Capacitors in series - class-XII
Description: capacitors in series | |
Number of Questions: 31 | |
Created by: Sundari Chatterjee | |
Tags: capacitance electrostatics physics electrostatic potential and capacitance electricity and magnetism |
Two capacitors of $1\mu F$ and $2\mu F$ are connected in series and this combination is changed upto a potential difference of $120$ volt. What will be the potential difference across $1 \mu F$ capacitor:
Three long concentric cylindrical shells have radii R, 2R and $2\sqrt{2}R$. Inner and outer shells are connected to each other. The capacitance across middle and inner shells per unit length is:
Six identical square metallic plates are arranged as shown in figure length of each plate is l the capacitance of this arrangement should be
Two capacitors of caacity ${ C } _{ 1 }$ and ${ C } _{ 2}$ are connected in series and potential difference V is applied across it. Then the potential difference across${ C } _{ 1 }$ will be
For capacitors in the series combination, the total capacitance C is given by
A series combination of two capacitances of value $0.1\ mu F$ and $1\mu F$ is connected with a source of voltage $500\ volts$. The potential difference in volts across the capacitor of value $0.1\ muF$ will be :
Two parallel plate capacitors are connected in series. Each capacitor has a plate area A and a separation d between the plates. The dielectric constant of the medium between their plates are 2 and 4 . The separation between the plates of a single air capacitors of plate area A which effectively replaces the combination is:
A capacitor comprises of two parallel circular plates. Diameter of each of plates is equal to $6 cm$. If capacitance of above system is equivalent to capacitance of sphere, whose diameter is equal to $200 cm$. Distance between two plates will be:-
A capacitor 1 mF withstands a maximum voltage of 6KV while another capacitor 2 mF withstands a maximum voltage of 4 KV. If the capacitors are connected in series, the system will withstand a maximum voltage of (MNR)
what is the series combination of condenses and $\dfrac { 1 }{ c } =\dfrac { 1 }{ { c } _{ 1 } } +\dfrac { 1 }{ { c } _{ 2 } } +\dfrac { 1 }{ { c } _{ 3 } } $ farad
Two identical capacitors are connected in series with a source of potential V. If Q is the charge on one of the capacitors, the capacitance of each capacitor is:
Two capacitors of $4\ \mu F$and $2\ \mu F$ are connected in series with the battery. If total potential difference across the two capacitors is $200$ volts then the ratio of potential difference across one capacitor to another is
A capacitor of capacitance $ 1 \mu F $ withstands a maximum voltage of 6 kilovolt while another capacitor of $ 2 \mu F $ withstands a maximum voltage 4 kilovolt . if the two capacitor are connected in series, the system will withstand a maximum of:
Three capacitors each of capacitance C and of breakdown voltage V are joined in series. The capacitance and breakdown voltage of the combination will be
When two condensers of capacitance $1\mu F$ and $2\mu F$ are connected is series then the effective capacitance will be :
Three condensers each of capacitance 2 F, are connected in series. The resultant capacitance will be :
A resistor $ ^{\prime} R^{\prime} $ and $2 \mu F $ capacitor in series is connected through a switch to $200 \mathrm{V} $ direct supply. Across the capacitor is a neon bulb that lights up at $120 \mathrm{V} $ Calculate the value of $ R $ to make the bulb light up $5 s $ after the switch has been closed. $ \left(\log _{10} 2.5=0.4\right) $
Two capacitors of capacitances $4\mu F$ and $6\mu F$ are connected across a 120 V battery in series with each other. What is the potential difference across the $4\mu F$ capacitor?
Two capacitor of capacity $C _{1}$ and $C _{2}$ are connected in series. The combined capacity $C$ is given by
Three condenser of capacitance $C(\mu F)$ are connected in parallel to which a condenser of capacitance $C$ is connected in series. Effective capacitance is $3.75$, then capacity of each condenser is
The equivalent capacitance of capacitors $6\mu F$ and $3\mu F$ connected in series is ______.
The two capacitors $2\mu F$ and $6\mu F$ are put in series, the effective capacity of the system is $\mu F$ is:
When two capacitors of capacities of $3\mu F$ and $6\mu F$ are connected in series and connected to $120\ V$, the potential difference across $3\mu F$ is:
Three capacitors, $3\mu F, 6\mu F$ and $6\mu F$ are connected in series to a source of 120V. The potential difference, in volts, across the $3\mu F$ capacitor will be
A capacitor of capacitance ${ C } _{ 1 }=1\mu F$ can with stand maximum voltage ${ V } _{ 1 }=6kV$ (kilo-volt) and another capacitor of capacitance ${ C } _{ 2 }=3\mu F$ can withstand maximum voltage ${ V } _{ 2 }=4kV$. When the two capacitors are connected in series, the combined system can withstand a maximum voltage of:
A capacitor of capacitance $1\mu F$ withstands a maximum voltage of $6\ kV$, while another capacitor of capacitance $2\mu F$, the maximum voltage $4\ kV$. If they are connected in series, the combination can withstand a maximum of
Complete the following statements with an appropriate word /term be filled in the blank space(s).
Which one of the following gives the resultant capacitor when capacitors are joined in series?
The current in a contining a capacitance C and a resistance R in series over the applied voltage of frequency $\cfrac { \omega }{ 2\pi } $ by.
A very thin metal sheet is inserted halfway between the parallel plates of an air-gap capacitor. The sheet is thin compared to the distance between the plates, and it does not touch either plate when fully inserted. The system had capacitance, $C$, before the plate is inserted.
What is the equivalent capacitance of the system after the sheet is fully inserted?
$4\ \mu F$ and $6\ \mu F$ capacitors are joined in series and $500\ v$ are applied between the outer plates of the system. What is the charge on each plate ?