Capacitors in parallel - class-XII
Description: capacitors in parallel | |
Number of Questions: 39 | |
Created by: Girish Goud | |
Tags: physics electrostatics capacitance electrostatic potential and capacitance electricity and magnetism |
A parallel plate capacitor has two square plates with equal and opposite charges. The surface charge densities on the plate are $+\sigma$ and $-\sigma$ respectively. In the region between the plates the magnitude of electric field is:
If the voltage across the parallel combination in increases which capacitor will undergo breakdown first?
A capacitors of $2 \mu F$ is required is an electric circuit across a potential difference of 1.0kv. A large number of $1 \mu F$ capacitors are available which can with stand a potential difference of not more than 300V The minimum number of capacitors required to achieve this is:
Two capacitors were charged to potentials 80 and 30 V. Then they connected in parallel. The potential difference across both condensers is 60 V. The ratio of the capacitances of the capacitors is
The plates of a parallel plate capacitor are $4$cm apart, the first plate is at $300$V and the second plate at $-100$V. The voltage at $3$cm from the second plate is?
Find the total capacitance for three capacitors of $10$f,$15$f and $35$f in parallel with each other?
Two capacitors of capacity $C _1$ and $C _2$ are connected in parallel, then the equivalent capacity is:
A parallel plate capacitor is connected to a battery and the distance between the plates is decreased then which quantity is same for the parallel plate capacitor
Capacity of a parallel plate capacitor is $2\mu F$. The two plates of the capacitor are given $400\mu C$ and $-200\mu C$charges respectively. The potential difference between the plates is
A parallel plate capacitor consist of two circular plates each of radius 2 cm, separated by a distance of 0.1 mm. If voltage across the plates is varying at the rate of $5 \times {10^{13}}V{s^{ - 1}}$ , then the value of displacement current is:
When $n$ identical capacitors are connected in series their effective capacity is $C _s$ and when they are connected in parallel their effective capacity is $C _p$. The relation between $C _p$ and $C _s$ is:
A capacitor $ C _1 = 4 \mu F $ is connected in series with another capacitor $ C _2 = 1 \mu F $. the combination is connected across a d.c. source of voltage 200 V. the ration of potential across $ C _1 $ and $C _2 $ is-
From a supply of identical capacitors rated $8\;\mu F, 250 \;V$ the minimum number of capacitors required to form a composite of $16\;\mu F, 1000 \;V$ is
In order to increase the capacity of parallel plate condenser one should introduce between the plates, a sheet of
A parallel plate capacitor is connected to a battery and a dielectric slab is inserted between the plates, then which quantity increase:
A parallel plate capacitor is made by stacking $n$ equally spaced plates connected alternatively. If the capacitance between any two adjacent plates is $C$, then the resultant capacitance is-
A parallel plate condenser has plates of area $200\mathrm { cm } ^ { 2 }$ and separation $0.05\mathrm { cm } .$ The space between plates have been filled with a dielectric having $\mathrm { k } = 8$ and then charged to $300$ volts. The stored energy:
A Parallel platecapacitor made of circular plates each of radius $R=6.0cm$ has a capacitance 100$\mathrm { pF }$ is connected to 230$\mathrm { V }$ of $\mathrm { AC }$ supply of 300 rad/sec.frequency. The rms value of displacement current
Two parallel plates have equal and opposite charge. When the space between them is evacuated. the electric field between the plates $2 \times {10^5}\,V/m.$ When the space is filed with dielectric the electric field becomes ${10^5}\,V/m$ The dielectric constant of he dielectric material is
3 identical capacitor are joined in parallel and are charged with a battery of 10V. now the battery is removed and they are joined in series with each other. in this condition what would be the potential difference between the free plates in combination?
Two capacitors of capacitance $2\, \mu F$ and $4\, \mu F$ are charge to $200\, V$ and $100\, V$ respectively. They are then connected in parallel to each other. What is the potential across each capacitor ?
A parallel plate capacitor has a capacity C.If a thin metal plate (M) joins the two coating A and B of the capacitor,its new capacitance is
A capacitor is charged by a battery. the battery is removed and another identical uncharged capacitor is connected in parallel. the total electromagnetic energy of resulting system
A parallel plate air capacitor has capacity 'C', a distance of separation between plate is 'd' and potential difference 'V' is applied between the plates. Force of attraction between the plates of the parallel plate air capacitor is:
The distance between the plates of a parallel plate capacitor is $1\ mm$. What must be the area of the plate of the capacitor if the capacitance is to be $1.0\mu F$?
Two parallel plate capacitor of capacitances C and 2C are conncected in parallel and changed to a potential difference V.If the bsttery is disconnected and the space between the plate of the capacitor of cpacince c is cpmpletely filled with a metrial of dielectric constant K, then the potential difference a cross the capacitor will be come
A parallel plate capacitor has circular plates of $8.0\ cm$ radius and are separated by $1.0\ mm$. Calculate the capacitance.
two similar capacitor are connected to potential v in parallel order by separating them and joining them in series
For a given potential difference V how would you connect two capacitors, to obtain greater stored charge :
A parallel plate capacitor is made by stacking n equally spaced plates connected alternatively. If the capacitance between any two adjacent plates is 'C' then the resultant capacitance is :
Two capacitors of capacitance $C _1$ and $C _2$ are connected in parallel across a battery. If $Q _1$ and $Q _2$ respectively be the charges on the capacitors, then $\dfrac {Q _1}{Q _2}$ will be equal to :
These questions consist of two statements, each printed as assertion and reason. While answering these question you are required to choose any one of the following five responses.
Reason: $\displaystyle \frac { 1 }{ { C } _{ p } } =\frac { 1 }{ { C } _{ 1 } } +\frac { 1 }{ { C } _{ 2 } } +\frac { 1 }{ { C } _{ 3 } } $
Calculate the ratio of the equivalent capacitance of the circuit when two identical capacitors are in series to that when they are in parallel?
Two capacitors of capacity $C _{1}$ and $C _{2}$ are connected in parallel, then the equivalent capacity is:
Complete the following statements with an appropriate word /term be filled in the blank space(s).
Three capacitance of capacity $10 \mu F , 5 \mu F $ are connected in parallel. The total capacity will be :
A parallel plate condenser has two circular metal plates of radius 15 cm. It is being charged so that electric field in the gap between its plates rises steadily at the rate of $10^12V/ms.$ what is the displacement current?
A capacitor is charged by a cell of emf $E$ and the charging battery is then removed. If an identical capacitor is now inserted in the circuit in parallel with the previous capacitor, the potential difference across the new capacitor is :