0

Archimedes' principle and its applications - class-XI

Attempted 0/40 Correct 0 Score 0

Assertion: To float; a body must displace liquid whose weight is equal to the actual weight.
Reason: The body will experience no net downward force in that case.

  1. Both assertion and reason are true and reason is correct explanation of assertion.

  2. Both assertion and reason are true but reason is not the correct explanation of assertion.

  3. Assertion is true but reason is false.

  4. Both assertion and reason are false.


Correct Option: A
Explanation:

If the body displaces liquid whose weight is equal to the actual weight of body, the downward force weight will be balanced by the buoyant force and the body won't experience any net downward force in that case.

State whether given statement is True or False
Archimede's principle describes the magnitude of a buoyant force acting on a body that is partly or completely submerged in a fluid.

  1. True

  2. False


Correct Option: A
Explanation:

Answer is A.

Archimedes' principle indicates that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially submerged, is equal to the weight of the fluid that the body displaces.
Hence, the given statement is true.

Which one of the following statements is true?

  1. Archimedes' principle can also be applied to gases

  2. The buoyant force depends on the nature of object immersed in the liquid.

  3. Ice floats in water because the density of ice is more than that of water.

  4. Force acting on a unit area is called thrust.


Correct Option: A
Explanation:

Answer is A.

The Archimedes principle, states that the buoyant force exerted on a body immersed in a fluid is equal to the weight of the fluid the body displaces. In other words, to calculate the buoyant force on an object we assume that the submersed part of the object is made of water and then calculate the weight of that water.
This principle is valid for any fluid not only liquids (such as water) but also gases (such as air).

 
Hence, only the statement in option A is true.

An iron needle sinks in water as its density is less than 1 $ \displaystyle g/cm^{3} $.

  1. True

  2. False


Correct Option: B
Explanation:

Any substance sinks in a liquid of density of S when density of substance is greater than that of liquid i.e.

$\boxed { density\quad of\quad substance\quad >\quad S } $

If a body X floats in liquid Y. The density of body X is greater than liquid Y. True or false

  1. True

  2. False


Correct Option: B
Explanation:

For a body to sink in water then density of body should be more than density of water or any fluid i.e. density of body > density of water.

Submarine's lactometers, hydrometers, etc. are designed according to __________.

  1. Archimedes principle

  2. Principles of hydrology

  3. Principles of fluid flow

  4. All of the above


Correct Option: A
Explanation:

Archimedes principle was an important work and has many application. It is used for designing submarines, ships etc. lactometer and hydrometer and also based on this principle and are used to check the purity of milk and density of liquids respectively.

Archimedes' principle states that the buoyant force applied to an object 

  1. is greater the weight of the fluid the object displaces

  2. is equal to the weight of the fluid the object displaces

  3. is less than the weight of the fluid the object displaces

  4. is zero


Correct Option: B
Explanation:

Archimedes' principle states that the buoyant force applied to an object is equal to the weight of the fluid the object displaces.

Archimedes principle works when the body is
  1. Partially immersed in a liquid

  2. Fully immersed in a liquid

  3. Both A and B

  4. This principle has nothing to do with the level of immersion of the body

Correct Option: C
Explanation:

Archimedes' Principle states that buoyant force acting on body upwards is equal in magnitude of the weight of liquid it displaces. Depending upon how much the body is immersed in liquid, and hence how much the weight of liquid is displaced, the buoyant force varies.

When an object is immersed in water, it displaces $20\,kg$ of water. How much is the buoyant force acting on the object in Newtons?
  1. $100$

  2. $200$

  3. $0$

  4. $400$


Correct Option: B
Explanation:

According to the Archimedes principle, the buoyant force acting on an object immersed in liquid is equal to the weight of liquid it displaces. Hence the buoyant force acting on the given object=$20kg\times 10m/s^2=200N$

Magnitude of buoyant force is given by 
  1. Newton's first law

  2. Archimedes principle
  3. Newton's second  law
  4. None of the above 


Correct Option: B
Explanation:

Archimedes principle, states that any body completely or partially submerged in a fluid (gas or liquid) at rest is acted upon by an upward, or buoyant force the magnitude of which is equal to the weight of the fluid displaced.

Archimedes principle is used for
  1. Determining the force applied on the object
  2. Determining the relative density of the object
  3. Determining the gravitational constant
  4. All the above


Correct Option: B
Explanation:
Hydrometer works on the Archimedes principle. The level at which it floats in liquid determines its relative density.
Quantitatively, $V _0dg=V _{immersed}\rho g$

$\implies $ relative density $\rho _r=\dfrac{d}{\rho}=\dfrac{V _{immersed}}{V _0}$
Fill in the blank.
It is the ______ which makes balloon to rise in air. 
  1. Upthrust

  2. Buoyant force

  3. Both A and B

  4. None


Correct Option: C
Explanation:

A balloon is filled with air at high pressure which leads to uprising of it because it experiences more buoyant force or we can say upthrust as they are same in this case.

Lactometers are based on
  1. Third law of motion

  2. Kepler's law

  3. Acceleration due to gravity

  4. Archimedes principle


Correct Option: D
Explanation:

Lactometer works on the Archimedes' Principle that a solid suspended in a fluid is buoyed by a force equal to the weight of the fluid displaced. If the milk sample is pure, then the lactometer floats on it and if it is adulterated or impure, then the lactometer sinks.

Fill in the blank. 

As per Archimedes principle the buoyant force on a submerged object is equal to_______ of liquid displaced by object. 

  1. Height

  2. Weight

  3. Nature

  4. Volume


Correct Option: B
Explanation:

According to the Archimedes principle, the buoyant force of a submerged object is equal to the weight of the liquid displaced.

$\therefore$ Buoyant force     $B = \rho gV$    where $\rho$ and $V$ is the density of liquid and volume of object respectively.

According to the law of floatation weight  of floating body is -

  1. Equal to the weight of liquid displaced

  2. Equal to the volume of liquid displaced

  3. Is greater than the weight of liquid displaced

  4. Is less than the weight of liquid displaced


Correct Option: A
Explanation:

According to Archimedes principle , weight of body in water or liquid is equal to the weight of the liquid displaced by it.

The specific gravity of ice is $0.9$. The area of the smallest slab of ice of height $0.5\ m$ floating in fresh water that will just support a $100\ kg$ man is

  1. $1.5\ m^{2}$

  2. $2\ m^{2}$

  3. $3\ m^{2}$

  4. $4\ m^{2}$


Correct Option: B
Explanation:

wt. of man = 1000 N

wt. of ice = $0.9\times area\times 0.5N$
wt. of water = $1\times area\times 0.5N$
So, wt. of water = wt. of ice + wt. of man
      area $\times 0.5=area\times 0.9\times 0.5+2000$
      1 area = 20000 = ${ 2m }^{ 2 }$

A block of ice with a lead shot embedded in It is floating on water contained in a vessel. The temperature of the system is maintained at $0^{\circ}$ C as the ice melts. When the ice melts completely the level of water in the vessel rises.

  1. True

  2. False


Correct Option: B
Explanation:

According to Archemedies principle if any object is floating on a liquid the weight of the liquid displaced is equal to the weight of the object, when the block of ice melts the bullet ultimately sink in water and displaces the same volume of water as its own volume was, but when it was embedded in the ice it displaced move volume, therefore level of water will fall.

A rectangular boat floating in water has length 4 m and breadth 1.5 m. A person gets into the boat as a result of w which the boat sinks by 2 cm. Mass of the person is :

  1. 80 kg

  2. 100 kg

  3. 120 kg

  4. 92 kg


Correct Option: C
Explanation:

Given,

$l=4m$
$b=1.5m$
$h=2cm=0.02m$
Volume, $V=lbh$
$V=4\times 1.5\times 0.02 =0.12m^3$
Density of water, $\rho=1000 kg/m^3$
Mass of the person, $M=\rho V$
$M=1000\times 0.12$
$M=120kg$
The correct option is C.

When a body is weighed in a liquid, the loss in its weight depends upon:

  1. volume of the body

  2. mass of the body

  3. shape of the body

  4. CG of the body


Correct Option: A
Explanation:

Loss in weight is dependent on volume of body.

$ \therefore$ Option $A$ is correct.

FIll in the blank. 

When a solid floats in a liquid,  the weight of _______ by its immersed part of the solid is equal to the weight of the solid. 

  1. less

  2. buoyant force

  3. weight

  4. liquid displaced


Correct Option: D
Explanation:

Liquid displaced.
This is known as Archimedes principle.
Archimedes' principle indicates that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially submerged, is equal to the weight of the fluid that the body displaces.

Archimedes' major contribution / discovery was:

  1. Photoelectric effect

  2. Principle of buoyancy

  3. Wave theory of light

  4. Law of inertia


Correct Option: B
Explanation:

Answer is B

Archimedes' principle indicates that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially submerged, is equal to the weight of the fluid that the body displaces. Because of this buoyancy a body is able to float or submerge over liquid surface.

An iron ball is weighed in air and then in water by a spring balance

  1. Its weight in air is more than in water

  2. Its weight in water is more than in air

  3. Its weight in same both in air and water

  4. Its weight is zero in water


Correct Option: A
Explanation:

By Archimedes Principle, an object immersed(partially or fully) in a fluid experiences a loss in weight, which is given by the weight of the fluid displaced by the body.


For the given iron ball, the weight measured in air is $W _1 = (m _\textrm{ball}-\rho _\textrm{air}V _\textrm{ball})g$
Similarly, weight measured in water is $W _2 = (m _\textrm{ball}-\rho _\textrm{water}V _\textrm{ball})g$

We know that, $\rho _\textrm{water} > \rho _\textrm{air}$
Hence, $W _2 <W _1$
i.e., Weight measured in air is more than that in water.

A cylinder is made up of a material of density $1.5\ g\ cm^{-3}$ is immersed inside a liquid of density $1\ g\ cm^{-3}$. State whether the cylinder moves up or not

  1. Yes

  2. No

  3. Maybe

  4. Can't say


Correct Option: B
Explanation:

Let the volume of cylinder be V

So weight of cylinder is $W=V\rho _{cylinder}g=1.5Vg$
Buoyancy force $F=V\rho _{liquid}g=V\times 1\times g=Vg$
Since weight is greater than buoyancy, $W>F$, so it will move downward.

$A$ and $B$ are two metallic pieces. They are fully immersed in water and then weighed. Now they show same loss of weight. The conclusion therefore is:

  1. $A$ and $B$ have same weight in air

  2. $A$ and $B$ have equal volumes

  3. The densities of the materials of $A$ and $B$ are the same

  4. $A$ and $B$ are immersed to the same depth inside water.


Correct Option: B
Explanation:

Same loss of weight implies equal buoyant forces on the object which is equal to weight of liquid displaced i.e. both the bodies have equal volumes.

Two solids A and B Float is a liquid. It is observed that A floats with half its volume immersed and B floats with $2/3$ of its volume immersed. Compare the densities of A and B.

  1. $4:3$

  2. $2:3$

  3. $3:4$

  4. $1:3$


Correct Option: C
Explanation:

$\dfrac { density\quad of\quad A }{ density\quad of\quad B } =\dfrac { density\quad of\quad immersed }{ Volume\quad of\quad B\quad immersed } =\dfrac { 1/2 }{ 2/3 } $

$\dfrac { density\quad of\quad A }{ density\quad of\quad B } =\dfrac { 3 }{ 4 } $

A piece of paraffin wax of density 0.9 g/cc floats on water.A layer of turpentine of density 0.87 g/cc is added on top of water until the wax is entirely submerged.The ratio of the volume of wax immersed in water to that in turpentine is 

  1. 3 : 13

  2. 87 : 90

  3. 90 : 87

  4. 3 : 10


Correct Option: D
Explanation:

Buoyant force = weight of liquid displaced

hence $0.9V=1\times { V } _{ 1 }+0.87\times { V } _{ 2 }$
            & $V={ V } _{ 1 }+{ V } _{ 2 }$
               $0.9\left( { V } _{ 1 }+{ V } _{ 2 } \right) ={ V } _{ 1 }+0.87{ V } _{ 2 }$
               $0.9{ V } _{ 1 }+0.9{ V } _{ 2 }={ V } _{ 1 }+0.87{ V } _{ 2 }$
                        $\boxed { \dfrac { { V } _{ 1 } }{ { V } _{ 2 } } =\dfrac { 3 }{ 10 }  } $

The densities of objects P,Q,R and S are ${200 kg/m^3}$, ${450 kg/m^3}$, ${1200 kg/m^3}$  and ${785 kg/m^3}$ respectively. Which one of these objects will sink when dipped in a bucket of water?

  1. P

  2. Q

  3. R

  4. S


Correct Option: C
Explanation:

Answer is C.

According to the laws of flotation, the more denser liquid will sink below and the less dense material will float.
In this case, the object R has the maximum density of $1200kg/{ m }^{ 3 }$.
Therefore, object R will sink when dipped in a bucket of water.

A 70 g substance has a volume of $35:cm^3$. It will float on the surface of the water.

  1. True

  2. False


Correct Option: B
Explanation:

Given:
Mass of substance $= 70g$.
Volume of substance $= 35cm^3$
density of water $= 1gm^{-3}$
By using the formula,
Density $=\dfrac{Mass}{Volume}$
Density of sub stance $= \dfrac{70}{35}=2gm^{-3}$
since, the density of the substance is more than the density, the gravitational force acting on it will be stronger than the buoyant force of water acting it, it will sink and not float on the surface of water

A piece of wood floats in water, completely inside it. What happens when it is dropped in ethanol?

  1. It floats higher

  2. Stays as before

  3. It sinks

  4. It sinks first and then rises


Correct Option: C
Explanation:

Since , the ethanol is less denser than the water.Therefore, a piece of wood floating completely in water will sink in the ethanol.

As the density of a series of liquids increases, the upthrust on the iron rod submerged

  1. Increases

  2. Decreases

  3. Remains constant

  4. Noting can be said


Correct Option: A
Explanation:

As the density of liquid increases & so does the buoyant force on the submerged rod which will result in increase in upthrust.

An object is placed in 3 beakers containing liquids A, B and C respectively. If the density of object (d) when compared to tensities of liquids A, B and C is given by $d _A < d < d _B < d _C$ then the body sinks in

  1. liquid A

  2. liquid B

  3. liquid C

  4. all the three liquids


Correct Option: A
Explanation:

When the density of the liquid is greater than that of object, then the weight of liquid displaced is greater than or equal to the weight of the object. This means that the buoyant force acting on the object is greater or equal to the weight of the object which makes the object to float in that liquid. 

Hence the object will float in liquids B and C as the densities of liquids B and C are more than that of the object while the object will sink in liquid A as the density of liquid A is less than that of the object.

A body of mass $120kg$ and density $600kg/{m}^{3}$ floats in water. What additional mass could be added to the body so that the body will just sink?

  1. $20kg$

  2. $80kg$

  3. $100kg$

  4. $120kg$


Correct Option: B
Explanation:

Weight of the water displaced= weight of body + additional mass

${ \rho  } _{ w }Vg=Mg$   ($M$ is the total mass)
${ \rho  } _{ w }V=M=\left( 100+m \right) \ V=\cfrac { 120 }{ 600 } =0.2{ m }^{ 3 }\ 1000\times 0.2=\left( 120+m \right) \ m=80kg$

Write the following steps in a sequence to verify Archimedes' principle.
(a) The object is completed immersed in a liquid.
(b) The weight of the object in air is measured by using a spring balance ($w _{1}$).
(c) The weight of the object in the given liquid is determined ($w _{1}$).
(d) The loss of weight of the object ($w _{1}-w _{2}$) is determined.
(e) The weight of the liquid displaced by the object (w) is determined.
(f) The value of ($w _{1}-w _{2}$) is compared with the value of (w).

  1. b a c d e f

  2. a b d c f e

  3. a b c d e f

  4. f e c a b d


Correct Option: A
Explanation:

Option (A) follows correct procedure as initially weight of the object is calculated in the air than it is immersed in liquid and its weight is measured in the liquid and then the diffrence between the two weights would be calculated  and than weight of liquid displaced by the body would be calculated and later the two diffrences would e compared.

so option (A) is correct.

The density of ice is $917\ kgm^{-3}$. What fraction of the volume of a piece of ice will be above water, when floating in fresh water?

  1. 0.06

  2. 0.083

  3. 0.038

  4. 0.068


Correct Option: C

Construction of a submarine is based on.

  1. Bernoulli's theorem

  2. Pascal's law

  3. Archimedes' principle

  4. None of these


Correct Option: C
Explanation:

Construction of a submarine is based on Archimedes' principle.

A body of density $\rho$ is dropped from rest from a height h into a lake of density $\sigma$, where $\sigma > \rho$. Neglecting all dissipative forces, the maximum depth to which the body sinks before returning to float on surface

  1. $\dfrac{h}{\sigma - \rho}$

  2. $\dfrac{h\rho}{\sigma}$

  3. $\dfrac{h\rho}{\sigma - \rho}$

  4. $\dfrac{h\sigma}{\sigma - \rho}$


Correct Option: C
Explanation:

${V _f}^2-V _1^2=2as$

$\Rightarrow r-(2gh)=2 \times -\left(\cfrac {\sigma}{\delta}-1\right)g \times s$
$\Rightarrow s=\left(\cfrac {h}{\cfrac {\sigma}{\delta}-1}\right)$
$\Rightarrow \left[s=\cfrac {h\rho}{\sigma-\rho}\right]$

A sphere of iron and another of wood, both of same radius are placed on the surface of water. State which of the two will sink? (It is given $\rho _{iron} > \rho _{water}$, and  $\rho _{wood} < \rho _{water}$)

  1. Sphere of iron will sink.

  2. Sphere of wood will sink.

  3. both will sink

  4. both will not sink


Correct Option: A
Explanation:

Since density of iron is more than that of wood, so weight of iron sphere will be more than upthrust due to water on it. But density of wood is less than that of iron so sphere of wood will float. 

How does the density of a substance determine whether a solid piece of density $\rho _s$ of that substance will float or sink in a given liquid of density $\rho _L$?

  1. The body will float if $\rho _s \leq \rho _L$ and it will sink if $\rho _s < \rho _L$.

  2. The body will float if $\rho _s \leq \rho _L$ and it will sink if $\rho _s > \rho _L$.

  3. The body will float if $\rho _s > \rho _L$ and it will sink if $\rho _s > \rho _L$.

  4. The body will float if $\rho _s > \rho _L$ and it will sink if $\rho _s < \rho _L$.


Correct Option: B
Explanation:

The body will float if $\rho _{s}$ < $\rho _{L}$ and it will sink if $\rho _{s}$ > $\rho _{L}$
If the density of the substance is less than the density of the liquid, then the substance will float in liquid.
If the density of the substance is greater than the density of the liquid, then the substance will sink in liquid.

The dimensions of a wooden raft (density $ =150\ kg/ m^3)$ are $3.0\ m\times 3.0\ m\times 1.0\ m$. What maximum load can it carry in seawater so that the plank just floats in water (density$=1020\ kg/m^3)$?

  1. $1350\ kg$

  2. $7830\ kg$

  3. $9200\ kg$

  4. $19,500\ kg$


Correct Option: B
Explanation:
Buoyancy is the upward force that an object feels from the water and when compared to the weight of the object.

Buoyancy force can be calculated with the equation 
$Fb=Vs\times D\times g$

where $F _b$ is the buoyancy force, $V _s$ is the submerged volume, $D$ is the density of the fluid the object is submerged in, and $g$ is the force of gravity.

It can also be given as the sum of the weight of the raft and the weight of the load. That is, ${ W } _{ raft }+{ W } _{ load }$ = $Fb=Vs\times D\times g$.

The weight of the raft
${ W } _{ raft }={ V } _{ raft }{ D } _{ raft }g$.

At maximum load, Volume of water displaced is equal to volume of the raft.

${ max(W } _{ load })=({ D } _{ water }-{ D } _{ raft }){ V } _{ raft }g$.
=$(1020kg/{ m }^{ 3 }-150kg/{ m }^{ 3 })(3m\times 3m\times 1m)g$
$=7830 kg.$

Hence, the maximum load the raft can carry sea water so that the plank just floats in water is $7830 kg.$

Two unequal blocks place over each other of different densities ${ \sigma  } _{ 1 }$ and ${ \sigma  } _{ 2 }$ are immersed in fluid of density of $\sigma$. The block of density ${ \sigma  } _{ 1 }$ is fully submerged and the block of density ${ \sigma  } _{ 2 }$ is partly submerged so that ratio of there masses is $1/2$ and $\sigma/{ \sigma  } _{ 1 }=2$ and $\sigma/{ \sigma  } _{ 2 }=0.5$. Find the degree of submergence of the upper block of density ${ \sigma  } _{ 2 }$.

  1. $50\%$ submerged

  2. $25\%$ submerged

  3. $75\%$ submerged

  4. Fully submerged


Correct Option: D
- Hide questions