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Different types of solutions - class-XI

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In amalgam of mercury with sodium, solvent is;

  1. mercury

  2. sodium

  3. amalgam

  4. none of these


Correct Option: B
Explanation:

Amalgam of mercury comes under the category of solid solutions in which the solute is a liquid and solvent is a solid. The liquid solute is mercury and the solid solvent is sodium.

hence option B is correct.

Homogeneous mixture of two or more than two components is called:

  1. solute

  2. solvent

  3. both (a) and (b)

  4. solution


Correct Option: D
Explanation:

A solution is the homogeneous mixture of two or more than two components.

hence option D is correct.

On dissolving sugar in water at room temperature solution feels cool to touch. Under which of the following cases dissolution of sugar will be most rapid?

  1. Sugar crystals in cold water

  2. Sugar crystals in hot water

  3. Powdered sugar in cold water

  4. Powdered sugar in hot water


Correct Option: D
Explanation:

Powdered sugar dissolves faster in hot water than it does in cold water because hot water has more energy than cold water. When water is heated, the molecules gain energy and, thus, move faster. As they move faster, they come into contact with the sugar more often, causing it to dissolve faster.

An example of solid in non-aqueous solvent is :

  1. sugar in Ethanol

  2. blood

  3. starch

  4. sugar sol


Correct Option: A
Explanation:

The solutions obtained by dissolving a solute in any solvent other than water are called non aqueous solutions (non acqueous means without water). For example, if a solute is dissolved in any solvent such as benzene, alcohol, ether, carbon, disulphide, carbon tetrachloride, acetone, etc., the solution obtained is called a non aqueous solution.
) Non Aqueous soln: Ethanol + glucose
Solid in non aqueous: Sugar in Ethanol
2) blood, starch, ink : Collidal Soln.
sugar sol., salt sol : true soln.

Carbon tetrachloride and benzene are:

  1. immiscible in water

  2. miscible in water

  3. both A and B

  4. none of these


Correct Option: A
Explanation:

Carbon tetrachloride is nonpolar and will not mix with water. Benzene is also non-polar and won't mix with water at all. 


Thus, both carbon tetrachloride and benzene are Immiscible liquid.  

So, option A is correct.

Which describes a species in which the solvent is water?

  1. Solute

  2. Solvent

  3. Solubility

  4. Aqueous solution

  5. Solvation


Correct Option: D
Explanation:

An aqueous solution is a solution in which the solvent is water. It is usually shown in chemical equations by appending (aq) to the relevant chemical formula. For example, a solution of table salt, or sodium chloride (NaCl), in water would be represented as Na+(aq) + Cl-(aq).

Which is the interaction between the solute and the solvent molecules?

  1. Solute

  2. Solvent

  3. Solubility

  4. Aqueous solution

  5. Solvation


Correct Option: E
Explanation:

Solvation, also sometimes called dissolution, is the process of attraction and association of molecules of a solvent with molecules or ions of a solute. 


As ions dissolve in a solvent they spread out and become surrounded by solvent molecules.

Hence the correct option is E.

A mixture from which some of the solute particles will settle on standing :

  1. Miscible

  2. Suspension

  3. Colloid

  4. Saturated

  5. Supersaturated


Correct Option: B
Explanation:

A suspension is a heterogeneous mixture in which some of the particles settle out of the mixture upon standing.


Hence the correct option is B.


The number of components in a binary solution are/is _______ .

  1. 1

  2. 2

  3. 3

  4. 4


Correct Option: B
Explanation:

Solution formed by mixing two different species is a binary solution. Hence number of components is $2$.

A solution is defined as a :

  1. homogeneous mixture of two or more substances

  2. hetrogeneous mixture of two or more substances

  3. homogeneous mixture of liquid and solid components only

  4. homogeneous mixture consisting of water as one of the components


Correct Option: A
Explanation:

A solution is defined as a homogeneous mixture of two or more substances.

Example: Salt in water

If the heat of combustion of carbon monoxide at constant volume and at $17^o$C is $-283.3$ kJ, then its enthalpy of combustion at constant pressure($R=8.314J degree^{-1} mol^{-}$)

  1. $-284.5$ kJ

  2. $284.5$ kJ

  3. $384.5$ kJ

  4. $-384.5$ kJ


Correct Option: A
Explanation:
Solution:- (A) $- 284.5 \; kJ$
Heat change at constant volume for the combustion of carbon monoxide $= -283.3 \; kJ$
${CO} _{\left( g \right)} + \cfrac{1}{2} {{O} _{2}} _{\left( g \right)} \longrightarrow {C{O} _{2}} _{\left( g \right)}$
From the above reaction,
$\Delta{{n} _{g}} = {n} _{P} - {n} _{R} = 1 - \left( \cfrac{1}{2} + 1 \right) = - \cfrac{1}{2}$
Temperature $\left( T \right) = 17 ℃ = \left( 17 + 273 \right) K = 290 K \; \left( \text{Given} \right)$
Now from first law of thermodynamics,
$\Delta{H} = \Delta{E} + \Delta{{n} _{g}} RT$
$\Delta{H} = -283.3 + \left( -\cfrac{1}{2} \right) \times 8.314 \times {10}^{-3} \times 290$
$\Rightarrow \Delta{H} = -283.3 - 1.205 = - 284.505 \; kJ$
Hence the heat of reaction at constant pressure will be $- 284.5 \; kJ$.

Dissolution of ionic solid in water is possible when:

  1. $H$ lattice $> H$ hydration

  2. $H$ lattice $= H$ hydration

  3. $H$ hydration $: H$ lattice = 2:1

  4. $H$ hydration $> H$ lattice


Correct Option: D
Explanation:

Solution:- (D) ${H} _{\text{hydration}} > {H} _{\text{lattice}}$

In order to dissolve an ionic solid, water molecules must break up the interactions between all of the ions in the solid. The heat of hydration $\left( {H} _{\text{hydration}} \right)$ offsets the lattice energy $\left( {H} _{\text{lattice}} \right)$ of an ionic solid to allow for solution formation to occur typically when ${H} _{\text{hydration}} > {H} _{\text{lattice}}$.

For an ideal binary liquid solution with $P^{\circ} _{A} > P^{\circ} _{B}$, which relation between $X _{A}$ (mole fraction of A in liquid phase) and $Y _{A}$(mole fraction of $A$ in vapour phase) is correct?

  1. $Y _{A} < Y _{B}$

  2. $X _{A} > X _{B}$

  3. $\dfrac{Y _{A}}{Y _{B}} > \dfrac{X _{A}}{X _{B}}$

  4. $\dfrac{Y _{A}}{Y _{B}} < \dfrac{X _{A}}{X _{B}}$


Correct Option: A
Explanation:

For an ideal binary liquid solution with $P _\overset {o}{A}>P _\overset {o}{B}$.

We know that, from Henry's law
$P _\overset {o}{A}\propto X _A$
So, $X _A > X _B$.
If mole fraction of $A$ in liquid phase is more then mole fraction of $A$ in vapour phase is less so, $Y _A < Y _B$.

Which of the following are correct about Tyndall effect?

  1. True solution do not show Tyndall effect due to very small size of the particles

  2. The diameter of the particles of the dispersed phase must not be much smaller than the wavelength of light used

  3. Tyndall effect is very weak in case of lyophobic sols

  4. The refractive index of the dispersed phase and dispersion must differ considerably


Correct Option: A

$100\ ml$ of an aqueous solution contains $6.0\times {10}^{21}$ solute molecules. The solution is diluted to $1$ lit. The number of solute molecules present in $10\ ml$ of the dilute solution is:

  1. $6.0\times {10}^{20}$

  2. $6.0\times {10}^{19}$

  3. $6.0\times {10}^{18}$

  4. $6.0\times {10}^{17}$


Correct Option: B
Explanation:
100 ml solution diluted to 1 liters (1000) ml contains $6.0 \times 10^{21}$ solute molecular

No of molecules present in 10 ml

$ = \dfrac{10 \times 6.0 \times 10 ^{21}}{1000} = 6 \times 10 ^{19} $

Highly pure dilute solution of sodium in liquid ammonia:

  1. on evaporation yield metals.

  2. exhibits electrical conductivity.

  3. produces sodium amide and hydrogen gas instantly.

  4. acts as powerful reducing agent.


Correct Option: A,B,D
Explanation:

$M+(x+y)NH _3\rightarrow [M(MH _3) _x]^++[4(NH _3) _y]^-$. Blue colour of the solution is due to ammoniated electrons and good conductor of electricity because of both ammoniated cations and ammoniated electrons.

The compound whose 0.1 ml solution isbasic is :

  1. Ammonium acetate

  2. Ammonium chloride

  3. Ammonium sulphate

  4. Sodium acetate


Correct Option: B

Homogeneous system among the following is

  1. milk

  2. sand in water

  3. urea in water

  4. benzene in water


Correct Option: C

When some liquid evaporates, the average speed of the molecules remaining will .......... .

  1. Increase because the more energetic molecules have left

  2. Decrease because the more energetic molecules have left

  3. Remain unchanged because all molecules have about the same speed

  4. Increase because there are fewer molecules


Correct Option: B
Explanation:

Answer is B.

A liquid is comprised of molecules that are in constant motion, traveling at different rates. The average speed of these particles depends on the liquids temperature.  A rise in temperature increases molecular velocity as well as aggregate kinetic energy.  If molecules gain enough energy, their fast-moving particles will begin to bump against their neighbors.  Eventually, particles near the liquids surface will impart sufficient speed, and therefore sufficient kinetic energy, to cause the surface particles to propel away from the liquid in the form of gaseous molecules or, more simply, as water vapor.
As the particles with the highest kinetic energy levels evaporate, the average kinetic energy of the remaining liquid (sweat) decreases.  Because a liquids temperature is directly related to the average kinetic energy of its molecules, the liquid cools as it evaporates.
Hence, w
hen some liquid evaporates, the average speed of the molecules remaining will decrease because the more energetic molecules have left.

When $1$ mole of a substance is present in $1$ L of the solution, it is known as :

  1. normal solution

  2. molar solution

  3. molal solution

  4. None of the above


Correct Option: B
Explanation:

Molar concentration is a measure of the concentration of a solute in a solution and its unit is mol L$^{-1}$. Molarity is a method to express the concentration of a solution. It is defined as the number of moles of solute dissolved per liter of solution. 


Hence, when $1$ mole of a substance is present in $1$ L of the solution, it is known as a molar solution.

Option B is correct.

A solution in which, still more number of solute can be dissolved, is known as :

  1. unsaturated

  2. super saturated

  3. saturated

  4. dilute

  5. concentrated


Correct Option: A
Explanation:

Saturated Solution: A solution with a solute that dissolves until it is unable to dissolve any more, leaving the undissolved substances at the bottom.


Unsaturated Solution: A solution (with less solute than the saturated solution) that completely dissolves,  in which still more solute can be dissolved.


Supersaturated solution: Solution that is more concentrated than a saturated solution is known as a supersaturated solution. If a crystal of solute is added to this solution, the excess of solute crystallizes.

A dilute solution: is one in which there is a relatively small amount of solute dissolved in the solution.

A concentrated solution: contains a relatively large amount of solute dissolved in the solution.


Hence option A is correct.

10g of sodium hydroxide dissolved in 1 L of water to make _____ solution.

  1. $0.25 M$

  2. $0.5 M$

  3. $1 M$

  4. $1.5 M$

  5. $4 M$


Correct Option: A
Explanation:
molar mass of sodium hydroxide $=$$40g/mole$
$Molarity = \dfrac{Mass\, of\, solute}{(Molar\, mass\, of\, the\, solute)\times(Volume\, of \, solution\, in\, litres)}$

So $Molarity$ $=$$10/(40\times1)$$=$$0.25M$

Which of the following sequences lists the relative sizes of particles in a water mixture from smallest to largest?

  1. Solutions, suspensions, colloids

  2. Solutions, colloids, suspensions

  3. Colloids, solutions, suspensions

  4. Colloids, suspensions, solutions

  5. Suspensions, colloids, solutions


Correct Option: B
Explanation:
The sequence that gives the relative sizes of particles in a water mixture from smallest to largest is solutions, colloids, suspensions. In true solution, the particle size is 0.1 nm to 1.0 nm. In colloidal solution, the particle size is 1 nm to 1000 nm. In suspension, the particle size is more than 1000 nm.

How much water, in liters, must be added to 0.5 L of 6 M HCl to make it 2 M?

  1. 0.33

  2. 0.5

  3. 1

  4. 1.5

  5. 2


Correct Option: C
Explanation:
Molarity =$\dfrac{Mass \,of\, the\, solute}{(Molar \,mass\, of\, the\, solute)\times {(Vol. of\, soln.\, in\, liters)}}$

Mass of solute will remain same before and after mixing water.
so 
       $M _1V _1$$=$$M _2V _2$
or 
       $V _2$$=$$6\times0.5/2$$=$$1.5L$
this is final total volume so water added $=$$1.5-0.5$$=$$1L$ 

What is the molar mass of a non-ionizing solid if 10 g of this solid, dissolved in 100 g of water, formed a solution that froze at $-1.21^o C$?

  1. 0.65 g

  2. 65 g

  3. 130 g

  4. 154 g

  5. 265 g


Correct Option: D

Which of the following is not miscible in alcohol?

  1. Water

  2. Petrol

  3. Diesel

  4. Kerosene


Correct Option: B,C,D
Explanation:

Water is miscible in alcohol due to hydrogen bonding between the hydrogen and oxygen atoms. Since petrol, diesel and kerosene are non-polar in nature, they are insoluble in alcohol which is a polar solvent.

Hydrogen gas adsorbed on surface of platinum is an example of solid in gas solution.

  1. True

  2. False


Correct Option: A
Explanation:

Platinum is present in solid state and when hydrogen gas is adsorbed on the surface of platinum then they are forming solid in gas solution because soild is very  small and is present as solute and the amount of gas adsorbed is much more then platinum so it act as solvent and complete solution is known as solid in gas.

Sugar is soluble in water due to:

  1. high solvation energy.

  2. ionic character of sugar.

  3. high dipole moment of water.

  4. hydrogen bond formation with water.


Correct Option: D
Explanation:

 The bond between the oxygen and hydrogen atoms ($O–H$ bond) in sugar (sucrose) gives the oxygen a slight negative charge and the hydrogen a slight positive charge.Sucrose is a polar molecule.

Which of the following is a true solution?

  1. $NaCl$ is sulphur dioxide

  2. Copper in silver

  3. Salt in petrol

  4. Mud in water


Correct Option: B
Explanation:

NaCl in sulphur dioxide from molten sodium sulfate. Copper and silver are melted together to forms an alloy, salt is insoluble in petrol because petrol is non-polar solvent. Mud in water forms a colloidal solution, so, from the given options Copper in silver forms a true solution. 

Which of the following is a true solution?

  1. Copper in gold

  2. Sulphur in water

  3. Milk

  4. Water in sulphur dioxide


Correct Option: A
Explanation:

Copper and gold are melted and mixed together to form an alloy, they form a solid-solid homogeneous mixture,

so, copper in gold is called as true solution.

Which of the following sequences lists the relative sizes of particles in a water mixture from smallest to largest?

  1. Solutions, suspensions, colloids

  2. Solutions, colloids, suspensions

  3. Colloids, solutions, suspensions

  4. Colloids, suspensions, solutions

  5. Suspensions, colloids, solutions


Correct Option: B
Explanation:
The increasing order for the relative particle size is solutions ( 0.1 to 1 ) < colloids  (1 to 1000 ) < suspensions (more than 1000). The numbers in parenthesis refer to particle size in nm.

A solution is defined as a:

  1. homogeneous mixture of two or more substances

  2. hetrogeneous mixture of two or more substances

  3. homogeneous mixture of liquid and solid components only

  4. homogeneous mixture consisting of water as one of the components


Correct Option: A
Explanation:

solution is a homogeneous mixture of two or more substances. A solution may exist in any phase. For example, in a saline solution, salt is the solute dissolved in water as the solvent.

Describes a solution containing solute particles of intermediate size that do not settle but do scatter light.

  1. Miscible

  2. Suspension

  3. Colloid

  4. Saturated

  5. Supersaturated


Correct Option: C
Explanation:

Colloid particle have a particle size range from 1 to 1000 nanometer and these particles do not settle at the bottom but scatter the light.

Arrange the following in the increasing order of their solubility in n-octane based on solute-solvent interaction: 

  1. $KCl < CH _3CN < CH _3OH < Cyclohexane$

  2. $KCl < Cyclohexane < CH _3OH < CH _3CN$

  3. $KCl < CH _3OH < CH _3 CN < Cyclohexane$

  4. $ KCl < Cyclohexane < CH _3CN < CH _3CN$


Correct Option: C

an organic liquid (A), containing C,H and O with boiling point $78^{\circ}$C and possessing a rather pleasant odour or heating with concenterated $H _{2}SO _{4}$ gives a gaseous product (B) with the empirical formula $CH _{2}$. B decolourises bromine water as well as alkaline $KMnO _{4}$ solution and takes up one mole of $H _{2}$(per mole of B) in the presence of finely divided nickle at high temperature. A and B are:

  1. $C _{2}H _{5}OH$, $C _{2}H _{2}$

  2. $CH _{3}OH$, $C _{2}H _{2}$

  3. $C _{2}H _{5}OH$, $C _{2}H _{4}$

  4. $(CH _{3}) _{2}CHOH$, $C _{3}H _{6}$


Correct Option: C
Explanation:

$C _2H _5OH$ or ethyl alcohol when treated with concentrated $H _2SO _4$ undergoes dehydration to form ethene($C _2H _4$). Ethane reacts with alkaline $KMnO _4$ undergoes oxidation to form ethylene glycol. Ethene  undergoes hydrogenation in presence of nickel heads of one mole of $H _2$ to form ethane.

The correct option is C

A sample of $CH _4$ of 0.08 g was subjected to combustion at $27^oC$ in a bomb calorimeter. The temperature of the calorimeter system was found to be raised by $0.25^oC$. If heat capacity of calorimeter is 18 kJ, $\Delta H$ for combustion of $CH _4$ at $27^oC$ is:

  1. $- 900$ kJ/mole

  2. $- 905$ kJ/mole

  3. $- 895$ kJ/mole

  4. $- 890$ kJ/mole


Correct Option: B
Explanation:

${ CH } _{ 4 }\left( g \right) +{ 2O } _{ 2 }\left( g \right) \longrightarrow { CO } _{ 2 }\left( g \right) +2{ H } _{ 2 }O\left( l \right) $

$\Delta E=$ Heat of combustion
        $=$ Heat capacity $\times$ rise in $T$ $\times$ $\dfrac { Molar\ mass }{ Mass\ of\ compound } $
        $=-18\times 0.25\times \dfrac { 16 }{ 0.08 } $
        $=-900$ KJ/mole                                         $R=8.314\times { 10 }^{ -3 }KJ{ mol }^{ -1 }$
$\Delta H=\Delta E+\Delta nRT$                                      $\Delta n=1-3=-2$
$=-900+\left( -2 \right) \times 8.314\times { 10 }^{ -3 }\times 300$           $T=300K$
$=-900-4.9884=-904.98\simeq -905KJ/mol$

$CoCl _{ 3 }.3NH _{ 3 }$ does not form any precipitate with excess ${ AgNO } _{ 3 }$ solution, whereas 1 mole of $CoCl _{ 3 }.5NH _{ 3 }$ gives two moles of $AgCl$ with excess ${ AgNO } _{ 3 }$. The van't Hoff factor for both the compounds respectively are:

  1. 0 and 2

  2. 0 and 3

  3. 1 and 3

  4. 1 and 2


Correct Option: C
Explanation:

To give ppt with ${ AgNO } _{ 3 }$ solution, a substance has to release ${ Cl }^{ - }$ ions.
$CoCl _{ 3 }.3NH _{ 3 }$ gives no ppt because it does not dissociate in solution.
$\therefore $ Number of particles in solution $=1$ i.e the molecule itself $CoCl _{ 3 }.5NH _{ 3 }$ gives 2 moles $AgCl$ ppt because it dissociate as follows
$CoCl _{ 3 }.5NH _{ 3 }\rightarrow \left[ Co\left( { NH } _{ 3 } \right) _{ 5 }Cl \right] ^{ 2+ }+2{ Cl }^{ - }$
It gives 3 ions on dissociation.
$\therefore $ its van't Hoff factor is 3.

The vapour pressure of two pure liquids A and B are 200 and 400 torr respectively at 300K . A liquid solution (ideal) of A and B for which the mole fraction of A is 0.40 is contained in a cylinder. The composition of components A and B in vapour phase after equilibrium is reached between vapour & liquid phase, respectively is 

  1. $X _A = 0.62 ; X _B = 0.38$

  2. $X _A = 0.50 ; X _B = 0.50$

  3. $X _A = 0.25 ; X _B = 0.75$

  4. $X _A = 0.30 ; X _B = 0.70$


Correct Option: C

When an ideal binary solution is in equilibrium with its vapour, molar ratio of the two components in the solution and in the vapour phases is 

  1. same

  2. different

  3. may or may not be same depending upon volatile nature of the two components

  4. None of the above


Correct Option: C
Explanation:
For Solution $A+B$,

$X' _{A}=$ mole fraction of $A$ in vapour  phase

$X' _{A}=\dfrac{X _{A}.P^{0} _{A}}{X _{A}.P^{0}A}$ = can be equal to $X _{A}$ or not which depend on $P^{0} _{A}$ & $P^{0} _{B}$.
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