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Applications of electrolysis - class-XI

Attempted 0/72 Correct 0 Score 0

If $Zn/Zn^{+2}$ electrode is diluted 100 times then the change in electromotive force will be :-

  1. increases of 59 mV

  2. decreases of 59 mV

  3. increases of 29.5 mV

  4. decreases of 29.5 mV


Correct Option: A

The process of depositing thin layer of a metal over an another metal with a help of electric current is called :

  1. electrorefining

  2. electroplating

  3. thermoplating

  4. none of the above


Correct Option: B
Explanation:

Electroplating is the process of plating one metal onto another, for decorative purposes or to prevent corrosion of a metal. 

Which pair of electrolytes could not be distinguished by the products of electrolysis using inert electrodes.

  1. $\text{1M CuSO} _4$ solution, $\text{1M CuCl} _2$ solution

  2. $\text{1M KCl}$ solution, $\text{1M Kl}$ solution

  3. $\text{1M AgNO} _3$ solution, $\text{1M Cu(NO} _3) _2$ solution

  4. $\text{1M KCl}$ solution, $\text{1M NaCl}$ solution

  5. $\text{1M CuBr} _2$ solution, $\text{1M CuSO} _4$ solution


Correct Option: A

Calculate the half cell potential at $298$K for the reactoin ,Zn$^{+2}$ + $2$e$^{-}$ $\rightarrow$ Zn if [Zn$^{+2}$] =$2$M,
E$^{o}$$ _{Zn^{+2}/Zn}$ =-$0.76$V

E$^{o}$



  1. -$0.90$ V

  2. -$0.75$ V

  3. A and B

  4. None of these


Correct Option: B

The volume of gases evolved at STP by passing 0.1 ampere of current 49 65 seconds to 1 aqua solution of potassium?

  1. 22.4

  2. 11.2

  3. 89.6

  4. 44.8


Correct Option: B

On passing one friday of electric charge through a dilute solution of an acid, the volume of hydrogen obtained at S.T.P. is :

  1. 22400 ML.

  2. 1120 mL

  3. 2240 mL

  4. 11200 ML.


Correct Option: D

Electrolysis rules of Faraday's states that mass depends on electrodes is proportional to:-

  1. $m \propto I^2$

  2. $m \propto Q$

  3. $m \propto Q^2$

  4. None of these


Correct Option: B

The process of electrolysis is used in:

  1. extraction of metals

  2. electroplating

  3. refining of metals

  4. all of the above


Correct Option: D
Explanation:

Answer is D.
Electrolysis has wide applications in industries. Some of the important applications are, as follows, 
(i) Production of hydrogen by electrolysis of water. 
(ii) Manufacture of heavy water. 
(iii) The metals like K, Mg, Al, etc., are obtained by electrolysis of fused electrolytes. 
(iv) Non-metals like hydrogen, fluorine, chlorine are obtained by electrolysis. 
(v) In this method pure metal is deposited at cathode from a solution containing the metal ions, etc. 
(vi) Compounds like NaOH, KOH, white lead, etc. are synthesised by electrosynthesis method.
(vii) Electroplating: The process of coating an inferior metal with a superior metal by electrolysis is known as electroplating. 
Hence, the options A, B and C are correct.

Electromeric effect involves the completer transfer of 

  1. $\sigma $ electorn

  2. $\pi $ electron

  3. proton

  4. Both $\sigma $ and $\pi $ electrons


Correct Option: B

Refining an impure metal to give a pure metal is known as:

  1. electro-refining

  2. electrode refining

  3. electroplating

  4. none of the above


Correct Option: A
Explanation:

Refining an impure metal to give a pure metal is known as electrorefining.

The most durable metal plating on iron to protect against corrosion is:

  1. tin plating

  2. zinc plating

  3. copper plating

  4. nickel plating


Correct Option: B
Explanation:

Metal plating protects the iron against corrosion by forming a sacrificial layer. This metal layer itself gets oxidize instead of iron and thus protects the iron itself. 


For a metal to be used as plating, its oxidation should be preferred over iron and thus should have lower reduction potential than iron. 

Among the given options, zinc has a lower reduction potential than iron and thus can be used for plating. The process is called galvanization.

Hence, option B is correct. 

Extracting metals in the pure form from its compound is known as:

  1. electrorefining

  2. electrochemicals

  3. extraction of metals

  4. electroplating


Correct Option: C
Explanation:

Extracting metals in the pure form from its compound is known as extraction of metals.

Electroplating is:

  1. the deposition of superior metal on the surface of inferior metal

  2. the deposition of inferior metal on the surface of inferior metal

  3. both A and B

  4. none of the above


Correct Option: A
Explanation:

The deposition of superior metal on the surface of inferior metal is known as electroplating.

In the electrolysis of molten $Al _2O _3$ with inert electrodes:

  1. Al is oxidized at anode to $Al^{3+}$

  2. $O _2$ gas is produced at anode

  3. $O^{2-}$ is reduced at cathode

  4. $O$ is oxidized at anode


Correct Option: B
Explanation:

The electrodes are inert so that they do not involve the electrode reactions but transfer electrons through them. Since the silvery metal i.e. $Al$ is produced at cathode.

At cathode: $Al^{3+}+3e^- \longrightarrow Al$
At anode, $O _2$ bubbles off.
At anode; $2O^{2-}\longrightarrow O _2+4e^-$
The cell reaction: $2Al _2O _3\longrightarrow 4Al+3O _2$

Cost of electricity for the production of $X$ litres of $H _2$ at $NTP$ at the cathode is Rs $X$, then cost of electricity for the production $X$ litres of $O _2$ gas at $NTP$ at the anode will be:


[Assume $1$ mole of electrons as one unit of electricity]

  1. $2X$

  2. $4X$

  3. $16X$

  4. $32X$


Correct Option: A
Explanation:

Electrolysis of water gives:


${ H } _{ 2 }O\rightarrow { H } _{ 2 }+\tfrac { 1 }{ 2 } { O } _{ 2 }$


On electrolysis of water, hydrogen, and oxygen formed in the ratio $2:1$.
Since $X$ litres of ${ H } _{ 2 }$ is formed. Amount of ${ O } _{ 2 }$ formed will be $\tfrac { X }{ 2 } $. Since cost of production of electricity from $\tfrac { X }{ 2 } $ litres of ${ O } _2$ = Rs $X$

So, cost of production of electricity from $X$ litres of ${ O } _2$ = Rs $2X$.

So, the correct answer is option $A$.

A solution of $CuSO _4$ is electrolysed for $7$ minutes with a current of $0.6A$. The amount of electricity passed is equal to:

  1. $4.2C$

  2. $2.6\times 10^{-3}F$

  3. $126C$

  4. $36C$


Correct Option: B
Explanation:

Quantity of electricity passed $\displaystyle Q(C) = I(A) \times t(s)$
$\displaystyle Q(C)=0.6 \ A \times 7 \ min \times 60 \ s/min$
$\displaystyle Q(C)=252 \ C$
Number of faraday passed $\displaystyle = \dfrac {252 \ C}{96500 \ C/F}=2.6 \times 10^{-3} \ F$

In the electroplating of iron by nickel, nickel sulphate solution is taken as electrolyte. What is the acid that is added to the electrolyte during the process?

  1. $HCl$

  2. $HCN$

  3. $HNO _3$

  4. $H _2SO _4$


Correct Option: D
Explanation:

Sulphuric acid is used for pH adjustment during electroplating of nickel.

During electrolysis of an aqueous solution of a salt, pH in the space near one of the electrodes is increased, which of the following salt solution was electrolysed?

  1. $KCl$

  2. ${ CuCl} _{ 2 }$

  3. ${ Cu(NO } _{ 3 }{ ) } _{ 2 }$

  4. ${ CuSO } _{ 4 }$


Correct Option: A
Explanation:
As the cation $\left( {K}^{+} \right)$ in $KCl$ has lower electrode potential than $H$, hydrogen is liberated at cathode.

There is an accumulation of ${H}^{+}$ at one electrode, resulting in an increase in pH.

Hence, option A is correct.

A 5-ampere current is passed through a solution of zinc sulphate for $40 $ minutes. The amount of zinc deposited at the cathode is:

  1. $0.4065 g$

  2. $65.04 g$

  3. $40.65 g$

  4. $4.065 g$


Correct Option: D
Explanation:

$\because$ $W=z.i.t$=$\cfrac{E}{F}\times{i}.{t}$$=\left(\cfrac{65.38\times5\times40\times60}{2\times96500}\right)g$.


                                $=4.065 g.$

The same amount of electricity was passed through two separate electrolytic cells containing solutions of nickel nitrate $\left[ Ni{ \left( { NO } _{ 3 } \right)  } _{ 2 } \right]$ land chromium nitrate $\left[Cr{ \left( { NO } _{ 3 } \right)  } _{ 3 } \right]$ respectively. If $0.3g$ of nickel was deposited in the first cell, the common of chromium deposited is :
$(at. Wt. Of Ni=59, at. Wt. Of Cr=52)$

  1. $0.1g$

  2. $0.17g$

  3. $0.3g$

  4. $0.6g$


Correct Option: B

A certain quantity of electricity when passed through solution of ${ AgNO } _{ 3 }$, ${ ZnSO } _{ 4 }$, ${ CrI } _{ 3 }$. If X moles of Cr are deposited at its cathode, how many moles of Ag and Zn are deposited at their respective cathodes.

  1. X, X

  2. 3X, 2X

  3. 3X, 1.5X

  4. none of these


Correct Option: C
Explanation:

$Ag^++e^- \longrightarrow Ag$

$Zn^{2+}+2e^- \longrightarrow Zn$
$Cr^{3+}+3e^-\longrightarrow Cr$
Given that $x$ moles of $Cr$ is deposited at it's cathode means in case of $Ag$ it will be $3X$  and for $Zn$ it will be $\cfrac {3X}{2}$ moles deposits at cathode.

How long (approximate) should water be electrolysed by passing through $100$ amperes current so that the oxygen realised can completely burn $27.66\ g$ of diborane?


(Atomic weight of $B=10.8\ u$ )

  1. $0.8$ hours

  2. $3.2$ hours

  3. $1.6$ hours

  4. $6.4$ hours


Correct Option: B

The mass of carbon anode consumed (giving only carbondioxide) in the production of 270 kg of Aluminium metal from bauxite by the Hall process is :

  1. 270 kg

  2. 540 kg

  3. 90 kg

  4. 180 kg


Correct Option: B

The same amount of electricity was passed through two separate electrolytic cells containing solutions of nickel nitrate $[Ni(NO _{3}) _{2}$] and chromium nitrate $[Cr(NO _{3}) _{3}$] respectively.If 0.3 g of nickel was deposited in the first cell, the amount of chromium deposited is:
(at.wt of Ni=59, at. wt. of Cr=52)

  1. 0.1 g

  2. 0.17 g

  3. 0.3 g

  4. 0.6 g


Correct Option: C

On electrolysing a solution of dilute ${ H } _{ 2 }{ SO } _{ 4 }$ between platinum electrodes, the gas evolved at the anode is 

  1. ${ SO } _{ 2 }$

  2. ${ SO } _{ 3 }$

  3. ${ O } _{ 2 }$

  4. ${ H } _{ 2 }$


Correct Option: A

In the manufacture of $NaOH$ by the electrolysis of $NaCl$ solution, the cathode and anode are separated using a diaphragm because :

  1. it prevents the reaction betweeen ${H _2}$ and $C{l _2}$ formed

  2. it prevents the mixing of $NaOH$ and $NaC{l _2}$

  3. it prevents the reaction betweeen $Na$ and $C{l _2}$ formed

  4. it increases the yield of $NaOH$


Correct Option: B

Charge required for liberating $710 g$ of $Cl _{2}(g)$ by electrolyzing a concentrated solution of $NaCl$ will be:

  1. $1.93$ x $10^{5}$ $C$

  2. $1.93$ x $10^{6}$ $C$

  3. $9.65$ x $10^{6}$ $C$

  4. $9.65$ x $10^{5}$ $C$


Correct Option: B
Explanation:

The reaction taking place at anode is given by:

$2Cl^- \rightarrow Cl _2+2e^-$
Thus, $2$ moles of $e^-$ are required to liberate $1$ mole of $Cl _2$
Moles of $Cl _2=\dfrac{710}{71}=10$
Hence moles of $e^-$ required $=2\times10=20$
Hence $Q=20F$
$\Rightarrow Q=20\times 96500$
$\Rightarrow Q=1.93\times10^6 C$

The correct relation is

  1. $\triangle G = -RT\ ln\ K/Q$

  2. $\triangle G = -RT\ ln\ K$

  3. $\triangle G = -RT\ ln\ Q/K$

  4. $\triangle G = +RT\ ln\ Q$


Correct Option: B
Explanation:

$\triangle G = \triangle G^{\circ} + RT\ ln Q$
$\triangle G = -RT\ ln \dfrac {K}{Q}$.

Which process occurs in the electrolysis of an aqueous solution of nickel chloride at nickel anode?

  1. $Ni\rightarrow Ni^{2+}+2e^{-}$

  2. $Ni^{2+}+2e^{-}\rightarrow Ni$

  3. $2CI^{-}\rightarrow 2CI _{2}+2e^{-}$

  4. $2H^{+}+2e^{-}\rightarrow H _{2}$


Correct Option: A

On the basic of information available from the reaction
$ 4AI + 3O _{2} \rightarrow 2AI _{2}O _{3}; \triangle G = -965$ kJ/mol of $O _{2}$
The minimum EMF required to carry out electrolysis of $ AI _{2}O _{3}$ is

  1. 0.833 V

  2. 2.5 V

  3. 5.0 V

  4. 1.67 V


Correct Option: B

By selecting electrolyte as sodium argentocyanide for electroplating of the metal article with silver. Which of the following condition ensures that deposit is smooth, firm and long-lasting?

  1. low direct current should be passing for long time

  2. low indirect current should be passing for long time

  3. low direct current should be passing for short time

  4. low indirect current should be passing for long time.


Correct Option: A

A current of 3.7 A is passed for 6 h between nickel electrodes in 0.50 1 of 2 M solution of $Ni(NO _{3}) _{2}$. The molarity of $Ni^{2+}$ at the end of electrolysis is

  1. 1.172 M

  2. 0.172 M

  3. 0.586 M

  4. 2 M


Correct Option: D

 Which electrolyte is selected for the electroplating of metal article with silver?

  1. Argentocyanide

  2. Silver nitrate

  3. Silver chloride

  4. Cyanochloride


Correct Option: A

During silver plating of an article using potassium argentocyanide as an electrolyte, the anode material should be :

  1. Cu

  2. Ag

  3. Pt

  4. Fe


Correct Option: B
Explanation:

During silver plating of an article using potassium argentocyanide as an electrolyte,
Cathode - Article to be electroplated.
Anode - Block of silver metal

During electroplating of an article with nickel, the reduction reaction of the electrolysis occurs at:

  1. cathode

  2. anode

  3. both $A$ and $B$

  4. none of these


Correct Option: A
Explanation:

No matter what, reduction always occurs at cathode. 

In the electroplating of silver, $AgNO _3$ solution is usually used as:

  1. oxidant

  2. reductant

  3. electrode

  4. electrolyte


Correct Option: D
Explanation:

The process of depositing a thin layer of silver electrolytically on the metal surface is called silver plating. The article to be silver-plated is used as cathode while anode consists of pure silver. 


The bath contains a solution of potassium argentocyanide ($AgNO _3$ + excess of KCN). The complex ion is very stable and ionisation is very small at a time with the result slow and uniform deposition of silver takes place. 

$[Ag(CN) _2]^2 \rightleftharpoons Ag^+ + 2CN^-$


Hence, option D is correct.

The metal which is deposited at the cathode during the electrolysis of the solution of silver chloride 

is:  

  1. Ag

  2. H

  3. Cl

  4. Na


Correct Option: A
Explanation:

Reactions:
At cathode:
$Ag^+ +e^-\rightarrow Ag$
At anode:
$2 H _2O \rightarrow O _2 + 4H^+ + 4 e^-$

Galvanization of iron denotes coating with:

  1. copper

  2. aluminium

  3. silver

  4. none of the above


Correct Option: D
Explanation:

Galvanization is the process of applying a protective zinc coating to steel or iron, to prevent rusting. Galvanization of Iron meaning coating with zinc.


It forms a coating of corrosion-resistant zinc which prevents corrosive substances from reaching the more delicate part of the metal. The zinc serves as a sacrificial anode so that even if the coating is scratched, the exposed iron will still be protected by the remaining zinc.

Which of the following is not an electrochemical process?

  1. Transmission of nerve impulses in human body

  2. Rusting of iron

  3. Lightning

  4. None of the above


Correct Option: C
Explanation:

Both transmission of nerve impulse and  rusting of iron are results of electrochemical reactions.In transmission of nerve impulse numerous small molecules function as neurotransmitters at various chemical synapses.Rust is an iron oxide, usually red oxide formed by the redox reaction of iron and oxygen in the presence of water or air moisture. Lightning is a sudden electrostatic discharge during an electrical storm between electrically charged regions of a cloud. 

Galvanized iron sheets are coated with :

  1. copper

  2. nickel

  3. zinc

  4. carbon


Correct Option: C
Explanation:

Galvanization is the process of applying a protective zinc coating to steel or iron in order to prevent it from rusting.

Electro refining which is based on phenomenon of Electrolysis where:

  1. impure metal is made anode and pure metal is cathode

  2. impure metal is cathode and pure metal is anode

  3. pure metal makes both anode and cathode

  4. none of the above


Correct Option: A
Explanation:

This method is based upon the phenomenon of electrolysis. The crude metal is made anode whereas the thin sheet of a pure metal is made cathode. The electrolyte is the solution of the soluble salt of the same metal, preferably a double salt on passing electricity the metal from anode goes into solutions as ions due to oxidation while the pure metal gets deposited at the cathode due to the reduction of metal ions the impurities settle down below the anode as Anode Mud.

State True or False:
Rusting of iron is a physical change.

  1. True

  2. False


Correct Option: B

Which of the following is the preferred electrolyte for silver plating?

  1. $AgCl+HCl$

  2. $Ag{NO} _{3}+H{NO} _{3}$

  3. ${Ag} _{2}{SO} _{4}$

  4. $AgCN+NaCN$


Correct Option: D
Explanation:

Silver plating is an electroplating process utilizing an electrolyte containing silver cyanide solution and some free cyanide ions and operating at pH value not less than $8$. Free cyanide prevents precipitation of silver cyanide salt from the solution, provides electrical conductivity of the electrolyte and helps in the dissolution of silver anodes.

Why is electroplating done?

  1. to increase attractiveness

  2. to purify an impure metal

  3. to prevent rusting

  4. all of the above


Correct Option: A,C

Electroplating is a process of deposition of ________ metal on the surface of _________ metal.

  1. inferior, superior

  2. superior, superior

  3. inferior, inferior

  4. superior, inferior


Correct Option: D
Explanation:

Electroplating is a process of deposition of superior metal on the surface of inferior metal.

Anode is the _________ block and cathode is the _________ block in electrorefining of metal.

  1. impure, pure

  2. pure, pure

  3. impure, impure

  4. pure, impure


Correct Option: A
Explanation:

Anode is the impure block and cathode is the pure block in electro-refining of metal.

Electroplating is ________________ of metals and electro-refining is ___________ of metals.

  1. depositing, refining

  2. plating, extracting

  3. refining, depositing

  4. none of the above


Correct Option: A
Explanation:

Electroplating is $depositing$ of metals and electro-refining is $refining$ of metals.

The main applications of electrolysis are:

  1. electroplating

  2. electrorefining

  3. extraction of metals

  4. All of the above


Correct Option: D
Explanation:

The main application of electrolysis are:


Electroplating: Electroplating is a process of depositing a layer of any desired metal on another material by means of electricity.

Electrorefining: Electrorefining refers to the process of using electrolysis to increase the purity of a metal extracted from its ore.

Extraction of metals: Extractions are a way to separate the desired substance when it is mixed with others. 

Hence, option D is correct.

Which one of the following is not a main application of electrolysis?

  1. Electrorefining

  2. Electrode cleaning

  3. Extraction of metals

  4. Electroplating


Correct Option: B
Explanation:

The main application of electrolysis are:

  • Electrorefining
  • Electroplating
  • Extraction of metals

When an external current is used to induce a non-spontaneous redox reaction, the process is called ________.

  1. neutralization

  2. hydrolysis

  3. electrolysis

  4. esterification

  5. galvanization


Correct Option: C
In an electroplating experiment with a $Cu^{2+}$ solution, $10.0$ amp is applied for $965\ sec$. How many moles of $Cu$ will be plated?
  1. $0.05\ \text{moles}$

  2. $0.1\ \text{moles}$

  3. $0.001\ \text{moles}$

  4. $0.005\ \text{moles}$


Correct Option: A
Explanation:
$w = {Z\times I\times t}$

$w = \dfrac{E\times I\times t}{96500}$

$w = \dfrac{Molecular\ weight \times I\times t}{2\times 96500}$                                                 [$\therefore E= M/n$]

n=2

$n = \dfrac{w}{M} = \dfrac{I\times t}{2\times 96500}$

$ n=$ $\dfrac{10\times 965}{2\times 96500} = 0.05\ moles$

Hence, option A is correct.

In the electrolysis of $CuCl _{2}$ solution, the mass of cathode increased by $6.4\ g$. What occurred at copper anode?

  1. $0.224$ litre of $Cl _{2}$ was liberated

  2. $1.12$ litre of oxygen was liberated

  3. $0.05\ mole\ Cu^{2+}$ passed into the solution

  4. $0.1\ mole\ Cu^{2+}$ passed into the solution


Correct Option: D
Explanation:

In the electrolysis process,

reduction takes place at cathode and oxidation takes place at anode
so, if we increase the mass on cathode then same number of moles get oxidised at anode and go into the solution,
so, moles of Cu passed into the solution = $\dfrac{6.4}{63.5} = 0.1 mole$

Which is correct about silver plating?

  1. Anode - pure $Ag$

  2. Cathode - object to be electroplated

  3. Electrolyte - $Na[Ag(CN) _{2}]$

  4. All of the above


Correct Option: D
Explanation:
In silver plating, the object to be plated (e.g., a spoon) is made from the cathode of an electrolytic cell. 

The anode is a bar of silver metal, and the electrolyte (the liquid in between the electrodes) is a solution of silver cyanide, $AgCN$, in water.

When a direct current is passed through the cell, positive silver ions ($Ag^+$) from the silver cyanide migrate to the negative anode (the spoon), where they are neutralized by electrons and stick to the spoon as silver metal.

Hence, option D is correct.

What is the number of moles of oxygen gas evolved by electrolysis of $180\ g$ of water?

  1. $2.5$

  2. $5.0$

  3. $7.5$

  4. $10.0$


Correct Option: B
Explanation:

$2{ H } _{ 2 }O(l)\rightarrow2{ H } _{ 2 }(g)+{ O } _{ 2 }(g)$

moles of water=$\frac { 180 }{ 18 } =10$
1 mole of oxygen for 2 moles of water.
So, 5 moles of oxygen for 10 moles of water.

When water is electrolysed, hydrogen and oxygen gases are produced. If $1.008\ g$ of $H _{2}$ is liberated at cathode, what mass of $O _{2}$ is formed at the anode?

  1. $32\ g$

  2. $16\ g$

  3. $8\ g$

  4. $4\ g$


Correct Option: C
Explanation:

$\dfrac {W _{1}}{W _{2}} = \dfrac {E _{1}}{E _{2}}$
$\dfrac {1.008}{W _{2}} = \dfrac {1.008}{8}$
$\therefore W _{2} = 8\ g$
where, $E _{1}$ and $E _{2}$ are equivalent masses of hydrogen and oxygen respectively.

Zn metal reduces ${SO _{3}}^{2-}$ ions into $H _{2}S$in presence of concentrated $H _{2}SO _{4}$ What weight of Zn is required for
reduction of 6.3 g $Na _{2}SO _{3}$ in presence of concentrated acid.

  1. 9.75 g

  2. 13 g

  3. 130 g

  4. 23 g


Correct Option: A
Explanation:

eq. of $Zn=$ eq.of ${SO _{3}}^{2-}$
$\frac{w}{65}\times 2 =\frac{6.3}{126}\times 6\Rightarrow w=\frac{6.3}{126}\times \frac{6\times 65}{2}=9.75 g$


$Zn\left( s \right) \left|\ Zn{ { \left( CN \right)  } } _{ 4 }^{ 2- }\ \left( 0.5\ M \right) ,{ CN }^{ - }\left( 0.01 \right)  \right| \left|\ Cu{ \left( { NH } _{ 3 } \right)  } _{ 4 }^{ 2+ }\ \left( 0.5\ M \right) ,{ NH } _{ 3 }\left( 1\ M \right)  \right|\ Cu\left( s \right) $
Given: ${ K } _{ f }$ of $Zn{ { \left( CN \right)  } } _{ 4 }^{ -2\  }=\ { 10 }^{ 16 }$, $\quad \quad \quad$ ${ K } _{ f }$ of $Cu{ \left( { NH } _{ 3 } \right)  } _{ 4 }^{ 2+ }\ =\ { 10 }^{ 12 }$
$\displaystyle \quad \quad \ \ { E } _{ Zn|{ Zn }^{ -2 } }\ =\ 0.76V\ ;\ { E } _{ { Cu }^{ +2 }|Cu }\ =\ 0.34V\ ,\ \dfrac { 2.303RT }{ F } =0.06$
The emf of above cell is:

  1. $1.22\ V$

  2. $1.10\ V$

  3. $0.98\ V$

  4. $None\ of\ these$


Correct Option: A

Calculate the mass of Ag deposited at cathode when a current of 2A was passed through a solution of $Ag{ NO } _{ 3 }$ for 15 min.
(Given : Molar mass of $Ag = 108\ g\ { mol }^{ -\ 1 }$ $\ 1F=96500\ C\ { mol }^{ -1 }$).

  1. $3.015\ g$

  2. $2.015\ g$

  3. $4.2\ g$

  4. $3.1\ g$


Correct Option: B
Explanation:

Given:

Molar Mass of Ag = 108 g/mol

$1F = 96500\ C mol^{−1}$

Reaction at cathode = $Ag + e^-  \rightarrow   Ag(s)$ 

$w = Zlt$

Where, w = Mass deposited at cathode

Z = electrochemical constant

I = current

t = time

Now I = 2amp

$t = 15\ min = 15\times 60 = 900\ seconds$

Z = Eq. wt of substance $/ 96500 = 108/96500$ 

So,

$w = \dfrac{108}{96500} \times 900 \times 2 $

= $2.015g$

The electrochemical equivalent of silver is $0.0011180g$. When an electric current of $0.5$ ampere is passed through an aqueous silver nitrate solution for $200sec$, the amount of silver deposited is:

  1. $1.1180g$

  2. $0.11180g$

  3. $5.590g$

  4. $0.5590g$


Correct Option: B
Explanation:

According to the data given when $1$ e is passed the amount of silver,

deposited is $0.0011180\,g$
$\therefore (0.5\times 200)c$ is passed
then $(0.0011180\times 100)g$
of silver gets deposited 
$=0.11180\,g$

Brine solution on electrolysis will not give__________.

  1. $NaOH$

  2. ${Cl} _{2}$

  3. ${H} _{2}$

  4. ${O} _{2}$


Correct Option: D

$H _2(g)$ and $O _2(g)$ , can be produced by the electrolysis of water. What total volume (in $L$) of $O _2$ and $H _2$ are produced at $STP$ when a current of $30$ A is passed through a $K _2SO _4\, (aq)$  solution for 193 minutes?

  1. 20.16

  2. 40.32

  3. 60.48

  4. 80.64


Correct Option: D

During the mid ninteenth century, Daguerro-type portraits were very popular. A portrait image of a person was made on silver plated copper by developing the image with ?

  1. Silver bromide

  2. Mercury vapour

  3. 'Hypo' (sodium hypochlorite)

  4. An iodine solution


Correct Option: B
Explanation:
The latent image was developed to visibility by several minutes of exposure to the forms given off by heated mercury in purpose made developing box.
So development process of Daguerro-type portraits is done with Mercury Vapour.

Silver can be spread as a thin sheet on another metal by electroplating. The film of silver sticks strongly to the metal. Which of the following metals cannot be properly plated with silver?

  1. Copper

  2. Iron

  3. Nickel

  4. Brass


Correct Option: B
Explanation:

Iron cannot be property plated with silver it becomes peel if plated with silver are to peeling of silver it cannot properly plated iron.

In electroplating of copper by silver, the silver acts as an :

  1. anode

  2. cathode

  3. electrode

  4. electrolyte


Correct Option: A
Explanation:

Silver plating on Steel spoon: A silver rod is made as anode and steel spoon as cathode. Potassiumargentocyanide $(K[Ag(CN) _2])$ is used as electrolyte.
$AgNO _3$ is not used as electrolyte because in that case the silver coating will be non-uniform as the electrolysis takes place rapidly.
In electroplating of copper by silver, silver rod is taken as anode.

Electrolysis of brine produces Na at cathode.

  1. True

  2. False


Correct Option: B
Explanation:

Electrolysis of brine or NaCl produces hydrogen at cathode and chlorine at anode while the electrolyte NaOH sodium hydroxide remains in the solution.

 In the silver plating of copper, $K[Ag(CN) _2]$ is used instead of $AgNO _3$. The reason is:

  1. a thin layer of Ag is formed on Cu

  2. more voltage requirement

  3. $Ag^+$ ions are completely removed from solution

  4. less availability of $Ag^+$ ions, as Cu cannot displace Ag from $[Ag(CN) _2]^-$ ion


Correct Option: D
Explanation:

Option D is correct 

less avaibality of $Ag+$ions as, $Cu$ cannot displace $Ag$ from $[Ag(CN) _2]$
$Cu$ can replace $Ag$ in $AgNO _3$. But In coordination compound $Ag$ can't be replaced.

In $Ag$ - $CuSO _{4}$ cell, silver electrode will serve as:

  1. anode

  2. cathode

  3. both anode and cathode

  4. none of the above


Correct Option: B
Explanation:
In $Ag - CuSO _4$ cell, silver electrode will serve as cathode, as reduction occurs here and silver metal is deposited. Copper being high in the reactivity series than silver, undergoes oxidation, and silver ions undergo reduction.

Electrolysis of a solution of $Mn{ SO } _{ 4 }$ in aqueous sulphuric acid is a method for the preparation of $MnO _ 2$. Passing a current of $27A$ for $24$ hours gives $1kg$ of $MnO _2$. The current efficiency in this process is:

  1. $100$%

  2. $95.185$%

  3. $80$%

  4. $82.951$%


Correct Option: B
Explanation:

The reaction taking place on the given reaction are,

$Mn^{2+}+2H _2O\rightarrow MnO _2+2H^{+}+H _2$

Amount of current is given by,
$m= Z \times I \times t$

$I=m\dfrac{F\times x}{t\times M}$

    $=1000g\times{\dfrac{96500\times 2}{24\times 60 \times 60 \times 86.9}}$

    $\implies I=25.70A$

Now current efficiency$=\dfrac{25.7}{27} \times 100=95.185$ %

Hence,option B is correct answer.

Consider the reaction : $Cr _2O _7^{2-} + 14H^+ + 6e^- \to 2Cr^{3+}+7H _2O$


What is the quantity of electricity in coulombs needed to reduced $1\ mol$ of $Cr _2O _7^{2-}$?

  1. $6 \times 10^6C$

  2. $5.79\times 10^5C$

  3. $5.25 \times 10^5C$

  4. None of these


Correct Option: B
Explanation:
$Cr _2O _7^{2-} + 14H^+ + 6e^- \to 2Cr^{3+}+7H _2O$

The valency factor for Chromium is $6$.

Applying faraday's first law-
$ \dfrac{Q} {F} =mole \times V.f.$

$  Q            =mole \times V.f. \times F$ 

$  Q            =1 \times 6 \times 96500$

$  Q            =5.79\times 10^5\ C$

Calculate the amounts of Na and chlorine gas produced during the electrolysis of fused $NaCl$ by the passage of 1 ampere current for 25 minutes. 

  1. 0.3565 gm and 0.55 gm

  2. 0.3565 gm and 0.66 gm

  3. 0.55 gm and 0.3565

  4. None of above


Correct Option: A
Explanation:
$i= 1 \ amp$
$t= 25 \ min = 25 \times 60 \ sec$
Molar mass of $Na= 23 \ g \ mol^{-1}$
Molar mass of $Cl _2= 71 \ g \ mol^{-1}$
$Cl^-= \cfrac 12 {(12)}=35.5 \ g$
Formula used, $m= \cfrac {Molar \ mass}{n \times F} \times i \times t$
For $Na$, $n=1$
$m= \cfrac {23}{1 \times 96500} \times 1 \times 25 \times 60$
$=0.3575 \ g$

For $Cl$, $n=1$
$m= \cfrac {35.5}{1 \times 96500} \times 1 \times 25 \times 60$
$=0.5518 \ g$

$\therefore$ The amounts of $Na$ and $Cl$ gas produced are $0.3575 \ g$ and $0.5518 \ g$ respectively.

A current of  $13.4\mathrm { A }$  is passed through  $1.0\mathrm { L }$  of  $1.0\mathrm { M }$  $HCl$  solution by using  $Pt$  electrodes for  $1.0\  \mathrm { hr }.$  The  $pH$  of the solution after the experiment is over at  $298 K$  will be about.

  1. $0.20$

  2. $0.30$

  3. $0.40$

  4. $0.50$


Correct Option: B
Explanation:
$ (B) 0.30 $ 
Change in coulombs $ = 13.4\times 1\times 60\times 60 = 48240 $

Moles of electric charge $ = \dfrac{48240}{96500} = 0.5 F $

Equivalent of HCl decomposed on electrolysis $ = 0.5 $

Mili equivalents of HCl along electrolysis $ = 500 $

Molarity of HCl after electrolysis $ = \dfrac{500}{1000} = 0.5 M$

$ [H ^{+}] = 5\times 10^{-1} $

$ p{H} = -\log [H^{+}] $

$ p{H} = -\log 5\times 10^{-1} = 0.30. $

A solution of ${ AgNO } _{ 3 }$ is a good electrolyte but is not used for electroplating an article with silver because :

  1. rapid deposition of silver takes place resulting in uneven coating

  2. slow deposition of silver takes place resulting in uneven coating

  3. poor conduction of silver

  4. none of the above


Correct Option: A
Explanation:

A solution of $AgNO _3$ is a good electrolyte but is not used for electroplating an article with silver because it undergoes very fast redox process and electroplating done through this process is not uniform.

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