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Study of orthoboric acid - class-XII

Description: study of orthoboric acid
Number of Questions: 44
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Tags: the p-block elements chemistry p- block elements-i some p-block elements the p-block elements - group 13
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Which of the following is correct statement?

  1. Boric acid is a protonic acid

  2. Beryllium exhibits coordination number of six

  3. Chlorides of both beryllium and aluminium have bridged chloride structures in solid phase

  4. ${B} _{2}{H} _{8}.2{NH} _{3}$ is known as borazone


Correct Option: C

$H _{3}BO _{3}$ is a:

  1. monobasic acid and weak Lewis acid

  2. monobasic acid and weak Bronsted acid

  3. monobasic acid and strong Lewis acid

  4. tribasic acid and weak Bronsted acid


Correct Option: A
Explanation:

It is a monobasic acid and a weak lewis acid. It accepts an electron pair from $OH^{-}$.


$B(OH) _{3} + 2H _{2} O \rightleftharpoons [B(OH) _{4} ]^{-} +H _{3} O^{+} $

Option A is correct.

Boric acid is the trival name for ?

  1. orthoboric acid

  2. metaboric acid

  3. pyroboric acid

  4. None of these


Correct Option: A
Explanation:

Answer:- (A) Orthoboric acid

Boric acid is a weak, mono-basic Lewis acid of boron, which is often used as an antiseptic, insecticide, flame retardant, neutron absorber, or precursor to other chemical compounds and also known as orthoboric acid (trival name).
The chemical formula of boric acid is $H _3BO _3 \; or \; B{(OH)} _3$.

Boric acid on heating at $100^oC$ gives:

  1. $B _2O _3$

  2. $H _2B _4O _7$

  3. $HBO _2$

  4. $H _2BO _3$


Correct Option: C
Explanation:
  • Orthoboric acid, $H _3BO _3$ is a white crystalline solid, with soapy touch. It is sparingly soluble in water but highly soluble in hot water.
  • On heating, orthoboric acid above 370K forms metaboric acid, $HBO _2$ which on further heating yields boric oxide, $B _2O _3.$
  • Hence option C is correct answer.

$\displaystyle B(OH) _{3}+NaOH\rightleftharpoons NaBO _{2}+Na[B(OH) _{4}]+H _{2}O$ 

How can this reaction is made to proceed in forward direction?

  1. Addition of cis 1,2 diol

  2. Addition of borax

  3. Addition of trans 1,2 diol

  4. Addition of $Na _{2}HPO _{4}$


Correct Option: A
Explanation:

cis -1,2 diol is added to make the recation proceed in the forward direction.

$H _{3}BO _{3}\xrightarrow{T _{1}}X \xrightarrow{T _{2}} Y\xrightarrow{red hot} B _{2}O _{3}$ if $T _{1}<T _{2}$then X and Y respectively are :

  1. X=Metaboric acid and Y= Tetraboric acid

  2. X=Tetraboric acid and Y= Metaboric acid

  3. X=Borax and Y= Metaboric acid

  4. X=Tetraboric acid and Y= Borax


Correct Option: A
Explanation:

$H _{3}BO _{3}\xrightarrow{100^oC}HBO _2 \xrightarrow{160^oC} H _2B _4O _7\xrightarrow{red hot} B _{2}O _{3}$
X is $HBO _2$ which is metaboric acid and Y is $H _2B _4O _7$ which is tetraboric acid.

Which of the following is correct statement?

  1. Boric acid is a protonic acid

  2. Beryllium exhibits coordination number of six

  3. Chlorides of both beryllium and aluminium have bridged chloride structures in solid phase

  4. ${B} _{2}{H} _{6}.2{NH} _{3}$ is known as borazone


Correct Option: D

Which one of the following is the correct statement?

  1. Boric acid is a protonic avid.

  2. Both ${\text{T}}{{\text{l}}^{{\text{3 + }}}}{\text{and}}\;{\text{A}}{{\text{l}}^{{\text{3 + }}}}$ ions act oxidsing agent in aqueous solution.

  3. Hydrogen bonding in gives it a layered structure

  4. imparts bile colour to the burner flame.


Correct Option: D

The equilibrium constant for the reaction: $ H _3BO _3 + glycerin \rightleftharpoons (H _3BO _3 + glycerin complex ) $ is 0.90. How much glycerin should be added to I L of $ 0.10 M-H _3BO _3 $ solution, so that 60% of the $ H _3BO _3 $ is converted to boric acid glycerin complex?

  1. Infinite

  2. 1.73 M

  3. 0.10 M

  4. 2.27 M


Correct Option: B

$H _3BO _3$ is :

  1. monobasic and weak Lewis acid.

  2. monobasic and weak Bronsted acid.

  3. monobasic acid and strong Lewis acid.

  4. tribasic acid and weak Bronsted acid.


Correct Option: A
Explanation:

$\mathrm{H} _{3}\mathrm{B}\mathrm{O} _{3}(\mathrm{C})$ (orthoboric acid) is a weak lewis acid.

$\mathrm{H} _{3}\mathrm{B}\mathrm{O} _{3}+\mathrm{H} _{2}\mathrm{O} _{-}^{-}\mathrm{E}(\mathrm{O}\mathrm{H}) _{4}^{-}+\mathrm{H}^{\oplus}$

So as it releases one $H^{+}$ so its Monobasic and weak Lewis acid

Hence option A is correct.

Which of the following statements regarding orthoboric acid $(H _3BO _3)$ is false?

  1. It acts as a weak monobasic acid.

  2. It is soluble in hot water.

  3. It has a planar structure.

  4. It acts as a tribasic acid.


Correct Option: D
Explanation:

Boric acid, also called hydrogen borate, , is a weak, monobasic lewis acid of boron

Option D only is the wrong statement because it acts as monobasic acid not tri basic .

Hence option D is correct.

$B(OH) _3+NaOH\rightarrow Na[B(OH) _4] _{(aq)}$

Then addition of which of the following proceeds the reaction in the forward direction :

  1. cis-1, 2 diol

  2. trans 1, 2 diol

  3. borax

  4. $Na _2HPO _4$


Correct Option: A
Explanation:

$B(OH) _3+NaOH\rightarrow Na[B(OH) _4] _{(aq)}$

This reaction is reversible reaction because sodium metaborate, $ Na [B(OH) _4]$ formed by the reaction between $B(OH) _3$ and NaOH gets hydrolysed to regenerate $B(OH) _3$ and NaOH.

$ Na [B(OH) _4]$ $\overset {hydrolysis}\rightarrow$ $NaOH$ + $B(OH) _3$

If, some quantity of polyhydroxy compounds like cis- 1, 2-diol, catechol, glycerol etc is added to the reaction mixture then the $B(OH) _3$ combines with such polyhydroxy compounds to give chelated complex compound. Due to complex compound formation, stability increases and due to higher stability of complex, reaction moves in forward direction.

Which one of the following is/are incorrect statement(s)?

  1. The hydroxide of aluminium is more acidic than that of boron.

  2. The hydroxide of boron is basic while that of aluminium is amphoteric.

  3. The hydroxide of boron is acidic while that of aluminium is amphoteric.

  4. The hydroxides of both boron and aluminium are amphoteric.


Correct Option: A,B,D
Explanation:

All the elements of this group 13 form oxides and hydroxide.


Boron is the only element in group III of the periodic table which is non-metallic. Metal hydroxides must form a stable cation and anion i.e $OH^-$. Boron does not form a stable cation. This is the reason why metals form basic hydroxides while boron forms a weak acid called boric acid.

 Boron forms acidic oxides and hydroxides, while Al and Ga form amphoteric oxides and hydroxides. In and Tl forms basic oxides and hydroxides.The acidic nature of hydroxides decreases down the group.

Hence options A,B & D are correct.

Boric acid is a very weak acid but in the presence of certain organic compounds, it acts as a strong acid. Which one of the following organic compound(s) cannot affect such change?

  1. Glycerol

  2. Acetic acid

  3. Ethyl alcohol

  4. Ethylene


Correct Option: B,C,D
Explanation:


Option (B),(C),(D) are correct.
Boric acid forms a stable cyclic complex with polyhydroxy compounds like glycerol. This helps in the release of $H^+$ as $H _3O^+$ and therefore boric acid acts as a strong acid. This is not possible with compounds such as acetic acid, ethyl alcohol and ethylene.

$2B+3H _{2}SO _{4}\rightarrow 2H _{3}BO _{3} +A$ 


The hybridization of central atom in compound A is :

  1. sp

  2. $sp^{2}$

  3. $sp^{3}$

  4. $sp^{3}d$


Correct Option: B
Explanation:

The balanced chemical reaction is as given below.
$2B+3H _{2}SO _{4}\rightarrow 2H _{3}BO _{3}\rightarrow + \underset {A} {SO _2}$
S atom in sulphur dioxide undergoes $sp^2$ hybridization.

$H _{3}BO _{3}\xrightarrow{375K} A \xrightarrow{Red \, Heat}B _{2}O _{3}$
$H _{3}BO _{3}\xrightarrow{435K} B \xrightarrow{Red \, Heat}B _{2}O _{3}$


The compounds A & B are:

  1. Orthoboric acid, metaboric acid

  2. Metaboric acid, Tetra boric acid

  3. Tetra boric acid, Metaboric acid

  4. Tetra boric acid, orthoboric acid


Correct Option: B
Explanation:

$H _{3} BO _{3} \overset{375K}{\rightarrow} HBO _{2} \overset{red heat}{\rightarrow} B _{2} O _{3} $
$H _{3} BO _{3} \overset{435K}{\rightarrow} H _{2} B _{4} O _{7} \overset{red heat}{\rightarrow} B _{2} O _{3} $

Orthoboric acid when heated to red hot gives:

  1. metaboric acid

  2. pyroboric acid

  3. boron and water

  4. boric anhydride


Correct Option: D
Explanation:

$H _{3} BO _{3} \overset{375K}{\rightarrow} HBO _{2} \overset{red heat}{\rightarrow} B _{2} O _{3} $ (Boric anhydride)

Which is the correct statement for $H _{3}BO _{3}$ ?

  1. It is used as antiseptic

  2. As preservative of foods

  3. It gives green colour to flame

  4. All are correct


Correct Option: D
Explanation:

It is antiseptic and its water solution is used as an eyewash. It is used as a preservative.
Boron burns with green flame when heated strongly with $O _{2} $.

$BCl _{3}$ on hydrolysis gives:

  1. $B _{2}O _{3}$ and $HCl$

  2. $B _{2}H _{6},\ HCl$ and $O _{2}$

  3. $H _{3}BO _{3}$ and $HCl$

  4. $B _{2}O _{3},\ H _{2}$ and $Cl _{2}$


Correct Option: C
Explanation:

$BCl _3$ on hydrolysis gives $H _3BO _3$ and $HCl$.

The reaction is as follows:
$BCl _{3} + 3H _{2} O \rightarrow B(OH) _{3}  + 3HCl$

Boric acid on heating yields:

  1. B

  2. $B _{2}H _{6}$

  3. $BO _{2}$

  4. $B _{2}O _{3}$


Correct Option: D
Explanation:

$H _{3} BO _{3} \overset{375K}{\rightarrow} HBO _{2} \overset{red heat}{\rightarrow} B _{2} O _{3} $

Thus boric acid on heating ginves boric oxide.

Which of the following statements about $H _{3}BO _{3}$ is not correct?

  1. It is prepared by acidifying an aqueous

    solution of borax

  2. It has a layer structure in which planar $BO _{3}$ units are joined by hydrogen bonds

  3. It does not act as proton donor but acts as

    Lewis acid by accepting hydroxyl ion

  4. It is a strong tribasic acid.


Correct Option: D
Explanation:

It is a monobasic lewis acid. It accepts an electron pair from $OH^{-}$.
$B(OH) _{3} + 2H _{2} O \rightleftharpoons [B(OH) _{4} ]^{-} +H _{3} O^{+} $

Solid oxy acids of boron are.

  1. $H _{3}BO _{3}$

  2. $HBO _{2}$

  3. $H _{2}B _{4}O _{7}$

  4. All


Correct Option: D
Explanation:

All are solids.

$H _{3}BO _{3}\overset{T _{1}}{\rightarrow}X\overset{T _{2}}{\rightarrow}Y\overset{red:hot}{\rightarrow}B _{2}O _{2}$


 if $T _{1}< T _{2}$ then X and Y respectively are-

  1. $X=$ Metaboric acid and $Y=$ Tetraboric acid

  2. $X=$ Tetraboric acid and $Y=$ Metaboric acid

  3. $X=$ Borax and $Y=$ Metaboric acid

  4. $X=$ Tetraboric acid and $Y=$ Borax


Correct Option: A
Explanation:
Effect of temperature at $100^{\circ}C \,,\,H _{3}BO _{3}$ losses water and convert into metaboric acid.

$H _{3}BO _{3}\xrightarrow{100^{\circ}C}HBO _{2}+H _{2}O$

metaboric acid form tetraboric acid on heating at $160^{\circ}C$

$4HBO _{2}\xrightarrow{160^{\circ}C}H _{2}B _{4}O _{7}+H _{2}O$

On strong heating, $B _{2}O _{3}$ is produced

$H _{2}B _{4}O _{7}\rightarrow 2B _{2}O _{3}+H _{2}O$

Hence, option $A$ is correct.

The states of hybridisation of boron and oxygen atoms in boric acid $(\mathrm{H} _{3}\mathrm{B}\mathrm{O} _{3})$ are respectively:

  1. $\mathrm{s}\mathrm{p}$ and $\mathrm{s}\mathrm{p}^{2}$

  2. $\mathrm{s}\mathrm{p}^{2}$ and $\mathrm{s}\mathrm{p}^{3}$

  3. sp3 and $\mathrm{s}\mathrm{p}^{2}$

  4. sp3 and sp3


Correct Option: B
Explanation:

The states of hybridisation of boron and oxygen atoms in boric acid $(\mathrm{H} _{3}\mathrm{B}\mathrm{O} _{3})$ are respectively are $\mathrm{s}\mathrm{p}^{2}$ and $\mathrm{s}\mathrm{p}^{3}$
respectively.

In boric acid the boron is surrounded by three bond pair thus it shows $sp^2$ hybridization while oxygen is surrounded by one two bond pair and two lone pairs so it shows $sp^3$ hybridization.

$\mathrm{H} _{3}\mathrm{B}\mathrm{O} _{3}$ is:


  1. Monobasic and weak Lewis acid

  2. Monobasic and weak Bronsted acid

  3. Monobasic and strong Lewis acid

  4. Tribasic and weak Bronsted acid


Correct Option: A
Explanation:

$\mathrm{H} _{3}\mathrm{B}\mathrm{O} _{3}(\mathrm{C})$ (orthoboric acid) is a weak lewis acid.
$\mathrm{H} _{3}\mathrm{B}\mathrm{O} _{3}+\mathrm{H} _{2}\mathrm{O} _{-}^{-}\mathrm{E}(\mathrm{O}\mathrm{H}) _{4}^{-}+\mathrm{H}^{\oplus}$
So as it releases one $H^{+}$ so its Monobasic and weak Lewis acid
Hence option A is correct.

Boric acid is :

  1. monobasic and weak lewis acid

  2. monobasic and weak bronsted acid

  3. monobasic and strong lewis acid

  4. tribasic and strong bronsted acid


Correct Option: A
Explanation:

Boric acid is monobasic acid and weak Lewis acid.


Boric acid contains $3-OH$ groups yet it acts as monobasic acid rather than tribasic acid. Because boric acid does not act as proton donor but it accepts a lone pair of electrons from $OH^{-}$ ions and forms ${B(OH) _4}^-$. Boric acid behaves as Lewis acid because it accepts a lone pair of electrons from $OH^{-}$ ions from water. 
Boric acid considered as weak acid because it does not dissociate to produce ions rather forms metaborate ion and in turn release ions.

Boric acid is a:

  1. strong tribasic acid

  2. strong monobasic acid

  3. weak tribasic acid

  4. weak monobasic acid


Correct Option: D
Explanation:

Boric acid is a weak, monobasic lewis of boron often used as an antiseptic, insecticide, flame retardant, neutron absorber or precursor to other chemical compounds. It has the chemical formula,$H _3BO _3$ (sometimes written $B(OH) _3$ and exists in the form of colourless crystals or a white powder that dissolves in water.

On the addition of mineral acid to an aqueous solution of borax, the compound formed is:

  1. orthoboric acid

  2. boron hydride

  3. metabolic acid

  4. pyroboric acid


Correct Option: A
Explanation:

Addition of mineral acid to an aqueous solution of Borax,

Orthoboric acid is formed.

$Na _2B _4O _7+2HCl+5H _2O\longrightarrow 4H _3BO _3 + 2NaCl$

Borax.        Hydrochloric      Orthoboric acid  Sodium chloride Acid

Boric acid is soluble in boiling water. When heated above $170^oC$, it dehydrates, forming metaboric acid $(HBO _2)$:

Acid melts at about $236^oC$, and when heated above about $300^o C$ further dehydrates, forming tetraboric acid, also called pyroboric acid $(H _2B _4O _7)$.

An aqueous solution of boric acid is found to be weakly acidic in nature. This acidic character arises due to the following reasons.

  1. It is a protic acid which donates protons in aqueous solution.

  2. It is a Lewis acid which abstracts $OH^-$ from water and leaves $H^+$ to make the solution acidic.

  3. It gives metaboric acid when dissolves in water

  4. It is prepared by reaction of borax with sulphuric acid hence it behaves as an acid.


Correct Option: B
Explanation:

Boric acid, when reacts with water, abstracts ${OH}^{-}$ ions and releases ${H _3O}^{+}$ ions.

$H _3BO _3 + H _2O \; \longrightarrow \; {H _3O}^{+} + {H _2BO _3}^{-}$
This property of boric acid makes it acidic.

Which of the following compounds are formed when $BCl _3$ is treated with water?

  1. $H _3BO _3$

  2. $B _2H _6$

  3. $B _2O _3$

  4. $HBO _2$


Correct Option: A
Explanation:
$B{Cl} _3$ hydrolyzes readily to give hydrochloric acid and boric acid.

$B{Cl} _3 + 3H _2O \; \xrightarrow{hydrolyzes} \; B{(OH)} _3 + 3HCl$

Hence, the correct answer is option $\text{A}$.

Which of the following is not an application of orthoboric acid ?

  1. As an antiseptic and eye wash

  2. In glass industry 

  3. In glazes for pottery

  4. In borax-bead test


Correct Option: D
Explanation:
Orthoboric acid is a weak, monobasic Lewis acid of boron, which is often used as an antiseptic, insecticide, flame retardant, neutron absorber, or precursor to other chemical compounds.

Borax on heating gives $B _2O _3 \; and \; NaBO _2$ which is glassy mass and used for the borax-bead test. Thus, there is no use of orthoboric acid in borax bead test.

Hence, the correct answer is option $\text{D}$.

Which one of the following statements is correct?

  1. Boric acid is a protonic acid.

  2. Both $Tl^{3+}$ and $Al^{3+}$ions act as oxidising agents in aqueous solution.

  3. Hydrogen bonding in $H _3BO _3$ gives it a layered structure.

  4. $B(OEt) _3$ imparts blue colour to the burner flame.


Correct Option: C
Explanation:

$(A)$ Boric acid is a weak monobasic Lewis acid, soluble in water and in aqueous solutions. The boron atom completes its octet by accepting $OH^-$ from water molecules.
$B(OH) _3+2H _2O\rightarrow [B(OH) _4]^-+H _3O^+$
$(B)$ Only $Tl^{3+}$ acts as an oxidising agent on account of inert pair effect.
$(C)$ In the solid state, the $B(OH) _3$ units are hydrogen bonded together into two dimensional sheets with almost hexagonal symmetry. This gives it a layered structure.
$(D)$ $B(OEt) _3$ imparts green colour to the burner flame.

Hence, option C is the correct answer.

The reaction,

$B(OH) _3+NaOH\rightarrow Na[B(OH) _4]$ can be made to proceed in forward direction by :

  1. adding cis-1, 2-diol.

  2. adding borax.

  3. adding trans-1, 2-diol.

  4. adding $Na _2HPO _4$.


Correct Option: A
Explanation:
If polyhydroxy compound like glycerol, mannitol or sugar are added to titration mixture than it can be titrated with $NaOH$.

Due to formation of chelated complex, the reaction moves in forward direction.

$B(OH) _{3}+NaOH\rightarrow Na[B(OH) _{4}]$

Aqueous solution of ortho-boric acid can be titrated against sodium hydroxide using phenolphthalein indicator only in presence of :

  1. trans-glycerol.

  2. catechol.

  3. cis-glycerol.

  4. both (b) and (c).


Correct Option: D
Explanation:

Aqueous solution of ortho-boric acid can be titrated against sodium hydroxide using phenolphthalein indicator only in presence of catechol and cis-glycerol.

Ortho-boric acid forms a stable cyclic complex with polyhydroxy compounds like catechol and cis-glycerol. This helps in the release of $H^+$ as $H _3O^+$ and therefore boric acid acts as a strong acid and hence can be titrated against NaOH with phenolphthalein.

Hence,option D is correct.

Orthoboric acid behaves as weak monobasic acid giving $H {3}O^{+}$ and ___.

  1. $H _{2}BO _{2}^{+}$

  2. $H _{2}BO _{2}^{-}$

  3. $[B\left ( OH \right ) _{4}]^{-}$

  4. $[B\left ( OH \right ) _{4}]^{+}$


Correct Option: C
Explanation:

It is a Lewis acid. It accepts an electron pair from $OH^{-}$.
The reaction follows:
$B(OH) _{3} + 2H _{2} O \rightleftharpoons [B(OH) _{4} ]^{-} +H _{3} O^{+} $

Ortho-boric acid can be represented as $B\left ( OH \right ) _{3}$. It is :

  1. a strong Arrhenius acid

  2. lewis acid and ionizes as monobasic acid

  3. an alkali capable of releasing $OH^{-}$ ions in water

  4. a weak acid existing as $B\left ( OH \right ) _{6}^{-3}$ in water


Correct Option: B
Explanation:

It is a monobasic (releases 1 H+ )lewis acid. It accepts an electron pair from $OH^{-}$.
$B(OH) _{3} + 2H _{2} O \rightleftharpoons [B(OH) _{4} ]^{-} +H _{3} O^{+} $

Asseriton : In water, orthoboric acid behaves as a week monobasic acid.
Reason : In water, orthoboric acid act as a proton donor

  1. Assertion is true, Reason is true, Reason is the correct explanation of Assertion

  2. Assertion is true, Reason is true, Reason is not the correct explanation of Assertion

  3. Assertion is true, Reason is false

  4. Assertion is false, Reason is true


Correct Option: C
Explanation:

It is a monobasic (releases 1 H+ )lewis acid. It accepts an electron pair from $OH^{-}$.
$B(OH) _{3} + 2H _{2} O \rightleftharpoons [B(OH) _{4} ]^{-} +H _{3} O^{+} $

Boric acid:

  1. exists in polymeric form due to inter-molecular hydrogen bonding

  2. it used in manufacturing of optical glasses

  3. is a tri-basic acid

  4. with borax, it is used in the preparation of a buffer solution.


Correct Option: A,B,C,D
Explanation:

Boric acid, also called hydrogen borate, boracic acid, orthoboric acid the chemical formula $H _3BO _3$ ($B(OH) _3$) (mono basic), and exists in the form of colorless crystals or a white powder that dissolves in water.
Boric acid, exists in polymeric form due to inter-molecular hydrogen bonding
Boric acid is in equilibrium with its conjugate base the borate ion which is widely used (in the concentration range 50 - 100 ppm boron equivalents) as a primary or adjunct pH buffer system in swimming pools(buffer solution).
The primary industrial use of boric acid is in the manufacture of monofilament fiberglass usually referred to as textile fiberglass
Hence options A,B, C& D are correct.

When orthoboric acid is strongly heated, residue are :

  1. meta boric acid

  2. boron

  3. both

  4. none of these


Correct Option: A
Explanation:

Boric acid is soluble in boiling water. When heated above 170 °C, it dehydrates, forming metaboric acid ($HBO _2$)

$H _3BO _3\rightarrow HBO _2 + H _2O$
Hence option A is correct.

Which of the following statements about $H _3BO _3$ is not correct?

  1. It is a strong tribasic acid

  2. It is prepared by acidifying an aqueous solution of borax

  3. It has a layer structure in which planar borate ions are joined by hydrogen bonding

  4. None of these


Correct Option: A
Explanation:

Boric acid, also called hydrogen borate is a weak, monobasic Lewis acid of boron. So it is not a strong tribasic acid. Remaning all options are correct

Hence option $A$ is correct.

The correct statement(s) about orthoboric acids is/are :

  1. It behaves as a weak acid in water due to self ionization.

  2. Acidity of its aqueous solution increases on adding ethyl alcohol.

  3. It has three dimension structure due to H-bonding.

  4. It is a weak electrolyte in water.


Correct Option: B,D

Which one of the following statements about $H _3BO _3$ is not correct?

  1. It is a strong tribasic acid

  2. It is a prepared by acidifying an aqueous solution of borax

  3. It has a layer structure in which planar $BO _3$ units are joined by hydrogen bonds

  4. It does not act as proton donor as it acts as a Lewis acid by accepting hydroxyl ions


Correct Option: A
Explanation:

It is weak monoprotic acid and it does not act as proton donor but removes proton from water.

$B _{2}Ca _{6}O _{11}+ Na _{2}CO _{3}\overset{\Delta }{\rightarrow}\left [ X \right ]+CaCO _{3}+NaBO _{2}$ (unbalanced equation)
Correct choice(s) for [X] is/are:

  1. structure of anion of crystalline [X] has one boron atom sp$^{3}$ hybridised and other three boron atoms sp$^{2}$
    hybridised

  2. X with NaOH (aq.) gives a compound which on reaction with hydrogen peroxide in alkaline medium yields
    a compound used as brightner in soaps

  3. hydrolysis of [X] with HCl or H$ _{2}$SO$ _{4}$ yields a compound which on reaction with HF gives fluoroboric acid

  4. [X] on heating with chromium salts in oxidising flame gives green coloured bead in cold


Correct Option: B,C,D
Explanation:

Compound [X] is Na$ _{2}$B$ _{4}$O$ _{7}$
(A) two boron atoms are $sp^{2}$ while other two boron atoms are $sp^{3}$ hybridised.
(B) product is sodium peroxoborate which is used as brightner in soaps.
(C) $H _{3}BO _{3}$ is formed which with HF gives $HBF _{4}$.
(D) Green bead in oxidising as well as in reducing flame in cold.

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