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Soluble or insoluble? - class-X

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What are transparent materials?

  1. The material which does not allow light to pass through it.

  2. The material which allows light to pass through it.

  3. The material through which light can pass partially.

  4. None of these.


Correct Option: B
Explanation:

Materials which allow light to completely pass through them without getting scattered are called Transparent material.

Example- a glass of water, clear eyeglasses.

What do you call a substance through which things are partially visible?

  1. Opaque object

  2. Transparent object

  3. Lustrous object

  4. Translucent object


Correct Option: D
Explanation:

The material which does not allow light to pass through it is called opaque and material which allows light to pass through it is called transparent. The material through which light can pass partially is called translucent, e.g. butter paper.

Which of the following substance is not transparent?

  1. Glass

  2. Pure Water

  3. Air

  4. Steel


Correct Option: D
Explanation:

Transparent material:- Materials which allow light to completely pass through them without getting scattered are called Transparent material.

Example- a glass of water, clear metal-containing.
Steel does not allow to pass light through it hence is an opaque object.

Translucent substances  __________.

  1. allow the light to pass through it completely

  2. allow the light to pass through it partially

  3. does not allow the light to pass through it

  4. none of these


Correct Option: B
Explanation:

Those materials that allow some light to pass through them are called translucent and include things like frosted glass and wax paper.

Name two transparent materials. 

  1. Glass and wood

  2. Plastic and cold wax

  3. Plastic and glass

  4. Water and honey


Correct Option: C
Explanation:

Materials which allow light to completely pass through them without getting scattered are called Transparent material.

Example- Plastic, Glass.

How many of the following are soluble in water?
salt, sugar, sand, dust

  1. 1

  2. 2

  3. 3

  4. 4


Correct Option: B

Which of the following type of bodies form sharp shadows when placed in the path of light?

  1. Transparent

  2. Translucent

  3. Transparent and translucent

  4. Opaque


Correct Option: D
Explanation:

Transport bodies allow light to pass through it while translucent bodies allow light partially through it but opaque bodies do not allow light to pass through it, so they form sharp shadows when placed in the path of light.

Option (D) is correct.

Which of the following type of bodies form sharp shadows when placed in the path of light?

  1. Transparent

  2. Translucent

  3. Both A and B

  4. Opaque


Correct Option: D
Explanation:
An opaque object is neither transparent (allowing all light to pass through) nor translucent (allowing some light to pass through). 

When light strikes an interface between two substances, in general, some may be reflected, some absorbed, some scattered, and the rest transmitted. 

Opaque object forms sharp shadow when placed in the path of the light.

Hence, option D is correct.

Select the objects which are opaque: 

  1. water, oil and soil

  2. soil, sand and dust

  3. glass, grass and gum

  4. marvel, oiled paper and magnet


Correct Option: B
Explanation:

Opaque objects are materials which do not allow light to pass through them.

Examples are- Soil, sand and dust.

Pick one material which is completely soluble in water:

  1. oil

  2. sawdust

  3. mud

  4. alum


Correct Option: D
Explanation:

Alum is a hydrated double salt sometimes used as water purifier is completely soluble in water.

Select a pair of solute and solvent materials to form solution:

  1. Chalk powder and water

  2. Alcohol and water

  3. Milk and oil

  4. Glass and water


Correct Option: B
Explanation:

In general, organic compounds are insoluble in water. Though alcohol is an organic compound it is soluble in water due to hydrogen bonding. 

Find odd one out on the basis of the solubility of the material.

  1. Sugar

  2. Salt

  3. Chalk

  4. Wood


Correct Option: D
Explanation:

Wood is not at all soluble in water whereas sugar and salt are soluble and chalk $(CaCO _3)$ is slightly soluble in water.

Which of the following floats on water?

  1. Air filled tube of a tyre

  2. A sharpener

  3. A stone

  4. A chain


Correct Option: A
Explanation:

Air filled tube floats on water as it contain air and which is very less dense than water.

The EMF of the cell: Ag, AgCl in $0.1 M - KCl \parallel$ satd. $ NH _{4}NO _{3}\parallel 0.1 M - Ag NO _{3},$ Ag is 0.42 V at $ 25^{\circ}C.$ 0.1 M-KCl is 50% dissociated and $0.1 M - Ag NO _{3}$ is 40% dissociated. The solubility product of $ AgCl $ is $ (2.303 RT/F = 0.0)$

  1. $1.0 \times 10^{-10} $

  2. $ 2.0 \times 10^{-9} $

  3. $ 1.0 \times 10^{-9}$

  4. $ 2.0 \times 10^{-10} $


Correct Option: D

Maximum of 9.72 g of potassium chloride dissolves in 30 g of water at $70^{\circ}$C. The solubility of potassium chloride at $70^{\circ} C$ is:

  1. 3.24 g

  2. 32.4 g

  3. 0.324 g

  4. 33.4 g


Correct Option: B
Explanation:

Solubility is defined as solubility of different substances in grams per 100 gm of water.
30 gm of water dissolves 9.72 g of $KCl$.
So, 100gm will dissolve in $9.72\times 100/30=32.4$ gm.

What do you understand by the statement "the solubility of copper sulphate in water at $20^{\circ}C$ is 20.7 g" ?

  1. A maximum of 20.7 grams of copper sulphate can be dissolved in 100 ml water at a temperature $20^{\circ}$C.

  2. A maximum of 20.7 grams of copper sulphate can be dissolved in 100 g of water at $20^{\circ}$C.

  3. A maximum of 20.7 grams of copper sulphate can be dissolved in 79.3 g of water at $20^{\circ}$C.

  4. A maximum of 20.7 grams of copper sulphate can be dissolved in 79.3 ml of water at $20^{\circ}$C.


Correct Option: B
Explanation:

Solubility is given in grams per 100 gm of water with temperature and 1 atmospheric pressure.

In the solvation of $NaCl$ in water, which of the following occur ?

  1. Hydrogen atom interacts with $Cl^-$ atom

  2. Oxygen atom interacts with $Na^+$ atom

  3. Both $A$ and $B$

  4. None of these


Correct Option: C
Explanation:

In the water molecule oxygen has higher electronegativity than hydrogen thus has a partial negative charge and hydrogen has a partial positive charge. So during the solvation of NaCl in water, hydrogen atoms interact with chlorine anion and oxygen interact with sodium cation.

______ is the chief component of natural gas.

  1. Ethane

  2. Methane

  3. Propane

  4. Butane


Correct Option: B
Explanation:

Natural gas is a fossil fuel. It is used for cooking, heating and electricity generation. It is found deep underground rock formation. It is a naturally occurring hydrocarbon gas mixture consisting primarily of methane. It is also used as fuel for vehicles.

DHOKALA is a __________ type of solution.

  1. solid-in-solid

  2. solid-in-gas

  3. solid-in-liquid

  4. gas-in-solid


Correct Option: D
Explanation:

DHOKALA is a Gas-in-solid type of solution.
The dispersed phase is gas (air) and the dispersion medium is solid (material from which dhokala is made).

Select the material which is insoluble in water.

  1. Glucose

  2. Washing soda

  3. Alcohol

  4. Benzene


Correct Option: D
Explanation:

As like dissolves like, in general, organic compounds are insoluble in water. Benzene $(C _6H _6)$ is an organic compound soluble in an organic solvent like carbon disulphide, and is insoluble in water.

At ${25}^{o}C$ the solubility of ${Ag} _{2}{CO} _{3}$ (${K} _{sp}=4.3\times {10}^{-13}$) would be in what order in the following solutions?

  1. $0.01M$ $Ag{NO} _{3}$

  2. $0.04M$ ${K} _{2}{CO} _{3}$

  3. pure water

  4. in a buffer ($pH=4$)


Correct Option: A

$Ca _3(PO _4) _2$ is insoluble in water. On adding a few drops of HCl to solid $Ca _3(PO _4) _2$ in contact with water, the solid dissolves. The reason is?

  1. The solvent becomes more polar on adding HCl

  2. $Ca _3(PO _4) _2$ combines with HCl to form soluble $CaCl _2$

  3. $Ca(H _2PO _4) _2$ is formed, which dissolves

  4. $H _3PO _4$, a weak acid is formed and the solubility product of $Ca _3(PO _4) _2$ decrease


Correct Option: A

The solubility of $A {2}X _{3}$ is $y$ $mol$ $dm^ {-3}$. Its solubility product is ____________.

  1. $6y^ {4}$

  2. $64y^ {4}$

  3. $36y^ {5}$

  4. $108y^ {5}$


Correct Option: A

What is the solubility of $Al(OH _{3}), K _{sp} = 1 \times 10^{-33}$, in a solution having $pH = 4$?

  1. $6 \times 10^{-3}$M

  2. $10^{-6}$M

  3. $1.5 \times 10^{-4}$M

  4. $2.47 \times 10^{-9}$M


Correct Option: D
Explanation:

The solubility equilibrium of $Al(OH) _3$ is

$Al(OH) _3$ ${\rightarrow} _{\leftarrow}$ $Al^{+3}$  + $3OH^-$
Therefore $x=1,\ y=2$ and $K _{sp}$=$[Al^{+3}]\times [OH^-]$ = $27S^4$
$S$ = $(\dfrac{10^{-33}}{27})^{1/4}$
Therefore $S$= $2.47\times 10^{-9}M$ in $ mol\ dm^{-3}$

Which of the following is most soluble?

  1. ${Bi} _{2}{S} _{3} \left({K} _{sp} = 1\times {10}^{-17}\right)$

  2. $MnS\left({K} _{sp} = 7\times {10}^{-16}\right)$

  3. $CuS\left({K} _{sp} = 8\times {10}^{-37}\right)$

  4. ${Ag} _{2}S\left({K} _{sp} = 6\times {10}^{-51}\right)$


Correct Option: A
Explanation:

Ksp (Solubility product constant) is the equilibrium between a solid and its respective ions in a solution. The value of the constant identifies the degree to which the compound can dissociate in water. The higher the Ksp the more soluble the compound is.
Bismuth is a large ion and sulphur is a small ion, the attractive forces between them are high thus the solubility is high. The solubility product can be calculated as :
$Bi _2S _3$
$K _sp = 1 \times 10^{-17}$
$K _sp = [Bi]^2 [S]^3$
$1 \times 10^{-17} = (2x)^2 (3x)^3 = 108x^5$
$x^5 = \dfrac{1 \times 10^{17}}{108} = 0.000156M $

The solubility of $Ag _{2}CO _{3}$ in water is $1.26 \times 10^{-4}$ mole/litre. What is solubility in 0.02 M $Na _{2}CO _{3}$ solution?
Note : Assume no hydrolysis of $CO _{3}^{2-}$ ion. (Take $\sqrt[3]{2} = 1.26$).

  1. $5 \times 10^{-6}$M

  2. $\sqrt{50} \times 10^{-6}$M

  3. $10^{-5}$M

  4. $2 \times 10^{-5}$M


Correct Option: C

$PbCl _2$ has maximum concentration of $1.0 \times 10^{-3}$ M in its saturated aq. solution at $25^0$C. Its solubility in $0.1$M NaCl solution will be : 

  1. $4 \times 10^{-7}$M

  2. $4 \times 10^{-9}$M

  3. $2 \times 10^{-7}$M

  4. $2 \times 10^{-9}$M


Correct Option: A
Explanation:

In saturated aqueous solution :
Maximum concentration in saturated aqueous solution is the solubility (S) of $\displaystyle PbCl _2$

$\displaystyle S=1.0 \times 10^{-3} \ M$

$\displaystyle [PbCl _2]=[Pb^{2+}]=S=1.0 \times 10^{-3} \ M$

$\displaystyle [Cl^-]=2 \times [PbCl _2]= 2 \times  S= 2 \times  1.0 \times 10^{-3} \ M=2.0 \times 10^{-3} \ M$

$\displaystyle K _{sp}=[Pb^{2+}] \times [Cl^-]^2$

$\displaystyle K _{sp}=1 .0 \times 10^{-3} \times [2.0 \times 10^{-3}]^2$

$\displaystyle K _{sp}=4.0 \times 10^{-9}$

In 0.1 M NaCl solution:

$\displaystyle [Cl^-]=[NaCl]=0.1 \ M$

Assuming $Cl^-$ ion from $PbCl _2$ is negligible

$\displaystyle K _{sp}=[Pb^{2+}] \times [Cl^-]^2$

$\displaystyle 4.0 \times 10^{-9}=[Pb^{2+}] \times [0.1]^2$

$\displaystyle [Pb^{2+}]=4.0 \times 10^{-7}  \ M$

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