current $\mathrm{i}$ is suspended in a magnetic field of induction $\overline{\mathrm{B}}$ , then the torque on the coil is
A rectangular coil of wire carrying a current is suspended in a uniform magnetic field. The plane of the coil is making an angle of $30^\circ{}$ with the direction of the field and the torque experienced by it is $\tau _{1}$ and when the plane of the coil is making an angle of $60^\circ{}$ with the direction of the field the torque experienced by it is $\tau _{2}$, then the ratio $\tau _{1}$ : $\tau _{2}$ is :
A vertical rectangular coil of sides $5 cm \times 2 cm$ has $10$ turns and carries a current of $2A$. The torque(couple) on the coil when it is placed in a uniform horizontal magnetic field of $0.1T$ with its plane perpendicular to the field is
A coil in the shape of an equilateral triangle of side $l$ is suspended between the pole pieces of a permanent magnet such that $B$ is in the plane of the coil. If due to current $i$ in the triangle, a torque $\tau $ acts on it. The side $l$ of the triangle is
A charge $q$ is spread uniformly over an insulated loop of radius $r$. If it is rotated with an angular velocity $\omega$ with respect to normal axis then the magnetic moment of the loop is
An electric dipole is placed at an angle of ${30}^{o}$ with an electric field of intensity $2 \times { 10 }^{ 5 }N\quad { C }^{ -1 }$. It experiences a torque equal to $4 \ N$ $m$. The charge on the dipole of the dipole length is $2 \ cm$ is
A circular coil of 25 turns and radius 12 cm is placed in a uniform magnetic field of 0.5 T normal to the plane of the coil. If the current in the coil is 6 A then total torque acting on the coil is
The magnitude of torque experienced by a square coil of side 12 cm which consists of 25 turns and carries a current 10 A suspended vertically and the normal to the plane of coil makes an angle of 30 with the direction of a uniform horizontal magnetic field of magnitude 0.9 T is:
A circular coil of 70 turns and radius 5 cm carrying a current of 8 A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.5 T. The field lines make an angle of 30 with the normal of the coil then the magnitude of the counter torque that must be applied to prevent the coil from turning is :
A dipole of magnetic moment $\vec{m}=30\hat{j}$A $m^2$ is placed along the y-axis in a uniform magnetic field $\bar{B}=(2\hat{i}+5\hat{j})$T. The torque acting on it is?
A circular coil of $100$ turns, radius $10$cm carries a current of $5$A. It is suspended vertically in a uniform horizontal magnetic field of $0.5$T and the field lines make an angle of $60^0$ with the plane of the coil. The magnitude of the torque that must be applied on it to prevent it from turning is going to be
The torque and magnetic potential energy of a magnetic dipole in most stable position in a uniform magnetic field $(\bar{B})$ having magnetic moment $(\bar{m})$ will be
The final torque on a coil having magnetic moment 25 A $m^2$ in a 5 T uniform external magnetic field, if the coil rotates through an angle of 60 under the influence of the magnetic field is:
The magnetic moment of a short bar magnet placed with its magnetic axis at $30^0$ to an external field of $900$G and experiences a torque of $0.02$N m is going to be
If a solenoid is having magnetic moment of $0.65 JT^{-1}$ is free to turn about the vertical direction and has a uniform horizontal magnetic field of $0.25$T applied. What is the magnitude of the torque on the solenoid when its axis makes an angle of $30^0$ with the direction of applied field is?
A bar magnet has a magnetic moment of $200 A m^2$. The magnet is suspended in a magnetic field of $0.30 N A^{-1} m^{-1}$. The torque required to rotate the magnet from its equilibrium position through an angle of $30^0$, will be then
A magnetic needle kept non parallel to the magnetic field in a non uniform magnetic field experience.
A uniform horizontal magnetic field of $7.5\times 10^{-2}$T is set up at angle of $30^o$ with the axis of an solenoid and the magnetic moment associated with it is $1.28$J $T^{-1}$. Then the torque on it is?