0

Hard water and soft water - class-IX

Description: hard water and soft water
Number of Questions: 104
Created by:
Tags: chemistry hydrogen and its compounds evs properties of water experiments with water hard water and soft water water hydrogen
Attempted 0/104 Correct 0 Score 0

A sample of water which freely lathers with soap solution is called hard water.

  1. True

  2. False


Correct Option: B
Explanation:

In hard water, lather is very difficult to form, leather is not formed in hard water.

A sample of water which starts lathering with soap solution on boiling is called temporary hard water.

  1. True

  2. False


Correct Option: A
Explanation:

A temporary hard water can from lather with soap. The ${ Ca }^{ 2+ }/{ Mg }^{ 2+ }$ ions of water displace ${ Na }^{ + }$ or ${ K }^{ + }$ ions from this salts & form insoluble $Ca/Mg$ salts of fatty acids. 

$\because $ it is temporary hard water, lathering of soap is not that difficult.

Which of the following has a low calcium and magnesium content?

  1. Soft water

  2. Hard water

  3. Contaminated water

  4. None of the above


Correct Option: A
Explanation:

Soft water is surface water that contains low  concentrations of ions and in particular is low in ions of calcium and magnesium. Soft water naturally occurs where rainfall and the drainage basin of rivers are formed of hard, impervious and calcium poor rocks.

What is hard water?

  1. Low mineral content

  2. Contaminated water

  3. High mineral content

  4. Both B and C


Correct Option: D
Explanation:

Hard water is water that has high mineral content (in contrast with "soft water"). Hard water is formed when water percolates through deposits of limestone and chalk which are largely made up of calcium and magnesium carbonates. Hard drinking water may have moderate health benefits, but can pose serious problems in industrial settings, where water hardness is monitored to avoid costly breakdowns in boilers, cooling towers, and other equipment that handles water.

Permanent hardness can be removed by simple boiling it.

  1. True

  2. False


Correct Option: B
Explanation:

Permanent hardness is caused by the presence of sulfates of $Ca/Mg$. Which further increases the hardness on boiling because boiling removes only water in the form of vapour while none of its mineral content boil away-they remain in the vessel.

.................. water does not lather with soap

  1. Hard water

  2. Soft water

  3. Contaminated water

  4. None of the above


Correct Option: A
Explanation:

Hard water does not lather with but instead forms a gooey mass called scum. Hard water is formed when water percolates through deposits of limestone and chalk which are largely made up of calcium and magnesium carbonates.

Boiling hard water with washing soda removes permanent hardness.

  1. True

  2. False


Correct Option: A
Explanation:

Boiling hard water with washing soda removes permanent hardness which removes ${ Ca }^{ 2+ }$ or ${ Mg }^{ 2+ }$ ions in a precipitation reaction.

If a boiled and filtered hard water is added to soap and it lathers, the water is :

  1. temporary hard water

  2. permanent hard water

  3. both a and b

  4. data insufficient


Correct Option: A
Explanation:

Hardness of water can be of two types temporary and permanent hardness. Temporary hard water contains only bicarbonates of magnesium and calcium. It can be removed by boiling. Such water on treating with soap lathers easily.

Types of hardness of water is :

  1. temporary and semi-permanent

  2. permanent and temporary

  3. permanent and partially permanent

  4. none of the above


Correct Option: B
Explanation:

Hardness of water can be of two types temporary and permanent hardness. Temporary hard water contains only bicarbonates of magnesium and calcium. It can be removed by boiling. Permanent hard water contains chlorides and sulfates of calcium and magnesium. It can be removed by adding washing soda.

What is the advantage of using detergents over soap in hard water?

  1. can be used with both hard and soft water

  2. used in acidic solutions

  3. prepared from hydrocarbons of petroleum

  4. all of above


Correct Option: D
Explanation:

Soaps are not suitable when hard water is used. Detergents can be used with both hard and soft water. Detergents are more soluble in water than soaps. They also have a stronger cleansing action than soaps. Detergents don't need expensive vegetable oil for their preparation as they can be prepared from hydrocarbons of petroleum. They can be used in acidic solutions whereas soaps cannot be used (free fatty acids are precipitated).

The given sample of lathers easily with water, it is :

  1. hard water.

  2. soft water.

  3. permanent hard water.

  4. temporary hard water.


Correct Option: B
Explanation:

Soft water is surface water that contains low concentrations of ions and in particular is low in ions of calcium and magnesium. Because soft water has few calcium ions, there is no inhibition of the action of soaps and no soap scum is formed in normal washing. It lathers easily with water. Similarly, soft water produces no calcium deposits in water heating systems.

A cloudy or milky appearance characterizes :

  1. soft water

  2. hard water

  3. chlorinated water

  4. both a and c


Correct Option: B
Explanation:

An easy way in which water manifests its hardness is scaling i.e. forming deposits through calcification that clog plumbing. These scales are usually white because calcium and magnesium are the most common sources of hardness in water. In swimming pools, a cloudy or milky appearance characterizes hard water.

Permanent hardness of water can be removed by :

  1. boiling

  2. filtration

  3. adding washing soda

  4. both b and c


Correct Option: C
Explanation:

Hardness of water can be of two types temporary and permanent hardness. Permanent hard water contains chlorides and sulphates of calcium and magnesium. It can be removed by adding washing soda.

A soap is :

  1. sodium or potassium salt of organic acid

  2. sodium salts of sulphonic acid

  3. both a and b

  4. chloride salts of organic and sulphonic acid


Correct Option: A
Explanation:

Soap is the sodium and potassium salt of organic fatty acid. Soap reacts with hard water forming scum. They are derived from the treatment of tryglycerides with a strong base (saponification). Soaps are made by rendering fats from animal sources.

Sodium salts of sulphonic acid are :

  1. soap

  2. detergents

  3. hard water

  4. soft water


Correct Option: B
Explanation:

Detergents are soap-like compounds which are used for cleaning purpose. They are sodium salts of long chain alkyl benzene sulphonic acids or sodium salts of long chain alkyl hydrogen sulphate, whereas, soaps are sodium salts of long chain carboxylic acids.

Washing soda soften both temporal and permanent hardness by :

  1. Dissolving salts

  2. Forming precipitate

  3. Forming soluble salts

  4. None of the above


Correct Option: B
Explanation:

Permanent hard water can be made soft by adding sodium carbonate (also called washing soda) to it. This will soften both temporal and permanent hardness. In this chemical reaction, the calcium and magnesium ions react with sodium to form a precipitate.

Water which gives lather with soap easily is called as :

  1. soft water.

  2. hard water.

  3. distilled water.

  4. both A and B


Correct Option: A
Explanation:

Water which gives lather with soap easily is called as soft water.

Which of the following is/are soluble in water?

  1. Ghee

  2. Curd

  3. Blood

  4. Sugar


Correct Option: C,D
Explanation:
Sucrose or sugar is a polar compound which can break the H-bond present in water due to this reason sugar can dissolve in water . 
Blood is a colloid or suspension composing red blood cells floating in a liquid plasma.If we add it to water, the plasma disperses in the water, becoming more dilute.
Oil and ghee are non-polar in nature as a result they can't interact with a polar solvent like water hence they are insoluble in water.

Which of the following is denser than water?

  1. Wooden plank

  2. Buttons

  3. Nails

  4. Paper


Correct Option: B,C
Explanation:
The density of nail (as of iron) is much larger than the water. So it sinks easily.
The button is more dense than the water and sinks in water.

Chemically calgon is:

  1. sodium aluminosilicate

  2. sodium sulphate

  3. sodium hexa meta phosphate

  4. alkyl sulphonic acid


Correct Option: C
Explanation:

Calgon is a trade name of a complex salt, sodium hexametaphosphate $(NaPO _3) _6$.

Which of the following substance is not present in clear water?

  1. $Ca\left ( HCO _{3} \right ) _{2}$

  2. $MgCl _{2}$

  3. $CaSO _{4}$

  4. $CaCO _{3}$


Correct Option: D
Explanation:

$CaCO _3$ is not present in the clear water. It attains the temporary hardness to the water.

Identify the substance that is not a water softener.

  1. $NaOH$

  2. $Na _{2}CO _{3}$

  3. $Na _{2}Al _{2}Si _{2}O _{8}$

  4. $MgCl _{2}$


Correct Option: D
Explanation:

The substance that is not a water softener $MgCl _2$, which is responsible for permanent hardness of water.


Other compounds are used for softening of water.

Option D is correct.

............ process is used for the removal of hardness of water.

  1. Calgon

  2. Baeyer

  3. Serpeck

  4. Hoope


Correct Option: A
Explanation:
Calgon process is used for the removal of hardness of water. 

Calgon is a trade name of a complex salt, sodium hexametaphosphate $(NaPO _3) _6$. 

It is used for softening hard water.

Option A is correct.

Hard water can be softened in ?

  1. A chromatograph

  2. An ion exchanger

  3. A calorimeter

  4. An earthenware pot


Correct Option: B
Explanation:

Answer:- (B) An ion exchanger

Explanation:-
In ion exchanger, the hard water is softened because it no longer contains calcium or magnesium ions. Ion exchange units that replaces calcium and magnesium ions from water are known as water softeners.

Sodium hexa-metaphosphate is known as:

  1. calgon

  2. permutit

  3. natalite

  4. nitrolim


Correct Option: A
Explanation:

Sodium hexametaphosphate $(NaPO _3) _6$, is known as calgon.

It is used for softening hard water.

Water which doesn't give lather immediately with soap is called soft water.
  1. True

  2. False


Correct Option: B
Explanation:
Soaps are basically sodium salt of fatty acids. 

In the presence of excess calcium and magnesium ions in water, the sodium ions are replaced by these ions and are precipitated as scum. 

Water containing an excess of these (calcium and magnesium) ions is called hard water.

Therefore option $B$ is correct.

One litre of a sample of hard water contain $4.44mg$ $Ca{Cl} _{2}$ and $1.9mg$ of $Mg{Cl} _{2}$, what is the total hardness in terms of ppm of $Ca{CO} _{3}$ :

  1. $2$ ppm

  2. $3$ ppm

  3. $4$ ppm

  4. $6$ ppm


Correct Option: D
Explanation:

$1$ mole $CaCl _2\equiv 1$ mole $CaCO _3\equiv 1$ mole $MgCl _2$

$\therefore 100g$ $CaCO _3$ produces $111g$ of $CaCl _2$
$\therefore 4.44mg$ $CaCl _2$ produces $\cfrac {4.44\times 100}{111}mg$ $CaCO _3$
Similarly, $100g$ $CaCO _3$ is required for $95g$ $MgCl _2$
$\therefore 1.9mg$ $MgCl _2=\cfrac {1.9\times 100}{95}mg$ $CaCO _3$
                               $=2mg$ $CaCO _3$
Total hardness= Hardness due to $CaCl _2$+Hardness due to $MgCl _2$
                         =$4+2$
Total hardness=$6$ $ppm$

Temporary hardness can be removed by:

  1. boiling

  2. clark's process

  3. calgon's process

  4. permutit method


Correct Option: A,B
Explanation:

By boiling : - On boiling, soluble $Mg{ \left( HC{ O } _{ 3 } \right)  } _{ 2 }$ is converted to insoluble $Mg{ \left( OH \right)  } _{ 2 }$ and $Ca{ \left( H{ CO } _{ 3 } \right)  } _{ 2 }$ to insoluble ${ CaCO } _{ 3 }$. It is because high solubility of $Mg{ \left( OH \right)  } _{ 2 }$ as compared to $Mg{ CO } _{ 3 }$, than $Mg{ \left( OH \right)  } _{ 2 }$ is precipitated. Precipitates can be removed by filtration.


By Clark's Method : Calculated amount of lime is added to hard water $\rightarrow Ca{ CO } _{ 3 }$ precipitates out & $Mg{ \left( OH \right)  } _{ 2 }$ can be filtered off.

Permanent hardness of water can be removed by:

  1. permutit process

  2. boiling

  3. ion-exchange

  4. calgon's process


Correct Option: A,C,D
Explanation:

Permanent hardness of water can be removed by permutit process. Permutite is an artifical zeolite used for softening of water. Through ion-exchange process, here cation-anion exchange chamber is used to obtain pure water. In calgon's process sodium hexa meta phosphate is used to soften the water.

Hard water causes _________ .

  1. burning of skin

  2. scales on the boiler walls

  3. relief to the body

  4. head-ache


Correct Option: A,B
Explanation:

Hard water contains minerals specifically $Ca,Mg$ and $Fe$ which can dry our skin and cause flaking and itching.

The presence of these minerals also causes scaling in boiler walls as these minerals are less soluble in hot than cold or to the presence of too high concentration of silica in relation to the alkalinity of water in the boiler.

Salts of calcium and magnesium like ___________ cause harness of water.

  1. bicarbonates

  2. chlorides

  3. sulphates

  4. phosphates


Correct Option: A,B,C
Explanation:
Hard water is the water that contains soluble salts of bivalent ions like calcium and magnesium principally in the form of bicarbonates, chlorides, and sulfates. Water is softened on a small scale by the addition of phosphates, together with sodium carbonate (washing soda) which separates the calcium and magnesium as white precipitates of their respective phosphates.
Therefore option $A,\ B,\ C$ are correct

If 10 g of a sample of water contains 16.2 g of  $ Ca(HCO _{3}) _{2} $, then the hardness of water is:

  1. 200 ppm

  2. 300 ppm

  3. 60 ppm

  4. 100 ppm


Correct Option: D
Explanation:

If density of water $=1\text{ }g/ml$

$\therefore 10\text{ }ml$ water contains $16.2\text{ }mg$ $Ca(HCO _3) _2$.
$\therefore 1L$ water contains $16.2\times 10^2\text{ }mg$ $Ca(HCO _3) _2$.
Equivalent of $CaCO _3=16.2\times 10^2\times \cfrac{100}{162}=100$
$\therefore $ Hardness in $ppm=100ppm$

The hardness of water due to $ HCO^{2-} _{3} $ is 122pm. Select the correct statement(s).

  1. The hardness of water in terms of $ CaCO _{3} $ is 200 ppm

  2. The hardness of water in terms of $ CaCO _{3} $ is 100 ppm

  3. The hardness of water in terms of $ CaCO _{3} $ is 222 ppm

  4. The hardness of water in terms of $ CaCO _{3} $ is 95 ppm


Correct Option: A
Explanation:

The hardness of water due to ${ HCO } _{ 3 }^{ 21 }$ is $122ppm$. Because the hardness of water in terms of ${ CaCO } _{ 3 }$ is $200$ $ppm$.

Temporary hardness maybe be removed from water by adding?

  1. $Ca(OH{ ) } _{ 2 }$

  2. $CaC{O } _{ 3 }$

  3. $CaS{O } _{ 4 }$

  4. $HCl$


Correct Option: A
Explanation:

  • Temporary hardness is caused by dissolved calcium or magnesium hydrogencarbonate.

Some of the methods to remove hardness from water are:

  • Chemical Process of Boiling Hard Water
  • Adding Slaked Lime (Clark's Process)
  • Adding Washing Soda
  • Calgon Process
  • Ion Exchange Process
  • Using Ion Exchange Resins

Clark’s method: In this method calculated amount of lime is added to hard water. It precipitates out calcium carbonate and magnesium hydroxide which can be filtered off.
$Ca(HCO _3) _2+Ca(OH) _2 \rightarrow 2CaCO _3(\downarrow)+2H _2O$
$Mg(HCO _3) _2+Ca(OH) _2 \rightarrow 2CaCO _3(\downarrow)+Mg(OH) _2(\downarrow)+2H _2O$

Permanent hardness in water is due to the presence of:

  1. $Ca^{2+},:Mg^{2+}$

  2. $CaCl _{2},:MgCl _{2}$

  3. $CaCO _{3},:MgCO _{3}$

  4. all of the above


Correct Option: B

The reagent commonly used to determine hardness of water is:

  1. oxalic acid

  2. disodium salt of EDTA

  3. sodium citrate

  4. sodium thiosulphate


Correct Option: B
Explanation:

Determination of hardness of water:

Determination of hardness of water is done by titration method using the technique of complexometric titration.    

Ethylenediamine tetra-acetic acid and its sodium salts (EDTA) form a chelated soluble complex when it is titrated against a solution containing certain metal cations that cause hardness to water.

Which of the following ions present as impurity cannot be removed by calgon process ?

  1. $Ca^{2+}$

  2. $Mg^{2+}$

  3. $Na^+$

  4. None of these


Correct Option: C

Which one of the following process will produce hard water?

  1. Saturation of water with $MgCO _{3}$

  2. Saturation of water with $CaSO _{4}$

  3. Addition of $Na _{2}SO _{4}$ to water

  4. Saturation of water with $CaCO _{3}$


Correct Option: B
Explanation:

Calcium sulfate $\left( CaS{ O } _{ 4 } \right) $ being less soluble in water causes permanent hardness in water.

Unstable hardness of water is due to the presence of:

  1. $CaCl _{2},:MgSO _{4}$

  2. $Ca^{+2},:Mg^{+2}$

  3. $K^{+},:CaCO _{3}$

  4. $Ca(HCO _{3}) _{2},:Mg(HCO _{3}) _{2}$


Correct Option: D
Explanation:

Hard water, water that contains salts of calcium and magnesium principally as bicarbonates, chlorides, and sulfates. Water hardness that is caused by calcium bicarbonate is known as temporary, because boiling converts the bicarbonate to the insoluble carbonate; hardness from the other salts is called permanent.

Temporary hardness of water can be removed by

  1. filtering

  2. boiling

  3. loading

  4. none of the above


Correct Option: B

In a sample of temporary hard water which of the following water softening process does NOT produced any precipitate of cation responsible for hardness ? 

  1. Boiling water

  2. Addition of lime water

  3. Addition of sodium hexameta phosphate

  4. Addition of sodium carbonate


Correct Option: B

One litre hard water contains $12 mg\, Mg^{2+}$ milli-equivalent of washing soda required to remove its hardness is: 

  1. $1$

  2. $12.16$

  3. $1\times 10^{-3}$

  4. $12.16\times 10^{-3}$


Correct Option: A

Which of the following pair of ions makes the water hard?

  1. $Na^+,SO _4^{+2}$

  2. $Ca^{2+},HCO _3^-$

  3. $Ca^{2+},NO _3$

  4. $NH _4^-,Cr$


Correct Option: B
Explanation:

Causes

1) High mineral (calcium and magnesium) content.
2) It can be found in groundwater as it passes through lime.
Types 
1) Permanent: It is caused due to the presence of sulphate and chloride salts.  Heating does not remove the permanent hardness of water so it is treated with chemicals.  Resins or water softeners are used to remove the permanent hardness.
2) Temporary: It is caused due to the presence of bicarbonate salts.  It can easily be removed by boiling.  Boiling decomposes the salts into insoluble carbonates.  Water can also be treated with calcium hydroxide to remove the hardness.Water Hardeners are Ca2+ and HCO3.   Nitrates and sulfates are used as water softener.  

Hardness of water is estimated by simple titration with 

  1. $EDTA$

  2. $H _{4}EDTA$

  3. $Na _{2}H _{2}EDTA$

  4. $Na _{3}HEDTA$


Correct Option: A

In water:

  1. temporary hardness is due to the bicarbonates of $Ca^{2+}$ and $Mg^{2+}$.

  2. permanent hardness is due to chlorides and sulphates of $Ca^{2+}$ and $Mg^{2+}$.

  3. hardness can be removed by adding phosphates.

  4. all of the above.


Correct Option: D

$Na _2CO _3$ is widely used in softening of hard water. If 1 L of hard water required $0.0106 g$ of $Na _2CO _3$, The hardness in ppm (parts per million i.e., $10^{6}$ ml) of $CaCO _3$ is:

  1. $0.01\,$ ppm $CaCO _3$

  2. $0.10\,$ ppm $CaCO _3$

  3. $1.00\,$ ppm $CaCO _3$

  4. $10.00\,$ ppm $CaCO _3$


Correct Option: D
Explanation:

Hardness (in ppm)=$\cfrac {Weight\quad of\quad Na _2CO _3\quad required\quad (in\quad mg)}{Volume\quad of\quad Hard\quad water\quad (in\quad L)}$

=$\cfrac {0.0106\times 10^{3}}{1}$
=$10.6$
$\approx 10 ppm$
$\therefore$ Hardness (in ppm)= $10$ ppm $CaCO _3$

A volume of 100 L of hard water requires 5.6 g of lime for removing temporary hardness. The temporary hardness in ppm of CaCO3CaCO3 is:

  1. 56

  2. 100

  3. 200

  4. 112


Correct Option: C
Explanation:

Temporary hardness is amount of $ CaCO _{3} $ in grams present in $ 10^{6}\,ml/grams $ of water


$ Ca(HCO _{3}) _{2}+CaO\rightarrow 2CaCO _{3}+H _{2}O $

$ 56\,g  $                      $ 2\times 100 = 200\,g $

$ 5.6\,g $                      $ 20\,g $ 

20 g $ CACO _{3} $ present in 100 L $ H _{2}O $

$ = 100\times 10^{3} = 10^{5}\,ml $

Then $ 10^{6} $ ml water contains 200g $ CaCO _{3} $

$ \therefore $ 200 ppm is temporary hardness 

Hence, the correct option is $\text{C}$.

Which element has variable covalency?

  1. F

  2. H

  3. I

  4. O


Correct Option: C

$ RH _{2} $ (ion exchange resin ) can replace $ Ca^{2+} $ in hard water as : 
$ RH _{2}+Ca^{2+}\rightarrow RCa+2H^{+} $.


One litre of hard water after passing through $ RH _{2} $ has pH = 2. Hence, hardness in ppm of $ Ca^{2+} $ is:

  1. 200

  2. 100

  3. 50

  4. 125


Correct Option: A
Explanation:

According to the given reaction 


$ RH _{2}+Ca^{2+}\rightarrow RCa+2H^{+} $

Each mole $ Ca^{2+} $ ion replaced by 2 moles $ H^{+}$

1 mole $ H^{+} $ replaced $ \Rightarrow \dfrac{1}{2} = 0.5\,mole \,Ca^{2+} $

Given,
$ pH = 2 $

$ H^{+} = 10^{-2} = 0.01 $

0.01 mole $ H^{+} $ replaced $ = 0.01\times 05 = 0.005\,moles\,Ca^{2+} $

Mass $ Ca^{2+}$ replaced $ = 0.005\times 40 = 0.2\,g = 200\,mg $

Concentration or Hardness of $ Ca^{2+} = 200\,mg/L $

$ = 200\,ppm $   

Hence, the correct option is $\text{A}$

In a laboratory, hard water, required for an experiment, is not available. However, the following salts are available in the school laboratory :
1. Sodium sulphate
2. Calcium sulphate
3. Magnesium chloride
4. Sodium chloride
5. Calcium chloride
6. Potassium sulphate
Which of the above salts may be dissolved in water to obtain hard water for the experiment?

  1. 1,3 and 5

  2. 1,2 and 5

  3. 1,2,4 and 6

  4. 3 and 5 only

  5. 2,3 and 5


Correct Option: E
Explanation:

The following salts may be dissolved in water to obtain hard water for the experiment
2. Calcium sulphate
3. Magnesium chloride
5. Calcium chloride

Both temporary and permanent hardness in water is removed by:

  1. boiling

  2. filtration

  3. distillation

  4. decantation


Correct Option: C
Explanation:

Both temporary and permanent hardness in water is removed by distillation. Temporary hardness can be removed by boiling and filtration. Permenant hardnesscan be removed by: (1) adding washing soda, (2) permutit method (3) by using ion exchange resins.

Both temporary and permanent hardness is removed on boiling water with :-

  1. $Ca(OH) _{2}$

  2. $Na _{2}CO _{3}$

  3. $CaCO _{3}$

  4. $CaO$


Correct Option: B
Explanation:

Temporary hardness is removed by boiling water with $NaOH$ and $Na _2CO _3$. $Ca(HCO _3 ) _2+2NaOH \rightarrow CaCO _3 \downarrow +Na _2CO _3+2H _2O$ Permanent hardness is removed by boiling water with sodium carbonate. $CaCl _2+Na _2CO _3 \rightarrow CaCO _3 \downarrow + 2 NaCl$

Both temporary and permanent hardness in water is removed by________.
  1. boiling

  2. filtration

  3. distillation

  4. decantation


Correct Option: C
Explanation:
Both temporary and permanent hardness in water is removed by distillation. Temporary hardness can be removed by boiling and filtration. permanent hydration can be removed by adding washing soda, permutit method and by using ion exchange resins.

Hard water can be used:

  1. in boilers

  2. in textile industry

  3. in paper industry

  4. in drinking


Correct Option: D

Calgon is an industrial name given to____________.

  1. normal sodium phosphate

  2. sodium meta-aluminate

  3. sodium hexametaphosphate

  4. hydrated sodium aluminium silicate


Correct Option: C
Explanation:

Calgon is an industrial name given to sodium hexametaphosphate. Its formula is $Na _{2}[Na _{4}(PO _{3}) _{6}]$.

Temporary hardness of water can be removed by :

  1. boiling

  2. saponification

  3. clark's method

  4. chlorination


Correct Option: A,C
Explanation:

The temporary hardness of water can be removed by boiling. $Ca(HCO _3) _2 \xrightarrow {boil} CaCO _3 \downarrow + CO _2 \uparrow + H _2O$.

Clark's method which uses lime (calcium hydroxide), it is also used for removal of temporary hardness of water.
$Ca(HCO _3) _2+Ca(OH) _2 \rightarrow 2CaCO _3+2H _2O$.

The exhausted permutit is regenerated by treating sodium hydroxide solution in Clark's method for removing permanent hardness.

  1. True

  2. False


Correct Option: A
Explanation:

Yes the exhausted permutit is regenerated by treating sodium hydroxide solution in Clark's method for removing permanent hardness.

Calgon removes hardness by forming complex compounds with the $Ca^{2+}$and $Mg^{2+}$ ions of hard water or by adsorption.

  1. True

  2. False


Correct Option: A
Explanation:

Calgon is $(Na _6P _6O _{18})$ i.e. sodium hexa-metaphosphate. The calgon when added to hard water forms a  soluble complex.


$Na _2[Na _4(PO _3) _6]+2CaSO _4\longrightarrow 2Na _2SO _4+Na _2[Ca _2(PO _3) _6]$ soluble

In the same way, $Mg^{2+}$ can also precipitate as $Na _2[Mg _2(PO _3) _6]$ and water becomes free from $Mg^{2+}$ and $Ca^{2+}$ ions.

Thus the answer is True.

The density of water is not same at all temperatures because of its anomalous expansion. The density is maximum at:

  1. $0^oC$

  2. $4^oC$

  3. $40^oC$

  4. $100^oC$


Correct Option: B
Explanation:

Due to anomalous expansion of water the density of water is not same at all temperatures. When water is cooled from room temperature it first contracts in volume and becomes increasingly dense as do other liquids but at $4^oC$ water reaches maximum density.

Calgon is an artificial zeolite for removing permanent hardness.

  1. True

  2. False


Correct Option: A
Explanation:

Calgon is an artificial zeolite, zeolites contains Na and Al which softens the hard water.

hence, calgon is used for removing permanent hardness.

State whether the given statement is true or false:

In anion exchange resin the anions of hard water get replaced by $OH^-$ ions.

  1. True

  2. False


Correct Option: A
Explanation:

In anoin exchange resin the reaction takes place as

$NH _4^+OH^- + HCl \rightarrow NH _4Cl + H _2O$
so, the anion of hard water get replaced by $OH^-$ ion.

Sodium carbonate softens permanent hard water.

  1. True

  2. False


Correct Option: A
Explanation:
Sodium carbonate, $Na _2CO _3$ is also known as washing soda. It can remove temporary and permanent hardness from water. It is soluble in water and adds a large amount of carbonate ions to the water. These react with dissolved calcium and magnesium ions in the water to produce insoluble precipitates.

Hence, it is a true statement.

Presence of magnesium chloride in water makes it temporary hard.

  1. True

  2. False


Correct Option: B
Explanation:

${ MgHCO } _{ 3 }$ and ${ MgCO } _{ 3 }$; with the presence ${ MgHCO } _{ 3 }$ or ${ MgCO } _{ 3 }$, water becomes temporary hard. 

Temporary hardness of water can be removed by:

  1. filtration

  2. boiling

  3. decantation

  4. washing soda


Correct Option: B
Explanation:

By boiling, the bicarbonates undergo decomposition to form insoluble carbonates of $Ca/Mg$ which can further be removed by filtration.

$Ca{ \left( { HCO } _{ 3 } \right)  } _{ 2 }\left( aq \right) \rightarrow CaC{ O } _{ 3\left( s \right)  }+{ CO } _{ 2\left( g \right)  }+{ H } _{ 2 }O(l)$
$Mg{ \left( HCO \right)  } _{ 3 }(aq)\rightarrow Mg{ CO } _{ 3\left( s \right)  }+{ CO } _{ 2\left( g \right)  }+{ H } _{ 2 }{ O } _{ (l )}$
Then the water obtained will be free from $Ca$ and $Mg$ ions and is soft.

The temporary hardness is caused due to:

  1. calcium carbonate only

  2. magnesium bicarbonate only.

  3. calcium bicarbonate only

  4. both magnesium and calcium bicarbonate


Correct Option: D
Explanation:

Temporary hardness is caused due to the presence of ${ Ca }^{ 2+ }/{ Mg }^{ 2+ }$ bicarbonates and carbonates.

Calcium bicarbonate in water makes it permanently hard.

  1. True

  2. False


Correct Option: B
Explanation:

Calcium bicarbonate in water is responsible for temporary hardness and not permanent hydrolysis.

Permanent hardness of water is due the presence of:

  1. calcium carbonate

  2. calcium chloride

  3. calcium bicarbonate

  4. calcium sulphide


Correct Option: B
Explanation:

Permanent hardness is due to the presence of sulphate or chloride salts of $Ca$ or $Mg$.

Hardness of water can be removed by :

  1. adding calcium hydroxide

  2. ion-exchange method

  3. both a and b

  4. none of above


Correct Option: C
Explanation:

Hardness of water can be removed by the following two methods:
CLARK'S METHOD 
In Clarks method a calculated amount of calcium hydroxide $Ca (OH) _2$ is added to hard water. Due to reaction, insoluble carbonates are obtained which are separated by filtration.
$Ca(HCO _3) _2 + Ca(OH) _2 2CaCO _3 + 2H _2O$
$Mg(HCO _3) _2 + Ca(OH) _2 CaCO _3 + MgCO _3 + 2H _2O$
ION-EXCHANGE METHOD
In this method sodium zeolite is used as ion-exchanger. Na-zeolite is passed through the pipes containing    hard water. Sodium zeolite is converted into calcium-zeolite or magnesium-zeolite. These are insoluble in water and are separated from water by filtration.
$Ca+2 + Na2-zeolite Ca-zeolite + 2Na+1$
$Mg+2 +Na2-zeolite Mg-zeolite + 2Na+1$

Temporal hardness can be removed by just boiling the water because :

  1. Form salts

  2. Converts magnesium to soluble magnesium

  3. Converts carbonate to soluble carbonate

  4. Converts carbonate to insoluble carbonate


Correct Option: D
Explanation:

Temporal hard water is caused by calcium bicarbonate. This hardness can be removed by just boiling the water, as this converts the carbonate to insoluble carbonate (This leaves a precipitate and can clog your boiler). 

The reddish brown stains when clothes are washed with hard water is due to :

  1. Limestone

  2. Calcium

  3. Ferrous ions

  4. All of the above


Correct Option: C
Explanation:

If the hard water has ferrous irons (oxidized to the ferrous form) it may leave some reddish brown stains on your clothing after laundry, or on the bathroom enamel surfaces.

Calgon used as water softner is:

  1. $Na _2[Na _4(PO _3) _6]$

  2. $Na _4[Na _2(PO _3) _6] $

  3. $Na _2[Na _4(PO _4) _5]$

  4. none of the above


Correct Option: A
Explanation:

Calgon $\rightarrow { Na } _{ 6 }{ P } _{ 6 }{ O } _{ 18 }\rightarrow { Na } _{ 2 }\left[ { Na } _{ 4 }{ \left( { PO } _{ 3 } \right)  } _{ 6 } \right] $ it is used as water softener, when added to hard water following reaction takes place :

${ Na } _{ 6 }{ P } _{ 6 }{ O } _{ 18 }\rightarrow { 2Na }^{ + }+{ Na } _{ 4 }{ P } _{ 6 }{ O } _{ 18 }^{ 2- }$
${ Ca }^{ 2+ }+{ Na } _{ 4 }{ P } _{ 6 }{ O } _{ 18 }^{ 2- }\rightarrow { \left[ { Na } _{ 2 }{ Ca }{ P } _{ 6 }{ O } _{ 18 } \right]  }^{ 2- }+{ 2Na }^{ + }$

Water which doesn't give lather immediately with soap is called soft water.

  1. True

  2. False


Correct Option: B
Explanation:

Soft water gives lather with soap immediately whether the hard water does not produce lather with soap.

At ________ $^0C$ water has its maximum density and its minimum volume.

  1. $40$

  2. $4$

  3. $14$

  4. $24$


Correct Option: B
Explanation:

The density of water is maximum at $4^oC$ and hence its volume at this temperature is minimum.

Hardness of water is mainly due to the dissolved salts of ________ and ________.

  1. calcium and magnesium

  2. calcium and sodium

  3. sodium and magnesium

  4. calcium and potassium


Correct Option: A
Explanation:

Hardness of water is mainly due to the dissolved salts of calcium and magnesium.

We can cook pulses easily in hard water. 

  1. True

  2. False


Correct Option: B
Explanation:

The dissolved salts in hard water do not let the pulses cook easily.

In permanent hardness of water, when washing soda is treated with water, ________ is precipitated out.

  1. sodium carbonate

  2. magnesium carbonate 

  3. calcium carbonate

  4. $Na _2CO _3  and\ MgCO _3$


Correct Option: C
Explanation:

The carbonate ions from sodium carbonate react with the calcium and magnesium ions in the water to produce insoluble product.

calcium ions + sodium carbonate calcium carbonate + sodium ions

$Ca^{+2} + Na _2CO _3\rightarrow CaCO _3 + 2Na^+$

The water is softened because it no longer contains dissolved calcium ions and magnesium ions, hence we can say that it is converted in soft water. It will now form lather  easily with soap.

Hardness of water is due to soluble salts:

  1. Bicarbonates

  2. Sulphates

  3. Chlorides

  4. All of these


Correct Option: D
Explanation:

Hardness of water is due to soluble salts such as bicarbonates, sulfates an chlorides of magnesium and calcium.

Calcium and Magnesium salts like _______ cause hardness of water

  1. bicarbonates

  2. chlorides

  3. sulphates

  4. phosphates


Correct Option: A,B,C
Explanation:

Calcium and Magnesium salts like sulphates, chlorides and bicarbonates cause hardness of water.

Hard water is unfit for laundries because:

  1. consumes much soap

  2. leaves dirty strains of '$Ca$' and '$Mg$'

  3. causes irritation on skin

  4. water is very hard to handle


Correct Option: A,B
Explanation:

Hard water is unfit for laundries because it can not form lather with soap, hence consumption of soap increases and it leaves dirty strains of calcium and magnesium. 

What is the mass of a mole of water containing 50% of heavy water $(D _2O)$?

  1. 18 g

  2. 19 g

  3. 20 g

  4. 21 g


Correct Option: B
Explanation:

Molar mass of $D _2O$ = $20g$

Molar mass of $H _2O$ = $18g$

If both are present in same ratio (i.e. 50:50) then,

Mass of a mole of water= $\cfrac {20+18}{2}$
=$19g$

 What happens on adding salt to the water in which eggs are boiled?  

  1. Egg will take more time to cook

  2. Egg will start floating on water

  3. Egg will cook faster

  4. Egg will sink in water


Correct Option: C

Water is liquid at room temperature, the most important reason for this is the :

  1. high boiling point of water

  2. high melting point of water

  3. high heat of vapourization of water

  4. cohesive forces due to hydrogen bonds in water


Correct Option: D
Explanation:

Water is liquid at room temperature, the most important reason for this is the cohesive forces due to hydrogen bonds in water.

Which of the following is true?

  1. Vegetable oil is heavier than water

  2. Ghee is soluble in water

  3. Curd is soluble in water

  4. A person who can not swim will not drown in dead sea


Correct Option: D
Explanation:

The salt is all dissolved in the water, this makes all of the water much denser than normal water, making it uncomfortable to swim in. Furthermore it means that the water is denser than the human body which is 70%, unsalted water. Meaning it is impossible to sink in the Dead Sea.

One litre of a samle of hard water contains 1 mg of $CaCl _2$ and 1 mg of $MgCl _2$.Then the total hardness in terms of parts of $CaCO _3$ per $10^8$ parts of water by mass is:

  1. 1.954 ppm

  2. 1.260

  3. 0.946

  4. none of these


Correct Option: A
Explanation:

$1$ mole of $CaCl _2\equiv1$ mole of $CaCO _3\equiv1$ mole of $MgCl _2$

$\therefore$ $100mg$ $CaCO _3$ is produced by $95mg$ $MgCl _2$
$\therefore$ $1mg$ of $MgCl _2$ gives $\cfrac {100}{95}mg$  $CaCO _3=$ $1.05mg$ $CaCO _3$

Similarly, $1mg$ of $CaCl _2$ gives $\cfrac {100}{111}mg$ $CaCO _3=$ $0.90mg$ $CaCO _3$

$\therefore$ Total $CaCO _3$ per litre of water= $1.05+0.90=1.95$ $mg$
Weight of $1000ml$ of water= $10^3g$=$10^6mg$

$\therefore$ Total hardness in terms of parts of $CaCO _3$ per $10^6$ parts of water by weight = $\cfrac {1.95}{10^6}\times 10^6$
=$1.95$ $ppm$

Answer: (A) $1.954$ $ppm$

100 ml of tap water containing $Ca(HCO _3) _2$ was titrated with N/50 $HCl$ with methyl orange as indicator. If 30ml of $HCl$ were required, calculate the temporary hardness as part of $CaCO _3$ per $10^6$ parts of water.

  1. 150 ppm

  2. 300 ppm

  3. 450 ppm

  4. 600 ppm


Correct Option: B
Explanation:

Milli equivalent of $Ca(HCO _{3}) _{2}$= miili equivalent of $CaCO _{3}$= mili equivalent of $HCl$

$N _{1}V _{1}= N _{2}V _{2}$
$1000 \times w$/($100$/$2$)= $30$/$50$
$w$= $0.03$ g
For $100$ml the amount of $CaCO _{3} = 0.03$ g
For $10^{6}$ = $0.03 \times 10^{6}$/$100=300$ ppm

The density of water is less in its solid state because:

  1. in solid state(ice) , water molecules are arranged in highly ordered open cage like structure

  2. more extensive hydrogen bonding is present in solid state ice

  3. the water molecules are closet in solid state of water

  4. water is a rigid crystalline, closely packed structure in its solid state.


Correct Option: A
Explanation:

The water has maximum density at 4 deg C. When liquid water is converted to ice, an open cage three dimensional structure is formed. Almost half the space is unoccupied. In liquid state, molecules are more closely packed.

The formula of calgon is:

  1. $Na _{2}\left [ Na _{4}\left ( PO _{3} \right ) _{6} \right ]$

  2. $Na _{4}\left [ Na _{2}\left ( PO _{3} \right ) _{6} \right ]$

  3. $Na _{4}\left [ Na _{2}\left ( PO _{3} \right ) _{3} \right ]$

  4. $Na _{2}\left [ Na _{4}\left ( PO _{3} \right ) _{4} \right ]$


Correct Option: A
Explanation:
The formula of calgon is $Na _2[Na _4(PO _3) _6]$. Calgon is a trade name of a complex salt, sodium hexametaphosphate $(NaPO _3) _6$. It is used for softening hard water. 
Calgon ionizes to give a complex anion.

The process used for the removal of hardness of water is:

  1. Baeyer

  2. Calgon

  3. Hoope

  4. Serpeck


Correct Option: B
Explanation:

Hard water is  percolated over Calgon (sodium hexameta phosphate $Na _6P _6O _{18}$). Calgon reacts calcium ( or magnesium) ions present in hard water. Inactive complex ions are formed that do not precipitate with soap.

Which of the following is not a disadvantage of using hard water?

  1. In production of steam in boilers

  2. Formation of scales in cooking utensils

  3. In cooking,bathing and washing

  4. In ion exchanges


Correct Option: D
Explanation:

In an ion exchange using hard water is not a disadvantage since it becomes soft by exchanging anions or cations. $Na^+$, $Ca^{2+}$ and $Mg^{2+}$ ions (from water) are exchanged with $H^+$ ions (from cation exchange resins). $Cl^-$, $SO _4^{2-}$ and $NO _3^{-}$ ions (from water) are exchanged with $OH^-$ ions (from anion exchange resins).

Polyphosphates like sodium hexametaphosphate (calgon) are used as water softening agents because they:

  1. form soluble complexes with anionic species

  2. precipitate anionic species

  3. form soluble complexes with cationic species

  4. precipitate catatonic species.


Correct Option: C
Explanation:

 Polyphosphates like sodium hexametaphosphate (calgon) form souble complex with cations like $Ca^{2+}$ and  $Mg^{2+}  $present in hard water and hence are used as water softening agents.
$Na _{6}P _{6}O _{18} \rightarrow 2Na^{+}+ Na _{4}P _{6}O^{2-} _{18}$
$M^{2+} + Na _{4}P _{6}O^{2-} _{18}\rightarrow [Na _{2}MP _{6}O _{18}]^{2-} + 2Na^{+}$

A water sample is said to contain permanent hardness if water contains:

  1. sulfates and chlorides of calcium and magnesium.

  2. carbonates of calcium and magnesium.

  3. bicarbonates of calcium and magnesium.

  4. sulfates and chlorides of sodium and potassium.


Correct Option: A
Explanation:
Permanent hardness of water is due to sulfates and chlorides of calcium and magnesium. Temporary hardness of water is due to bicarbonates of calcium and magnesium.

Which of the following compounds is used for water softening?

  1. $Ca _3 (PO _4) _2$

  2. $Na _3PO _4$

  3. $Na _6 P _6O _18$

  4. $Na _2HPO _4$


Correct Option: C
Explanation:

Sodium hexametaphosphate $ (Na _6P _6O _{18}),$ commercially called 'calgon' is used for water softening. Calgon reacts with salts of $Ca/Mg$ (present in hard water) and forms inactive complex anions that do not precipitate in soap solution.

The brownish-white deposit on kettles, heating elements and utensils formed by boiling water is due to:

  1. moisture in the air

  2. temporary hardness of water

  3. permanent hardness of water

  4. reaction of sulphur dioxide in the air with hot water


Correct Option: B
Explanation:

The temporary hardness of water is due to the presence of calcium or magnesium bicarbonates. 

The brownish-white deposit on kettles, heating elements, and utensils formed by boiling water are due to the temporary hardness of water. 
It can be removed from water by heating due to which the hydrogen carbonate decomposes to original insoluble carbonate.

What is meant by demineralised water?

  1. Water free from cations and anions

  2. Watrer free from minerals dissolved in it

  3. Wtaer free from impurities

  4. Water free from $Na^{+}$ and $K^{+}$ ions


Correct Option: A
Explanation:

Water free from cations $(Ca^{2+}, Mg^{2+}, etc.)$ and anions $(Cl^{-}, SO^{2-} _{4}, HCO^{-} _{3}, etc)  $ is called deionised or demineralised water.

Permanent hardness is due to presence of soluble salts of Mg and Ca in the form of chlorides and sulphates in ${H} _{2}O$. It can be removed by:

  1. boiling

  2. Clark's method

  3. treatment with ${Na} _{2}{CO} _{3}$

  4. all of these


Correct Option: C
Explanation:

Answer:-

Sodium carbonate can remove temporary and permanent hardness from water. Sodium carbonate is soluble but calcium carbonate and magnesium carbonate are insoluble.
The carbonate ions from sodium carbonate react with the calcium and magnesium ions in the water to produce insoluble precipitates.

${{Ca}^{+2}} _{\left( aq. \right)} + {{Na} _{2}C{O} _{3}} _{\left( aq. \right)} \longrightarrow {CaC{O} _{3}} _{\left( s \right)}  + 2{{Na}^{+}} _{\left( aq. \right)}$
${{Mg}^{+2}} _{\left( aq. \right)} + {{Na} _{2}C{O} _{3}} _{\left( aq. \right)} \longrightarrow {MgC{O} _{3}} _{\left( s \right)}  + 2{{Na}^{+}} _{\left( aq. \right)}$

Which of the following ions will cause hardness in water sample?

  1. $Ca^{2+}$

  2. $Na^+$

  3. $Cl^-$

  4. $K^+$


Correct Option: A
Explanation:

Presence of calcium and magnesium salts in the form of hydrogencarbonate, chloride and sulphate in water makes water 'hard'.

Permanent hardness is due to the presence of soluble salts of Mg and Ca in the form of chlorides and sulphates in ${ H } _{ 2 }O$. It can be removed by:

  1. boiling

  2. the Clark's method

  3. treatment with ${ Na } _{ 2 }{ CO } _{ 3 }$

  4. all of these.


Correct Option: C
Explanation:

Boiling and Clark's method are used for removing temporary hardness. They cannot be used for removing permanent hardness. Permanent hardness can be removed by treatment with $Na _2CO _3$ which takes place as follows:-

$Ca^{+2}(aq)+Na _2CO _3(aq)\longrightarrow CaCO _3(s)+2Na^{+}(aq)$
Due to the removal of dissolved $Ca^{+2}$ and $Mg^{+2}$ ions, there is no longer existence of salts which makes the water soft.

$6$ ml of a standard soap solution $(1$ ml $= 0.001$ g$)$ of  $CaCO _{3}$ were required in titrating $50$ ml of water to produce a good lather. Its degree of hardness is:

  1. $120$ ppm

  2. $100$ ppm

  3. $50$ ppm

  4. $60$ ppm


Correct Option: A
Explanation:

Degree of hardness $=\dfrac {6\times 0.001}{0.05} =120$ ppm.

On treatment with cold water, an element (A) reacts readily liberating a colorless, odorless gas (B) and a solution (C). Lithium is reacted with (B) yielding a solid product (D) which effervescence with water to give a strongly basic solution (E). When $CO _2$ gas is bubbled through the solution (C), a white ppt (F) is formed but this redissolved forming solution (G) when more $CO _2$ is passed. The precipitate (F) effervesced when moistened with conc.$HCl$ and give deep red coloration to the Bunsen burner flame. (F) on heating with an excess of carbon at $2000^oC$ give (H).

Solution (G) contains a salt which:

(i) causes permanent hardness of water
(ii) can not be obtained in solid-state
(iii) causes temporary hardness of water
(iv) can be obtained in solid-state


Identify the salt with correct options.

  1. (i) and (ii)

  2. (i) and (iv)

  3. (ii) and (iii)

  4. (ii) and (iv)


Correct Option: C
Explanation:

The metal A is calcium. It reacts with cold water to form calcium hydroxide (C) and hydrogen gas (B) which is colourless and odourless.
$Ca+2H _2O \rightarrow Ca(OH) _2 + H _2$

Lithium reacts with hydrogen gas (B) to form a solid product LiH (D).
$2Li+H _2 \rightarrow 2LiH$

olid product LiH (D) effervescence with water to give a strongly basic solution (E). 
$LiH + H _2O \rightarrow LiOH+ H _2 $

When $CO _2$ gas is bubbled through calcium hydroxide solution (C) , a white ppt of calcium carbonate (F) is formed but this redissolved forming calcium bicarbonate (G) when more $CO _2$ is passed. 

$Ca(OH) _2 + CO _2 \rightarrow CaCO _3 \rightarrow+H _2O$

$CaCO _3+H _2O+CO _2 \rightarrow Ca(HCO _3) _2$

The precipitate (F) (calcium carbonate) effervesced when moistened with concentrated HCl and give deep red colouration to the Bunsen burner flame
$CaCO _3+2HCl \rightarrow CaCl _2 + H _2O +CO _2$

The deep red colour is the characteristic colour of calcium.
Calcium carbonate (F) on heating with excess of carbon at $2000^oC$ give calcium carbide (H).
$CaCO _3 + 3C \xrightarrow {2000^0C} CaC _2+CO+CO _2$

It is $CaHCO _3$ which cannot be obtained in solid-state and causes temporary hardness. Temporary hardness is due to the presence of calcium hydrogen carbonate.   

Hence Option-C is correct

Calculate the temporary and permanent hardness of water sample having the following the following constituents per litre:
$ Ca(HCO _{3}) _{2} = 162\, mg, MgCl _{2} = 95 =\, mg, $
$ NaCl = 585\, mg, Mg(HCO _{3}) _{2} = 73\, mg, $
$ CaSO _{4} = 136\, mg $ 

  1. 200 ppm, 150 ppm

  2. 100 ppm, 150 ppm

  3. 150 ppm, 200 ppm

  4. 150 ppm, 150 ppm


Correct Option: C
Explanation:

mole of $ Ca(HCO _{3}) _{2} = \dfrac{162\times 10^{-3}mg}{162\,g/mole} = 1\times 10^{-3}\,moles $


Mole of $ Ca(SO _{4}) = \dfrac{136\times 10^{-3}g}{136\,g/mole} = 1\times 10^{3}\,mole $

Total mole of $ Ca = 2\times 10^{-3}\,mole $

mass of $ CaCO _{3} = 2\times 10^{-3}\times 100 = 0.2\,g $

$ \therefore $ ppm (permanent hardness) $ = \dfrac{6.2}{1000}\times 10^{6} = 200\,ppm $

Mole of $ MgCl _{2} = \dfrac{95\times 10^{-3}}{95} = 1\times 10^{-3}\,mole $ 

Mole Mg $ (HCg) _{2} = \dfrac{73\times 10^{-3}}{146} = 5\times 10^{-4}\,mole $
mole Mg $ = 1.5\times 10^{-4}\,mole $

Mole g $ CaCO _{3} $ (In terms of mg) $ = 1.5\times 10^{-3} $

mass $ = 1.5\times 10^{-3} = 0.150\,g $

ppm (temporary hardness) $ = \dfrac{0.150}{100}\times 106 = 150\,ppm $

Hence, the correct option is $\text{C}$

One litre of a sample of hard water contains 55.5 mg of $CaCl _2$ and 4.75 mg of $MgCl _2$. The total harness in terms of ppm of $CaCO _3$ is :

  1. 9 ppm

  2. 10 ppm

  3. 20 ppm

  4. none of these


Correct Option: D
Explanation:

$55.5$ mg of $CaCl _2$ in 1 litre of water corresponds to $55.5$ ppm.


$4.75$ mg of $MgCl _2$ in 1 litre of water corresponds to $4.75$ ppm.

Also $1 CaCl _2 = 1 CaCO _3$

$111$ ppm $= 100$ ppm

Hence, $55.5$ ppm $=\dfrac {100}{111} \times 55.5=50$ ppm.

Also $1 MgCl _2 = 1 CaCO _3$

$95$ ppm $= 100$ ppm

Hence, $4.75$ ppm $=\dfrac {95}{111} \times 4.75=5$ ppm.

Hence, the total hardness will be $5$ ppm.

In a permutit, the calcium and magnesium ions of hard water are exchanged by:

  1. $CO^{2-} _{3} $and $HCO _3{^-}$ ions of permutit

  2. $Na^{+}$ ions of permutit

  3. $Al^{3+}$ ions of permutit

  4. $Si^{4+}$ ions of permutiti


Correct Option: B
Explanation:
Permutit is an artificial zeolite. It is sodium aluminium orthosilicate $Na _{2}Al _{2}Si _{2}O _{8}.xH _{2}O$.
$\underset {\text { permutit}}{Na _{2}Al _{2}Si _{2}O _{8}.xH _{2}O} + Ca^{2+}(or Mg^{2+}) \rightarrow  \underset {\text { exhausted permutit }}{Ca Al _{2}Si _{2}O _{8}.xH _{2}O} + 2Na^{+}$

The molecular formula of a commercial resin used for exchanging ions in water softening is $C 8H _7SO _3 $ (Mol. wt. 206). Water would be the maximum uptake of $Ca^{2+} $ ions by the resin when expressed ____ in mole per gram of resin.

  1. $\dfrac{2} {309} $

  2. $\dfrac{1} {412} $

  3. $\dfrac{1} {103} $

  4. $\dfrac{1} {206} $


Correct Option: B
Explanation:

The chemical reaction for softening water can be given as:-


$2C _8H _7(SO _3)Na+Ca^{+2}\longrightarrow [C _8H _7(SO _3)] _2Ca+2Na^{+}$

$\therefore$  $2$ moles of resin$\equiv1$ mole of $Ca^{2+}$

$\therefore$  Mass of resin = $206\times 2=412g$

For $412g$ of resin, $1$ mole of $Ca^{2+}$ is required.

$\therefore$  Maximum uptake of $Ca^{2+}$ ions $= \cfrac {1}{412}$ mole/gram of resin.

The formula for permutit or zeolite which is used as softer in ion-exchange method is:

  1. $NaAlSiO _{4}$

  2. $NaAlO _{2}$

  3. both $A$ and $B$

  4. $Na _{2}SO _{4}$


Correct Option: A
Explanation:
Permutit is an artificial zeolite. It is sodium aluminium orthosilicate $Na _{2}Al _{2}Si _{2}O _{8}.xH _{2}O$.
$\underset {\text { permutit}}{Na _{2}Al _{2}Si _{2}O _{8}.xH _{2}O} + Ca^{2+}(or Mg^{2+}) \rightarrow  \underset {\text { exhausted permutit }}{Ca Al _{2}Si _{2}O _{8}.xH _{2}O} + 2Na^{+}$
- Hide questions