Logarithmic notation - class-XI
Description: logarithmic notation | |
Number of Questions: 48 | |
Created by: Ankita Patil | |
Tags: real numbers physics maths elementary mathematics logarithms basic algebra basic mathematical concepts |
If $\log\ (-2x)=2\log\ (x+1)$, then $x$ can be equal to
If $\displaystyle \log _3 x = 0$, then value of $x$ is equal to
State true or false:
The value of $\log _{10}0.01$ is equal to
The exponential form of $\log _{10}1 = 0$ is $10^{m} = 1$, then the value of $m$ is
The value of $\log _5\ 125$ is equal to
The value of $\log _5 1$ is equal to
If exponential form of $\log _{10} 0.01 = -2$ is $10^{m} = 0.01$, then value of $m$ is equal to
Express the following in logarithmic form$\,\colon$
$81\,=\,3^{4}$
If $log 27 = 1.431$, then the value of $log 9$ is
Find the correct expression, if $\log _{ c }{ a } =x$.
Which of the following statements is not correct?
If $log _{10} 2 = 0.3010$, the value of $log _{10}$ 80 is
If $log 2 = 0.3010 $ and $3 = 0.4771$, the value of $log _5 512$ is
If $log 2 = 0.30103$, the number of digits in $2^{64}$ i
If $log _x \left( \dfrac{9}{16} \right) = - \dfrac{1}{2}$, then x is equal to
What is the value of $\dfrac {1}{2}\log _{10} 25 - 2 \log _{10} 3 +\log _{10} 18$?
The value of $log _2$ 16 is
The logarithmic form of ${5}^{2}=25$ is
The exponential form of $\log _{ 2 }{ 16 } =4$ is
If mantissa of logarithm of 719.3 to the base 10 is 0.8569 , then mantissa of logarithm of 71.93 is
If $2\log y -\log x -3=0$, express $x$ in terms of $y.$
If $2\log y -\log x-3=0$ express $x$ in terms of $y.$
If $2x^{{log _4}^3}+3^{\log _4x}=27$, then x is equal to?
$\log _{ 4 }{ 18 } $ is
The value of x, for which the 6th term in the expansion of $\left{ { 2 }^{ { log } _{ 2 }\sqrt { \left( { 9 }^{ x-1 }+7 \right) } }+\dfrac { 1 }{ { 2 }^{ { \left( 1/5 \right) log } _{ 2 }\left( { 3 }^{ x-1 }+1 \right) } } \right} ^{ 7 }$ is 84, is equal to
If x = ${ log } _{ 3 }243,y={ log } _{ 2 }64,$, Then $\sqrt { x-2\sqrt { y } } $ is
Logarithmic form of $3 \sqrt { 8 } = 2$ is
Number of solutions of $\log _{4}{\left(x-1\right)}=\log _{2}{\left(x-3\right)}$
The value of x, which satisfies the equation $2 \log _ { 2 } \left( \log _ { 2 } x \right) + \log _ { 12 } \left( \log _ { 2 } ( 2 \sqrt { 2 } x ) \right) = 1$ is greater
The logarithm form of $\displaystyle 5^3 = 125$ is equal to
The logarithmic form of $\displaystyle (81)^{\frac {3}{4}} = 27$ is
Given $\displaystyle 3^{x} = \frac {1}{9}$ then $x=?$
Express in logarithmic form and find x: $\displaystyle 10^{x} = 0.001$ (i.e base 10)
The logarithm form of $10^{-3} = 0.001$ is $\log _{10} 0.001 = -m$, then value of $m$ is
The value of $\displaystyle \log _{10}0.001 $ is equal to
The value of $\log _{0.5}16$ is equal to
The logarithm of $0.001$ to the base $10$ is equal to
$\log V = 2 \log 2 - \log 3 + \log \pi + 3 \log r$ can be expressed as
Which of the following is true for $\log _25$?
If $\log _{10}(x - 10) = 1$, then value of $x$ is
The value of $7 log _a \displaystyle \frac{16}{15} + 5 log _a \frac{25}{24} + 3 log _a \frac{81}{80}$ is
If $log _{10} x - log _{10} \sqrt x = \displaystyle \frac{2}{log _{10} x}$, then value of x is
If $\displaystyle \frac{log _2 (9 - 2^x)}{3 - x} = 1$, then value of x is
The value of $\log _{ \frac{1}{2} }{ 4 } $ is
The equation ${ \left( \log _{ 10 }{ x+2 } \right) }^{ 3 }+{ \left( \log _{ 10 }{ x-1 } \right) }^{ 3 }={ \left( 2\log _{ 10 }{ x+1 } \right) }^{ 3 }$ has