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Operations on measurements - class-V

Description: operations on measurements
Number of Questions: 21
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Tags: maths problems on measurement measurement of length, mass and capacity capacity weight and volume equal sharing many more litres length how much does it weigh? weight
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Simplify : $4 \times 4 - 2 \times 3 + 16 + 4 =$

  1. $20$

  2. $13/2$

  3. $30$

  4. None of these


Correct Option: C
Explanation:
$ 4\times 4-2\times 3+16+4 $
Using BODMAS Rule (BBracket, O of D Diviion,
M Multiplication, A Addition, S Subtraction) we get 
$ = 16-6+16+4 $
$ = 16-6+20 $
$ = 36-6 $
$ = 30 $ 

Divide $4\ kg\ 64\ g$ by $4$.

  1. $1.16\ kg$

  2. $10.16\ kg$

  3. $1.016\ kg$

  4. $101.6\ kg$


Correct Option: C
Explanation:

$1\ \ kg=1000g$

$\Rightarrow 1\ \ g=\dfrac{1}{1000}\ \ kg$
$4\ \ kg\ \ 64\ \ g=4+\dfrac{64}{1000}=4.064\ \ kg$
$\dfrac{4.064}{4}=1.016\ \ kg$
Option $C$ is correct.

Vineet packed $\dfrac {3}{4} kg$ of sugar each into $42$ plastic bags. Find the total weight of sugar Vineet packed.

  1. $34.5\ kg$

  2. $3.45\ kg$

  3. $31.5\ kg$

  4. $345\ kg$


Correct Option: C
Explanation:

Weight of sugar in $1\ bag = \dfrac {3}{4} kg$
$\therefore$ Weight of sugar in $42$ bags
$= \left (\dfrac {3}{4}\times 42\right ) kg = \dfrac {63}{2} kg = 31.5\ kg$.

What is $2:15+2:00$ in minutes and hours?

  1. $2$ hrs $15$ minutes

  2. $2$ hrs $45$ minutes

  3. $4$ hrs $45$ minutes

  4. $4$ hrs $15$ minutes


Correct Option: D
Explanation:

$2:15+2:00$

$=4:15$
So it is $4$ hours and $15$ minutes.

What is $3:13 A.M.+1:15 A.M. =$ ?

  1. $4:28 A.M.$

  2. $3:28 A.M.$

  3. $5:08A.M.$

  4. $1:15A.M.$


Correct Option: A
Explanation:

$3:13 A.M.+1:15A.M.$

$=4:28 A.M.$
Option $A$ is correct.

Calculate the time $1:30+4:45$.

  1. $5:15$

  2. $5:45$

  3. $6:15$

  4. $6:45$


Correct Option: C
Explanation:

$1:30+4:45$

Adding hours $=1+4=5$ hours
Adding minutes $30+45=75$ minutes
Now $60$ minutes $=1 $ hour
$\therefore 75$ minutes $=1$ hour $+15$ minutes
So total time is $(5+1=6)$ hours and  $15$ minutes 
$=6:15$

If Tina weighs $\dfrac{2}{3}$times than Reema and Reema weighs $45$ kg, then Tina's weight is

  1. $45$

  2. $30$

  3. $15$

  4. $50$


Correct Option: B
Explanation:

Weight of Reema $=w=45\ \ Kg$

Weight of Tina $=\dfrac{2}{3}w=\dfrac{2}{3}\times{45}=30\ \ Kg$
Option $B$ is correct.

What is $3:50-2:45$ ? 

  1. $1:00$

  2. $1:05$

  3. $1:15$

  4. $1:25$


Correct Option: B
Explanation:

$3:50-2:45$

Subtracting hour from hour and minutes from minutes 
$\Rightarrow 1:05$
So option $B$ is correct.

What is $4:15-3:30$ ?

  1. $00:45$

  2. $-1:15$

  3. $-00:15$

  4. $1:15$


Correct Option: A
Explanation:

$4:15$

$=4\times 60+15$ minutes
$=255$ minutes
$3:30$
$=3\times 60+30$ minutes
$210$ minutes
$\therefore 4:15-3:30=255-210=45$ minutes
So time is $00:45$

Gabriel watched $3$ old movies on videotape. The first movie was $62$ minutes long. The
second was $1$ hour $34$ minutes long. The third was $1$ hour $25$ minutes long. He started
watching at $3:15$ P.M. At what time did the last movie end?

  1. $7:00$ P.M.

  2. $7:08$ P.M.

  3. $7:12$ P.M.

  4. $7:16$ P.M.


Correct Option: D
Explanation:

First movie $62$ min.

Second movie $94$ min
Third movie $85$ min
so total time of movie will be $241$ minutes
which makes $4$ hours and 1 minute
So he should finish $3:15 + 4:01$ = $7:16 $ P.M.

The ratio at which the point $(5,4)$ divides the line $(3,2)$ and $(8,7)$

  1. $\dfrac 23$

  2. $\dfrac{-3}{2}$

  3. $\dfrac{1}{2}$

  4. $\dfrac{1}{9}$


Correct Option: A
Explanation:
Given points $(3,2);(8,7)$
Let the ratio be $m:n$
The dividing point is given as $\dfrac{8m+3n}{m+n}=5\\8m+3n=5m+5n\\3m=2n\\\dfrac mn=\dfrac 23$

Mr Sahoo attended a 1-day workshop from 09:15 a.m. to half five in the evening. The workshop included a $1\frac{1}{4}$ hour lunch break, two 15 minutes tea breaks and 13 activities, each of equal duration. Calculate the duration of each activity.

  1. $30$ minutes

  2. $20$ minutes

  3. $25$ minutes

  4. $40$ minutes


Correct Option: A
Explanation:

Total time of the workshop =$8$ hours and $15$ min

$=8 \times 60+15=495 $ min

Total time of tea break = $30$ min

lunch break time = $75$ min

hence time available for 13 activities 
$=495-75-30$ $=6$ hours and $30$ min
$=390 $ min

So, time devoted to each activity $=\dfrac{390}{13}=30$ min

The greatest length which may be used to measure exactly $\displaystyle13\frac{3}{4}:ft$., $\displaystyle17\frac{1}{2}$., 20 ft. and $\displaystyle21\frac{1}{4}:ft$. is given by

  1. 3"

  2. 15"

  3. 18"

  4. 21"


Correct Option: B
Explanation:

$\displaystyle13\frac{3}{4}:ft=165:inches$

$\displaystyle17\frac{1}{2}:ft=210:inches$ 

$20:ft=240:inches$ 

and $\displaystyle21\frac{1}{4}:ft=255:inches$ 

In order to find the greatest length we have to find the G. C. M. of 165", 210", 240" and 255" and the G. C. M. of these four numbers is 15".

One inch is equivalent to $2.54$ cm. How many centimeters are in two feet? Round your answer to two decimal places.

  1. $5.08$ cm

  2. $12.62$ cm

  3. $60.96$ cm

  4. $30.48$ cm


Correct Option: C
Explanation:

First convert 2 feet to inches and then convert the result to centimeters. One foot is equivalent to 12 inches, so there are 24 inches in 2 feet. Since there are 2.54 cm in a foot, multiply 24 by 2.54 to convert feet to centimeters.
$24$ $\times$ $2.54 = 60.96$
Therefore, there are $60.96$ cm in $2$ feet.

Subtract $778\ m\ 78\ cm$ from $2\ km\ 768\ cm$

  1. $1228.9\ m$

  2. $571.1\ m$

  3. $1221.988\ m$

  4. $189.22\ m$


Correct Option: A
Explanation:

First we have to convert both the quantities in $m$

$1\ \ m=100\ \ cm$
$\Rightarrow 1\ \ cm=.01 \ m$
$778 \ \ m\ \ 78\ \ cm =778+.01\times 78=778.78\ \ m$
$1\ \ km=1000\ \ m$
$2\ \ km\ \ 768\ \ cm =2\times1000+.01\times768=2007.68\ \ m$
Now subtracting both 
$2007.86-778.8=1128.9\ \ m$
Option $A$ is correct.

Add $1.25\ cm$ and $13.45\ cm$

  1. $2.595$

  2. $1.470$

  3. $14.70$

  4. $25.95$


Correct Option: C
Explanation:

$1.25\ \ cm+13.45\ \ cm=14.70\ \ cm$

So option $C$ is correct.

Subtract :
$23.67\ m$ from $1.4\ km$

  1. $116.33$

  2. $1376.33\ m$

  3. $13976.33\ m$

  4. $22.27\ m$


Correct Option: B
Explanation:

First we have to convert $km$ into $m$

$1\ \ km=1000\ \ m$
$\Rightarrow 1.4\ \ km=1.4\times1000=1400\ \ m$
Now subtracting both
$1400 \ \ m-23.67\ \ m=1376.33\ \ m$
So option $C$ is correct.

Add $23.456\ m$ and $26.5\ cm$ .

  1. $499.56\ cm$

  2. $49.956\ cm$

  3. $237.16\ cm$

  4. $2372.6\ cm$


Correct Option: D
Explanation:
First we have to convert $m$ into $cm$
$1\ \ m=100\ \ cm$
$\Rightarrow 23.456\ \ m=23.456\times100=2345.6\ \ cm$
Now adding both
$2345.6\ \ cm+26.5\ \ cm=2372.6\ \ cm$
None of the options are correct

A pole is painted yellow and black. The yellow part is $1.8\ m$ long and the black is three times longer than yellow part. Find the length of pole.

  1. $5.4\ m$

  2. $7.2\ m$

  3. $3.6\ m$

  4. $none\ of\ these$


Correct Option: B
Explanation:

Length of yellow Part $=Y=1.8m$

Length of Black Part $=3Y=5.4m=B$
So, Length of Pole $=L=Y+B=1.8+5.4=7.2m$

Rita had $\displaystyle 38\frac { 1 }{ 4 } $ m long rope. She cut it into 5 equal parts. Then the length of each piece will be- 

  1. $\displaystyle 1\frac { 1 }{ 4 } $ m

  2. $\displaystyle 2\frac { 3 }{ 4 } $ m

  3. $\displaystyle 3\frac { 1 }{ 4 } $ m

  4. $\displaystyle 1\frac { 3 }{ 4 } $ m


Correct Option: D
Explanation:

Length of the rope $\displaystyle= 8\dfrac { 3 }{ 4 } m\ Number\quad of\quad peices\quad cut\quad =5\ Length\quad of\quad each\quad peice\quad =8\dfrac { 3 }{ 4 } m\div 5=\dfrac { 35 }{ 4 } m\times \dfrac { 1 }{ 5 } \ =\left( \dfrac { 35 }{ 4 } \times \dfrac { 1 }{ 5 }  \right) m=\dfrac { 7 }{ 4 } m=1\dfrac { 3 }{ 4 } m\ \therefore The\quad length\quad of\quad each\quad piece\quad of\quad the\quad rope\quad =1\dfrac { 3 }{ 4 } m.$

If Harry runs $23\ m\ 5\ cm$ and Joy runs $14.37\ m$ from the same starting point, then how far is Joy from Harry.

  1. $8.68\ m$

  2. $9.13\ m$

  3. $86.8\ m$

  4. $91.3\ m$


Correct Option: A
Explanation:

We low that $1 m=100 cm$

Hence distance run by Harry $=23 m + 5 cm\=23 m+ \dfrac{5}{100} m\=23.05 m$
Distance run by Joy $=14.37 m$
Distance between them $=23.05 m -14.37 m\=8.68 m$
                                                 

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